Array of Struct - c++

Question

I want to just hard code these values into a table. when I try to use 2D arrays, I run into the problem of dealing with characters and integers. When I do a struct I have this so far but it doesn't divide the information up in columns, and I'm not sure how to format it that way. (I only did 3 rows to start off with, if I get them working, the rest will just be the same)
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
typedef struct table
{
std::string game;
int year;
float rating;
int num_voters;
}t;
void processTab(t*);
int main()
{
t tabl[2] = {0,0};
int i;
processTab(tabl);
for(i=0; i<2; i++)
{
std::cout << "Game: " << setw(20) << tabl[i].game;
std::cout << "\tYear: " << setw(4) << tabl[i].year;
std::cout << "\tRating: " << fixed << setprecision(2) << tabl[i].rating;
std::cout << "\tVoters: " << setw(6) << tabl[i].num_voters;
}
system("pause");
return 0;
}
void processTab(t*tab)
{
(tab[0].game, "twilight struggles");
tab[0].year = 2005;
tab[0].rating = 8.226;
tab[0].num_voters = 10690;
(tab[1].game, "Agricloa");
tab[1].year = 2007;
tab[1].rating = 8.17;
tab[1].num_voters = 23738;
(tab[2].game, "Puerto Rico");
tab[2].year = 2002;
tab[2].rating = 8.163;
tab[2].num_voters = 27433;
}
Table Data:
Game (0) Year (1) Rating (2) Num Voters (3)
Twilight Struggle 2005 8.226 10690
Agricola 2007 8.17 23738
Puerto Rico 2002 8.163 27433
Through the Ages 2006 8.153 8137
Power Grid 2004 8.02 21655
Le Havre 2008 7.972 9258
Eclipse 2011 7.968 3194
Brass 2007 7.911 5814
Dominion: Intrigue 2009 7.895 10889
Caylus 2005 7.878 13878

Answer 1

What I think you are looking for is <iomanip>
#include <iomanip>
std::cout << "Game: " << setw(20) << tabl[i].game;
std::cout << "\tYear: " << setw(4) << tabl[i].year;
std::cout << "\tRating: " << fixed << setprecision(3) << tabl[i].rating;
std::cout << "\tVoters: " << setw(6) << tabl[i].num_voters;
std::cout << std::end;
Notes:
setw adds padding when writing out stuff, so it will always be at least a certain width
setprecision specifies how many decimal places to display
fixed makes floating point never use scientific notation
Your game member is a letter, and you're attemptying to assign it a string. Don't use strcpy in C++, use the std::string class instead.
#include <string>
struct table
{
std::string game;
int year;
double rating;
int num_voters;
};
Avoid using namespace std;, when you get to complex code with many namespaces, those few letters are a small price to pay for avoiding confusion.
Avoid endl: it flushes buffers which is slow. If you just want a newline, use '\n'.
Also, you can use the new initialization syntax to initialize your list:
std::vector<table> tbal = {
{"twilight struggles ", 2005, 8.226, 10690},
{"Agricola ", 2007, 8.17 , 23738},
{"Puerto Rico ", 2002, 8.163, 27433}
};

Answer 2

Short answer: use std::vector, not a raw array.
The following is as close to your original code as I could make it, introducing a minimum number of new features for you:
#include <assert.h> // assert
#include <iostream> // std::cout, std::endl
#include <stddef.h> // ptrdiff_t
#include <string> // std::string
#include <utility> // std::begin, std::end
#include <vector> // std::vector
using namespace std;
typedef ptrdiff_t Size;
template< class Container >
Size countOf( Container& c ) { return end( c ) - begin( c ); }
struct Game
{
string game;
int year;
double rating;
int num_voters;
};
void initialize( vector<Game>& games )
{
assert( countOf( games ) == 0 );
games.resize( 3 );
games[0].game = "twilight struggles";
games[0].year = 2005;
games[0].rating = 8.226;
games[0].num_voters = 10690;
games[1].game = "Agricloa";
games[1].year = 2007;
games[1].rating = 8.17;
games[1].num_voters = 23738;
games[2].game = "Puerto Rico";
games[2].year = 2002;
games[2].rating = 8.163;
games[2].num_voters = 27433;
}
int main()
{
vector<Game> games;
initialize( games );
for( int i = 0; i < countOf( games ); ++i )
{
cout << i << endl;
cout <<"\tGame: " << games[i].game << endl;
cout<<"\tYear: " << games[i].year << endl;
cout<<"\trating: " << games[i].rating << endl;
cout<<"\tnum voters: " << games[i].num_voters << endl;
}
}
There are ways to just declare the data more directly, including brace initializers; check out your C++ textbook.

Answer 3

First you need to define your table (bad name for a struct, by the way) correctly. You're trying to use game to store a string, but have defined it as only a single char. You probably want to change that to a std::string instead.
Then you probably want to do your formatting in an operator<< overloaded to take a reference to table as the type. #MooingDuck has already covered the formatting itself quite well, so it's mostly a matter of how you package that:
std::ostream &operator<<(std::ostream &os, table const &t) {
os << "Game: " << setw(20) << t.game;
os << "\tYear: " << setw(4) << t.year;
os << "\tRating: " << fixed << setprecision(2) << t.rating;
return os << "\tVoters: " << setw(6) << t.num_voters;
}
Along with that, you almost certainly want to change tabl from an array to std::vector<table>:
std::vector<tabl> tabl;
Then processing the table becomes:
std::copy(tabl.begin(), tabl.end(), std::ostream_iterator<table>(std::cout, "\n"));
One other minor detail: you seem to have two entirely different/separate functions, both named processTab. You probably want to rename at least one of those. Just glancing at them, I'd probably call one initializeTable or something on that order.