Error when changing a vector value in a class - c++

I am attempting to change a value in a vector which is a variable in a class using a function of a class. When I compile, i get the following errors pointing to the "check[c] = cval;" line:
error C3867: 'acc::check': function call missing argument list; use '&acc::check' to create a pointer to member
error C2109: subscript requires array or pointer type
Note: I have already initialized C to be 0 elsewhere in the program. It might be throwing an error because I am giving the address a variable instead of an integer, but when I substitute the variable with an integer, I still get the same errors.
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <cstring>
using namespace std;
class acc
{
public:
void add_Cval(double cval);
private:
vector<double> check(); //vector of all checks
int c; //loop marker for cvals
};
void acc::add_Cval(double cval)
{
check[c] = cval;
c++;
}

vector<double> check(); isn't what you think it is. You just declared a function named check that returns a vector<double>. Get rid of the parenthesis like so vector<double> check;.
Also, your vector<double> is empty, you need to give it some space if you want to do check[c] = cval; (or use check.push_back(cval); instead), allocate the space in the constructor (use "initialization lists" as that is what they are for):
Example:
acc(int vecsize) : check(vecsize), c(0) {}
You might also want to make sure check[c] is a valid position in the vector before assigning anything to it.

check is a method, not a data member, so you need to invoke it - check().
void acc::add_Cval(double cval)
{
check()[c] = cval;
c++;
}
or make it a data member:
class acc
{
public:
void add_Cval(double cval);
private:
vector<double> check; //vector of all checks
int c; //loop marker for cvals
};

The compiler is looking for a function called check() that returns a vector of type double.
private:
vector<double> check(); // A private function that returns a vector of type <double>
Needs to be:
private:
vector<double> check; // A private data member

Related

C++ Vectors with pre-determined size throwing compile errors

I am very new to C++ and trying to create a simple Student class with a vector of scores of type int.
Here's my class:
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <fstream>
#include <sstream>
using namespace std;
class Student {
string last;
string first;
vector<int> scores(10);
public:
Student():last(""), first("") {}
Student(string l, string f) {
last = l;
first = f;
}
~Student() {
last = "";
first = "";
}
Student(Student& s) {
last = s.last;
first = s.first;
scores = s.scores;
}
Student& operator = (Student& s) {
last = s.last;
first = s.first;
scores = s.scores;
return *this;
}
void addScore(int n) {
scores.push_back(n);
}
};
For some reason, I'm getting multiple reference to non-static member function must be called; did you mean to call it with no arguments in reference to the vector scores.
Here's my full list of errors:
main.cpp:15:22: error: expected parameter declarator
vector<int> scores(10);
main.cpp:15:22: error: expected ')'
main.cpp:15:21: note: to match this '('
vector<int> scores(10);
main.cpp:30:4: error: reference to non-static member function must be called; did you mean to call it with no arguments?
scores = s.scores;
main.cpp:35:4: error: reference to non-static member function must be called; did you mean to call it with no arguments?
scores = s.scores;
main.cpp:35:15: error: reference to non-static member function must be called; did you mean to call it with no arguments?
scores = s.scores;
main.cpp:40:4: error: reference to non-static member function must be called; did you mean to call it with no arguments?
scores.push_back(n);
I've tried many things but still have no idea where these errors are coming from. I'm very new to C++, so please forgive me. Any help would be appreciated.
You can't initialize a data member like this:
vector<int> scores(10);
You need one of these forms instead:
vector<int> scores = vector<int>(10);
vector<int> scores = vector<int>{10};
vector<int> scores{vector<int>(10)};
The reason is to avoid initializations that could look like function declarations. Note that this is syntactically valid:
vector<int>{10};
but it initializes the vector to have size 1, with a single element with value 10.
You can't call a constructor in member definition of your class; you need to call it from the initialiser list:
class Student {
string last;
string first;
vector<int> scores;
public:
Student():last(""), first(""), scores(10) {}
Edit At least this was the way pre c++11...
You should use initialization list for this case:
Student():scores(10) {}
What is the reason to create vector with 10 elements if you use push_back() next in the code ?
void addScore(int n) {
scores.push_back(n);
}
This code adds 11th element to the vector. Is it the correct behavior for your project?

passing an array into a class function from another class's constructor

Sorry for the confusing title, basically I have created two classes, one is an object, and the other being a box that contains an array of such objects. so what I want to do is create a function/constructor inside the object class that takes in an array of ints and stores them inside the box. I want to be able to call this function through the box class constructor to initialize these objects. So ive tried something like below but it isnt working at all, since only the first value of the array gets passed through. What am I doing wrong?
#include <iostream>
#include <string>
class object{
string objectName;
int values[];
public:
void createObject(int[]);
}
class Box{
object objects[100];
public:
Box();
}
Box::Box (void){
int array1[2];
int array2[15];
object[1].createObject(array1);
object[2].createObject(array2);
}
Object::Object(int Values[]){
values = Values;
}
You should really use std::vector. The problem with arrays is that they decay to pointers when passed as arguments to functions. As a consequence, If you want to store a private copy of the elements you are forced to use heap-allocated objects and consequently do memory management by hand (with all the pain it causes).
It is much better to rely on data members that permit applying the rule of zero.
Here's a tentative solution:
#include <iostream>
#include <string>
#include <vector>
class object {
public:
object(std::vector<int> const& v, std::string const& object_name): v_(v.begin(), v.end()), object_name_(object_name) {}
private:
std::vector<int> v_;
std::string object_name_;
};
class box {
public:
box(std::vector<object> const& objects): objects_(objects) {};
private:
std::vector<object> objects_;
};
I recommend you instead use a std::vector. Arrays don't really work well being passed to functions. When you define Object::Object(int Values[]) you are simply passing the first element of this array by value. If you were to use vectors, the function would look like this:
Object::Object(std::vector<int> &Values):
values(Values)
{
}
The problem with the code is in your thinking on what the array is. In C++, all an array is, is a memory pointer. The language allows you to pass an index into the array pointer to access whatever chunk of data lives at that index.
Whenever you pass arrays between functions or classes, pass the array name only. It will be interpreted as a pointer, and won't copy any data. When you do this, you must also pass the length of the array.
Granted, most people stick with vector<> because it's easier, takes care of memory leaks (mostly) and is VERY efficient. But I like doing it myself. It's good for you. I would try:
#include <iostream>
#include <string>
class Object
{
string _objectName;
int *_values;
int _myLength;
Object();
~Object();
void createObject(int *pValues, int arrLength);
}
class Box
{
_Object objects[100];
Box();
}
Box::Box(void) {
int array1[2];
int array2[15];
object[1].createObject(array1, 2);
object[2].createObject(array2, 15);
}
Object::Object() {
_values = null_ptr;
_myLength = 0;
}
Object::~Object() {
delete[] _values;
}
void Object::createObject(int *pvalues, int arrLength) {
_myLength = arrLength;
_values = new int[_myLength];
for(int ndx=0; ndx<arrLength; ndx++) {
_values[ndx] = pvalues[ndx];
}
}
-CAUTION-
I just adapted your code you provided, and added some conventions. There are a couple places in the code where I'm not sure what the purpose is, but there you go. This should give you a good head start.

C++ - Return multidimensional array from function

I am writing a code for Cellular Automata and I need an evolution function to calculate the state of the automata after a time step.
I choose to call this function evol, to test it I created an elementary function in C++. Unfortunately it does not compile since the compiler cannot understand that I need it to return an array. Here is the code :
#include <iostream>
#include <cmath>
#include <vector>
#include <string>
using namespace std;
const int N = 51; // Size of the grid; two columns/rows are added at the beginning and the end of the array (no evolution of the CA on the boundaries)
class Cell{
//defining whats a cell here
};
void showCA(Cell CA[N+2][N+2]){
//function to print the CA grid in the terminal
}
Cell[N+2][N+2] evol(Cell CA[N+2][N+2]){
return CA;
}
int main()
{
// Initialisation
cout << "Initialisation" << endl;
static Cell CA[N+2][N+2];
// some code here to initialize properly the Cell array.
showCA(CA);
CA = evol(CA);
showCA(CA);
return 0;
}
The compiler returns this error :
error: expected unqualified-id
Cell[N+2][N+2] evol(Cell CA[N+2][N+2]){
Any idea on how I should implement this ?
You cannot return arrays from functions:
§ 8.3.5/8
Functions shall not have a return type of type array or function, although they may have a return type of type pointer or reference to such things.
If you are wishing to return raw, C-style arrays from functions, then you have to use a reference or pointer. For example, here's how it is done using a reference (you can do the same using a pointer by replacing & with *):
Cell (&evol(Cell (&CA)[N+2][N+2]))[N+2][N+2];
However, this is very unintuitive and hard to read. If your compiler supports the latest standard (C++11) the return type can be cleaned up using a trailing return type:
auto evol(Cell (&CA)[N+2][N+2]) -> Cell(&)[N+2][N+2];
But again, this is probably still harder to read.
C++11 facilitates the handling of C-style arrays with the container std::array<>. Non-C++11 code should use std::vector<>:
using Cells = std::array<std::array<Cell, N+2>, N+2>;
Cells const& evol(Cells const& CA);
You can use
typedef std::vector<std::vector<Cell>> CellArray;
CellArray Cells(N+2); // resize main dimension
for (size_t i=0; i<N+2; i++)
Cells[i].resize(N+2); // resize all cells of main dimension
to hold your cell array, but you also need to add a copy constructor and operator= in Cell class
class Cell {
public:
Cell() { ... default ctor code here ... }
Cell(const Cell &c) { *this = c; }
Cell &operator=(const Cell&c)
{
if (this != &c)
{
... copy data from c members to this members here ...
}
return *this;
}
};
Your evol function then can return a CellArray:
CellArray evol(CellArray &c)
{
CellArray r;
... do some calculations with c and r ...
return r;
}
once you have declared a variable using the array syntax like you have:
Cell CA[N+2][N+2];
you cannot assign CA to be something else. You can only assign values to its contents. Hence,
CA = evol(CA);
is wrong.
You can do the following:
Cell (*CA2)[N+2] = evol(CA);
As the number of elements seems to be fixed, I suggest you use the std::array container:
const int N = 51;
typedef std::array<std::array<Cell,N+2>, N+2> datatype;
You can then use this type as a return type:
datatype Evol( const datatype& d );
You can access elements just as if it was a "C" array:
datatype d;
Cell c;
d[10][20] = c;
I would strongly suggest encapsulate your array into a class. You cannot return an array, but you can return an object that contains an array.

Error with implement map within template c++

I need to use a map with various type within es int,int or char,int or char,char....
This is my c++ code:
#include <iostream>
#include<map>
using namespace std;
template< class A, class B >
class MyClass {
private:
std::map<A,B> DatMap;
public:
MyClass<K,T>(){
DatMap = 0;
}
~MyClass(){
delete DatMap;
}
void DatInsert( A k ,B v ) {
DatMap.insert( std::pair<A,B>( k, v) );
}
};
int main(){
DatMap<int,int> datmap1();
diz1.DatInsert();
}
I found this error on: diz1.DatInsert(); line
the error is:
error: request for member ‘DatInsert’ in ‘datmap1’, which is of non-class type ‘DatMap<int, int>()’|
What am I doing wrong?
This is a function declaration:
// functon datamap1, returns DatMap<int, int>
DatMap<int,int> datmap1();
You need
DatMap<int,int> datmap1;
Alternatively, this syntax is valid since C++11
DatMap<int,int> datmap1{};
Vlad and Jauncho make good points but have both missed another error
DatMap<int,int> datmap1(); isn't valid also because there is no public type DatMap exposed. The class is MyClass
You should be saying:
MyClass<int,int> datmap1; // or datmap1{};
There are several errors in the code.
For example identifiers K and T used in this code snippet
MyClass<K,T>(){
DatMap = 0;
}
are undefined. Also the assignment DataMap by zero is invalid.
You shall not delete DatMap in destructor
~MyClass(){
delete DatMap;
}
because DatMap is not a pointer.
These both statements in main
DatMap<int,int> datmap1();
diz1.DatInsert();
are invalid. The first one is a declaration of a function that shall not be compiled. And the second statement contains call of member function DatInsert without arguments. You defined the function as having two parameters
void DatInsert(A k ,B v){
DatMap.insert(std::pair<A,B>(k,v));
}
so you need to provide two arguments.

passing vector to function c++

I have a main.cpp test.h and test.cpp> I am trying to pass my vector through so i can use it in test.cpp but i keep getting errors.
//file: main.cpp
int main(){
vector <Item *> s;
//loading my file and assign s[i]->name and s[i]-address
tester(s);
}
//file: test.h
#ifndef TEST_H
#define TEST_H
struct Item{
string name;
string address;
};
#endif
//file: test.cpp
int tester(Item *s[]){
for (i=0; i<s.sizeof();i++){
cout<< s[i]->name<<" "<< s[i]->address<<endl;
}
return 0;
}
---------------errors--------
In file included from main.cpp:13:
test.h:5: error: âstringâ does not name a type
test.h:6: error: âstringâ does not name a type
main.cpp: In function âint main()â:
main.cpp:28: error: cannot convert âstd::vector<Item*, std::allocator<Item*> >â to âItem**â for argument â1â to âint tester(Item**)â
A std::vector<T> and T* [] are not compatible types.
Change your tester() function signature as follows:
//file: test.cpp
int tester(const std::vector<Item>& s) // take a const-reference to the std::vector
// since you don't need to change the values
// in this function
{
for (size_t i = 0; i < s.size(); ++i){
cout<< s[i]->name<<" "<< s[i]->address<<endl;
}
return 0;
}
There are several ways you could pass this std::vector<T> and all have slightly different meanings:
// This would create a COPY of the vector
// that would be local to this function's scope
void tester(std::vector<Item*>);
// This would use a reference to the vector
// this reference could be modified in the
// tester function
// This does NOT involve a second copy of the vector
void tester(std::vector<Item*>&);
// This would use a const-reference to the vector
// this reference could NOT be modified in the
// tester function
// This does NOT involve a second copy of the vector
void tester(const std::vector<Item*>&);
// This would use a pointer to the vector
// This does NOT involve a second copy of the vector
// caveat: use of raw pointers can be dangerous and
// should be avoided for non-trivial cases if possible
void tester(std::vector<Item*>*);
Pass it as std::vector<Item *> & (reference to vector) and use iterator to iterate through it.
You should #include <string>.
string name should read std::string name etc. Same goes for std::vector.
You're calling tester() with a vector, yet it expects an array (the two are not interchangeable).
s.sizeof() is incorrect for both an array and a vector; for the latter, use s.size() or, better yet, use an iterator.
These are just the errors that immediately jump out; there may be more.
A vector is not an array.
int tester(vector<Item *> &s)
(pass as a reference to avoid copying or if you need to modify)
You also need to modify your code inside the tester function to work correctly as a vector.
You should fix
test.h:5: error: âstringâ does not name a type
first, probably by using namespace std; and #include <string>
You are missing includes
#include <string>
#include <vector>
and you need to use std::string and std::vector<>. A std::vector is not an array, so you should pass the vector as reference
int tester(std::vector<Item*> & vec) { //... }
or even as const std::vector<Item*> & if you are not going to modify the passed vector.
Also, are you sure, that you'll need a vector of pointers? What are you trying to achieve?