Checking whether a number exist in the same row or column - c++

Question

I have been staring at this code for few hours, tried walkthrough,debugging with autos and breakpoints and it's no solution so far. Maybie someone's fresh look would help me ;) .
#include <iostream>
using namespace std;
int matrix[9][9] = {{0, 0, 6, 0, 0, 0, 1, 0, 5},
{0, 4, 0, 7, 0, 6, 0, 3, 9},
{2, 0, 0, 9, 3, 0, 6, 0, 0},
{7, 0, 0, 1, 8, 0, 5, 0, 4},
{0, 0, 4, 0, 6, 0, 9, 0, 0},
{1, 0, 9, 0, 5, 2, 0, 0, 3},
{0, 0, 1, 0, 9, 3, 0, 0, 7},
{6, 7, 0, 5, 0, 8, 0, 9, 0},
{9, 0, 8, 0, 0, 0, 4, 0, 0}};
bool check(int column ,int row,int checkedValue)
{
//column check
for(int i=0; i<9; i++)
{
if(i==row)continue;
if(checkedValue==matrix[column][i]) return false;
}
//row check
for(int i=0; i<9; i++)
{
if(i==column) continue;
if(checkedValue==matrix[i][row]) return false;
}
return true;
}
int main()
{
cout<<check(4,0,4); //Why does it output 0? There is no "4" in the 5th column and the 1st row.
system("pause");
return 0;
}
The function check(column,row,value) was designed to return 0 when number occurs at least once in the "matrix" two dimensional table. This program is a chunk of sudoku solver.

Answer 1

You mixed the indices up in the if statements. They should be:
if(checkedValue==matrix[i][column]) return false; // not matrix[column][i]
and
if(checkedValue==matrix[row][i]) return false; // not matrix[i][row]
The reason is that the first dimension is the row. You can check this by printing matrix[2][0].
For your matrix, you will get 2 (and not 6).