Call method right after blocking call - c++

Question

I'm using a third party library which has a blocking function, that is, it won't return until it's done; I can set a timeout for that call.
Problem is, that function puts the library in a certain state. As soon as it enters that state, I need to do something from my own code. My first solution was to do that in a separate thread:
void LibraryWrapper::DoTheMagic(){
//...
boost::thread EnteredFooStateNotifier( &LibraryWrapper::EnterFooState, this );
::LibraryBlockingFunction( timeout_ );
//...
}
void LibraryWrapper::EnterFooState(){
::Sleep( 50 ); //Ensure ::LibraryBlockingFunction is called first
//Do the stuff
}
Quite nasty, isn't it? I had to put the Sleep call because ::LibraryBlockingFunction must definitely be called before the stuff I do below, or everything will fail. But waiting 50 milliseconds is quite a poor guarantee, and I can't wait more because this particular task needs to be done as fast as possible.
Isn't there a better way to do this? Consider that I don't have access to the Library's code. Boost solutions are welcome.
UPDATE: Like one of the answers says, the library API is ill-defined. I sent an e-mail to the developers explaining the problem and suggesting a solution (i.e. making the call non-blocking and sending an event to a registered callback notifying the state change). In the meantime, I set a timeout high enough to ensure stuff X is done, and set a delay high enough before doing the post-call work to ensure the library function was called. It's not deterministic, but works most of the time.

Answer 1

Would using boost future clarify this code? To use an example from the boost future documentation:
int calculate_the_answer_to_life_the_universe_and_everything()
{
return 42;
}
boost::packaged_task<int> pt(calculate_the_answer_to_life_the_universe_and_everything);
boost::unique_future<int> fi=pt.get_future();
boost::thread task(boost::move(pt));
// In your example, now would be the time to do the post-call work.
fi.wait(); // wait for it to finish
Although you will still presumably need a bit of a delay in order to ensure that your function call has happened (this bit of your problem seems rather ill-defined - is there any way you can establish deterministically when it is safe to execute the post-call state change?).

Answer 2

The problem as I understand it is that you need to do this:
Enter a blocking call
After you have entered the blocking call but before it completes, you need to do something else
You need to have finished #2 before the blocking call returns
From a purely C++ standpoint, there's no way you can accomish this in a deterministic way. That is without understanding the details of the library you're using.
But I noticed your timeout value. That might provide a loophole, maybe.
What if you:
Enter the blocking call with a timeout of zero, so that it returns immediately
Do you other stuff, either in the same thread or synchronized with the main thread. Perhaps using a barrier.
After #2 is verified to be done, enter the blocking call again, with the normal non-zero timeout.
This will only work if the library's state will change if you enter the blocking call with a zero timeout.