C++ adjacency list of pointers and structs - c++

Working on adjacency list --> directed weighted graph
One class looks like this, i.e. header:
class CGraph;
class CMap {
public:
//voided constructors and destructors
//functions one is:
void SetDirGraph(string commands);
private:
CGraph* m_myMap;
};
Second class:
class CNode {
public:
//voided constructor and desctructor
int m_distance, m_vert;
bool m_isKnown;
};
typedef struct edges {
int v2, weight;
} edge;
class CGraph {
public:
CGraph(int map_size);
~CGraph(void);
void AddMap(int v1, int v2, int weight);
void AddEndVert(int v2, int weight);
private:
list<edge> List;
int size;
public:
CNode* verts;
};
I'm reading vertices from a file, and that works. My problem is I am having trouble creating an adjacency list based on the code given. I'm trying to use pointers first that points to a list and it is not working correctly. I don't know how to create my pointers to the list without writing over them.
void CMap::SetDirGraph(string command) {
istringstream buffer(command)
char ch;
int num, vert1, vert2, weight; //specify vertices and weight and number of vertices
buffer>>ch; //throw away first character (not needed)
buffer>>num // size of vertices
while(!buffer.eof()) { // keep reading until end of line
buffer>>v1; // vertex start
buffer>>v2; // vertex end
buffer>>weight;
m_myMap = new CGraph(map_size); //initialize m_myMap.
m_myMap->verts->m_vert = v1; // mymap->verts->vert points to first edge
m_myMap->AddMap(v1, v2, weight); // create list?
m_myMap->AddEndVert(v2, weight); //create list? push v2 and weight on my list using my list.
}
}
I've tried several different ways and I keep confusing myself, any point in the right direction would be awesome.
EDIT:
I have more code too if needed to be produced, just publishing the main stuff.
What I mean by "not working" is that I am just writing over the previous vertex. I don't know if I should create an array using m_myMap (tried and still writes over and get a memory error as well). No compiler errors.

I don't know how to create my pointers to the list without writing over them.
Apart from your application, the answer to this question is the new operator, which I assume you are aware of, since you used it within your example code. Code like int * a = new int(42); allocates memory for an int on the heap and you are responsible for cleaning it up when it is not needed anymore. You thereby have full control over how long a variable will be available. In int x = 42; int * a = &x; on the other hand, x will automatically be cleaned up when it runs out of scope, and a will be a pointer to a memory block that has no meaningful data in it anymore. If you try to dereference it, you will encounter undefined behavior, and, if you are lucky, your program will blow up.
If you can use the C++11 standard, or a library that offers smart pointers, you should prefer those over managing the pointer yourself whenever possible. A smart pointer is an object that holds the allocated memory and frees it automatically when it is destructed. More specific information depends heavily on which sort of smart pointer you are using. The reason for using smart pointers is that doing the management yourself is tedious and error prone. If you do not delete your pointers you had allocated, your application will keep on allocating more memory until it blows up some day (depending on how often and how much memory you allocate); this is called leaking. If you call delete more than once, your program will bail out as well. Here is an example of C++11 shared_ptr in your application:
class CMap
{
private:
std::shared_ptr<CGraph> m_myMap;
// etc.
};
// in SetDirGraph
m_myMap.reset( // if the smart pointer has previously been managing
// memory, it will free it before allocating new
new CGraph(map_size) // allocate CGraph as before
);
Besides that, what hopefully answers your question, I have run into several potential problems concerning your code:
Definitely wrong:
In SetDirGraph you set m_myMap->verts->m_vert = v1. m_myMap->verts is a pointer. You have freshly created m_myMap and thus verts is not initialized, hence pointing at a random block of memory. You then try to dereference it by m_myMap->verts->m_vert = v1. This cannot work. You need to create verts first, i.e. verts = new CNode;.
typedef struct edges { /* etc */ } edge; is a C construct and there is no need for the typedef wrapper in C++. It does work and all, but it is really redundant and lots of those constructs just pollute the namespace you are working in.
Do you really need pointers in the first place? Your provided snippets do not hint at why you would need to use them. You will want to reduce usage of pointers to a minimum (or at least use smart pointers, see above)

Related

C++ Tree Data Structure

Background:
So I've been porting some of my older Java code to C++, and I've come across an issue that's making proceeding quite difficult. My project uses a tree data-structure to represent the node hierarchy for 3D animation.
Java:
public final class Node {
private final Node mParent;
private final ArrayList<Node> mChildren;
//private other data, add/remove children / parents, etc ...
}
In Java, its quite simple to create a tree that allows for modification etc.
Problem:
I'm running into issues is with C++, arrays cannot easily be added to without manually allocating a new chunk of memory and having the existing ones moved over so I switched to std::vector. Vectors have the issue of doing what I just described internally making any pointers to there elements invalid. So basically if you wan't to use pointers you need a way to back them so memory holding the actual nodes doesn't move. I herd you can use std::shared_ptr/std::unique_ptr to wrap the nodes in the std::vector, and I tried to play around with that approach but it becomes quite unwieldy. Another option would be to have a "tree" class that wraps the node class and is the interface to manipulate it, but than (for my use case) it would be quite annoying to deal with cutting branches off and making them into there own trees and possibly attaching different branches.
Most examples I see online are Binary trees that have 2 nodes rather than being dynamic, or they have many comments about memory leaks / etc. I'm hoping there's a good C++ alternative to the java code shown above (without memory leak issues etc). Also I won't be doing ANY sorting, the purpose of the tree is to maintain the hierarchy not to sort it.
Honestly I'm really unsure of what direction to go, I've spent the last 2 days trying different approaches but none of them "feel" right, and are usually really awkward to manage, any help would be appreciated!
Edit:
An edit as to why shared_ptrs are unwieldy:
class tree : std::enable_shared_from_this<tree> {
std::shared_ptr<tree> parent;
std::vector<std::shared_ptr<tree>> children;
public:
void set_parent(tree& _tree) {
auto this_shared_ptr = shared_from_this();
if (parent != nullptr) {
auto vec = parent->children;
auto begin = vec.begin();
auto end = vec.end();
auto index = std::distance(begin, std::find_if(begin, end, [&](std::shared_ptr<tree> const& current) -> bool {
return *current == this_shared_ptr;
}));
vec.erase(std::remove(begin, end, index), end);
}
parent = std::shared_ptr<tree>(&_tree);
if (parent != nullptr) {
parent->children.push_back(this_shared_ptr);
}
}
};
working with pointers like above becomes really quite verbose, and I was hoping for a more simple solution.
You could store your nodes in a single vector and use relative pointers that are not changed when the vectors are resized:
typedef int32_t Offset;
struct Node {
Node(Offset p) : parent(p) {}
Offset parent = 0; // 0 means no parent, so root node
std::vector<Offset> children;
};
std::vector<Node> tree;
std::vector<uint32_t> free_list;
To add a node:
uint32_t index;
if (free_list.empty()) {
index = tree.size();
tree.emplace_back(parent_index - tree.size());
} else {
index = free_list.back();
free_list.pop_back();
tree[index].parent = parent_index - index;
}
tree[parent_index].children.push_back(index - parent_index);
To remove a node:
assert(node.children.empty());
if (node.parent) {
Node* parent = &node + node.parent;
auto victim = find(parent->children.begin(), parent->children.end(), -node.parent);
swap(*victim, parent->children.back()); // more efficient than erase from middle
parent->children.pop_back();
}
free_list.push_back(&node - tree.data());
The only reason for the difference you're seeing is if you put the objects directly in the vector itself in c++ (which you cannot do in Java.) Then their addresses are bound to the current allocated buffer in the vector. The difference is in Java, all the objects themselves are allocated, so only an "object reference" is actually in the array. The equivalent in c++ would be to make a vector of pointers (hopefully wrapped in smart pointer objects) so the vector elements only are an address, but the objects live in fixed memory. It adds an extra pointer hop, but then would behave more like what you expect in java.
struct X {
char buf[30];
};
std::vector<X> myVec{ X() };
Given the above, the X elements in myVec are contiguous, in the allocation. sizeof(myVec[0]) == sizeof(X). But if you put pointers in the vector:
std::vector<unique_ptr<X>> myVec2{ make_unique<X>() };
This should behave more like what you want, and the pointers will not become invalid when the vector resizes. The pointers will merely be copied.
Another way you could do this would be to change things a little in your design. Consider an alternate to pointers entirely, where your tree contains a vector of elements, and your nodes contain vectors of integers, which are the index into that vector.
vector, forward_list, ..., any std container class (other than built-in array or std::array) may be used.
Your trouble seems to be that java classes are refrence types, while C++ classes are value types. The snippet below triggers "infinite recursion" or "use of incomplete type" error at compiletime:
class node{
node mParent;//trouble
std::vector<node> children;
//...
};
the mParent member must be a reference type. In order to impose reference semantics you can make it a raw pointer:
node* mParent;
you may also use pointer as the argument type to the container, but as a C++ beginer that would most probably lead to memory leaks and wierd runtime errors. we should try to stay away from manual memory management for now. So the I modify your snippet to:
class node{
private:
node* const mParent;
std::vector<node> children;
public:
//node(node const&)=delete;//do you need copies of nodes? you have to properly define this if yes.
node(node *parent):
mParent{parent}{};
void addChild(/*???*/){
children.emplace_back(this);
//...
};
//...
};

Adding of a vertex in graph using adjacency-list in c++

This is how I've defined my graph. This is not a typical graph, it is specific to the type of problem I'm dealing with.
class Vertex;
class Edge
{
public:
Vertex *org;
Vertex *dest;
bool dir;
};
struct Vertex{
int id;
vector<Edge> edges;
int weight;
};
struct Graph{
vector<Vertex> vertices;
};
I'm having problem in adding a vertex in the graph. This is how I'm doing it
Graph* graph1;
Vertex* first = addVertex(0);
graph1->vertices.push_back(*first);
The addVertex function is working properly, but if you still want to refer, here it is
Vertex* addVertex(int id){
Vertex*newVertex = new Vertex;
newVertex->id=id;
newVertex->weight=0;
return newVertex;
}
The function stops working just before graph1->vertices.push_back(*first);
graph1 itself is an unitialized pointer. So, calling it's members is causing the program to crash. Initialize it with new operator.
graph1 = new Graph();
// .......
delete graph1;
Or use a smart pointer like std::unique_ptr to automatically manage memory.
In addition to the uninitialized Graph* graph1, there is another memory management problem in your code:
addVertex allocates a single Vertex in its own block of heap memory. But then
graph1->vertices.push_back(*first);
copies first into the block of memory managed by graph1's std::vector.
I guess that you are new to C++ coming from another language like Java or Python. You should read an introductory C++ book. Memory management in C++ has a lot of pitfalls and concepts to keep track of compared to other languages.

Unable to populate vector inside struct

I'm new to C++ so bear with me.
I made a struct that looks like this:
struct node{
double startPoint;
double endPoint;
vector<node*> children;
void addChild(node *aNode){
children.push_back(aNode);
}
void addPoints(double start, double end){
startPoint = start;
endPoint = end;
}
};
Down the line in my program, I have the following:
vector<node*> data;
....
node *temp = (node*)malloc(sizeof(node));
temp->addPoints(lexical_cast<double>(numbers[0]), lexical_cast<double>(numbers[1]));
data[index]->addChild(temp);
where "Index" is a index of the vector data. the lexical_cast stuff is taking those numbers from string to doubles.
Everything works until the addChild(temp) line.
The terminal spit this out:
First-chance exception at 0x585b31ea (msvcr90d.dll) in Tree.exe: 0xC0000005: Access violation reading location 0xcdcdcdc1.
Unhandled exception at 0x585b31ea (msvcr90d.dll) in Tree.exe: 0xC0000005: Access violation reading location 0xcdcdcdc1.
But I have no idea how to deal with that.
malloc allocates some space, but doesn't put anything in it. It works fine for plain-old-data structures (or trivially initializable classes), and in C that's all you have.
In C++ you have classes, like std::vector amongst others, which need to be properly constructed in order to establish some invariants. This is done with a straight declaration for objects with automatic storage duration, but for dynamically-allocated objects you need to use new instead of malloc.
For example,
std::vector<int> global; // (1)
void foo() {
std::vector<int> local; // (2)
std::vector<int> *bad = malloc(sizeof(*bad)); // (3)
std::vector<int> *good = new std::vector<int>; // (4)
std::unique_ptr<std::vector<int>> better(new std::vector<int>); (5)
}
is fine - this global is initialized (by which I mean the constructor is called) automatically
is fine - this local variable is also constructed automatically, and destroyed properly as soon as foo exits
you can't use bad for anything, because any method you call will assume the constructor ran already, and it didn't
ok, you can't use bad for anything without explicitly constructing it using placement new. You shouldn't do this though, it's only appropriate where you're doing clever or tricky stuff with custom allocation.
this is ok (but note you have to delete it manually - foo has a memory leak)
this is better - you don't need to clean up manually
Now, note that your node class also has a constructor. In this case, it's automatically-generated, and does nothing but call the vector constructor. Still, you need it to be called, which means using new for dynamically allocating a node.
So, your program should probably look more like:
std::vector<std::unique_ptr<node>> data;
...
std::unique_pre<node> temp(new node);
temp->addPoints(...);
data[index]->addChild(temp);
Note I'm assuming data[index] is valid (I see from addChild you know how to populate a vector already), and that the single-owner model implemented by unique_ptr is appropriate.
As far as the code I see, you never add any nodes into the data array
data.push_back(something);
So accessing data[index] would be out of the allocated memory of the array. It won't complain until you try to set memory in that block (via addChild trying to push an element into the children array).
I would recommend that you store a node instead of a node* in your vector so you don't have to manage the memory on your own.
this is C++ so you don't have to malloc the space for a node you can use new like so:
Node * n = new Node();
New is much better because it calls the constructor and allocates space, whereas malloc just does the latter.
You haven't shown much of your code, but I would restructure the node class like this.
struct node{
double startPoint;
double endPoint;
vector<node> children;
node(){} //add default constrcutor
void addChild(node aNode){
children.push_back(aNode);
}
node & operator=(const node & n) {
startPoint = n.startPoint;
endPoint = n.endPoint;
return *this;
}
node(double start, double end): startPoint(start),endPoint(end){
} //in c++ you have constructors which this should have been in the first place
//constructors are used for initializing objects
};
this is better is that now you can't pass add child nullptr avoiding a lot of problems in your code. You also have a constructor now. Now you can add a node like this.
node temp(start,end); data[index]=temp;
You have a constructor now which addPoints should have been in the first place
I also made an assignment operator
Using the style of coding where you allocate memory on the stack and don't use new is called RAII and is a vital technique for learning c++ and producing exception safe code, this is the main reason I advocate not storing node*'s

Pushing pointers into c++ vectors, and cleanup

I am converting some code between different systems, and I have a question regarding c++ vectors.
If I do something like this:
In header file:
struct Vertex
{
float x;
float y;
float z;
}
struct submesh
{
Vertex *meshdata;
}
std::vector<submesh> meshes;
In a routine in the c++ file:
{
Vertex *data = new Vertex[1024];
submesh g;
g.meshdata = data;
meshes.push_back(g);
delete [] data;
}
Will I be in trouble? My assumption is that the vector would hold a pointer to data that is no longer valid once I called delete on it. Do I need to write a copy constructor for Vertex so that the data is copied first?
Additional:
The question was more to do with how do I put a pointer to allocated memory into a std::vector<> and still cleanup the locally allocated data. Essentially, how do I copy the data into the vector so I can still clean up my copy.
The original code was in DirectX. I am porting it to the iPhone. The original code allocated a submesh locally in a routine using:
{
ID3DXMesh* subMesh = 0;
D3DXCreateMesh(SubGrid::NUM_TRIS, SubGrid::NUM_VERTS, D3DXMESH_MANAGED, elems, gd3dDevice, &subMesh));
//
// ... do some magical things to submesh
//
SubGrid g;
g.mesh = subMesh;
g.box = bndBox;
mSubGrids.push_back(g);
}
I am trying to duplicate how ID3DXMesh is able to be added to a vector, then lose it's scope in the routine.
As I don't have access to D3DXCreateMesh(), I figured I would simply allocate the vertices I needed, throw them into a vector, and clean up.
Sorry, I wanted to keep the nitty gritty details out of it, as the question is simply how do I allocate a chunk of data, put a pointer into a std::vector<>, then clean up the locally allocated memory. :)
I assumed a copy constructor had to be written somewhere. Just wasn't sure where or how.
A subgrid looks like this:
struct SubGrid
{
ID3DXMesh* mesh;
AABB box;
// For sorting.
bool operator<(const SubGrid& rhs)const;
const static int NUM_ROWS = 33;
const static int NUM_COLS = 33;
const static int NUM_TRIS = (NUM_ROWS-1)*(NUM_COLS-1)*2;
const static int NUM_VERTS = NUM_ROWS*NUM_COLS;
};
And the vector they get added to looks like:
std::vector<SubGrid> mSubGrids;
Don't directly dynamicly-allocate when you don't need to, and in this case you don't. Since you're filling your own submesh data rather than using ID3DXMesh, the container of that data should be RAII-compliant. If I were coding this I would remove the submesh class entirely and just use:
// vector containing list of vertices.
typedef std::vector<Vertex> SubMesh;
Your SubGrid class can then become a simple container that holds, as one of its properties, a submesh collection. I noticed you also have a class AABB for a box object. You would continue to keep that inside SubGrid. I don't have ton to work with here, so I'm making some of these up as I go along, but something like the following:
// a simple 3-value triplet of floats
struct Vertex
{
float x,y,z;
};
// a Submesh is an arbitrary collection of Vertex objects.
typedef std::vector<Vertex> SubMesh;
// I'm defining AABB to be an 8-vertex object. your definition
// is likely different, but I needed something to compile with =)
typedef Vertex AABB[8];
class SubGrid
{
public:
SubGrid() {};
// comparator for container ordering
bool operator <(const SubGrid&);
// submesh accessors
void setSubmesh(const SubMesh& mesh) { submesh = mesh;}
SubMesh& getSubmesh() { return submesh; }
const SubMesh& getSubmesh() const { return submesh; }
// box accessors
AABB& getBox() { return box; }
const AABB& getBox() const { return box;}
private:
SubMesh submesh;
AABB box;
};
// arbitrary collection of SubGrid objects
typedef std::vector<SubGrid> SubGrids;
When adding this to your global SubGrid collection g, you have several possibilities. You could just do this:
// declared globally
Subgrids g;
// in some function for adding a subgrid item
SubGrid subgrid;
AABB& box = subgrid.getBox();
SubBesh& submesh = subgrid.getSubmesh();
// ... initialize your box and submesh data ...
g.push_back(subgrid);
But you'd be copying a lot of data around. To tighten up the memory access you could always do this instead:
// push an empty SubGrid first, then set it up in-place
g.push_back(SubGrid());
Subgrid& subgrid = *(g.back());
AABB& box = subgrid.getBox();
SubMesh& submesh = subgrid.getSubmesh();
//... initialize your box and submesh data ...
This will establish a reference to the SubGrid just added to the global collection, then allow you to modify it in-place. This is but-one of a number of possible setup options. It should be noted that if you have C++11 in your toolchain (and if you're doing this on MacOS or iOS, you likely do, as Apple LLVM 4.2's clang is pretty good on C++11 compliance) this can get even more efficient with judicious usage of move-constructors and move-assignment-operators.
Most importantly, not a new or delete to be seen.
Anyway, I hope this gives you some ideas.
Your code looks fine in single threaded application. Your code only allocate data memory once and delete [] data once.
Do I need to write a copy constructor for Vertex so that the data is copied first?
Your code is clean as you shown, meshes points to only allocated data. If you meant to copy data when call meshes.push_back(g), then your code doesn't do what you meant to.
You might want to use std::vector instead:
struct submesh
{
std::vector<Vertex> meshdata;
}
vector<submesh> meshes;
void Func()
{
meshes.emplace_back(submesh());
meshes.at(0).meshdata.resize(100);
}
STL container uses RAII idiom, it manages memory deallocation for you automatically.
Yes of course, vector will have a pointer to deleted memory. What you need is either:
Create copy constructor for submesh (not Vertex).OR
Changesubmesh to have array of Vertex (not just a pointer).
Copy constructor can be done like this:
struct submesh
{
Vertex *meshdata;
unsigned meshsize;
submesh(Vertex* v = 0, unsigned s= 0) : meshdata(v), meshsize(s){}
submesh(const submesh& s)
{
if(meshdata) /*we have stored data, delete it.*/ delete(meshdata);
meshdata = new Vertex[s.meshsize];
meshsize = s.meshsize;
memcpy(meshdata, s.meshdata, sizeof(Vertex) * meshsize);
}
};
For sure it is much recommended to use unique_ptr (if you use c++11) or auto_ptr for old c++. To avoid the nightmare of memory management as much as you can.
Check How to avoid memory leaks when using a vector of pointers to dynamically allocated objects in C++?

C++ Template Class

Hey..
I'm having trouble with some homework.
We are working on VectorList ( kinda like linked list but with vectors - don't ask why.. )
Anyway I have something like this:
#ifndef VECTORLIST_H
#define VECTORLIST_H
#include <iostream>
#include <vector>
using namespace std;
template< typename NODETYPE >
class VectorList
{
public:
VectorList(); // constructor
~VectorList(); // destructor
void insertAtFront( const NODETYPE & );
void insertAtBack( const NODETYPE & );
bool removeFromFront( NODETYPE & );
bool removeFromBack( NODETYPE & );
bool isEmpty() const;
void print() const;
private:
vector< NODETYPE > *vList; // list data as a vector
};
I need to fill in the functions.. my problem is that I do not understand how
to use STIL when I have *vList.. its a pointer to the first vector element?
// display contents of VectorList
template< typename NODETYPE >
void VectorList< NODETYPE >::print() const
{
// Fill in the missing code
}
My Idea was to use a for loop on the vector and use cout<< vector[i]<< endl;
to print the vector out..
Problem is that I get all sorts of errors and seg faults.
I do not understand how to access the vector in the function,
and how to access its elements.
This is a header file, and in the main we declare an object of VectorList<NODETYPE> IntVector...
So how can I do this?
Any help with understanding of how this *vList plays a role here would help a lot and
I'd probably be able to finish the rest..
Also, for isEmpty(), I assume I can use vList.empty().. but since vList is a pointer..
it doesn't work quite well.
== For the constructor/destructor what can I do?
I know for destructor I should iterate through the vector and use delete on each element.
But shoul
Please explain this to me, I am frustrated =[
my problem is that I do not understand how to use STL when I
have *vList.. its a pointer to the first vector element?
I assume that you are required as part of your homework to use pointer-to-vector instead of a vector itself. As a rule, I never use pointers-to-containers. In fact, the best thing that I discovered in switching from C to C++ was that I could write entire programs with no pointers at all, thanks to STL programming. Unless you are required to use pointer-to-vector, I recommend that you use the vector directly.
Certainly it is easier to use the vector proper than a pointer, but don't worry. Using the pointer isn't too bad.
First, in order to use a pointer-to-something, one must allocate the something. So, in your constructor, invoke new.
vList = new std::vector<NODETYPE>;
Anytime we invoke new, we must have a matching delete somewhere. Since our new is in our constructor, we need to invoke delete in the destructor:
delete vList;
You said:
but since vList is a pointer.. it doesn't work quite well.
Here is where life gets easy. Generally, if p is a pointer to some type, then (*p) is the object to which p points. Here are some examples:
int i = 1;
int *pInt = &i;
i = 4;
(*pInt) = 4;
std::cout << i << " " << (*pInt) << "\n";
std::vector<NODETYPE> v;
std::vector<NODETYPE> *pVector;
v.push_back();
(*pVector).push_back();
it = v.begin();
it = (*pVector).end();
So, invoking members of vList is easy : (*vList).empty().
So, your code might be :
void insertAtFront(const NODETYPE& node) { (*vList).push_front(node); }
There is a short-cut operator -> that makes the above somewhat easier to read:
void insertAtFront(const NODETYPE& node) { vList->push_front(node); }
The expression x->y is more-or-less equivalent (*x).y.
To sum up:
Allocate your vList in your constructor with new. Destroy your vList in your destructor with delete. Invoke members of vList using either (*vList).function() or vList->function().
Good luck, and come back if you have other questions!
P.s. Since you have a non-trivial destructor, you'll need to consider the rule of three.
P.P.s. You said something about iterating the vector in your destructor and deleting each of the objetcs you find there. You would only need to do that if your data type were vector-of-pointers-to-NODETYPE (contrast to what you declared: pointer-to-vector-of-NODETYPE). Until and unless you become completely comfortable with pointers, I recommend that you never store pointers in STL containers.
You should construct your object in the constructor (if you really need using bare pointers): vList = new vector< NODETYPE >();, free memory in the destructor: delete vList;, translate your methods to corresponding methods of the container class. For example, insertAtBack would be implemented as vList->push_back(elem);