Uint8 - Missing Type specifier - c++

Question

I'm trying to write a singleton class to hold the state of inputs from the user (mouse/keyboard data). The SDL API returns keyboard data as Uint8 pointer array, however, why I try to create the Uint8 pointer, I get these errors at the line w/ the uint8:
error C2143: syntax error : missing ';' before '*'
error C4430: missing type specifier - int assumed. Note: C++ does not support default-int
I've used Uint8 as a data type without defining it before, so I'm not sure what is causing the issue here. Here is my code:
class InputState {
public:
InputState()
{};
~InputState()
{};
static InputState *getInputState(void)
{
static InputState *state = new InputState();
return state;
};
public:
Uint8 *keys;
struct MouseState
{
int LeftButtonDown;
int RightButtonDown;
int MiddleButtonDown;
int x;
int y;
MouseState ()
{
LeftButtonDown = 0;
RightButtonDown = 0;
MiddleButtonDown = 0;
x = 0;
y = 0;
}
};
MouseState *mouseState;
};

Answer 1

The type Uint8 is a typedef that is defined in one of the SDL header. If you want to use it, you need to include the SDL.h header in your file.
// You need this include if you want to use SDL typedefs
#include <SDL.h>
class InputState {
public:
InputState()
{};
~InputState()
{};
// ...
public:
Uint8 *keys;
// ...
};