c++ print buffer (integer to string) - c++

Question

Code:
#include "stdafx.h"
#include <windows.h>
#include <iostream>
#include <iomanip>
#include <locale>
#include <sstream>
#include <string>
int main()
{
HWND handle = FindWindow(0 ,TEXT("window name"));
if(handle == 0)
{
MessageBox(0,TEXT("Failed to find window"),TEXT("Return"),MB_OK);
}
else
{
DWORD ID;
GetWindowThreadProcessId(handle,&ID);
HANDLE hProcess = OpenProcess(PROCESS_VM_WRITE|PROCESS_VM_OPERATION , FALSE, ID);
hProcess = OpenProcess(PROCESS_VM_READ , FALSE, ID);
if(!hProcess)
{
Beep(1000,1000);
}else {
int buffer;
if (ReadProcessMemory(hProcess,(void *)0x00963FC4,&buffer,4,NULL))
{
printf(buffer);
}
else {
MessageBox(0,TEXT("Could not Read"),TEXT("Return"),MB_OK);
}
}CloseHandle(hProcess);
}
}
I tried to make this program that reads memory address,
but I got this error:
IntelliSense: argument of type "int" is incompatible with parameter of type "const char *
I tried printf(buffer);
I tried to make string and also doesn't work.
string test;

Answer 1

First, try using the correct printf() call with format string:
printf("%d", buffer);
C is a statically typed language and you cannot do python-like stuff with printf() to output anything you want. The printf() function always prints only the first "const char *" argument allowing to substitute some values in this string according to the rules.
Second, I see the TEXT() macros in your code, so you might be using the Unicode strings in your project setup. If so (you should get link errors 2019/2005 in VC++), you have to use the wprintf() function:
wprintf(L"%d", buffer);
To print the std::string object you must also convert it to the "const char*". This is done by the string::c_str() call:
std::string MyString("Test");
printf("Your string is = %s", MyString.c_str());