All,
I am new to REGEX world...
I know that there are lot of regex avail for validating the common URL with http in it.
But I am looking for a regex to validate the URL in the following formats(without HTTP/HTTPS):
www.example.com/user/login
www.example.com
www.exmaple.co.xx
www.example.com/user?id=234&name=fname
in case if the URL contains only,
www.example(without the domain - .com OR .co.xx)
example.com (without "www")
I should throw an error to the user.
any help would be highly appreciated...
Thanks
Raj
This regex will pass your first set, but not match the second set:
^www\.example\.(com|co.xx)(/.*)?$
In English, this regex requires:
starts with www.example.
followed by either com or co.xx
optionally followed by / then anything
You could be more prescriptive about what can follow the optional slash by replacing (/.*) with (/(user|buy|sell)\?.*) etc
Related
I need to fix my url pattern:
/^((http(s)?(\:\/\/)){1}(www\.)?([\w\-\.\/])*(\.[a-zA-Z]{2,4}\/?)[^\\\/#?])[^\s\b\n|]*[^\.,;:\?\!\#\^\$ -]/
I thought this regex was ok, but it is not working for urls like: https://xx.xx (without www). 'www' should be optional ((www.)?). Where is the bug?
The problem is not in the (www\.)? part but that parts after that.
Take a look at the [^\\\/#?] and the [^\.,;:\?\!\#\^\$ -] parts.
So a valid URL would be https://xx.xx plus none of \/#? plus none of .,;:?!#^$_- making the url valid if you add those, for example https://xx.xx11.
I do advice you to not try to create your own regex because you are missing a lot!
For example, tlds like .amsterdam are valid. And why are you capturing so many groups?
Your regex as an image made with https://www.debuggex.com/:
I hope someone can help, this is driving me crazy!
I am attempting to modify Logstash Grok filters to parse a domain name.
Currently the regex is:
\b(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(\.?|\b) and correctly separates the domain however, I need to add an additional check to remove www..
This is what I have come up with so far:
\b(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(^(?<!www$).*$?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(\.?|\b)
I can only seem to keep the www. part of the domain, and not the domain itself.
Example of what I need to achieve:
www.stackoverflow.com should be stackoverflow.com.
I need to remove specifically www. and not the entire subdomain.
Thank you in advance!
UPDATE
Example inputs to expected outputs (using this post as an example):
In it's current state:
https://stackoverflow.com/questions/37070358/ returns www.stackoverflow.com
What I need is for it to return stackoverflow.com
You can add a (?!www\.) and (?!http:\/\/www\.) negative lookaheads right after the first \b to exclude matching www. or http://www.:
\b(?!www\.)(?!http:\/\/www\.)(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(?:\.?|\b)
^^^^^^^^^^^^^^^^^^^^^^^^^^^
See the regex demo
You may add more negative lookaheads to exclude https:// or ftp/ftps links.
ALTERNATIVE:
\b(?!(?:https?|ftps?):\/\/)(?!www\.)(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(?:\.?|\b)
See this regex demo
The (?!(?:https?|ftps?):\/\/) and (?!www\.) lookaheads will just let you skip the protocol and www parts of the URLs.
This will match the part after www if the url starts with www.
(?!www\.)\b(?:(?!-)[0-9A-Za-z]{1,63})(?:\.(?:(?!-)[0-9A-Za-z-]{1,63}))*(\.?|\b)
I simplified the rest of your regex too by using a negative look ahead for - in the subdomains.
I'm struggling with forming a regex that would match:
Just domain in case of URL
Whole string in case of no URL
Acceptance test (regex should match bold text):
http://mozart.co.uk
https://avocado.si/hmm
http://www.qwe123qwe.com
Starbucks
Benchmark 123
So far I've come up with this:
([^\/\/]+)(?:,|$)
It works fine, but not for URLs with trailing slash on the end. How can I modify the expression to include full path (everything on the right side of http(s)://) as well? Thank you.
This regex will match them if it starts with http:// or https:// until the next slash. If it doesn't start with http:// nor https:// then it will match the whole string. Close enough?
(?:^https?:\/\/([^\/]+)(?:[\/,]|$)|^(.*)$)
I should note that most languages have functions built in to properly parse URLs and these are preferable.
You should note that I've got 2 sets of capturing parentheses, so depending on your language that may be significant.
Maybe that ^(http[s]?:\/\/)?(.*)$. Play here: https://regex101.com/r/iZ2vL4/1
This will have Matching groups, the domain you want will be in the 4th matching group.
/^((http[s]?|ftp):\/\/)?\/?([^\/\.]+\.)*?([^\/\.]+\.[^:\/\s\.]{1,3}(\.[^:\/\s\.]{1,2})?(:\d+)?)($|\/)([^#?\s]+)?(.*?)?(#[\w\-]+)?$/mg
Regex101.com workbench to check out your URLs just paste them in the "TEST STRING" Textbox to test it out.
Don't recall where I got this... so I don't know who to credit. But it's pretty slick!
I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+
We've got some incoming URLs that needs to be redirected, but we are having trouble with URLs that contains pluses (+).
For example any incoming URL must be redirected to the Homepage of the new site:
/eng/news/2005+01+01.htm
Should be redirected to to the home page of the new site
/en/
Using UrlRewriter.net we've set up a rule which works with 'normal' URLs but does not work for the above
<redirect url="~/eng/(.+)" to="/en/index.aspx" />
However it works fine if i change the incoming URL to
/eng/news/2005-01-01.htm
What's the problem and can anyone help?
I don't know about UrlRewriter.net, and I'm not sure which regex syntax it uses. I give some hint based on Perl regex.
what is the ~ at the beginning? Perhaps you mean ^, i.e. beginning of the string.
(.+) matches any character repeated one or more time; it does not match the + sign as you want
This is one way to write a (Perl) regex matching URLs starting with the string /eng/ and containg a + sign:
^\/eng\/.*\+.*
I hope this helps.