I'm trying to join lines of data information in Notepad ++, currently, the data looks like this:
It has the above format for about 100,000 rows. I want to combine row 1 with row 2, but sometimes row 2 and row 3 combine and look something like this:
I want the output to look like this (all on one line):
I tried using this formula:
SEARCH: (.+)\R(.+)
REPLACE: \1 \2
If you want to match specific characters in Regex, you can simply type that character. for example, apple will only match apple. If you want to match a number, you can use \d. This will match 8, but not d.
If you want to match only things that end in 4 numbers separated by a dot, try this one: \n(.*?\d\d\.\d\d)\n
An explanation for each part can be found here.
I have a large text file with several lines and I want to replace several of those lines with a blank line. I used regex to search for certain patterns, marked and bookmarked them, then used:Search > Bookmark > Inverse Bookmark to hopefully highlight those strings I want to blank-replace.
However, I find only Remove Bookmarked Lines and Remove Unmarked Lines, both of which strip line breaks in the text file.
Is there a way to preserve line breaks while replacing those inverse-bookmarked lines with a blank line?
Sample text (lines 1 and 6 are bookmarked for replacing with an empty/blank line):
1 Oroc-Osoc PS
2 Osiao Paglingap Elementary School
3 Osmena E/S
4 Osmena Elementary School
5 Osmena ES
6 Pablo .M. Conag CS
Expected output:
1
2 Osiao Paglingap Elementary School
3 Osmena E/S
4 Osmena Elementary School
5 Osmena ES
6
You can do any of those alternatives:
Alternative A)
Copy a space to the clpiboard with Control+C for example
Do: Search => Bookmark => Replace bookmarked lines
If you don't want to leave a space at the beginning of the lines use Alternative B)
Copy something that cannot repeated on the whole file to the clipboard <<<EOL>>> for example.
Do: Search => Bookmark => Replace bookmarked lines
Replace <<<EOL>>> by \r\n be sure to mark extended match
I work with text files, and I need to be able to see when the gps (last 3 columns of csv) "hangs up" for more than a few lines.
So for example, usually, part of a text file looks like this:
5451,1667,180007,35.7397387,97.8161897,375.8
5448,1053z,180006,35.7397407,97.8161814,375.7
5444,1667,180005,35.7397445,97.8161674,375.6
5439,1668,180004,35.7397483,97.8161526,375.5
5435,1669,180003,35.7397518,97.8161379,375.5
5431,1669,180002,35.7397554,97.8161269,375.6
5426,1054z,180001,35.7397584,97.8161115,375.6
5420,1670,175959,35.7397649,97.8160931,375.9
But sometimes there is an error with the gps and it looks like this:
36859,1598,202603.00,35.8867316,99.2515545,555.700
36859,1598,202608.00,35.8867316,99.2515545,555.700
36859,1142z,202610.00,35.8867316,99.2515545,555.700
36859,1597,202612.00,35.8867316,99.2515545,555.700
36859,1597,202614.00,35.8867316,99.2515545,555.700
36859,1596,202616.00,35.8867316,99.2515545,555.700
36859,1595,202618.00,35.8867316,99.2515545,555.700
I need to be able to figure out a way to search for matching strings of 7 different numbers, (the decimal portion of the gps) but so far I've only been able to figure out how to search for repeating #s or consecutive numbers.
Any ideas?
If you were to find such repetitions in an editor (such as Notepad++), you could use the following regex to find 4 or more repeating lines:
([^,]+(?:,[^,]+){2})\v+(?:(?:[^,]+,){3}\1(?:\v+|$)){3,}
To go a bit into detail
([^,]+(?:,[^,]+){2})\v+ is a group consisting of one or more non-commas followed by comma and another one or more non-commas followed by a vertical space (linebreak), that is not part of the group (e.g. 1,1,1\n)
(?:[^,]+,){3} matches one or more non-commas followed by comma, three times (your columns that don't have to be considered)
\1 is a backreference to group 1, matching if it contains exactly the same as group 1
(?:\v+|$) matches either another vertical whitespaces or the end of the text
{3,} for 3 or more repetitions - increase it if you want more
Here you can see, how it works
However, if you are using any programming language to check this, I wouldn't walk on the path of regex, as checking for those repetitions can be done a lot easier. Here is one example in Python, I hope you can adopt it for your needs:
oldcoords = [0,0,0]
lines = [line.rstrip('\n') for line in open(r'C:\temp\gps.csv')]
for line in lines:
gpscoords = line.split(',')[3:6]
if gpscoords == oldcoords:
repetitions += 1
else:
oldcoords = gpscoords
repetitions = 0
if repetitions == 4: #or however you define more than a few
print(', '.join(gpscoords) + ' is repeated')
If you can use perl, and if I understood you:
perl -ne 'm/^[^,]*,[^,]*,[^,]*,([^,]*,[^,]*,[^,]*$)/g; $current_line=$1; ++$line_number; if ($prev_line==$current_line){$equals++} else {if ($equals>=6){ print "Last three fields in lines ".($line_number-$equals-1)." to ".($line_number-1)." are equals to:\n$prev_line" } ; $equals=0}; $prev_line=$current_line' < onlyreplacethiswithyourfilepath should do the trick.
Sample output:
Last three fields in lines 1 to 7 are equals to:
35.8867316,99.2515545,555.700
Last three fields in lines 16 to 22 are equals to:
37.8782116,99.7825545,572.810
Last three fields in lines 31 to 44 are equals to:
36.6868916,77.2594245,581.358
Last three fields in lines 57 to 63 are equals to:
35.5128764,71.2874545,575.631
This is my first post so I hope it is clear enough.
I am having a problem regarding cleaning my CSV files before I can read them into R and have spent the entire day trying to find a solution.
My data is supposed to be in the form of two columns. The first column is a timestamp consisting of 10 digits and the second an ID consisting of 11 or 12 Letters and numbers (the first 6 are always numbers).
For example:
logger10 |
0821164100 | 010300033ADD
0821164523 | 010300033ADD
0821164531 | 010700EDDA0F0831102744
010700EDDA0F|
would become:
0821164100 | 010300033ADD
0821164523 | 010300033ADD
0821164531 | 010700EDDA0F
0831102744 | 010700EDDA0F
(please excuse the lines in the middle, that was my attempt at separating the columns...).
The csv file seems to occasionally be missing a comma which means that sometimes one row will end up like this:
0923120531,010300033ADD0925075301,010700EDD00A
My hardware also adds the word logger10 (or whichever number logger this is) whenever it restarts which gives a similar problem e.g. logger10logger100831102744.
I think I have managed to solve the logger text problem (see code) but I am sure this could be improved. Also, I really don't want to delete any of the data.
My real trouble is making sure there is a line break in the right place after the ID and, if not, I would like to add one. I thought I could use regex for this but I'm having difficulty understanding it.
Any help would be greatly appreciated!
Here is my attempt:
temp <- list.files(pattern="*.CSV") #list of each csv/logger file
for(i in temp){
#clean each csv
tmp<-readLines(i) #check each line in file
tmp<-gsub("logger([0-9]{2})","",tmp) #remove logger text
pattern <- ("[0-9]{10}\\,[0-9]{6}[A-Z,0-9]{5,6}") #regex pattern ??
if (tmp!= pattern){
#I have no idea where to start here...
}
}
here is some raw data:
logger01
0729131218,020700EE1961
0729131226,020700EE1961
0831103159,0203000316DB
0831103207,0203000316DB0831103253,010700EDE28C
0831103301,010700EDE28C
0831103522,010300029815
0831103636,010300029815
0831103657,020300029815
If you want to do this in a single pass:
(?:logger\d\d )?([\dA-F]{10}),?([\dA-F]{12}) ?
can be replaced with
\1\t\2\n
What this does is look for any of those rogue logger01 entries (including the space after it) optionally: That trailing ? after the group means that it can match 0 or 1 time: if it does match, it will. If it's not there, the match just keeps going anyway.
Following that, you look for (and capture) exactly 10 hex values (either digits or A-F). The ,? means that if a comma exists, it will match, but it can match 0 or 1 time as well (making it optional).
Following that, look for (and capture) exactly 12 hex values. Finally, to get rid of any strange trailing spaces, the ? (a space character followed by ?) will optionally match the trailing space.
Your replacement will replace the first captured group (the 10 hex digits), add in a tab, replace the second captured group (the 12 hex digits), and then a newline.
You can see this in use on regex101 to see the results. You can use code generator on the left side of that page to get some preformatted PHP/Javascript/Python that you can just drop into a script.
If you're doing this from the command line, perl could be used:
perl -pe 's/(?:logger\d\d )?([\dA-F]{10}),?([\dA-F]{12}) ?/\1\t\2\n/g'
If another language, you may need to adapt it slightly to fit your needs.
EDIT
Re-reading the OP and comments, a slightly more rigid regex could be
(?:logger\d\d\ )?([\dA-F]{10}),?(\d{6}[\dA-F]{5,6})\ ?
I updated the regex101 link with the changes.
This still looks for the first 10 hex values, but now looks for exactly 6 digits, followed by 5-6 hex values, so the total number of characters matched is 11 or 12.
The replacement would be the same.
Paste your regex here https://regex101.com/ to see whether it catches all cases. The 5 or 6 letters or digits could pose an issue as it may catch the first digit of the timestamp when the logger misses out a comma. Append an '\n' to the end of the tmp string should work provided the regex catches all cases.
I'm trying to match a file which is delimited by multiple spaces. The problem I have is that the first field can contain a single space. How can I match this with a regex?
Eg:
Name Other Data Other Data 2
Bob Smith XX1 0101010101
John Doe XX2 0101010101
Bob Doe XX3 0101010101
John Smith XX4 0101010101
Can I split these lines into three fields with a regex, splitting by a space but allowing for the single space in the first field?
Hi the following regex should work
(\w*\s\w*)\s+\w{2}\d\s+\d*
This would work:
Pattern:
(.*?)[ ]{2,}(.*?)[ ]{2,}(.*)
Replacement:
+$1+ -$2- *$3*
$1 contains the first column, $2 the second and $3 the third one.
Example:
http://regexr.com?32tbt
You could split at two or more spaces:
[ ]{2,}
But you are probably better off, determining the lengths of the captures of this regular expression:
(Name[ ]+)(Other Data[ ]+)
And then to use a simple substring method that slices your lines into portions of the same length.
So in your case the first capture would be 15 characters long, the second 14 and the column would have 13 (but the last one doesn't really matter, which is why it isn't actually captured). Then you take the first 15, the next 14 and the remaining characters of every line and trim each one (remove trailing whitespace).
I think the simplest is to use a regex that matches two or more spaces.
/ +/
Which breaks down as... delimiter (/) followed by a space () followed by another space one or more times (+) followed by the end delimiter (/ in my example, but is language specific).
So simply put, use regex to match space, then one or more spaces as a means to split your string.
Usually, with this kind of files, the best approach is to get a substring based on where your required information is and then trim it. I see your file contains 16 chars before the second field, you can get a substring of length 16 from the beginning which will contain your desired text. You should trim it to get only the text you need without the spaces.
If the spacing pattern you posted is consistent (if it won't change among different files of this kind) you have also another problem: what happens to longer names?
Name Other Data
Johnny AppleseeXX1
TutankamonfirstXX2
if you really want to use a regex, be sure to avoid those corner cases.