I used dollar sign to have a prefix in dollar but my problem is i need it to be in GBP/british pound like this "£". how can i do this? thanks
var data2 = new google.visualization.DataTable();
var formatted = new google.visualization.NumberFormat({prefix: '$'});
data2.addColumn('string', 'Company');
data2.addColumn('number', 'Amount');
You will need to use the javascript \u followed by the hex code for the unicode character.
In this case \u00A3
Related
I'm trying to implement a validation form with regex where I have to check whether a string is properly Tab and New Line delimited or not. I'm using jqBootstrapValidation. Column numbers can vary from 2 to 10. Like this image below:
What regex should I use?
I believe this is what you're looking for.
([A-Za-z0-9]+[\t\n])+[a-zA-Z0-9]+
This solution will work:
var s = "string here";
var regex = /\t/g;
var lines = s.split(/\n/).length - 1;
var valid = s.match(regex).length == 2 * lines;// valid or not.
alert(valid); // true or false.
Demo: http://jsfiddle.net/VP6Uj/2
I need to replace multiple contiguous new line/line feed characters in flex with a single new line character.
Example:
The string
"My name is blah blah \n\n\n\n
My name is blah \r\n\r\n\r\n"
Should be converted to
"My name is blah blah \n
My name is blah \n"
Hope the example makes it easier to understand.
I am using a component to render it.
I guess using regex would be the easiest way to do this, but still it would be great if people can point me out to references/examples to get this done with ease.
I am using flex 4.5.
Thanks,
Neeraj
You can use String.replace method to do the job, it's possible to use both string or regular expressions to match some part of a string value. So regarding to your question the code will look like below:
var filter: String = "My name is blah\r\r\r blah \n\n\n\r\nMy name is blah\r\n\r\r\n\n\n\r\n";
filter = filter.replace(/(\r|\n)+/g, "\n");
multiple contiguous new line/line feed characters
If you mean sequence "\r\n" then:
var myString:String = "text\r\ntext\r\ntext\r\n";
myString = myString.split("\r").join("\n").split("\n\n").join("\n");
How can i put break line in string.
Something like this.
string var = "hey
s";
Would be something like this.
hey
s
You should just put a \n between hey and s. So:
string var = "hey\ns";
Line breaking can be achieved using Dan's advice:
string var = "hey\ns";
Note that you cannot do this the way you wanted:
string var = "hey // this is not
s"; // valid code
and it's a design choice of C++.
Older languages generally do not allow you to define multiline strings.
But, for example, Python does allow you exactly this:
someString = """
this is a
multiline
string
"""
and printing someString will give you a true multiline string.
You can forget about this when using C++, though.
A line break is encoded as the char '\n'. So just write \n into your string.
You can also do this:
string var =
"\
some text\n\
some more text\n\
and even more text\
";
and var would be equels to
some text
some more text
and even more text
you should try this
string var = "hey"."/n"."s";
i have: \£\d+\.\d\d
should find: £6.95 £16.95 etc
+ is one or more
\. is the dot
\d is for a digit
am i wrong? :(
JavaScript for Greasemonkey
// ==UserScript==
// #name CurConvertor
// #namespace CurConvertor
// #description noam smadja
// #include http://www.zavvi.com/*
// ==/UserScript==
textNodes = document.evaluate(
"//text()",
document,
null,
XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE,
null);
var searchRE = /\£[0-9]\+.[0-9][0-9];
var replace = 'pling';
for (var i=0;i<textNodes.snapshotLength;i++) {
var node = textNodes.snapshotItem(i);
node.data = node.data.replace(searchRE, replace);
}
when i change the regex to /Free for example it finds and changes. but i guess i am missing something!
Had this written up for your last question just before it was deleted.
Here are the problems you're having with your GM script.
You're checking absolutely every
text node on the page for some
reason. This isn't causing it to
break but it's unnecessary and slow.
It would be better to look for text
nodes inside .price nodes and .rrp
.strike nodes instead.
When creating new regexp objects in
this way, backslashes must be
escaped, ex:
var searchRE = new
RegExp('\\d\\d','gi');
not
var
searchRE = new RegExp('\d\d','gi');
So you can add the backslashes, or
create your regex like this:
var
searchRE = /\d\d/gi;
Your actual regular expression is
only checking for numbers like
##ANYCHARACTER##, and will ignore £5.00 and £128.24
Your replacement needs to be either
a string or a callback function, not
a regular expression object.
Putting it all together
textNodes = document.evaluate(
"//p[contains(#class,'price')]/text() | //p[contains(#class,'rrp')]/span[contains(#class,'strike')]/text()",
document,
null,
XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE,
null);
var searchRE = /£(\d+\.\d\d)/gi;
var replace = function(str,p1){return "₪" + ( (p1*5.67).toFixed(2) );}
for (var i=0,l=textNodes.snapshotLength;i<l;i++) {
var node = textNodes.snapshotItem(i);
node.data = node.data.replace(searchRE, replace);
}
Changes:
Xpath now includes only p.price and p.rrp span.strke nodes
Search regular expression created with /regex/ instead of new RegExp
Search variable now includes target currency symbol
Replace variable is now a function that replaces the currency symbol with a new symbol, and multiplies the first matched substring with substring * 5.67
for loop sets a variable to the snapshot length at the beginning of the loop, instead of checking textNodes.snapshotLength at the beginning of every loop.
Hope that helps!
[edit]Some of these points don't apply, as the original question changed a few times, but the final script is relevant, and the points may still be of interest to you for why your script was failing originally.
You are not wrong, but there are a few things to watch out for:
The £ sign is not a standard ASCII character so you may have encoding issue, or you may need to enable a unicode option on your regular expression.
The use of \d is not supported in all regular expression engines. [0-9] or [[:digit:]] are other possibilities.
To get a better answer, say which language you are using, and preferably also post your source code.
£[0-9]+(,[0-9]{3})*\.[0-9]{2}$
this will match anything from £dd.dd to £d[dd]*,ddd.dd. So it can fetch millions and hundreds as well.
The above regexp is not strict in terms of syntaxes. You can have, for example: 1123213123.23
Now, if you want an even strict regexp, and you're 100% sure that the prices will follow the comma and period syntaxes accordingly, then use
£[0-9]{1,3}(,[0-9]{3})*\.[0-9]{2}$
Try your regexps here to see what works for you and what not http://tools.netshiftmedia.com/regexlibrary/
It depends on what flavour of regex you are using - what is the programming language?
some older versions of regex require the + to be escaped - sed and vi for example.
Also some older versions of regex do not recognise \d as matching a digit.
Most modern regex follow the perl syntax and £\d+\.\d\d should do the trick, but it does also depend on how the £ is encoded - if the string you are matching encodes it differently from the regex then it will not match.
Here is an example in Python - the £ character is represented differently in a regular string and a unicode string (prefixed with a u):
>>> "£"
'\xc2\xa3'
>>> u"£"
u'\xa3'
>>> import re
>>> print re.match("£", u"£")
None
>>> print re.match(u"£", "£")
None
>>> print re.match(u"£", u"£")
<_sre.SRE_Match object at 0x7ef34de8>
>>> print re.match("£", "£")
<_sre.SRE_Match object at 0x7ef34e90>
>>>
£ isn't an ascii character, so you need to work out encodings. Depending on the language, you will either need to escape the byte(s) of £ in the regex, or convert all the strings into Unicode before applying the regex.
In Ruby you could just write the following
/£\d+.\d{2}/
Using the braces to specify number of digits after the point makes it slightly clearer
I have to parse out color information from HTML data. The colors can either be RGB colors or file names to a swatch image.
I used http://www.gskinner.com/RegExr/ to develop and test the patterns. I copied the AS regular expression code verbatim from the tool into Flex Builder. But, when I exec the pattern against the string I get a null.
Here are the patterns and an example of the string (I took the correct HTML tags out so the strings would show correctly):
DIV data:
<div style="background-color:rgb(2,2,2);width:10px;height:10px;">
DIV pattern:
/([0-9]{1,3},[0-9]{1,3},[0-9]{1,3})/
IMG data:
<img src="/media/swatches/jerzeesbirch.gif" width="10" height="10" alt="Birch">
IMG pattern:
/[a-z0-9_-]+/[a-z0-9_-]+/[a-z0-9_-]+\.[a-z0-9_-]+/
Here's my Actionscript code:
var divPattern : RegExp = new RegExp("/([0-9]{1,3},[0-9]{1,3},[0-9]{1,3})/");
var imgPattern : RegExp = new RegExp("/[a-z0-9_-]+/[a-z0-9_-]+/[a-z0-9_-]+\.[a-z0-9_-]+/");
var divResult : Array = divPattern.exec(object.swatch);
var imgResult : Array = imgPattern.exec(object.swatch);
Both of the arrays are null.
This is my first foray into AS coding, so I think I'm declaring something wrong.
Steve
(I don't know ActionScript but I know Javascript and they should be close enough to solve your problem.)
To construct a RegExp object for e.g. the pattern ^[a-z]+$, you either use
var pattern : RegExp = new RegExp("^[a-z]+$");
or, better,
var pattern : RegExp = /^[a-z]+$/
The code new RegExp("/^[a-z]+$/") is wrong because this expects a slash before the ^ and after the $.
Therefore, your DIV pattern should be written as
var divPattern : RegExp = /([0-9]{1,3},[0-9]{1,3},[0-9]{1,3})/;
but, as you know, the ( and ) are special characters for capturing, you need to escape them:
var divPattern : RegExp = /\([0-9]{1,3},[0-9]{1,3},[0-9]{1,3}\)/;
For the IMG pattern, as / delimitates a RegEx, you need to escape it as well:
var imgPattern : RegExp = /[a-z0-9_-]+\/[a-z0-9_-]+\/[a-z0-9_-]+\.[a-z0-9_-]+/
Finally, you could use \d in place of [0-9] and \w in place of [a-zA-Z0-9_].
I don't know enough to tell if your regex patterns are correct, but from the docs on the AS3 RegExp class, it looks like your new RegExp() call needs a second argument to declare flags for case sensitivity etc.
EDIT: Also, as Bart K has pointed out, you don't need the / delimiters when using the new method.
So you can use either:
var divPattern:RegExp = new RegExp("([0-9]{1,3},[0-9]{1,3},[0-9]{1,3})", "");
OR you can also use the alternate syntax with /:
var divPattern:RegExp = /([0-9]{1,3},[0-9]{1,3},[0-9]{1,3})/;
... in which case the flag string (if any) is included after the final /