Remove elements based on other element's value -- XSLT - xslt

I have a style-sheet that I am using to remove certain elements based on the value of an other element. However, it is not working ...
Sample Input XML
<Model>
<Year>1999</Year>
<Operation>ABC</Operation>
<Text>Testing</Text>
<Status>Ok</Status>
</Model>
If Operation value is 'ABC' then remove Text and Status nodes from XML.
And gives the following output.
<Model>
<Year>1999</Year>
<Operation>ABC</Operation>
</Model>
Here is my style sheet that I am using but it is removing Text and Status nodes from all XMLs even when operation is not 'ABC'.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="ID" select="//Operation"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Text | Status">
<xsl:if test ="$ID ='ABC'">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Thanks in Advance
How would I do the same when namespace is present like
<ns0:next type="Sale" xmlns:ns0="http://Test.Schemas.Inside_Sales">

Here is a complete XSLT transformation -- short and simple (no variables, no xsl:if, xsl:choose, xsl:when, xsl:otherwise):
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match=
"*[Operation='ABC']/Text | *[Operation='ABC']/Status"/>
</xsl:stylesheet>
When this transformation is applied on the provided XML document:
<Model>
<Year>1999</Year>
<Operation>ABC</Operation>
<Text>Testing</Text>
<Status>Ok</Status>
</Model>
the wanted, correct result is produced:
<Model>
<Year>1999</Year>
<Operation>ABC</Operation>
</Model>

Change your xsl:if as follows:
<xsl:if test="../Operation!='ABC'">
and you can get rid of xsl:variable.

A better pattern in XSLT than using <xsl:if> is to add new templates with match conditions:
<xsl:template match="(Text | Status)[../Operation != 'ABC']"/>

I found this works:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/Model">
<xsl:choose>
<xsl:when test="Operation[text()!='ABC']">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:copy>
<xsl:apply-templates select="Year"/>
<xsl:apply-templates select="Operation"/>
</xsl:copy>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>

Related

XSLT 1.0 - Move certain elements into a new parent

Thank you for taking the time to look at my question
I have a source xml that looks like so
<root>
<a>asdf</a>
<b>asdfdsaf</b>
<c>adfasd</c>
<d>asddf</d>
<e></e>
<others>
<foo>sdfd</foo>
<bar>hghg</bar>
</others>
</root>
I need to wrap certain elements Eg:a,b,c into a new parent and remove empty elements.
so output like so
<root>
<newparent>
<a>asdf</a>
<b>asdfdsaf</b>
<c>adfasd</c>
</newparent>
<d>asddf</d>
<others>
<foo>sdfd</foo>
<bar>hghg</bar>
</others>
</root>
I managed to remove the empty elements using this XSL -
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(#*) and not(*) and (not(text()) or .=-1)]"/>
<xsl:template match="name">
</xsl:template>
</xsl:stylesheet>
Getting stuck at adding the newparent node. Any pointers/help is much appreciated.
Try it this way:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/root">
<xsl:copy>
<newparent>
<xsl:apply-templates select="a|b|c"/>
</newparent>
<xsl:apply-templates select="*[not(self::a or self::b or self::c)]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(#* or node())]"/>
</xsl:stylesheet>
<xsl:template match="root">
<xsl:copy>
<newparent>
<xsl:copy-of select="a|b|c"/>
</newparent>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[.= '' or name() ='a' or name()='b' or name()='c']"/>
check it if it is fullfill your requirement.

Removal of XML empty tags using XSLT [duplicate]

I am trying to recursively remove 'empty' elements (no children, no attribute or empty attribute) from the xml. This is the XSLT I have
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(*) and
string-length(.)=0 and
(not(#*) or #*[string-length(.)=0])]">
<xsl:apply-templates/>
</xsl:template>
This is the input XML. I expect this XML to be transformed to a empty string
<world>
<country>
<state>
<city>
<suburb1></suburb1>
<suburb2></suburb2>
</city>
</state>
</country>
</world>
But instead I am getting
<world>
<country>
<state/>
</country>
</world>
Can anyone help? I've researched many threads in the forum but still no luck.
The condition not(*) is false for any element that has children - regardless of what the children contain.
If you want to "prune" the tree of any branches that do not carry "fruit", try:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*[descendant::text() or descendant-or-self::*/#*[string()]]">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*[string()]">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
So, fighting whitespace, try this:
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(*) and
string-length(normalize-space(.))=0 and
(not(#*) or #*[string-length(normalize-space(.))=0])]">
<xsl:apply-templates/>
</xsl:template>

Filter out elements and replace element value in one step

I am trying to filter out elements, and rename element value, but I can't get it to work:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:template match="xml">
<xsl:copy>
<xsl:for-each select="product[matches(code, 'C17.*[^V]$')]">
<xsl:copy>
<xsl:copy-of select="#*|node()"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Example input data:
<?xml version="1.0" encoding="UTF-8"?>
<xml>
<product>
<code>C17020</code>
<title>Apple</title>
</product>
<product>
<code>C1723V</code>
<title>Samsung</title>
</product>
</xml>
I want to leave <product>'s starting with C17, but not ending to V. I use C17.*[^V]$ regex for this. This part is working.
The problem is with renaming title function. If I add this step to a new XSLT with code:
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
at the begin, then it works.
What I am doing wrong here?
The problem is you are doing <xsl:copy-of select="#*|node()"/> in your template matching xml. This will copy the attributes and child nodes, buy will not apply any templates. So your template matching title is just not used.
You need to use xsl:apply-templates here, but also include the identity template (the template you mention using in your new XSLT code) which ensures code gets copied too
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xml">
<xsl:copy>
<xsl:for-each select="product[matches(code, 'C17.*[^V]$')]">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note you can actually simplify your XSLT. Rather than being explicit in what you want to copy, by using the identity template you can instead have templates to remove what you don't want to copy....
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:strip-space elements="*" />
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="product[not(matches(code, 'C17.*[^V]$'))]" />
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Another thing to note is that matches and replace is for XSLT 2.0 only.

xsl:strip-space combined with xsl:text messes up automatic indentation

Using XSLT 1.0 I would like to comment out certain XML elements and replace other XML elements, while keeping the XML nicely formatted.
For example, the following XML document
<doc>
<e1>foo</e1>
<e2>bar</e2>
</doc>
should be converted to
<doc>
<!--<e1>foo</e1>-->
<e3>foobar</e3>
<e4>foobar</e4>
</doc>
I am using the following XSL transformation and xsltproc for testing it:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*" />
<xsl:output indent="yes" />
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="e1">
<xsl:text disable-output-escaping="yes"><!--</xsl:text> <!--*-->
<xsl:copy>
<xsl:apply-templates />
</xsl:copy>
<xsl:text disable-output-escaping="yes">--></xsl:text> <!--*-->
</xsl:template>
<xsl:template match="e2">
<e3>foobar</e3><e4>foobar</e4>
</xsl:template>
</xsl:stylesheet>
But what I get is this:
<doc><!--<e1>foo</e1>--><e3>foobar</e3><e4>foobar</e4></doc>
The problem seems to be caused by the lines marked with '*' in my transformation; more specifically from inserting <!-- and -->. When I remove these two elements, the result is indented as expected.
Is there a way to wrap elements in comments while still keeping the output document nicely formatted?
Try whether outputting a comment with the serialization of the element, as in
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:import href="http://lenzconsulting.com/xml-to-string/xml-to-string.xsl"/>
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="e1">
<xsl:comment>
<xsl:call-template name="xml-to-string"></xsl:call-template>
</xsl:comment>
</xsl:template>
<xsl:template match="e2">
<e3>foobar</e3><e4>foobar</e4>
</xsl:template>
</xsl:stylesheet>
gives you a better result.

Picking Multiple Attributes in XSLT

Below Is My Input XML.
<ServiceIncident xmlns="http://b2b.ibm.com/schema/IS_B2B_CDM/R2_2">
<ProviderID>INC0011731</ProviderID>
<ProviderPriority>4</ProviderPriority>
<WorkflowStatus>NEW</WorkflowStatus>
<ServiceProvider1>
<Person Role="AffectedUser">
<ContactID>ITELLA_BRIDGE_USER</ContactID>
<FullName>Chad Whaley</FullName>
</Person>
</ServiceProvider1>
Below is my XSL
<xsl:template match="r2:Person/#Role">
<xsl:attribute name="Role">Owner</xsl:attribute>
</xsl:template>
<xsl:template match="r2:Person/#Role">
<xsl:attribute name="Role">ReportedBy</xsl:attribute>
</xsl:template>
My issue is i want to get these 2 fields in output replacing the old one in input.Iam able to get one value in output but iam not getting other value.
I put on a space as a separator between attributes:
<xsl:stylesheet version='1.0' xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:r2="http://b2b.ibm.com/schema/IS_B2B_CDM/R2_2" exclude-result-prefixes="r2">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="r2:Person">
<xsl:copy>
<xsl:attribute name="Role">Owner ReportedBy</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>