How to include the node XML in my XSLT text output? - xslt

Question

I'm trying to convert an XML file into a flat, pipe-delimited file with XSLT (for bulk-loading into Postgres). I would like the last column in my output to be the actual XML of the node (for additional post-processing and debugging). For example:
<Library>
<Book id="123">
<Title>Python Does Everythig</Title>
<Author>Smith</Author>
</Book>
<Book id="456">
<Title>Postgres is Neat</Title>
<Author>Wesson</Author>
</Book>
</Library>
Should generate
Python Does Everything|Smith|<Book id="123"><Title>Python Does Everythig</Title>Author>Smith</Author></Book>
Postgres is Neat|Wesson|<Book id="456"><Title>Postgres is Neat</Title><Author>Wesson</Author></Book>
My current XSL is
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*" />
<xsl:output method="text" omit-xml-declaration="yes" indent="no" />
<xsl:template match="//Book">
<xsl:value-of select="Title" />
<xsl:text>|</xsl:text>
<xsl:value-of select="Author" />
<!-- put in the newline -->
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>

Answer 1

I am not sure if this is a recommended solution, but you could try setting the output method to xml, and then just using the xsl:copy-of function.
So, the following XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*" />
<xsl:output method="xml" omit-xml-declaration="yes" indent="no" />
<xsl:template match="//Book">
<xsl:value-of select="Title" />
<xsl:text>|</xsl:text>
<xsl:value-of select="Author" />
<xsl:text>|</xsl:text>
<xsl:copy-of select="." />
<!-- put in the newline -->
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
When applied to your sample XML, generates the following output
Python Does Everythig|Smith|<Book id="123"><Title>Python Does Everythig</Title><Author>Smith</Author></Book>
Postgres is Neat|Wesson|<Book id="456"><Title>Postgres is Neat</Title><Author>Wesson</Author></Book>

Answer 2

Try that :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="//Book"/>
</xsl:template>
<xsl:template match="Book">
<xsl:value-of select="Title" />
<xsl:text>|</xsl:text>
<xsl:value-of select="Author" />
<xsl:text>|</xsl:text>
<xsl:apply-templates select="." mode="outputTags"/>
</xsl:template>
<xsl:template match="*" mode="outputTags">
<xsl:text><</xsl:text>
<xsl:value-of select="local-name()"/>
<xsl:apply-templates select="#*"/>
<xsl:text>></xsl:text>
<xsl:apply-templates mode="outputTags"/>
<xsl:text></</xsl:text>
<xsl:value-of select="local-name()"/>
<xsl:text>></xsl:text>
<xsl:if test="self::Book">
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:template>
<xsl:template match="#*">
<xsl:text> </xsl:text>
<xsl:value-of select="local-name()"/>
<xsl:text>="</xsl:text>
<xsl:value-of select="."/>
<xsl:text>"</xsl:text>
</xsl:template>
</xsl:stylesheet>
It produces the following result from your input file :
Python Does Everythig|Smith|<Book id="123"><Title>Python Does Everythig</Title><Author>Smith</Author></Book>
Postgres is Neat|Wesson|<Book id="456"><Title>Postgres is Neat</Title><Author>Wesson</Author></Book>