Django: associating a user with model instance - django

Question

Let's say that I have a model that handles recipes, and I want to allow users to input their own recipes via a form. I then want to associate that recipe entry with the user ID of the user who inputted it. My guess is that my model would look something like this:
class Recipe(models.Model):
name = models.CharField(max_length=100)
body = models.TextField()
creator = models.ManyToManyField(User)
def __unicode__(self):
return self.creator
Is that correct? And if I created a model form, it would look something like this:
class RecipeForm(ModelForm):
class Meta:
model = Recipe
But how would I go about automatically passing the user information to the Recipe model upon submission? Would this take place in my view?
My current view is like this:
def recipe(request):
if request.method == 'POST':
form = RecipeForm(request.POST) #if POST method, bound form to POST data
if form.is_valid():
form.save()
else:
form = RecipeForm() #unbound form.
recipe_list = Recipe.objects.all()
return render_to_response('forms/recipes.html',
{'form': form, 'recipe_list': recipe_list},
context_instance = RequestContext(request))
How would I set the user to the model before saving it?

Answer 1

Yes, your view would need to set the user on the recipe model before saving it.

Answer 2

Edit:
You should accept Ignacio's answer, since he added it in the comment.
Here is how you would add your user:
from django.shortcuts import render
def recipe(request):
if request.method == 'POST':
form = RecipeForm(request.POST) #if POST method, bound form to POST data
if form.is_valid():
obj = form.save(commit=False) # don't save to DB
obj.creator = request.user # adds the user
obj.save()
else:
form = RecipeForm() #unbound form.
recipe_list = Recipe.objects.all()
return render(request,'forms/recipes.html',
{'form': form, 'recipe_list': recipe_list})