I'm very bad at regex.
The below expression does mostly what I need, but it requires the user to input "0.XX" for decimals, rather than allowing ".XX", without having to type the "0".
Could someone give me the heads up on this?
Thanks!
ValidationExpression="^([0-9]{1,3}(\.[0-9]{1,2})?)?$"
The {1,3} means that the RE will allow 1 to 3 of the previous atom (digits 0-9), so just change it to {0,3} to allow 0 to 3 digits preceding the decimal.
Related
I want to check if a number is 50 or more using a regular expression. This in itself is no problem but the number field has another regex checking the format of the entered number.
The number will be in the continental format: 123.456,78 (a dot between groups of three digits and always a comma with 2 digits at the end)
Examples:
100.000,00
50.000,00
50,00
34,34
etc.
I want to capture numbers which are 50 or more. So from the four examples above the first three should be matched.
I've come up with this rather complicated one and am wondering if there is an easier way to do this.
^(\d{1,3}[.]|[5-9][0-9]|\d{3}|[.]\d{1,3})*[,]\d{2}$
EDIT
I want to match continental numbers here. The numbers have this format due to internal regulations and specify a price.
Example: 1000 EUR would be written as 1.000,00 EUR
50000 as 50.000,00 and so on.
It's a matter of taste, obviously, but using a negative lookahead gives a simple solution.
^(?!([1-4]?\d),)[1-9](\d{1,2})?(\.\d{3})*,\d{2}\b
In words: starting from a boundary ignore all numbers that start with 1 digit OR 2 digits (the first being a 1,2,3 or 4), followed by a comma.
Check on regex101.com
Try:
EDIT ^(.{3,}|[5-9]\d),\d{2}$
It checks if:
there 3 chars or more before the ,
there are 2 numbers before the , and the first is between 5 and 9
and then a , and 2 numbers
Donno if it answer your question as it'll return true for:
aa50,00
1sdf,54
But this assumes that your original string is a number in the format you expect (as it was not a requirement in your question).
EDIT 3
The regex below tests if the number is valid referring to the continental format and if it's equal or greater than 50. See tests here.
Regex: ^((([1-9]\d{0,2}\.)(\d{3}\.){0,}\d{3})|([1-9]\d{2})|([5-9]\d)),\d{2}$
Explanation (d is a number):
([1-9]\d{0,2}\.): either d., dd. or ddd. one time with the first d between 1 and 9.
(\d{3}\.){0,}: ddd. zero or x time
\d{3}: ddd 3 digit
These 3 parts combined match any numbers equals or greater than 1000 like: 1.000, 22.002 or 100.000.000.
([1-9]\d{2}): any number between 100 and 999.
([5-9]\d)): a number between 5 and 9 followed by a number. Matches anything between 50 and 99.
So it's either the one of the parts above or this one.
Then ,\d{2}$ matches the comma and the two last digits.
I have named all inner groups, for better understanding what part of number is matched by each group. After you understand how it works, change all ?P<..> to ?:.
This one is for any dec number in the continental format.
^(?P<common_int>(?P<int>(?P<int_start>[1-9]\d{1,2}|[1-9]\d|[1-9])(?P<int_end>\.\d{3})*|0)(?!,)|(?P<dec_int_having_frac>(?P<dec_int>(?P<dec_int_start>[1-9]\d{1,2}|[1-9]\d|[1-9])(?P<dec_int_end>\.\d{3})*,)|0,|,)(?=\d))(?P<frac_from_comma>(?<=,)(?P<frac>(?P<frac_start>\d{3}\.)*(?P<frac_end>\d{1,3})))?$
test
This one is for the same with the limit number>=50
^(?P<common_int>(?P<int>(?P<int_start>[1-9]\d{1,2}|[1-9]\d|[1-9])(?P<int_end>\.\d{3})+|(?P<int_short>[1-9]\d{2}|[5-9]\d))(?!,)|(?P<dec_int_having_frac>(?P<dec_int>(?P<dec_int_start>[1-9]\d{1,2}|[1-9]\d|[1-9])(?P<dec_int_end>\.\d{3})+,)|(?P<dec_short_int>[1-9]\d{2}|[5-9]\d),)(?=\d))(?P<frac_from_comma>(?<=,)(?P<frac>(?P<frac_start>\d{3}\.)*(?P<frac_end>\d{1,3})))?$
tests
If you always have the integer part under 999.999 and fractal part always 2 digits, it will be a bit more simple:
^(?P<dec_int_having_frac>(?P<dec_int>(?P<dec_int_start>[1-9]\d{1,2}|[1-9]\d|[1-9])(?P<dec_int_end>\.\d{3})?,)|(?P<dec_short_int>[1-9]\d{2}|[5-9]\d),)(?=\d)(?P<frac_from_comma>(?<=,)(?P<frac>(?P<frac_end>\d{1,2})))?$
test
If you can guarantee that the number is correctly formed -- that is, that the regex isn't expected to detect that 5,0.1 is invalid, then there are a limited number of passing cases:
ends with \d{3}
ends with [5-9]\d
contains \d{3},
contains [5-9]\d,
It's not actually necessary to do anything with \.
The easiest regex is to code for each of these individually:
(\d{3}$|[5-9]\d$|\d{3},|[5-9]\d)
You could make it more compact and efficient by merging some of the cases:
(\d{3}[$,]|[5-9]\d[$,])
If you need to also validate the format, you will need extra complexity. I would advise against attempting to do both in a single regex.
However unless you have a very good reason for having to do this with a regex, I recommend against it. Parse the string into an integer, and compare it with 50.
I have a string of 8 separated hexadecimal numbers, such as:
3E%12%3%1F%3E%6%1%19
And I need to check if the number 12 is located within the first 4 set of numbers.
I'm guessing this shouldn't be all that complex, but my searches turned up empty. Regular expressions are always a trouble for me, but I don't have access to anything else in this scenario. Any help would be appreciated.
^([^%]+%){0,3}12%
See it in action
The idea is:
^ - from the start
[^%]+% - match multiple non % characters, followed by a % character
{0,3} - between 0 and 3 of those
12% - 12% after that
Here you go
^([^%]*%){4}(?<=.*12.*)
This will match both the following if that is what is intended
1%312%..
1%123%..
Check the solution if %123% is matched or not
If the number 12 should stand on its own then use
^([^%]*%){4}(?<=.*\b12\b.*)
Am playing around with regexp's but this is my headache. I have a dynamic number which needs a suffix. The suffix is always 0 to 9, 99 or 999.
Example:
I have the number 461200 and now I want to create an regexp that will match 461200 to 461209. What I've learned it should be ^46120[0-9]$? Is this correct or somewhere to the left of hell?
Ok, let us assume it is correct and I now want to match 461200 - 461299? This is where I get lost.
^4612[0-9]{2}?
It cannot be. I am yet to figure this out.
Any help appreciated.
For 1 digit at the end you need:
^4612[0-9]$
2 digits at the end:
^4612[0-9]{2}$
3 digits at the end:
^4612[0-9]{3}$
The number in braces {} means the number of time the preceding character or set has to be repeated.
Ok, let us assume it is correct and I now want to match 461200 -
461299?
You can either repeat the desired character class by saying [0-9][0-9] or use quantifiers [0-9]{2}.
It can be either:
^4612[0-9][0-9]$
or
^4612[0-9]{2}$
Both would work.
maybe try this regex:
^4612\d{2}$
I need to only accept input that meets these rules...
0.25-24
Increments of .25 (.00, .25, .50, .75)
First digit doesn't have to be required.
Would like trailing zeros to be optional.
Examples of some valid entries:
0.25
.50
.5
1
1.0
5.50
23.75
24 (max allowed)
UPDATE: nothing at all, null/blank, should also be accepted as valid
Example of some invalid entries:
0
.0
.00
0.0
0.00
24.25
-1
I understand that RegEx is a pattern matching language therefore it's not great for ranges, less-than, and great-than checking. So to check if it's less than or equal to 24 means I'd have to find a pattern, right? So there are 24 possible patters which would make this a long RegEx, am I understanding this correctly? I could use ColdFusion to do the check to make sure it's in the 0-24 range. It's not the end of the world if I have use ColdFusion for this part, but it'd be nice to get it all into the RegEx if it doesn't cause it to be too long. This is what I have so far:
^\d{0,2}((\.(0|00|25|5|50|75))?)$
http://regex101.com/r/iS7zM3
This handles pretty much all of it except for the 0-24 range check or the check for just a zero. I'll keep plugging away at it but any help would be appreciated. Thanks!
Change \d{0,2} to (?:1[0-9]?|2[0-4]?|[3-9])? and it'll match from 1 to 24 (or nothing).
You can also simplify the second part to (?:\.(?:00?|25|50?|75))? - you could go further to (?:\.(?:[05]0?|[27]5))? but that might obfuscate the intent a bit too far.
To exclude 24.25 you could perhaps use a negative lookahead (?!24\.[^0]) to prevent anything other than 24.0 or 24.00, but it's probably simpler to just exclude 24 from the main pattern and include a specific check for 24/24.0/24.00 at the start:
(?x)
# checks for 24
^24$|^24\.00?$
|
# integer part
^
(?:1[0-9]?|2[0-3]?|[3-9]|0(?=\.[^0])|(?=\.[^0]))
# decimal part
(?:\.(?:00?|25|50?|75))?
$
That also includes a check for 0(?=\.[^0]) which uses a positive lookahead to only allow an initial 0 if the next char is a . followed by a non-zero (so 0.0 and 0.00 isn't allowed).
The (?x) flag allows whitespace to be ignored, allowing readable regex in your code - obviously preferable to squashing it all onto a single line - and also enables the use of # to start line comments to explain parts of a pattern. (Literal whitespaces and hashes can be escaped with backslash, or encoded via e.g. \x23 for hash.)
For comparison, here's a pure-CFML way of doing it:
IsNumeric(Num)
AND Num GT 0
AND Num LTE 24
AND NOT find('.',Num*4)
Now, are you really sure it's better as a regex...
You could try this regex (broken down):
^
(?:
(?:[1-9]|1\d|2[0-3])(?:\.(?:[05]0?|[27]5))? # Non-zeros with optional decimal
|
0?(?:\.(?:50?|[27]5)) # Decimals under 1
|
24(?:\.00?)? # The maximum
)
$
In one line:
^(?:(?:[1-9]|1\d|2[0-3])(?:\.(?:[05]0?|[27]5))?|0?(?:\.(?:50?|[27]5))|24(?:\.00?)?)$
regex101 demo
^([0-1]?[0-9]|2[0-4])((\.(0|00|25|5|50|75))?)$
This means the one's place can be 0-9 if the tens place is missing, a 0, or 1.
If the tens place is a 2, then the ones place can be 0-4.
The second part is great, it's simple and readable too. It has an extra set of parens though that can be removed, reducing it to this:
^([0-1]?[0-9]|2[0-4])(\.(0|00|25|5|50|75))?$
My aim is to write a regular expression for a decimal number where a valid number is one of
xx.0, xx.125, xx.25, xx.375, xx.5, xx.625, xx.75, xx.875 (i.e. measured in 1/8ths) The xx can be 0, 1 or 2 digits.
i have come up with the following regex:
^\d*\.?((25)|(50)|(5)|(75)|(0)|(00))?$
while this works for 0.25,0.5,0.75 it wont work for 0.225, 0.675 etc .
i assumed that the '?' would work in a case where there is preceding number as well.
Can someone point out my mistake
Edit : require the number to be a decimal !
Edit2 : i realized my mistake i was confused about the '?'. Thank you.
I would add another \d* after the literal . check \.
^\d*\.?\d*((25)|(50)|(5)|(75)|(0)|(00))?$
I think it would probably just be easier to multiply the decimal part by 8, but you don't consider digits that lead the last two decimals in the regex.
^\d{0,2}\.(00?|(1|6)?25|(3|8)?75|50?)$
Your mistake is: \.? indicates one optional \., not a digit (or anything else, in this case).
About the ? (question mark) operator: Makes the preceding item optional. Greedy, so the optional item is included in the match if possible. (source)
^\d{0,2}\.(0|(1|2|6)?25|(3|6|8)?75|5)$
Regular expressions are for matching patterns, not checking numeric values. Find a likely string with the regex, then check its numeric value in whatever your host language is (PHP, whatever).