Template function messed up - c++

Question

so im having a bit of problem with my ResourceManager class for a game im working on with c++.
so i tried to make a template function out of my regular addImage function so it will add sounds too but i got some errors which i cant really handle can you guys help me? :D
.hpp
#ifndef RESOURCE_MANAGER_HPP
#define RESOURCE_MANAGER_HPP
#include "Image.cpp"
#include "SoundBuffer.cpp"
#include <SFML/Graphics.hpp>
#include <SFML/Audio.hpp>
typedef std::map<std::string, sz::Image*> ImagesContainer;
typedef std::map<std::string, sz::Image*>::iterator ImagesContainerIt;
typedef std::map<std::string, sz::SoundBuffer*> SoundsContainer;
typedef std::map<std::string, sz::SoundBuffer*>::iterator SoundsContainerIt;
typedef std::map<std::string, sf::Music*> MusicContainer;
typedef std::map<std::string, sf::Music*>::iterator MusicContainerIt;
namespace sz
{
// meanwhile this class is only for images, need to edit later for
// it to be also able to load sounds, etc...
class ResourceManager{
private:
ResourceManager() {};
ResourceManager(ResourceManager const&) {};
static ResourceManager *rm;
// add functions and variables here
ImagesContainer imagesContainer;
SoundsContainer soundsContainer;
MusicContainer musicContainer;
template <class type>
void AddNew(std::string imagePath);
public:
static ResourceManager *Instance();
// add functions here
template <class type>
type *Get(std::string imagePath);
};
}
#endif
.cpp
#include "ResourceManager.hpp"
#include <typeinfo>
namespace sz
{
ResourceManager *ResourceManager::rm = NULL;
ResourceManager *ResourceManager::Instance()
{
if (!rm)
rm = new ResourceManager;
return rm;
}
template <class type>
void ResourceManager::AddNew(std::string filePath)
{
type *item = new type(filePath);
if(typeid(type) == typeid(sz::Image))
imagesContainer[filePath] = item;
else if(typeid(type) == typeid(sz::SoundBuffer))
soundsContainer[filePath] = item;
else
return;
}
template <class type>
type *ResourceManager::Get(std::string filePath)
{
if(typeid(type) == typeid(sz::Image))
{
ImagesContainerIt it = imagesContainer.find(filePath);
if(it == imagesContainer.end())
{
AddNew<type>(filePath);
}
it = imagesContainer.find(filePath);
return it->second;
}
else if(typeid(type) == typeid(sz::SoundBuffer))
{
SoundsContainerIt it = soundsContainer.find(filePath);
if(it == soundsContainer.end())
{
AddNew<type>(filePath);
}
it = soundsContainer.find(filePath);
return it->second;
}
else
return NULL;
}
}
the errors #_#
g++ -Wall -c "Sprite.cpp" (in directory: /home/gannash/Desktop/Open Heroes/Engine)
In file included from Sprite.cpp:2:0:
ResourceManager.cpp: In member function ‘type* sz::ResourceManager::Get(std::string) [with type = sz::Image, std::string = std::basic_string<char>]’:
Sprite.cpp:10:65: instantiated from here
ResourceManager.cpp:50:15: error: cannot convert ‘sz::SoundBuffer*’ to ‘sz::Image*’ in return
ResourceManager.cpp: In member function ‘void sz::ResourceManager::AddNew(std::string) [with type = sz::Image, std::string = std::basic_string<char>]’:
ResourceManager.cpp:36:5: instantiated from ‘type* sz::ResourceManager::Get(std::string) [with type = sz::Image, std::string = std::basic_string<char>]’
Sprite.cpp:10:65: instantiated from here
ResourceManager.cpp:23:4: error: cannot convert ‘sz::Image*’ to ‘std::map<std::basic_string<char>, sz::SoundBuffer*>::mapped_type {aka sz::SoundBuffer*}’ in assignment
ResourceManager.cpp: In member function ‘type* sz::ResourceManager::Get(std::string) [with type = sz::Image, std::string = std::basic_string<char>]’:
ResourceManager.cpp:55:2: warning: control reaches end of non-void function [-Wreturn-type]
Compilation failed.

Answer 1

Ok, this is my idea after having a look at the code and error messages.
You cannot return Image and Sound from the same function like that. They are individual types. And you have to specify what type is going to be returned. When you put the if/else in your template it still will check to see if it can return all those types, and that will fail.
You have to return a BaseClass*(or whatever you want to call it) that both Image and Sound inherits from.

Answer 2

The templated function have to be completely defined for the compiler to able to use them. That means you have to move the body of those function from the source file to the header file.
Edit:
You have to check the how you use the template class. See for example this error message:
ResourceManager.cpp:50:15: error: cannot convert ‘sz::SoundBuffer*’ to ‘sz::Image*’ in return
Unless sz::SoundBuffer inherits from sz::Image you have a mismatch between types.

Answer 3

"Compile-time if" is done via template partial specialization. But here it's not even needed:
template<typename type> struct Container {
static std::map<std::string, type*> container;
};
std::map<std::string, sz::Image*>& ImagesContainer = Container<sz::Image>::container;
// etc...
template <class type>
void ResourceManager::AddNew(std::string filePath)
{
type *item = new type(filePath);
Container<type>::container[filePath] = item;
}