Compiling SkyFireEMU error, sizeof(void *) is neither - c++

I'm trying to compile SkyFireEMU (https://github.com/ProjectSkyfire/SkyFireEMU) with Visual Studio 2010 (32 BIT) but I get an error (On almost all files of "worldserver"):
fatal error C1189: #error : sizeof(void *) is neither sizeof(int) nor sizeof(long) nor sizeof(long long)
This rederects me to this peace of code:
#if SIZEOF_CHARP == SIZEOF_INT
typedef int intptr;
#elif SIZEOF_CHARP == SIZEOF_LONG
typedef long intptr;
#elif SIZEOF_CHARP == SIZEOF_LONG_LONG
typedef long long intptr;
#else
#error sizeof(void *) is neither sizeof(int) nor sizeof(long) nor sizeof(long long)
#endif
Can someone help me with fixing this problem? What does the error mean? I really don't know what goes wrong.

The code is old. Today you can use typedef intptr_t intptr (aka std::intptr_t in <cstdint>).

SIZEOF_CHARP is not being set appropriately (according to whoever wrote that code), hence invoking the error message. Your best bet is to consult the SkyFireEMU documentation, you may need to set this flag before compiling, or something along these lines.
Having said this, I did a quick Google and found this, which describes an identical error message. It suggests writing the following right before the block you provide:
#ifndef SIZEOF_CHARP
#define SIZEOF_CHARP SIZEOF_LONG
#endif
There may still be an underlying problem though, since this really only suppresses the error.

Related

lseek error when -D_FILE_OFFSET_BITS=64 is used on solaris

I am using -D_FILE_OFFSET_BITS=64 flag while compiling my application on Unix. It gets built properly on RHEL, SuSE, HP-uX and AIX.
On Solaris, I am getting an error for following:
long lPos = 0L;
long UTMPSIZE = sizeof(struct utmp);
int fd = 0;
fd = open("/etc/utmp", O_RDONLY);
UTMPSIZE = sizeof(struct utmpx);
lPos = lseek(fd, -UTMPSIZE, SEEK_END); // error: conversion from `long int' to non-scalar type `off_t' requested
I read somewhere that using -D_FILE_OFFSET_BITS=64, the long gets #defined to off_t.
If that is so, why this error happens?
I wrote the same steps in a cpp program, compiled and executed on a soalris system, and it works. However only while compiling the application, the error is seen.
This is what i have in types.h:
#if __STDC__ - 0 == 0 && !defined(_NO_LONGLONG)
typedef long long longlong_t;
typedef unsigned long long u_longlong_t;
#else
/* used to reserve space and generate alignment */
typedef union {
double _d;
int32_t _l[2];
} longlong_t;
typedef union {
double _d;
uint32_t _l[2];
} u_longlong_t;
#endif /* __STDC__ - 0 == 0 && !defined(_NO_LONGLONG) */
#ifndef _OFF_T
#define _OFF_T
#if defined(_LP64) || _FILE_OFFSET_BITS == 32
typedef long off_t; /* offsets within files */
#elif _FILE_OFFSET_BITS == 64
typedef longlong_t off_t; /* offsets within files */
#endif
#if defined(_LARGEFILE64_SOURCE)
#ifdef _LP64
typedef off_t off64_t; /* offsets within files */
#else
typedef longlong_t off64_t; /* offsets within files */
#endif
#endif /* _LARGEFILE64_SOURCE */
#endif /* _OFF_T */
If I use long long in code, the error is now changed to "long long int".
To solve above problem, I have added #define _FILE_OFFSET_BITS 64. It was found that in one of the header same flag value was set to 32. I don't know what happened but, using compile time flag did not override that #define. I then added following after the #include:
#ifdef <SunOS>
#undef _FILE_OFFSET_BITS
#define _FILE_OFFSET_BITS 64
#endif
This rectifies the compile time error. But now there is another problem, the stat structure members after stat() call are not getting populated properly. I have no clue why is it happening so.
Any help here is much appreciated..
The "non-scalar type" part of the error message is suspicious, as it implies that off_t is being implemented as some kind of struct instead of a 64-bit integer.
Is gcc up-to-date on the Solaris machine? Specifically, if you are using gcc 4.3.0 on Solaris, you may be experiencing GCC bug 30513 (https://gcc.gnu.org/bugzilla/show_bug.cgi?id=30513). If you look at comment 9 in the bug report, you can see they get a very similar error: "conversion from 'jlong' to non-scalar type 'off_t' requested".

Compiler Depenedent Error with typedef

I am trying to compile my project with different compilers. i have a stable compiled version of the project compiling without any error with the ARM 4.41 compiler. I want to compiler the exactly same source code with the ARM 5 compiler and the Win64 compiler. How ever without any change in the source code, just by switching the compiler from ARM 4.41 to ARM 5 && ARM 4.41 to Win64 i am getting the following error with the typedef's.
I am not able to figure it out, why does it behaves so..?
Header file with typedef's - a_stdtypes.h
#define _STD_TYPE_H
typedef unsigned char bool; // Error #84: invalid combination of type specifiers
typedef unsigned char bit8;
typedef unsigned short bit16;
typedef unsigned long bit32;
This isn't legal C++ code. bool is a reserved keyword of the language - a type. You cannot redefine its meaning. It would be legal C code, though.
I guess it was wrote because someone want to define bool for C, then someone else want to use it from C++.
a neater solution is to use cplusplus macro, like this:
#ifndef __cplusplus
typedef unsigned char bool;
#endif
typedef unsigned char bit8;
typedef unsigned short bit16;
typedef unsigned long bit32;

Typedef redefinition of UInt32 in MacTypes.h, from definition in CFBase.h

I'm getting a typedef redefinition error on two lines in MacTypes.h, in the following chunk of code:
#if __LP64__
typedef unsigned int UInt32;
typedef signed int SInt32;
#else
typedef unsigned long UInt32; // error here
typedef signed long SInt32; // error here
#endif
The Clang error points to the following previous definition, in CFBase.h (in CoreFoundation.framework):
#if !defined(__MACTYPES__)
#if !defined(_OS_OSTYPES_H)
typedef unsigned char Boolean;
typedef unsigned char UInt8;
typedef signed char SInt8;
typedef unsigned short UInt16;
typedef signed short SInt16;
typedef unsigned int UInt32; // previous definition is here
typedef signed int SInt32; // previous definition is here
typedef uint64_t UInt64;
typedef int64_t SInt64;
typedef SInt32 OSStatus;
#endif
...
This is very strange, since __LP64__ is apparently always true on the Mac platform, so why is that typedef even being evaluated? And why is there a path of compilation in which two OS-provided definitions are contradicting each other?
EDIT: Here is a screenshot of the errors in Xcode.
I've blanked out the path of the file that includes <Carbon/Carbon.h> since it contains the name of my client (the file is the same for both errors). The full path names below that are as follows (all contained within Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.8.sdk/System/Library/Frameworks):
Carbon.framework/Headers/Carbon.h:20
CoreServices.framework/Headers/CoreServices.h:18
CoreServices.framework/Frameworks/AE.framework/Headers/AE.h:20
CoreServices.framework/Frameworks/CarbonCore.framework/Headers/CarbonCore.h:27
CoreServices.framework/Frameworks/CarbonCore.framework/Headers/MacTypes.h:27
Update:
In my own code, just before #include <Carbon/Carbon.h> I've added the following:
#if __LP64__
#error Has LP64
#else
#error Doesn't have LP64
#endif
...and I'm getting the 'Doesn't have LP64' error, so this seems to be the root of the problem. However, when I compile the following in Sublime Text 2 (with SublimeClang)...
int main()
{
#if __LP64__
#error Has LP64
#else
#error Doesn't have LP64
#endif
return 0;
}
...I get "Has LP64". Doing a project text search for #define __LP64__ I can't find anything in my project, and when searching for __LP64__ it just comes up with a load of #ifs and #ifdefs. Does anyone know where this error could have come from?
In the end it turned out this problem was due to multiple installs of Xcode: I had recently installed Xcode 4.4 (from the App Store) and I still had an install of Xcode 3 somewhere. I solved this by running uninstall-devtools which removed Xcode 3, along with all its various paths in the Library and Developer folders. I'm not sure why conflicting installs of Xcode would cause a problem like this, but removing Xcode 3 solved it. I hope this helps anyone who has a problem like this - it's certainly not what I expected the problem to be.

how to tell if 32 or 64 bit? [duplicate]

I'm looking for a way to reliably determine whether C++ code is being compiled in 32 vs 64 bit. We've come up with what we think is a reasonable solution using macros, but was curious to know if people could think of cases where this might fail or if there is a better way to do this. Please note we are trying to do this in a cross-platform, multiple compiler environment.
#if ((ULONG_MAX) == (UINT_MAX))
# define IS32BIT
#else
# define IS64BIT
#endif
#ifdef IS64BIT
DoMy64BitOperation()
#else
DoMy32BitOperation()
#endif
Thanks.
Unfortunately there is no cross platform macro which defines 32 / 64 bit across the major compilers. I've found the most effective way to do this is the following.
First I pick my own representation. I prefer ENVIRONMENT64 / ENVIRONMENT32. Then I find out what all of the major compilers use for determining if it's a 64 bit environment or not and use that to set my variables.
// Check windows
#if _WIN32 || _WIN64
#if _WIN64
#define ENVIRONMENT64
#else
#define ENVIRONMENT32
#endif
#endif
// Check GCC
#if __GNUC__
#if __x86_64__ || __ppc64__
#define ENVIRONMENT64
#else
#define ENVIRONMENT32
#endif
#endif
Another easier route is to simply set these variables from the compiler command line.
template<int> void DoMyOperationHelper();
template<> void DoMyOperationHelper<4>()
{
// do 32-bits operations
}
template<> void DoMyOperationHelper<8>()
{
// do 64-bits operations
}
// helper function just to hide clumsy syntax
inline void DoMyOperation() { DoMyOperationHelper<sizeof(size_t)>(); }
int main()
{
// appropriate function will be selected at compile time
DoMyOperation();
return 0;
}
Unfortunately, in a cross platform, cross compiler environment, there is no single reliable method to do this purely at compile time.
Both _WIN32 and _WIN64 can sometimes both be undefined, if the project settings are flawed or corrupted (particularly on Visual Studio 2008 SP1).
A project labelled "Win32" could be set to 64-bit, due to a project configuration error.
On Visual Studio 2008 SP1, sometimes the intellisense does not grey out the correct parts of the code, according to the current #define. This makes it difficult to see exactly which #define is being used at compile time.
Therefore, the only reliable method is to combine 3 simple checks:
1) Compile time setting, and;
2) Runtime check, and;
3) Robust compile time checking.
Simple check 1/3: Compile time setting
Choose any method to set the required #define variable. I suggest the method from #JaredPar:
// Check windows
#if _WIN32 || _WIN64
#if _WIN64
#define ENV64BIT
#else
#define ENV32BIT
#endif
#endif
// Check GCC
#if __GNUC__
#if __x86_64__ || __ppc64__
#define ENV64BIT
#else
#define ENV32BIT
#endif
#endif
Simple check 2/3: Runtime check
In main(), double check to see if sizeof() makes sense:
#if defined(ENV64BIT)
if (sizeof(void*) != 8)
{
wprintf(L"ENV64BIT: Error: pointer should be 8 bytes. Exiting.");
exit(0);
}
wprintf(L"Diagnostics: we are running in 64-bit mode.\n");
#elif defined (ENV32BIT)
if (sizeof(void*) != 4)
{
wprintf(L"ENV32BIT: Error: pointer should be 4 bytes. Exiting.");
exit(0);
}
wprintf(L"Diagnostics: we are running in 32-bit mode.\n");
#else
#error "Must define either ENV32BIT or ENV64BIT".
#endif
Simple check 3/3: Robust compile time checking
The general rule is "every #define must end in a #else which generates an error".
#if defined(ENV64BIT)
// 64-bit code here.
#elif defined (ENV32BIT)
// 32-bit code here.
#else
// INCREASE ROBUSTNESS. ALWAYS THROW AN ERROR ON THE ELSE.
// - What if I made a typo and checked for ENV6BIT instead of ENV64BIT?
// - What if both ENV64BIT and ENV32BIT are not defined?
// - What if project is corrupted, and _WIN64 and _WIN32 are not defined?
// - What if I didn't include the required header file?
// - What if I checked for _WIN32 first instead of second?
// (in Windows, both are defined in 64-bit, so this will break codebase)
// - What if the code has just been ported to a different OS?
// - What if there is an unknown unknown, not mentioned in this list so far?
// I'm only human, and the mistakes above would break the *entire* codebase.
#error "Must define either ENV32BIT or ENV64BIT"
#endif
Update 2017-01-17
Comment from #AI.G:
4 years later (don't know if it was possible before) you can convert
the run-time check to compile-time one using static assert:
static_assert(sizeof(void*) == 4);. Now it's all done at compile time
:)
Appendix A
Incidentially, the rules above can be adapted to make your entire codebase more reliable:
Every if() statement ends in an "else" which generates a warning or error.
Every switch() statement ends in a "default:" which generates a warning or error.
The reason why this works well is that it forces you to think of every single case in advance, and not rely on (sometimes flawed) logic in the "else" part to execute the correct code.
I used this technique (among many others) to write a 30,000 line project that worked flawlessly from the day it was first deployed into production (that was 12 months ago).
You should be able to use the macros defined in stdint.h. In particular INTPTR_MAX is exactly the value you need.
#include <cstdint>
#if INTPTR_MAX == INT32_MAX
#define THIS_IS_32_BIT_ENVIRONMENT
#elif INTPTR_MAX == INT64_MAX
#define THIS_IS_64_BIT_ENVIRONMENT
#else
#error "Environment not 32 or 64-bit."
#endif
Some (all?) versions of Microsoft's compiler don't come with stdint.h. Not sure why, since it's a standard file. Here's a version you can use: http://msinttypes.googlecode.com/svn/trunk/stdint.h
That won't work on Windows for a start. Longs and ints are both 32 bits whether you're compiling for 32 bit or 64 bit windows. I would think checking if the size of a pointer is 8 bytes is probably a more reliable route.
You could do this:
#if __WORDSIZE == 64
char *size = "64bits";
#else
char *size = "32bits";
#endif
Try this:
#ifdef _WIN64
// 64 bit code
#elif _WIN32
// 32 bit code
#else
if(sizeof(void*)==4)
// 32 bit code
else
// 64 bit code
#endif
Below code works fine for most current environments:
#if defined(__LP64__) || defined(_WIN64) || (defined(__x86_64__) && !defined(__ILP32__) ) || defined(_M_X64) || defined(__ia64) || defined (_M_IA64) || defined(__aarch64__) || defined(__powerpc64__)
#define IS64BIT 1
#else
#define IS32BIT 1
#endif
"Compiled in 64 bit" is not well defined in C++.
C++ sets only lower limits for sizes such as int, long and void *. There is no guarantee that int is 64 bit even when compiled for a 64 bit platform. The model allows for e.g. 23 bit ints and sizeof(int *) != sizeof(char *)
There are different programming models for 64 bit platforms.
Your best bet is a platform specific test. Your second best, portable decision must be more specific in what is 64 bit.
Your approach was not too far off, but you are only checking whether long and int are of the same size. Theoretically, they could both be 64 bits, in which case your check would fail, assuming both to be 32 bits. Here is a check that actually checks the size of the types themselves, not their relative size:
#if ((UINT_MAX) == 0xffffffffu)
#define INT_IS32BIT
#else
#define INT_IS64BIT
#endif
#if ((ULONG_MAX) == 0xfffffffful)
#define LONG_IS32BIT
#else
#define LONG_IS64BIT
#endif
In principle, you can do this for any type for which you have a system defined macro with the maximal value.
Note, that the standard requires long long to be at least 64 bits even on 32 bit systems.
People already suggested methods that will try to determine if the program is being compiled in 32-bit or 64-bit.
And I want to add that you can use the c++11 feature static_assert to make sure that the architecture is what you think it is ("to relax").
So in the place where you define the macros:
#if ...
# define IS32BIT
static_assert(sizeof(void *) == 4, "Error: The Arch is not what I think it is")
#elif ...
# define IS64BIT
static_assert(sizeof(void *) == 8, "Error: The Arch is not what I think it is")
#else
# error "Cannot determine the Arch"
#endif
Borrowing from Contango's excellent answer above and combining it with "Better Macros, Better Flags" from Fluent C++, you can do:
// Macro for checking bitness (safer macros borrowed from
// https://www.fluentcpp.com/2019/05/28/better-macros-better-flags/)
#define MYPROJ_IS_BITNESS( X ) MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_##X()
// Bitness checks borrowed from https://stackoverflow.com/a/12338526/201787
#if _WIN64 || ( __GNUC__ && __x86_64__ )
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_64() 1
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_32() 0
# define MYPROJ_IF_64_BIT_ELSE( x64, x86 ) (x64)
static_assert( sizeof( void* ) == 8, "Pointer size is unexpected for this bitness" );
#elif _WIN32 || __GNUC__
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_64() 0
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_32() 1
# define MYPROJ_IF_64_BIT_ELSE( x64, x86 ) (x86)
static_assert( sizeof( void* ) == 4, "Pointer size is unexpected for this bitness" );
#else
# error "Unknown bitness!"
#endif
Then you can use it like:
#if MYPROJ_IS_BITNESS( 64 )
DoMy64BitOperation()
#else
DoMy32BitOperation()
#endif
Or using the extra macro I added:
MYPROJ_IF_64_BIT_ELSE( DoMy64BitOperation(), DoMy32BitOperation() );
Here are a few more ways to do what you want in modern C++.
You can create a variable that defines the number of system bits:
static constexpr size_t sysbits = (CHAR_BIT * sizeof(void*));
And then in C++17 you can do something like:
void DoMy64BitOperation() {
std::cout << "64-bit!\n";
}
void DoMy32BitOperation() {
std::cout << "32-bit!\n";
}
inline void DoMySysBitOperation()
{
if constexpr(sysbits == 32)
DoMy32BitOperation();
else if constexpr(sysbits == 64)
DoMy64BitOperation();
/*else - other systems. */
}
Or in C++20:
template<void* = nullptr>
// template<int = 32> // May be clearer, pick whatever you like.
void DoMySysBitOperation()
requires(sysbits == 32)
{
std::cout << "32-bit!\n";
}
template<void* = nullptr>
// template<int = 64>
void DoMySysBitOperation()
requires(sysbits == 64)
{
std::cout << "64-bit!\n";
}
template<void* = nullptr>
void DoMySysBitOperation()
/* requires(sysbits == OtherSystem) */
{
std::cout << "Unknown System!\n";
}
The template<...> is usually not needed, but since those functions will have the same mangling name, we must enforce the compiler to pick the correct ones. Also, template<void* = nullptr> may be confusing ( The other template may be better and more logically correct ), I only used it as a workaround to satisfy the compiler name mangling.
If you can use project configurations in all your environments, that would make defining a 64- and 32-bit symbol easy. So you'd have project configurations like this:
32-bit Debug
32-bit Release
64-bit Debug
64-bit Release
EDIT: These are generic configurations, not targetted configurations. Call them whatever you want.
If you can't do that, I like Jared's idea.
I'd place 32-bit and 64-bit sources in different files and then select appropriate source files using the build system.
I'm adding this answer as a use case and complete example for the runtime-check described in another answer.
This is the approach I've been taking for conveying to the end-user whether the program was compiled as 64-bit or 32-bit (or other, for that matter):
version.h
#ifndef MY_VERSION
#define MY_VERSION
#include <string>
const std::string version = "0.09";
const std::string arch = (std::to_string(sizeof(void*) * 8) + "-bit");
#endif
test.cc
#include <iostream>
#include "version.h"
int main()
{
std::cerr << "My App v" << version << " [" << arch << "]" << std::endl;
}
Compile and Test
g++ -g test.cc
./a.out
My App v0.09 [64-bit]

Determining 32 vs 64 bit in C++

I'm looking for a way to reliably determine whether C++ code is being compiled in 32 vs 64 bit. We've come up with what we think is a reasonable solution using macros, but was curious to know if people could think of cases where this might fail or if there is a better way to do this. Please note we are trying to do this in a cross-platform, multiple compiler environment.
#if ((ULONG_MAX) == (UINT_MAX))
# define IS32BIT
#else
# define IS64BIT
#endif
#ifdef IS64BIT
DoMy64BitOperation()
#else
DoMy32BitOperation()
#endif
Thanks.
Unfortunately there is no cross platform macro which defines 32 / 64 bit across the major compilers. I've found the most effective way to do this is the following.
First I pick my own representation. I prefer ENVIRONMENT64 / ENVIRONMENT32. Then I find out what all of the major compilers use for determining if it's a 64 bit environment or not and use that to set my variables.
// Check windows
#if _WIN32 || _WIN64
#if _WIN64
#define ENVIRONMENT64
#else
#define ENVIRONMENT32
#endif
#endif
// Check GCC
#if __GNUC__
#if __x86_64__ || __ppc64__
#define ENVIRONMENT64
#else
#define ENVIRONMENT32
#endif
#endif
Another easier route is to simply set these variables from the compiler command line.
template<int> void DoMyOperationHelper();
template<> void DoMyOperationHelper<4>()
{
// do 32-bits operations
}
template<> void DoMyOperationHelper<8>()
{
// do 64-bits operations
}
// helper function just to hide clumsy syntax
inline void DoMyOperation() { DoMyOperationHelper<sizeof(size_t)>(); }
int main()
{
// appropriate function will be selected at compile time
DoMyOperation();
return 0;
}
Unfortunately, in a cross platform, cross compiler environment, there is no single reliable method to do this purely at compile time.
Both _WIN32 and _WIN64 can sometimes both be undefined, if the project settings are flawed or corrupted (particularly on Visual Studio 2008 SP1).
A project labelled "Win32" could be set to 64-bit, due to a project configuration error.
On Visual Studio 2008 SP1, sometimes the intellisense does not grey out the correct parts of the code, according to the current #define. This makes it difficult to see exactly which #define is being used at compile time.
Therefore, the only reliable method is to combine 3 simple checks:
1) Compile time setting, and;
2) Runtime check, and;
3) Robust compile time checking.
Simple check 1/3: Compile time setting
Choose any method to set the required #define variable. I suggest the method from #JaredPar:
// Check windows
#if _WIN32 || _WIN64
#if _WIN64
#define ENV64BIT
#else
#define ENV32BIT
#endif
#endif
// Check GCC
#if __GNUC__
#if __x86_64__ || __ppc64__
#define ENV64BIT
#else
#define ENV32BIT
#endif
#endif
Simple check 2/3: Runtime check
In main(), double check to see if sizeof() makes sense:
#if defined(ENV64BIT)
if (sizeof(void*) != 8)
{
wprintf(L"ENV64BIT: Error: pointer should be 8 bytes. Exiting.");
exit(0);
}
wprintf(L"Diagnostics: we are running in 64-bit mode.\n");
#elif defined (ENV32BIT)
if (sizeof(void*) != 4)
{
wprintf(L"ENV32BIT: Error: pointer should be 4 bytes. Exiting.");
exit(0);
}
wprintf(L"Diagnostics: we are running in 32-bit mode.\n");
#else
#error "Must define either ENV32BIT or ENV64BIT".
#endif
Simple check 3/3: Robust compile time checking
The general rule is "every #define must end in a #else which generates an error".
#if defined(ENV64BIT)
// 64-bit code here.
#elif defined (ENV32BIT)
// 32-bit code here.
#else
// INCREASE ROBUSTNESS. ALWAYS THROW AN ERROR ON THE ELSE.
// - What if I made a typo and checked for ENV6BIT instead of ENV64BIT?
// - What if both ENV64BIT and ENV32BIT are not defined?
// - What if project is corrupted, and _WIN64 and _WIN32 are not defined?
// - What if I didn't include the required header file?
// - What if I checked for _WIN32 first instead of second?
// (in Windows, both are defined in 64-bit, so this will break codebase)
// - What if the code has just been ported to a different OS?
// - What if there is an unknown unknown, not mentioned in this list so far?
// I'm only human, and the mistakes above would break the *entire* codebase.
#error "Must define either ENV32BIT or ENV64BIT"
#endif
Update 2017-01-17
Comment from #AI.G:
4 years later (don't know if it was possible before) you can convert
the run-time check to compile-time one using static assert:
static_assert(sizeof(void*) == 4);. Now it's all done at compile time
:)
Appendix A
Incidentially, the rules above can be adapted to make your entire codebase more reliable:
Every if() statement ends in an "else" which generates a warning or error.
Every switch() statement ends in a "default:" which generates a warning or error.
The reason why this works well is that it forces you to think of every single case in advance, and not rely on (sometimes flawed) logic in the "else" part to execute the correct code.
I used this technique (among many others) to write a 30,000 line project that worked flawlessly from the day it was first deployed into production (that was 12 months ago).
You should be able to use the macros defined in stdint.h. In particular INTPTR_MAX is exactly the value you need.
#include <cstdint>
#if INTPTR_MAX == INT32_MAX
#define THIS_IS_32_BIT_ENVIRONMENT
#elif INTPTR_MAX == INT64_MAX
#define THIS_IS_64_BIT_ENVIRONMENT
#else
#error "Environment not 32 or 64-bit."
#endif
Some (all?) versions of Microsoft's compiler don't come with stdint.h. Not sure why, since it's a standard file. Here's a version you can use: http://msinttypes.googlecode.com/svn/trunk/stdint.h
That won't work on Windows for a start. Longs and ints are both 32 bits whether you're compiling for 32 bit or 64 bit windows. I would think checking if the size of a pointer is 8 bytes is probably a more reliable route.
You could do this:
#if __WORDSIZE == 64
char *size = "64bits";
#else
char *size = "32bits";
#endif
Try this:
#ifdef _WIN64
// 64 bit code
#elif _WIN32
// 32 bit code
#else
if(sizeof(void*)==4)
// 32 bit code
else
// 64 bit code
#endif
Below code works fine for most current environments:
#if defined(__LP64__) || defined(_WIN64) || (defined(__x86_64__) && !defined(__ILP32__) ) || defined(_M_X64) || defined(__ia64) || defined (_M_IA64) || defined(__aarch64__) || defined(__powerpc64__)
#define IS64BIT 1
#else
#define IS32BIT 1
#endif
"Compiled in 64 bit" is not well defined in C++.
C++ sets only lower limits for sizes such as int, long and void *. There is no guarantee that int is 64 bit even when compiled for a 64 bit platform. The model allows for e.g. 23 bit ints and sizeof(int *) != sizeof(char *)
There are different programming models for 64 bit platforms.
Your best bet is a platform specific test. Your second best, portable decision must be more specific in what is 64 bit.
Your approach was not too far off, but you are only checking whether long and int are of the same size. Theoretically, they could both be 64 bits, in which case your check would fail, assuming both to be 32 bits. Here is a check that actually checks the size of the types themselves, not their relative size:
#if ((UINT_MAX) == 0xffffffffu)
#define INT_IS32BIT
#else
#define INT_IS64BIT
#endif
#if ((ULONG_MAX) == 0xfffffffful)
#define LONG_IS32BIT
#else
#define LONG_IS64BIT
#endif
In principle, you can do this for any type for which you have a system defined macro with the maximal value.
Note, that the standard requires long long to be at least 64 bits even on 32 bit systems.
People already suggested methods that will try to determine if the program is being compiled in 32-bit or 64-bit.
And I want to add that you can use the c++11 feature static_assert to make sure that the architecture is what you think it is ("to relax").
So in the place where you define the macros:
#if ...
# define IS32BIT
static_assert(sizeof(void *) == 4, "Error: The Arch is not what I think it is")
#elif ...
# define IS64BIT
static_assert(sizeof(void *) == 8, "Error: The Arch is not what I think it is")
#else
# error "Cannot determine the Arch"
#endif
Borrowing from Contango's excellent answer above and combining it with "Better Macros, Better Flags" from Fluent C++, you can do:
// Macro for checking bitness (safer macros borrowed from
// https://www.fluentcpp.com/2019/05/28/better-macros-better-flags/)
#define MYPROJ_IS_BITNESS( X ) MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_##X()
// Bitness checks borrowed from https://stackoverflow.com/a/12338526/201787
#if _WIN64 || ( __GNUC__ && __x86_64__ )
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_64() 1
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_32() 0
# define MYPROJ_IF_64_BIT_ELSE( x64, x86 ) (x64)
static_assert( sizeof( void* ) == 8, "Pointer size is unexpected for this bitness" );
#elif _WIN32 || __GNUC__
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_64() 0
# define MYPROJ_IS_BITNESS_PRIVATE_DEFINITION_32() 1
# define MYPROJ_IF_64_BIT_ELSE( x64, x86 ) (x86)
static_assert( sizeof( void* ) == 4, "Pointer size is unexpected for this bitness" );
#else
# error "Unknown bitness!"
#endif
Then you can use it like:
#if MYPROJ_IS_BITNESS( 64 )
DoMy64BitOperation()
#else
DoMy32BitOperation()
#endif
Or using the extra macro I added:
MYPROJ_IF_64_BIT_ELSE( DoMy64BitOperation(), DoMy32BitOperation() );
Here are a few more ways to do what you want in modern C++.
You can create a variable that defines the number of system bits:
static constexpr size_t sysbits = (CHAR_BIT * sizeof(void*));
And then in C++17 you can do something like:
void DoMy64BitOperation() {
std::cout << "64-bit!\n";
}
void DoMy32BitOperation() {
std::cout << "32-bit!\n";
}
inline void DoMySysBitOperation()
{
if constexpr(sysbits == 32)
DoMy32BitOperation();
else if constexpr(sysbits == 64)
DoMy64BitOperation();
/*else - other systems. */
}
Or in C++20:
template<void* = nullptr>
// template<int = 32> // May be clearer, pick whatever you like.
void DoMySysBitOperation()
requires(sysbits == 32)
{
std::cout << "32-bit!\n";
}
template<void* = nullptr>
// template<int = 64>
void DoMySysBitOperation()
requires(sysbits == 64)
{
std::cout << "64-bit!\n";
}
template<void* = nullptr>
void DoMySysBitOperation()
/* requires(sysbits == OtherSystem) */
{
std::cout << "Unknown System!\n";
}
The template<...> is usually not needed, but since those functions will have the same mangling name, we must enforce the compiler to pick the correct ones. Also, template<void* = nullptr> may be confusing ( The other template may be better and more logically correct ), I only used it as a workaround to satisfy the compiler name mangling.
If you can use project configurations in all your environments, that would make defining a 64- and 32-bit symbol easy. So you'd have project configurations like this:
32-bit Debug
32-bit Release
64-bit Debug
64-bit Release
EDIT: These are generic configurations, not targetted configurations. Call them whatever you want.
If you can't do that, I like Jared's idea.
I'd place 32-bit and 64-bit sources in different files and then select appropriate source files using the build system.
I'm adding this answer as a use case and complete example for the runtime-check described in another answer.
This is the approach I've been taking for conveying to the end-user whether the program was compiled as 64-bit or 32-bit (or other, for that matter):
version.h
#ifndef MY_VERSION
#define MY_VERSION
#include <string>
const std::string version = "0.09";
const std::string arch = (std::to_string(sizeof(void*) * 8) + "-bit");
#endif
test.cc
#include <iostream>
#include "version.h"
int main()
{
std::cerr << "My App v" << version << " [" << arch << "]" << std::endl;
}
Compile and Test
g++ -g test.cc
./a.out
My App v0.09 [64-bit]