Django Hidden Foreign Key in form using Meta model - django

Question

I am working on a cookbook website using django and have run into a problem with a foreign key field in my form
the problem is that when i create my recipe i need to have a foreign key pointing to the cookbook that created this recipe but I don't want the user creating the recipe to see the original_cookbook field (they shouldn't have to)
I believe I need to use a widget (HiddenInput) but am I getting confused with the examples given on other sites. Also my friend mentioned something about setting an initial value in the original_cookbook view
tl;dr: I want to point the fk to the users cookbook while keeping the original_cookbook field hidden.
relevant code:
form:
class RecipeForm(forms.ModelForm):
class Meta:
model = Recipe
model:
class Recipe(models.Model):
def __unicode__(self):
return self.name
original_cookbook = models.ForeignKey(Cookbook)
#cookbooks = models.ManyToManyField('Cookbook', related_name = 'recipes')
name = models.CharField(max_length=200)
author = models.CharField(max_length= 100)
picture = models.ImageField(upload_to = 'Downloads', blank=True)
pub_date = models.DateTimeField('date published', auto_now_add=True, blank=True)
ingredients = models.TextField()
steps = models.TextField()
prep_time = models.IntegerField()
TYPE_CHOICES= (
('SW', 'Sandwich'),
('AP', 'Appetizers'),
('SD', 'Sauces and Dressings'),
('SS', 'Soups and Salads'),
('VG', 'Vegetables'),
('RG', 'Rice, Grains and Beans'),
('PA', 'Pasta'),
('BR', 'Breakfast'),
('MT', 'Meat'),
('SF', 'Seafood'),
('BP', 'Bread and Pizza'),
('DT', 'Desserts'),
)
type = models.CharField(max_length = 2, choices=TYPE_CHOICES)
def index_queryset(self):
return self.objects.all()
view:
def createrecipe(request):
if not request.user.is_authenticated():
return HttpResponseRedirect('/index/')
else:
if request.method == 'POST':
form = RecipeForm(request.POST)
if form.is_valid():
recipe = form.save()
user = request.user
cookbooks = user.cookbooks
cookbook = cookbooks.all()[0]
cookbook.recipes.add(recipe)
return HttpResponseRedirect('/account')
else:
form = RecipeForm()
return render_to_response('cookbook/createrecipe.html',
{'form':form},
context_instance=RequestContext(request))

Answer 1

Add exclude = ('original_cookbook',) to your form's Meta class.
Then, in your if form.is_valid() code, do something like:
....
recipe = form.save(commit=False)
recipe.original_cookbook = whatever_that_is
recipe.save()
...

Answer 2

This is answered in the documentation.
from django import forms
class RecipeForm(forms.ModelForm):
class Meta:
model = Recipe
widgets = {'cookbook': forms.HiddenInput