I need the for loop to execute 4 times in the program and then to exit at the fourth time and give the total of the results.
It should not count X as a spoilt vote
The three totals and the number of spoilt votes are initialised to 0.
Now a for loop follows, going from 1 to the number of voting stations.
Inside this loop is a while loop. A prompting message appears on the screen, asking the
voter for which candidate he or she wants to vote. The choice of the voter is then input.
Inside the while loop is a switch statement to increment the correct total. The default
option is used to count the number of spoilt votes.
The while loop is exited when X is entered for the choice.
When the for loop is exited, the three totals and the number of spoilt votes are displayed.
Here is my code
int main()
{
const int NR_VOTING_STATIONS = 4;
int votesForA, votesForB, votesForC, spoiltVotes;
char vote;
// initialise totals
votesForA = 0;
votesForB = 0;
votesForC = 0;
spoiltVotes = 0;
// LOOP of INTEREST START
//loop over the voting stations
for ( int i = 1; i <= NR_VOTING_STATIONS; i++)
{
//loop over voters
while (vote != 'X')
{
cout << "Vote for candidate A, B or C : " << endl;
cin >> vote;
switch(vote)
{
case 'A':
votesForA++;
break;
case 'B':
votesForB++;
break;
case 'C':
votesForC++;
break;
default:
spoiltVotes++;
}
}
}
// LOOP of INTEREST END
//display results
cout << endl << endl;
cout << "Total candidate A : " << votesForA << endl;
cout << "Total candidate B : " << votesForB << endl;
cout << "Total candidate C : " << votesForC << endl;
cout << "Total spoilt votes: " << spoiltVotes << endl;
system("pause");
return 0;
}
Thanks
just add in the switch:
case 'X':
break;
because the while condition will not be executed until the next round.
If the question is
It should not count X as a spoilt vote
The answer would be to add a case:
case 'X':
break;
Also, be careful to initialize vote first, or use do { } while() rather than while { }
If you need the for loop to execute four times why not just surround it in another for loop?
In the while loop you should check whether the Voters in that polling sttion are still available. Since you are neutral at the input 'X', you should add it as one of the cases in the switch.
Your new while loop should look like:
Voters_Still_Present = 1;
while (Voters_Still_Present)
{
cout << "Vote for candidate A, B or C : " << endl;
cin >> vote;
switch(vote)
{
case 'A':
votesForA++;
break;
case 'B':
votesForB++;
break;
case 'C':
votesForC++;
break;
case 'X':
//do nothing
break;
default:
spoiltVotes++;
}
/* Here, find out if voters are still available in the present station.
If yes, Voters_Still_Present = 1; else Voters_Still_Present = 0;
*/
}
Related
I'm self-teaching myself here so I don't have a model answer available.
Working through program flow examples and trying to get a number guesser based on binary searching. I've got it to run and catch edge cases successfully but one objective is to have main() return the number of guesses made. I refactored the main code into a separate function to make it clearer, but I can't get the return code correct, I suspect it's to do with variable scope but can't figure it out.
#include <iostream>
using namespace std;
int guessNumber(int highest, int lowest, int lAttempts)
{
int guess = lowest + ((highest - lowest) * 0.5);
char response = 'a';
lAttempts++;
cout << "My guess is " << guess << ", am I correct?" << endl;
cout << "(y)es/too (h)igh/too (l)ow/(q)uit" << endl;
cin >> response;
while (response != 'y' && response != 'h' && response != 'l' && response != 'q')
{
cout << "I'm sorry, I didn't understand that" << endl;
cout << "(y)es/too (h)igh/too (l)ow/(q)uit" << endl;
cin >> response;
}
switch (response)
{
case 'y':
cout << "I guessed correctly after " << lAttempts << " attempts";
break;
case 'h':
highest = guess;
guessNumber(highest, lowest, lAttempts);
break;
case 'l':
lowest = guess;
guessNumber(highest, lowest, lAttempts);
break;
case 'q':
cout << "Exiting program";
break;
}
return lAttempts;
}
int main()
{
cout << "Think of a number between 1-100" << endl;
int highest = 100;
int lowest = 0;
int attempts = 0;
attempts = attempts + guessNumber(highest, lowest, attempts);
return attempts;
}
cout returns the correct number of attempts but the program (so main()) always exits with 1.
What am I missing here?
Thanks.
You're missing to update your attempt variable within your switch statements.
It should be like this.
lAttempts = guessNumber(highest, lowest, lAttempts);
so for one of my projects I am supposed to give the user multiple games to choose from, which can be played however many times they would like. As soon as they exit, the program should display the total amount of games played.
I have the code for the games done, I'm just working on the menu separately. For some reason when I call for the total at the end, it doesn't output anything. Not even the initial value that I place for the integer.
Any help is much appreciated!
#include <iostream>
using namespace std;
int main() {
int totalGames = 0;
while (true) {
int gameChoice;
cout << "Which game would you like to play?\n\n";
cin >> gameChoice;
switch (gameChoice)
{
case 1 :
cout << "You chose option 1";
totalGames++;
break;
case 2 :
cout << "You chose option 2";
totalGames++;
break;
case 3 :
cout << "You chose option 3";
totalGames++;
break;
case 4 :
return false;
break;
default:
cout << "Invalid Option";
break;
}
}
cout << "Total games: " << totalGames << endl;
return 0;
}
As already suggested in comment and #MichaelVeksler, case 4 exits the program and thus it doesn't output anything.
For instance, you can output it terminating while-loop using a boolean flag as follows:
DEMO
bool doContinue = true; // flag
while (doContinue)
{
int gameChoice;
cout << "Which game would you like to play?\n\n";
cin >> gameChoice;
switch (gameChoice)
{
case 1 :
cout << "You chose option 1";
totalGames++;
break;
case 2 :
cout << "You chose option 2";
totalGames++;
break;
case 3 :
cout << "You chose option 3";
totalGames++;
break;
case 4 :
doContinue = false;
break;
default:
cout << "Invalid Option";
break;
}
}
The issue is with:
case 4 :
return false;
Which exits the program, before reaching the printing statement.
I'm trying to get it back to loop if they enter anything from the choices. everytime I enter 4, it just ends. and if I pick the right one it also ends. Is there anyway I can get it to ask user to input the right one?
void towsoncourse ()
{
cout << "Enter Course: 1 is COSC,2 is ENGL,3 is MATH" << endl;
int course;
bool finish;
bool finishcourse = true;
cin >> course;
while (finishcourse != true)
{
cout << "Enter correct number for course" << endl;
if (course == 1 || course == 2 | course == 3)
{
finish = true;
}
else
{
cout<< "Error: Enter number corresponding to course." << endl;
}
}
switch (course)
{
case 1:
cout << "COSC" << endl;
break;
case 2:
cout << "ENGL" << endl;
break;
case 3:
cout << "MATH" << endl;
break;
default:
cout << "Error: Enter number corresponding to course" << endl;
}
}
int main ()
{
towsoncourse ();
return 0;
}
Not a complete answer, but rather a guide to point the way.
You want to keep reading an input until it is one of 3 possible values. So a good place to read and test the input would be inside a loop, exiting only when the test conditions are met.
while loops test continue criteria before each execution. do loops test continue criteria after each execution. In you case it is necessary to execute at least once.
There were some issues with the code.
1) while (finishcourse != true) condition was wrong. It should be while (finishcourse == true).
2) finish = true; assignment was wrong. It should have been finishcourse = false;
3) cin >> course; should be taken inside the loop. Because if you place it outside, it will lead to infinite loop in case of incorrect entry.
So, Just to ensure readability, I have rewritten the code. I have assumed that it gets back to the loop in case of incorrect entry and in case of correct entry, it terminates.
#include <iostream>
using namespace std;
void towsoncourse ()
{
bool finishcourse = true;
while (finishcourse == true)
{
int course;
cout << "Enter Course: 1 is COSC,2 is ENGL,3 is MATH" << endl;
cin >> course;
switch (course)
{
case 1:
cout << "COSC" << endl;
finishcourse = false;
break;
case 2:
cout << "ENGL" << endl;
finishcourse = false;
break;
case 3:
cout << "MATH" << endl;
finishcourse = false;
break;
default:
cout << "Error: Enter number corresponding to course." << endl;
}
}
}
int main ()
{
towsoncourse ();
return 0;
}
This code is working fine, however this whole time I've tried avoiding using the goto statements that you will see in the switch (dice_total) statement.
Without the goto statements, the program will not loop back to the beginning of while (again=='y' || again=='Y'), and instead it keeps looping itself when it reaches the do-while loop.
However, I believe that it is also important to say, that if dice_total is = to the point_total the first time around then the program will function properly, and loop back to the beginning. For example, when the program starts, the first round will generate the point_total, which we will say its 10. Which is a value that will allow the program to continue to the next round, and if the dice_total also gets the same number, 10, the program will say you win, and the loop will work properly. However, if the program reaches the do while loop, and generates a number that isn't 10, but generates a 10 after a few loops, then the program will not loop to the beginning. So what I want to ask, what is wrong with my switch(dice_total) statement, and how can I fix it, to give the program the same effect without using the goto statements?
#include "stdafx.h"
#include <iostream>
#include <random>
#include <string>
using namespace std;
int main()
{
//Declared Variables***********************************
char again = 'y';
int point1;
int point2;
int point_total;
int round_1=1;
int dice1;
int dice2;
int dice_total;
//*****************************************************
//RANDOM SEED******************************************
random_device rd;
mt19937 mt(rd());
uniform_int_distribution<int>dist(1, 6);
//*****************************************************
start://TEMPORARY
while (again == 'y'||again=='Y')
{
int round_1 = 1;
system("CLS");
cout << "WELCOME TO THE CRAPS GAME" << endl;
cout << "THROWING ROUND:" << round_1 << " DICES.............." << endl;
point1 = dist(mt);
point2 = dist(mt);
point_total = point1 + point2;
cout << "ROUND: " << round_1 << " First dice is: " << point1 << " and second dice is: " << point2 <<" and the total is:"<<point_total<< endl;
switch (point_total)
{
case 7:
case 11:
cout << "YOU WON CONGRATS PRESS Y TO PLAY AGAIN!!" << endl;
cin >> again;
break;
case 2:
case 3:
case 12:
cout << "YOU LOST, PRESS Y TO TRY AGAIN" << endl;
cin >> again;
break;
default:
do
{
++round_1;
cout << "ROUND " << round_1 << endl;
dice1 = dist(mt);
dice2 = dist(mt);
dice_total = dice1 + dice2;
cout << "THROWING ROUND: " << round_1 << " DICES.............." << endl;
cout << "ROUND 1 DICE TOTAL IS: " << point_total << endl;
cout << "ROUND: " << round_1 << " First dice is: " << dice1 << " and second dice is: " << dice2 << " and the total is:" << dice_total << endl;
switch (dice_total)
{
case 11:
cout << "YOU WON CONGRATS PRESS Y TO PLAY AGAIN!!" << endl;
cin >> again;
goto start;
case 2:
case 3:
case 7:
case 12:
cout << "YOU LOST, PRESS Y TO TRY AGAIN" << endl;
cin >> again;
goto start;
default:
if (dice_total == point_total)
{
cout << "YOU WON CONGRATS PRESS Y TO PLAY AGAIN!!<<endl;
cin >> again;
break;
}//if
else
{
cout << "Going to next round" << endl;
}
}//dice_total
}//do
while (dice_total != point_total);
break;
}//switch point
}//again while
}//main
The problem you're facing is usual when you have too many nested loops in the same function, and is an indicator that you need to refactor parts of your code to be in their own functions.
If you do this, then you have more possibilities to control the flow of your code: in each function you have break and return, and as you can return a custom value, you can use it to determine in the surrounding function if you need to break or return again.
Besides, this gives you the opportunity to put self-explanatory names to your functions, which makes your code clearer for people that look at it for the first time (as it's written, it's so dense that I can't understand it unless I stare at it for some minutes).
An example of what I mean in code:
Before
int main() {
start:
while (a) {
b1();
switch(c) {
case 1:
do {
d();
if (cond) goto start;
} while(e);
break;
}
b2();
}
}
After
int main() {
while (a) {
if (!doStuff1())
break;
}
...
}
bool doStuff1() {
b1();
while (a) {
bool res = doStuff2();
if (res) return true;
}
b2();
...
}
bool doStuff2() {
switch(c) {
case 1:
if (doStuff3()) return true;
}
return false;
}
bool doStuff3() {
do {
d();
if (cond) return true;
} while (e);
return false;
}
How about this design?
bool stop=false;
while(!stop && (again == 'y'||again=='Y'))
{
while(again == 'y'||again=='Y')
{
// ...
break; /* breaks inner while*/
// ...
stop=true;
break; /* breaks inner while, and prevents running outer loop*/
}
}
#include <iostream>
using namespace std;
int main()
{
int grade;
int aCount;
int bCount;
int cCount;
int dCount;
int fCount;
cout << "Enter the letter grades." << endl
<< "Enter the EOF character to end input." << endl;
while ((grade = cin.get()) != EOF)
{
switch (grade)
{
case 'A':
case 'a':
aCount++;
break;
case 'B':
case 'b':
bCount++;
break;
case 'C':
case 'c':
cCount++;
break;
case 'D':
case 'd':
dCount++;
break;
case 'F':
case 'f':
fCount++;
break;
case '\n':
case '\t':
case ' ':
break;
default:
cout << "Incorrect letter grade entered." << "Enter a new grade." << endl;
break;
}
}
cout << "\n\nNumber of students who received each letter grade:"
<< "\nA: " << aCount
<< "\nB: " << bCount
<< "\nC: " << cCount << "\nD: " << dCount << "\nF: " << fCount << endl;
system("PAUSE");
return 0;
}
This is an exact code provided by my C++ textbook. While I was practicing these switch statement codes by copying these codes then compile it, my Visual Studio 2010 express keep gives me an error saying that "aCount is being used without assigned..." same applies to fCount. This program should read any letter from A to F from a keyboard then increment whatever letter that was recognized. I think there should be cin>>grade somewhere in the codes but I don't find it. By the way, can "cin.get()" could work as cin>>grade??
When you are declaring your variables try giving them the value of 0 like this:
int grade = 0;
int aCount = 0;
int bCount = 0;
int cCount = 0;
int dCount = 0;
int fCount = 0;
This will ensure that you are in fact assigning a value to the variable before it is being used.
Then try to run it, I bet it works!
It is advisable for you to initialize your variables being using it. Some compiler will not even give you a warning before compilation, but assigns some "garbage values" to your un-initialize variables.
Initializing your variables to 0 is suffice in this scenario (Like what other user mentioned).
int grade=0;
int aCount=0;
int bCount=0;
int cCount=0;
int dCount=0;
int fCount=0;
By the way, can "cin.get()" could work as cin>>grade??
That depends on how you want to use it. cin.get can be used to extract a:
single character
multiple characters and store them as c-string (char array) or
store them into a stream buffer object
from the input stream.
You may realize cin.get can't accept numbers, so if you are accepting input of characters or string, it is fine. But in future, if you want it to accept numbers, just use cin >> number
An example on using cin.get()
char cStr[50];
cin.get(cStr,5); //It will take n-1 characters
cout << cStr;
//Input: abcde
//Output: abcd