Excluding namespaces from XML - xslt

Question

My xsl file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:go="http://www.google.com"
exclude-result-prefixes="go">
<xsl:include href="SomeLibrary.xsl"/>
<xsl:template match="/">
<xsl:call-template name="SomeTemplate">
<xsl:with-param name="Element" select="'randomParam'"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
The SomeLibrary.xsl file:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.google.com">
<xsl:template name="SomeTemplate">
<xsl:param name="Element"/>
<Blabla>
<xsl:value-of select="$Element" />
</Blabla>
</xsl:template>
</xsl:stylesheet>
Input xml: just use an empty XML. The result is this:
<?xml version="1.0" encoding="UTF-8"?>
<Blabla xmlns="http://www.google.com">
randomParam
</Blabla>
What I want is to have the "Blabla" node without a namespace. How can I remove it or make sure it doesn't get there, without modifying my "SomeLibrary.xsl"?

Answer 1

In case you don't want to edit the imported stylesheet code, the way to remove the namespace is with a two-pass transformation (which in XSLT 1.0 requires using an xxx:node-set() extension function):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext" >
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:variable name="vrtfPass1">
<xsl:call-template name="SomeTemplate">
<xsl:with-param name="Element" select="'randomParam'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="vPass1" select="ext:node-set($vrtfPass1)"/>
<xsl:apply-templates select="$vrtfPass1/node()" mode="pass2"/>
</xsl:template>
<xsl:template match="*" mode="pass2">
<xsl:element name="{name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="pass2"/>
</xsl:element>
</xsl:template>
<xsl:template name="SomeTemplate" xmlns="http://www.google.com">
<xsl:param name="Element"/>
<Blabla>
<xsl:value-of select="$Element" />
</Blabla>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on any XML document (not used), the wanted result (the default namespace removed) is produced:
<Blabla>randomParam</Blabla>
Update:
The OP has indicated in a comment that he is using Xalan 2.07.
Below is almost the same solution, but with namespace and name for the xxx:node-set() function, as used in Xalan:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:x="xmlns:xalan="http://xml.apache.org/xalan" exclude-result-prefixes="x" >
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:variable name="vrtfPass1">
<xsl:call-template name="SomeTemplate">
<xsl:with-param name="Element" select="'randomParam'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="vPass1" select="x:nodeset($vrtfPass1)"/>
<xsl:apply-templates select="$vrtfPass1/node()" mode="pass2"/>
</xsl:template>
<xsl:template match="*" mode="pass2">
<xsl:element name="{name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="pass2"/>
</xsl:element>
</xsl:template>
<xsl:template name="SomeTemplate" xmlns="http://www.google.com">
<xsl:param name="Element"/>
<Blabla>
<xsl:value-of select="$Element" />
</Blabla>
</xsl:template>
</xsl:stylesheet>

Answer 2

Explicitly create them with:
<xsl:element name="Blabla" namespace="">...</xsl:element>
but this means fiddling with the SomeLibrary.xsl file.

Answer 3

add exclude-result-prefixes="go" to the stylesheet element.
and, of course, update the namespace declaration from the default one to xmlns:go="http://www.google.com"