How to assign formated value to other variable in xslt - xslt

Question

<xsl:value-of select="substring-before($temp1,';')" disable-output-escaping="yes"/>
where temp1="fassdf sdf; asdf &dfsdfsdf;fsdfsf;"
The above code I am using to split value using ";". The problem is temp1 having &, so it splits this value by the escaped sequence character ;. So i am getting wrong output. But if I use the disable-output-escaping="yes" then the "&" is converted to &.
How to get the formatted value from the string? So if i split the string i will not get any issue. Because I will get string with & instead of &

Answer 1

Lets assume a sample XML for your/our convenience ..
<?xml version="1.0" encoding="utf-8"?>
<root>
<child>sharepoint; R&D;Department;</child>
</root>
XSLT code to output the desired one:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="text" indent="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="node()"/>
</xsl:template>
<xsl:template match="child">
<xsl:call-template name="SplitString">
<xsl:with-param name="StringVal" select="concat(.,';')"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="SplitString">
<xsl:param name="StringVal"/>
<xsl:variable name="first" select="substring-before($StringVal, ';')" />
<xsl:variable name="remaining" select="substring-after($StringVal, ';')" />
<xsl:value-of select="normalize-space($first)" disable-output-escaping="yes" />
<xsl:if test="$remaining">
<xsl:value-of select="'
'"/>
<xsl:call-template name="SplitString">
<xsl:with-param name="StringVal" select="$remaining" />
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
This is the Output you get:
sharepoint
R&D
Department