multiple inheritance and polymorphism - c++

my dizzyCreature class inherits from both a creature class and a dizzy class. It is also part of a polymorphic collection of creature classes. If I know that my object in the creature class is a dizzyCreature, is there a way to call a function from the dizzy class?
I have tried
creature[2].dizzyCreature::someFunction();
and
dizzyCreature::creature[2].someFunction();
and neither works. Any ideas?

If I understand correctly what you have is something like this: list<Creature*>. This list contains some dizzyCreature instances. On those instances you want to call methods of dizzy class. If this is the objective then you can use dynamic_cast to achieve this. Lets say you have Create* pCreature then you can do:
dizzyCreature* pDizzyCreature = dynamic_cast<dizzyCreature*>(pCreature);
if(pDizzyCreature )
{
pDizzyCreature->someDizzyClassMethod();
}

You need to first check if the class is of the correct type, then cast it using dynamic_cast, as has already been suggested. This solution is elegant since the dynamic cast itself does the type-checking - i.e. it will return NULL if you try to make an invalid cast. (There is no need to use typeid)
As a side note, if I were you, I'd attempt to do whatever it is you're trying to do without multiple inheritance if possible. Multiple inheritance can open up a whole can of worms and is best avoided unless there is no other alternative.

Related

C++ inheritance pattern

I am after your opinion on how best to implement an inheritance pattern in C++. I have two base classes, say
class fooBase{
protected:
barBase* b;
};
class barBase{};
where fooBase has a barBase. I intend to put these classes in a library, so that wherever I have a fooBase it can use its barBase member.
I now intend to create a specialisation of these in a specific program
class fooSpec : public fooBase{};
class barSpec : public barBase{};
Now I want fooSpec::b to point to a barSpec instead of a barBase. I know that I can just initialise b with a new barSpec, but this would require me to cast the pointer to a barSpec whenever I wanted to use specific functions in the specialisation wouldn't it?
Is there another way that this is often acheived?
Cheers.
Create a method in your specclass to cast the b into the special version.
That way instead of casting it all the time, it looks like a getter.
On the other hand OO is about programming towards interfaces and not objects. So what you are doing here looks like programming towards objects. But the is difficult to see as this example is purely theoretical.
You may consider the template solution:
template <class T>
class fooBase{
protected:
T* b;
};
and then use it as
class fooSpec : public fooBase<barSpec>{};
while ordinarily, the base would be used as fooBase<barBase>.
Is this what you want?
Normally we create a function that has the cast and returns the pointer -- and use that instead of the member directly.
Now I want fooSpec::b to point to a barSpec instead of a barBase.
There's no such thing as fooSpec::b. b belongs to fooBase, and your new class fooSpec is a (specialization of) a fooBase. You can't change the fact that b, a fooBase member, is of type barBase. This is a property of all the instances of fooBase that you can't invalidate in the particular subset of instances concerned by your specialization.
I know that I can just initialise b with a new barSpec, but this would
require me to cast the pointer to a barSpec whenever I wanted to use
specific functions in the specialisation wouldn't it?
Yes and no. Yes, you need to do that cast; but no, you don't need to do it every time. You can encapsulated in a function of fooSpec.
Is there another way that this is often acheived?
Not that I'm aware of.
this would require me to cast the pointer to a barSpec whenever I wanted to use specific functions in the specialisation wouldn't it?
That depends on whether the method you are trying to invoke is defined in the superclass and whether it is virtual.
You need to cast the pointer before invoking a method if one of the following is true...
The method belongs to the subclass only
The superclass has an implementation of the method and the subclass's implementation does not override the implementation in the superclass. This amounts to a question of whether the function is a virtual function.
Avoid data members in non-leaf classes, use pure virtual getters instead. If you follow this simple rule, your problem solves itself automatically.
This also makes most non-leaf classes automatically abstract, which may seem like an undue burden at first, but you get used to it and eventually realize it's a Good Thing.
Like most rules, this one is not absolute and needs to be broken now and then, but in general it's a good rule to follow. Give it a try.
If it looks too extreme, you may try one of the design patterns that deal with dual hierarchies such as Stairway to Heaven.

Calling a non-virtual function in derived class using a base class pointer

As noted in this answer:
high reliance on dynamic_cast is often an indication your design has gone wrong.
What I'd like to know is how can I call a custom function in a derived class, for which there is no same-name function in the base class, but do so using a base class pointer and perhaps without dynamic_cast if in fact there is a better way.
If this function was a virtual function defined in both, that's easy. But this is a unique function only in the derived class.
Perhaps dynamic_cast is the best way afterall?
In order to call a function of Derived class you have to obtain a pointer to derived class. As an option (depending on situation) you may want using static_cast instead of dynamic, but as you said:
it is often an indication your design has gone wrong
Also, sometimes I think it's ok to use casts. When I was designing a GUI library for a game it has a base class Widget and lots of subclasses. An actual window layout was made in an editor and later some Loader class was inflating this layout. In order to fill widgets from the layout with actual specific for each widget data (game related) I made a method for quering widget's child from a widget. This function retuned Widget* and then I dynamic_casted it to actual type. I have not found a better design for this.
Later I also found that GUI system on Android works the same way
What I'd like to know is how can I call a custom function in a derived class ... without dynamic_cast if in fact there is a better way
As indicated in the quote, it's a design issue, not an implementation issue. There's no "better way" to call that function; the "better way" is to redesign your types so that subtypes don't need to add functionality to their parents. By doing so, your types satisfy (a common interpretation of) the Liskov Substitution Principle, and are easier to use since users don't need to know about the subtypes at all.
If it's impossible or unreasonably difficult to redesign the types in such a way, then perhaps you do need RTTI. The advice doesn't say "All use of ...", just "High reliance on ...", meaning that RTTI should be a last resort, not a default approach.
This is more like an option then a real answer, so don't stone me to death.
class Derived;
class Base
{
public:
virtual Derived * getDerived()const
{
return NULL;
}
};
class Derived : public Base
{
public:
virtual Derived * getDerived()const
{
return this;
}
};
I guess you get the picture...
P.S. Mike Seymour, thanks :-)

Dynamically pass the type name to a static_cast

Is it possible to dynamically choose the type you wish to cast to, during runtime?
For example, suppose I have:
ClassType * pointer=static_cast<ClassType*>(baseClassPointer);
At run time, however, I'd like to choose what the ClassType is, rather than having to hardcode it into the function.
Is this possible? The two ways I'm thinking I'd want to use it is either passing an actual char * that contains the name of the type I want to use, or somehow extracting the type information from an existing class and using that as the cast.
The reason I want to do this, is I have several derived classes from a common base class. I can get the basic functionality of the base class for each of the derived classes, but if I want a pointer to access some of the specific functionality that only exists in the derived class, I need to cast that pointer as such. And I'd like to have a function that allows me to do this casting dynamically for any of the derived classes.
Templates might be able to serve your purpose here for whenever you need it to statically cast upwards.
template <typename TTo> derived_cast ( BaseClass* b ) {
static_assert( std::is_base_of<BaseClass, TTo>::value, "You can't cast to a class that's not derived from BaseClass!" );
return static_cast<TTo*>( b );
}
The syntax becomes a bit more compressed then:
Derived* d = derived_cast<Derived>( b );
The static_assert to makes sure TTo is actually derived and such.
Now, for run-time, you'd have to use dynamic_cast, but that involves other things than what the code you have up there implies.
EDIT: Beyond this point are dragons of a crazy kind.
In C++, dynamically casting and operating on an object (without ever knowing that type at compile-time) is impossible, save for using a robust base class or if/else on some kind of run-time identifier to then provide static type information. In almost all cases, you would be better to just use a virtual method on a base class and then override them in derived classes. Switching on strings and other things is not only slow but painful when you have to keep adding extra cases: do not do it. However, if you are going to ignore my advice, here's some built-in pieces you can work with to get sort of what you want:
typeid - an operator that defines an implementation-defined, but unique-to-the-class, object (type_info) that compares uniquely to that class. You can compare them typeid( Dog) == typeid( Dog ) and get true/false correctly. This will allow you some run-time typing information.
dynamic_cast - a cast that fails on up-casting or to a class of a certain type (abridged definition, for more information see cppreference on dynamic_cast). You can use this to dynamically cast pointers and other such things, with it returning null on failure to cast. It might help you here, but you still need to know the types statically that you're working with (after switching on, say, typeid).
With these two, you could do a better implementation of what you see in the other answer with the string usage. But that's about it. Anything else requires things like boost::variant, a stronger base class, or a different design. A stronger base class sounds like what you could use here, but I can't say with 100% certainty.
Good luck!
Bad design spotted !
What about overriding your derived classes ? You are messing with something really dangerous
If you have for example base class Animal, and you have derived classes Dog and Cat, you can always cast Animal to Dog or Cat (if you know which it is):
void doCustomOperation(Animal *animal, string runtimeDecision) {
if (runtimeDecision == "dog") {
((Dog *)animal).bark();
}
if (runtimeDecision == "cat") {
((Cat *)animal).chaseMouse();
}
}
Even if you could do this at runtime (which I don't think you can), what would you do with the derived class pointer you get back? You wouldn't know at the time you write the code what type of object you'll get back so how would you know what methods you can call?
I think you would be better off either adding virtual methods to your base class to capture the necessary functionality or alternatively you could employ the Visitor Pattern.

Is there any way to avoid declaring virtual methods when storing (children) pointers?

I have run into an annoying problem lately, and I am not satisfied with my own workaround: I have a program that maintains a vector of pointers to a base class, and I am storing there all kind of children object-pointers. Now, each child class has methods of their own, and the main program may or not may call these methods, depending on the type of object (note though that they all heavily use common methods of the base class, so this justify inheritance).
I have found useful to have an "object identifier" to check the class type (and then either call the method or not), which is already not very beautiful, but this is not the main inconvenience. The main inconvenience is that, if I want to actually be able to call a derived class method using the base class pointer (or even just store the pointer in the pointer array), then one need to declare the derived methods as virtual in the base class.
Make sense from the C++ coding point of view.. but this is not practical in my case (from the development point of view), because I am planning to create many different children classes in different files, perhaps made by different people, and I don't want to tweak/maintain the base class each time, to add virtual methods!
How to do this? Essentially, what I am asking (I guess) is how to implement something like Objective-C NSArrays - if you send a message to an object that does not implement the method, well, nothing happens.
regards
Instead of this:
// variant A: declare everything in the base class
void DoStuff_A(Base* b) {
if (b->TypeId() == DERIVED_1)
b->DoDerived1Stuff();
else if if (b->TypeId() == DERIVED_2)
b->DoDerived12Stuff();
}
or this:
// variant B: declare nothing in the base class
void DoStuff_B(Base* b) {
if (b->TypeId() == DERIVED_1)
(dynamic_cast<Derived1*>(b))->DoDerived1Stuff();
else if if (b->TypeId() == DERIVED_2)
(dynamic_cast<Derived2*>(b))->DoDerived12Stuff();
}
do this:
// variant C: declare the right thing in the base class
b->DoStuff();
Note there's a single virtual function in the base per stuff that has to be done.
If you find yourself in a situation where you are more comfortable with variants A or B then with variant C, stop and rethink your design. You are coupling components too tightly and in the end it will backfire.
I am planning to create many different children classes in different
files, perhaps made by different people, and I don't want to
tweak/maintain the base class each time, to add virtual methods!
You are OK with tweaking DoStuff each time a derived class is added, but tweaking Base is a no-no. May I ask why?
If your design does not fit in either A, B or C pattern, show what you have, for clairvoyance is a rare feat these days.
You can do what you describe in C++, but not using functions. It is, by the way, kind of horrible but I suppose there might be cases in which it's a legitimate approach.
First way of doing this:
Define a function with a signature something like boost::variant parseMessage(std::string, std::vector<boost::variant>); and perhaps a string of convenience functions with common signatures on the base class and include a message lookup table on the base class which takes functors. In each class constructor add its messages to the message table and the parseMessage function then parcels off each message to the right function on the class.
It's ugly and slow but it should work.
Second way of doing this:
Define the virtual functions further down the hierarchy so if you want to add int foo(bar*); you first add a class that defines it as virtual and then ensure every class that wants to define int foo(bar*); inherit from it. You can then use dynamic_cast to ensure that the pointer you are looking at inherits from this class before trying to call int foo(bar*);. Possible these interface adding classes could be pure virtual so they can be mixed in to various points using multiple inheritance, but that may have its own problems.
This is less flexible than the first way and requires the classes that implement a function to be linked to each other. Oh, and it's still ugly.
But mostly I suggest you try and write C++ code like C++ code not Objective-C code.
This can be solved by adding some sort of introspection capabilities and meta object system. This talk Metadata and reflection in C++ — Jeff Tucker demonstrates how to do this using c++'s template meta programming.
If you don't want to go to the trouble of implementing one yourself, then it would be easier to use an existing one such as Qt's meta object system. Note that this solution does not work with multiple inheritance due to limitations in the meta object compiler: QObject Multiple Inheritance.
With that installed, you can query for the presence of methods and call them. This is quite tedious to do by hand, so the easiest way to call such a methods is using the signal and slot mechanism.
There is also GObject which is quite simmilar and there are others.
If you are planning to create many different children classes in different files, perhaps made by different people, and also I would guess you don't want to change your main code for every child class. Then I think what you need to do in your base class is to define several (not to many) virtual functions (with empty implementation) BUT those functions should be used to mark a time in the logic where they are called like "AfterInseart" or "BeforeSorting", Etc.
Usually there are not to many places in the logic you wish a derived classes to perform there own logic.

Is there a way to determine at runtime if an object can do a method in C++?

In Perl, there is a UNIVERSAL::can method you can call on any class or object to determine if it's able to do something:
sub FooBar::foo {}
print "Yup!\n" if FooBar->can('foo'); #prints "Yup!"
Say I have a base class pointer in C++ that can be any of a number of different derived classes, is there an easy way to accomplish something similar to this? I don't want to have to touch anything in the other derived classes, I can only change the area in the base class that calls the function, and the one derived class that supports it.
EDIT: Wait, this is obvious now (nevermind the question), I could just implement it in the base that returns a number representing UNIMPLEMENTED, then check that the return is not this when you call it. I'm not sure why I was thinking of things in such a complicated manner.
I was also thinking I would derive my class from another one that implemented foo then see if a dynamic cast to this class worked or not.
If you have a pointer or reference to a base class, you can use dynamic_cast to see which derived class it is (and therefore which derived class's methods it supports).
If you can add methods to the base class, you can add a virtual bool can_foo() {return false;} and override it in the subclass that has foo to return true.
C++ does not have built in run-time reflection. You are perfectly free to build your own reflection implementation into your class hierarchy. This usually involves a static map that gets populated with a list of names and functions. You have to manually register each function you want available, and have consistency as to the calling convention and function signature.
I believe the most-correct way would be to use the typeid<> operator and get a reference to the type_info object, and then you could compare that (== operator) to the desired type_info for the data types you wish to care about.
This doesn't give you method-level inspection, and does require that you've built with RTTI enabled (I believe that using typeid<> on an object that was built without RTTI results with "undefined" behavior), but there you are.
MSDN has an online reference to get you started : http://msdn.microsoft.com/en-us/library/b2ay8610%28VS.80%29.aspx