Solution for printing information to the screen in c++? - c++

Question

I have to make a loop to gather all the information from the users input of the employees. As you can see, I have gotten the parts where I ask the user how many employees and what their information is. Now all I have to is print that information to the screen like this, just without the periods between each and with a few spaces between each :
Weekly Payroll:
Name...............Title........Gross.......Tax.........Net
----------------------------------------
Ebenezer Scrooge.....................Partner...250.00......62.25.....187.75
Bob Cratchit...............................Clerk.......15.00........2.00.......13.00
And this is what I have :
#include <iostream>
using namespace std;
const int MAXSIZE = 20;
struct EmployeeT
{
char name[MAXSIZE];
char title;
double SSNum;
double Salary;
double Withholding_Exemptions;
};
EmployeeT employees[MAXSIZE];
int main()
{
cout << "How many Employees? ";
int numberOfEmployees;
cin >> numberOfEmployees;
while(numberOfEmployees > MAXSIZE)
{
cout << "Error: Maximum number of employees is 20\n" ;
cout << "How many Employees? ";
cin >> numberOfEmployees;
}
char name[MAXSIZE];
int title;
double SSNum;
double Salary;
double Withholding_Exemptions;
for (int count=0; count < numberOfEmployees; count++)
{
cout << "Name: ";
cin >> employees[ count ].name;
cout << "Title: ";
cin >> employees[ count ].title;
cout << "SSNum: \n";
cin >> employees[ count ].SSNum;
cout << "Salary: \n";
cin >> employees[ count ].Salary;
cout << "Withholding Exemptions: \n";
cin >> employees[ count ].Withholding_Exemptions;
}
double gross;
double tax;
double net;
double adjusted_income;
gross = employees[ count ].Salary;
adjusted_income = employees[ count ].Salary - 1.00;
tax = adjusted_income * .25;
net = gross - tax;
cout << "Weekly Payroll:\t Name \t Title \t Gross \t Tax \t Net \n";
for (int count=0; count < numberOfEmployees; count++)
{
cout << employees[count].name << " \t" << employees[count].title << " \t" <<
gross << "\t" << tax << "\t" << net << "\n";
}
system("pause");
}
Ok I updated the program. Now I'm trying to do the calculations. This what I'm doing...
To calculate payroll:
Gross pay is the weekly salary which was previously entered for the employee.
Net pay is calculated as the gross pay minus the amount of tax.
To calculate tax: Deduct $1 from the salary for each withholding exemption. This is the adjusted income. If the adjusted income is less than 0, then use 0 as the adjusted income.
Multiply the adjusted income by the tax rate, which you should assume is a flat 25%.
As an example, if Bob Cratchit has a weekly income of $15 and 7 dependents, then his adjusted income would be $8. His tax would be 25% of $8 which is $2, and therefore his net pay is $13.
I have started trying to get this. I put it between the second loop and the last loop. Is this right?

Answer 1

A small example for printing columns using C++ streams:
#include <iomanip>
#include <ios>
std::ostream& operator<<(std::ostream& a_out, const EmployeeT& a_e)
{
a_out << std::setfill(' ')
<< std::left
<< std::setw(sizeof(a_e.name))
<< a_e.name
<< std::setw(0)
<< a_e.title
<< " "
<< std::setw(10)
<< a_e.SSNum
<< a_e.Salary
<< a_e.Withholding_Exemptions;
return a_out;
}
This would allow you to write an employee to standard output using:
std::cout << employees[n] << "\n";
Use a similar approach for the column headings.
Other points:
Prefer std::string to char[] (or char*) then you don't have to limit the length of the string (or explicitly manage the memory)
Use std::vector instead of a fixed array to avoid a limit
Make use of STL algorithms (std::for_each, std::copy for example) for performing operations on elements in containers (or array)

Answer 2

you can use the same loop for insertion and displaying or anything!! because it traverses through the whole loop.
cout << "Weekly Payroll:\t Name \t Title \t Gross \t Tax \t Net \n";
for (int count=0; count < numberOfEmployees; count++)
{
cout << employees[count].name << " \t" << employees[count].title << " \t" <<
Gross << "\t" << tax << "\t" << Net << "\n";
}
Find net,tax and gross of each structure object and print.
Check if you want name as int at the marked position.
#include <iostream>
using namespace std;
const int MAXSIZE = 20;
struct EmployeeT {
char name[MAXSIZE];
char title;
double SSNum;
double Salary;
double Withholding_Exemptions;
};
EmployeeT employees[MAXSIZE];
int main() {
cout << "How many Employees? ";
int numberOfEmployees;
cin >> numberOfEmployees;
while(numberOfEmployees > MAXSIZE) {
cout << "Error: Maximum number of employees is 20\n" <<
"How many Employees? ";
cin >> numberOfEmployees;
}
int name; // name is char[] or string
int title;
double SSNum;
double Salary;
double Withholding_Exemptions;
for (int count = 0; count < numberOfEmployees; count++) {
cout << "Name: \n";
cin >> employees[ count ].name;
cout << "Title: \n";
cin >> employees[ count ].title;
cout << "SSNum: \n";
cin >> employees[ count ].SSNum;
cout << "Salary: \n";
cin >> employees[ count ].Salary;
cout << "Withholding Exemptions: ";
cin >> employees[ count ].Withholding_Exemptions;
}
}

Answer 3

You can use the '\t' sequence, which represent in C++ a "Tab space" (like when you press Tab on your Keyboard).
As for the loop, it should be something like:
cout << "Weekly Payroll:\t Name \t Title \t Gross \t Tax \t Net \n";
for(int n=0; n < employees; n++)
{
cout << employees[n].name << " \t" << employees[n].title << " \t" ...... << "\n";
}
It should work :)

Answer 4

You could look into the STL iomanip header functions, like setw()
Formatting Cout Output in C++ using iomanip
. With that it should be possible to get decent fix sized columns, which tabs likely wont.

Answer 5

Your code has seems OK, although it is more complicated than it should be, and the input-loop has no error-handling (if a user enters something invalid, your program will stop working).
Here are some general pointers that can help you make your program better:
Use std::vector<EmployeeT> instead of an array - this way you don't have to limit the number of employees you can handle, because the vector can grow dynamically.
Provide an operator<<-overload for EmployeeT.
Look into Iostream-manipulators, particularly std::setw; This question is similar to your problem, and one solution uses manipulators to format the output.