I'd like to iterate through the INSTALLED_APPS in my Django settings file like so:
#task
def test_app
print settings.INSTALLED_APPS
How do I access my settings file in a fabfile?
Thanks.
It's documented: http://docs.fabfile.org/en/latest/api/contrib/django.html
from fabric.contrib import django
django.settings_module('myproject.settings')
from django.conf import settings
Related
My settings are structured like:
/settings/__init__.py
/settings/base.py
/settings/dev.py
/settings/prod.py
The constant RANDOM_VAR is set in dev.py
When I do the following in e.g. urls.py
from django.conf import settings
print(settings.RANDOM_VAR)
I get
AttributeError: 'Settings' object has no attribute 'RANDOM_VAR'
After further testing I see that all my database settings etc. are loaded from dev.py. But when I want to access my dev.py settings through from django.conf import settings it doesn't work.
I don't want to use from <your_path>.settings import dev, because this would not work on production.
Any ideas?
Your settings structure should be like this,
/settings/__init__.py
/settings/base.py
/settings/dev.py
/settings/prod.py
the you can try something like this
from <your_path>.settings import dev
print(dev.RANDOM_VAR)
Hope this helps you
In my project, I have a main static folder and a sub folder named static. When I make changes in my sub folder named static (which I specified in COLLECTSTATIC_DIRS within the settings file), I save the file and run the collectstatic command.
This successfully saves the changes, however is really inefficient as I am constantly changing css and Javascript files inside my project, which I store as static files.
I browsed the web, and came across a solution named whitenoise, which is a pip package. But this package only works for a short period of time, and after a few times of closing and opening my project folder, it completely stopped working.
Does anybody have another solution to deal with this problem? Thank you.
You can use python-watchdog and write your own Django command:
import time
from django.conf import settings
from django.core.management import call_command
from django.core.management.base import BaseCommand
from watchdog.events import FileSystemEventHandler
from watchdog.observers import Observer
class Command(BaseCommand):
help = "Automatically calls collectstatic when the staticfiles get modified."
def handle(self, *args, **options):
event_handler = CollectstaticEventHandler()
observer = Observer()
for path in settings.STATICFILES_DIRS:
observer.schedule(event_handler, path, recursive=True)
observer.start()
try:
while True:
time.sleep(1)
finally:
observer.stop()
observer.join()
class CollectstaticEventHandler(FileSystemEventHandler):
def on_moved(self, event):
super().on_moved(event)
self._collectstatic()
def on_created(self, event):
super().on_created(event)
self._collectstatic()
def on_deleted(self, event):
super().on_deleted(event)
self._collectstatic()
def on_modified(self, event):
super().on_modified(event)
self._collectstatic()
def _collectstatic(self):
call_command("collectstatic", interactive=False)
You can use 3rd party solution which doesn't belong to Django to monitor your files and run commands on the files changes.
Take a look at fswatch utility Bash Script - fswatch trigger bash function
How to manage static files "Django-way"
Please check details on https://docs.djangoproject.com/en/3.0/howto/static-files/ what is a Django-way to do it correct :)
First of all set DEBUG = True while working on development.
Then add these lines to your project's urls.py:
from django.conf import settings
from django.views.decorators.cache import cache_control
from django.contrib.staticfiles.views import serve
from django.conf.urls.static import static
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL,
view=cache_control(no_cache=True, must_revalidate=True)(serve))
Here's an example using Python watchfiles and a Django management command.
# Lives in /my_app/manangement/commands/watch_files.py
import time
from django.conf import settings
from django.core.management import call_command
from django.core.management.base import BaseCommand
from watchfiles import watch
class Command(BaseCommand):
help = "Automatically calls collectstatic when the staticfiles get modified."
def handle(self, *args, **options):
print('WATCH_STATIC: Static file watchdog started.')
#for changes in watch([str(x) for x in settings.STATICFILES_DIRS]):
for changes in watch(*settings.STATICFILES_DIRS):
print(f'WATCH_STATIC: {changes}', end='')
call_command("collectstatic", interactive=False)
You can then run the Django management command in the background in whatever script you use to start Django.
python manage.py watch_static &
python manage.py runserver 0.0.0.0:8000
Currently using a REST API and the generic views CreateUpdateDestroy, and my admin display GUI looks like this :
All the sources online that I've followed, tutorials etc get a generic view which looks much nicer.
Here is my views.py:
from rest_framework import generics
from models import Results
from serializers import ResulutsSerializer
class ResultsList(generics.ListAPIView):
queryset = Results.objects.all()
serializer_class = ResultsSerializer
class ResultsDetail(generics.RetrieveUpdateDestroyAPIView):
queryset = Results.objects.all()
serializer_class = ResultsSerializer
and urls.py:
from django.urls import path
from main import views
urlpatterns = [
path('results/', views.ResultsList.as_view()),
path('<int:pk>/', views.ResultsDetails.as_view())
]
what am I doing wrong?
It looks like you need to collect your app assets:
$ python manage.py collectstatic
# You can provide option: --settings=<your-settings-file> if you're using custom settings which is not default in manage.py
You will need to configure staticfiles settings in your Django settings module if not already configured – e.g. settings.py. Please follow documentation at:
https://docs.djangoproject.com/en/2.0/howto/static-files/
https://docs.djangoproject.com/en/2.0/ref/contrib/staticfiles/
If you are developing locally:
You should set DEBUG=True in your Django Settings Module (i.e. normally settings.py)
i am trying to import the client in django for testing. but when i do, i get this wierd error:
ImproperlyConfigured: Requested setting DATABASES, but settings are not configured. You must either define the environment variable DJANGO_SETTINGS_MODULE or call settings.configure() before accessing settings.
from django.utils import unittest
from django.utils import simplejson as json
from django.test.client import Client
this is how i imported the client so that i could use it for testing. can someone explain this to me please.
Try this:
import os
import sys
sys.path.append('/home/username/www/site_folder')
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
from django.utils import unittest
from django.utils import simplejson as json
from django.test.client import Client
But replace project with folder name, where your settings.py is
The Client is looking for the settings.py. You could simply load the client by typing this in your project folder:
python manage.py shell
In Pycharm which I use, after following this Running Django tests in PyCharm
my problem was solved.
It's in the file > settings > Django Support, and then select the right settings.
I had a small proof of concept set up on a development server on a local machine. I'm now trying to move it over to django on a production server, which I'm using webfaction for. However, now that I'm switched over to apache from the built in django server I get the following:
ViewDoesNotExist: Could not import orgDisplay.views. Error was: No module named orgDisplay.views
But when check my orgDisplay apps folder there is a view.py in it. What am I doing wrong? I've tried adding the following to my settings.py by suggestion of the django IRC room.
import sys
sys.path.append(r"/home/user/webapps/django_project/myproject/orgDisplay")
which is the path to my app.
any ideas on how to even begin to trouble shoot this?
Thanks in advance.
I assume you're using mod_wsgi (which is recommended by Django authors), not mod_python. This is the way you should use your sys.path:
django.wsgi:
import os, sys
sys.path.append(r"/home/user/webapps/django_project/myproject/")
os.environ["DJANGO_SETTINGS_MODULE"] = "settings"
sys.stdout = sys.stderr # Prevent crashes upon print
import django.core.handlers.wsgi
application = django.core.handlers.wsgi.WSGIHandler()
urls.py:
from django.conf.urls.defaults import *
urlpatterns = (
("", include("orgDisplay.urls")),
# ...
)
orgDisplay/urls.py:
import views
urlpatterns = (
(r'^some_view/$', views.some_view), # It is actually orgDisplay.views.some_view
# many more records ...
)
It is a bad idea to add project dir itself to path since you're be getting name conflicts between multiple projects.
I think you're appending the wrong directory to sys.path. I think Python is looking in the .../myproject/orgDisplay folder for the orgDisplay package. Try removing the orgDisplay from your string, like this:
import sys
sys.path.append(r"/home/user/webapps/django_project/myproject")
The other option would be to simply add myproject (or whatever your project is actually called) in the import statement.
# instead of "from orgDisplay import views"
from myproject.orgDisplay import views
Also, make sure to restart Apache after every edit.
looking at manage.py, it does it like so:
import sys
from os.path import abspath, dirname, join
from django.core.management import setup_environ
# setup the environment before we start accessing things in the settings.
setup_environ(settings_mod)
sys.path.insert(0, join(PINAX_ROOT, "apps"))
sys.path.insert(0, join(PROJECT_ROOT, "apps"))
Provided your WSGI file is in your project directory, a slightly more flexible way is this:
import os, sys
sys.path.append(os.path.dirname(__file__))
This will enable you to change your project location later without having to modify your WSGI file.