I have the below regex, but how can I remove the querystring entirely if it is present:
^~/(.*)/restaurant/(.*)
eg. the url
/seattle/restaurant/sushi?page=2
or
/seattle/restaurant/sushi?somethingelse=something
or
/seatthe/restaurant/sushi
should just return seattle and restaurant and sushi and remove any querystring if it is present.
(sorry for reposting a similar question, but I couldn't get the answer to work in my previous question).
thanks
Thomas
This regex:
(/[^?]+).*
Should match the initial section of your URL and put it in a group.
So it will match /seattle/restaurant/sushi and put the value in a group.
You can use something like this: (/.*?/restaurant[^?]+).* if you want to handle just URLs with the word restaurant as the second word between the slashes.
Edit: Something like so should yield 3 groups: /(.*?)/(restaurant)/([^?]+).*. Group 1 being seatthe, group 2 being restaurant and group 3 being sushi. If after the last / there is a ?, the regex discards the ? and everything which follows.
You should change your final /./ to match "anything but a question mark" like this
^~/(.*)/restaurant/([^?]*)
Related
I am trying to write the following regexes for google analytics usage and so far I was unable to.
Case 1. to match with all the URLs containing /cms/en/product/{variable slug}/ which only contains one slug after the /product/. I mean something like the following:
/cms/en/product/firstslug/
Case 2. to match with all the URLs containing /cms/en/product/{variable slug1}/{variable slug2}/ which only contains two slugs after the /product/. I mean something like the following:
/cms/en/product/firstslug/secondslug/
Really appreciate anyone's help in advance.
I have already tried basics like the following and it doesn't work:
`/cms/en/product/.*/$
^/cms/en/product/.*/$
^/cms/en/product/.*/$
/cms/en/product/([^/]+)/?$
^/cms/en/product/([^/]+)/?$`
^/cms/en/product/[^/]+/$ matches "/cms/en/product/firstslug/"
^/cms/en/product/[^/]+/[^/]+/$ matches "/cms/en/product/firstslug/secondslug/"
^/cms/en/product/[^/]+/([^/]+/)?$ matches both "/cms/en/product/firstslug/" and "/cms/en/product/firstslug/secondslug/"
where
[^/]+ matches a single slug, i.e. one or more character(s) (+) which are not "/" ([^/])
([^/]+/)? matches an optional slug, i.e. an optional (?) group (()) of one or more character(s) (+) which are not "/" ([^/]) followed by a single "/"
Anyway: I would suggest using Content Grouping on collection.
This is probably straightforward but I'm not even sure which phrase I should google to find the answer. Forgive my noobiness.
I've got strings (filenames) that look like this:
site12345678_date20160912_23001_to_23100_of_25871.txt
What this naming convention means is "Records 23001 through 23100 out of 25871 for site 12345678 for September 12th 2016 (20160912)"
What I want to do is extract the date part (those digits between _date and the following _)
The Regex: .*(_date[0-9]{8}).* will return the string _date20160912. But what I'm actually looking for is just 20160912. Obviously, [0-8]{8} doesn't give me what I want in this case because that could be confused with the site, or potentially record counts
How can I responsibly accomplish this sort of 'substringing' with a single regular expression?
You just need to shift you parentheses so as to change the capture group from including '_date' in it. Then you would want to look for your capture group #1:
If done in python, for example, it would look something like:
import re
regex = '.*_date([0-9]{8}).*'
str = 'site12345678_date20160912_23001_to_23100_of_25871.txt'
m = re.match(regex, str)
print m.group(0) # the whole string
print m.group(1) # the string you are looking for '20160912'
See it in action here: https://eval.in/641446
The Regex: .*(_date[0-9]{8}).* will return the string _date20160912.
That means you are using the regex in a method that requires a full string match, and you can access Group 1 value. The only thing you need to change in the regex is the capturing group placement:
.*_date([0-9]{8}).*
^^^^^^^^^^
See the regex demo.
I have been asked to make 2 regex to determine by the URL if a page is a product page or a category page.
These are the URLs:
Product page: www.domain.com/art/something/someotherthing/article(X123456.123)/
Category page: www.domain.com/art/something/someotherthing
I created this regex which works fine for the product page:
^.*\/art.*\/[xX]?[0-9]{6,7}\.[0-9]+\/$
Now I have problems with the category page. The only thing I see that is possible is to make sure it does not end with the pattern that check the ending numbers "[xX]?[0-9]{6,7}.[0-9]+". But I also need to make sure that it starts with /art/ after the domain.
My first try was this for the category page:
.*\/art.*\/(?!([xX]?[0-9]{6,7}\.[0-9]+\(\/)?))$
This doesn't work since negative lookup is positive since it does not find the pattern after the 2nd any characters matching (.*).
Looks like a differencing factor is the number of slashes, possibly excluded by an optional end-slash that is often ignored.
^[^\/]*(\/[^\/]*){3}\/?$ would match the category, and
^[^\/]*(\/[^\/]*){4}\/?$ would match the product.
I think you don't have to use any lookarounds here.
Since the domain is permanent and the art is permanent and the last part of the product like article+something is permanent you can use them explicitly in the regex making it faster.
For product:
^www\.domain\.com\/art\/[^\/]+\/[^\/]+\/article\([^\/]+\)\/$
For category:
^www\.domain\.com\/art\/[^\/]+\/[^\/]+\/$
From the question description and the URL data given...
Product URLs
matched by ^([^\/\r\n]+?)\/(art)\/(.*)\/.*?\(([xX]?[0-9]{6,7}\.[0-9]+)\).*?\/?$
1st capture == domain
2nd capture == art (main category?)
3rd capture == category
4th capture == Product ID
Category URLs
matched by ^([^\/\r\n]+?)\/(art)\/((?!.*[xX]?[0-9]{6,7}\.[0-9]+).*?)\/?$
1st capture == domain
2nd capture == art (main category?)
3rd capture == category
I did infer that the trailing / was optional for both URLs, but that may be an incorrect assumption.
The above regex's link to live regex101 fiddlers with the given regex plus test data.
Do note that the \r\n inclusion within the character class for the domain match is only needed because the regex101 fiddler match is done globally on combined test data. You can remove that character sequence if you are only matching against a single URL at a time.
I moved to a new website and it mangled up my URL's. Now blog posts are accessible from multiple URL's and would like to redirect one pattern to the other.
I am trying to redirect the first case to the second case:
~/blogs/johndoe/john-doe/2014/03/14/test-article1 =>
~/blogs/john-doe/2014/03/14/test-article1
~/blogs/jimjones/jim-jones/2014/03/14/test-articleb =>
~/blogs/jim-jones/2014/03/14/test-articleb
How do I create a pattern smart enough to slice out the first "johndoe" and "jimjones"? I am using this for IIS rewrite but I think any RegEx should work. Thanks for any help.
This works:
^~/blogs/\w+/(\w+)-(\w+)/(\d{4})/(\d\d)/(\d\d)/([\w-]+)$
Debuggex Demo
It just discards the non-dash name. It doesn't know if its equal to the dash name or not. And it also assumes that the date numbers are valid. 9899/45/33 would be matched.
Capture groups:
First name
Last name
Year
Month
Day
Article name
I don't know about IIS rewrites, but this should work:
/^~/blogs\/[a-z]+\/ -> ~/blogs/
The regular expression will match the start of a string, following by ~/blogs/, followed by a string of all lowercase characters.
I don't use IIS, but this should be at least close.
Pattern:
^blogs/\w+/(\w+/)
Action
blogs/{R:1}
Handy usage doc
I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+