Wrap two nodes with values greater than 0 with a div - xslt

Question

I need to convert the following xml with xslt
<item>0</item>
<item>1</item>
<item>2</item>
<item>3</item>
<item>0</item>
<item>6</item>
into the following html
<div>
<i>1</i>
<i>2</i>
</div>
<div>
<i>3</i>
<i>6</i>
</div>
In other words to remove nodes with 0 value and to wrap every 2 nodes with one div

Answer 1

I would do it like this:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="value" select="0"/>
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates select="item[not(. = $value)][position() mod 2 = 1]" mode="group"/>
</xsl:copy>
</xsl:template>
<xsl:template match="item" mode="group">
<div>
<xsl:apply-templates select=". | following-sibling::item[not(. = $value)][1]"/>
</div>
</xsl:template>
</xsl:stylesheet>
then with the input being
<root>
<item>0</item>
<item>1</item>
<item>2</item>
<item>3</item>
<item>0</item>
<item>6</item>
</root>
you get the result
<root>
<div>
<item>1</item>
<item>2</item>
</div>
<div>
<item>3</item>
<item>6</item>
</div>
</root>
If you also want to transform item to i elements simply add the template
<xsl:template match="item">
<i>
<xsl:apply-templates/>
</i>
</xsl:template>
in the stylesheet.