I would like to add line feed after semi-comas in my text.
Something like replace(";",";\n\r")
But i need to exclude the semi-comas inside double quotes, how can i do this with regex?
In case of quotes i want this replacement:
var="Hello;World";
var="Hello;World";\r\n
and not this:
var="Hello;World";
var="Hello;\r\nWorld";\r\n
Thnak you!
You could do something like:
s/;(?=[^"\n]*(?:"[^"\n]*"[^"\n]*)*$)/;\n/gm; # perl synax
If there are no escaped quotes in the strings, and the strings do not span multiple lines.
That is replace:
;(?=[^"\n]*(?:"[^"\n]*"[^"\n]*)*(?m:$))
with
;\n
Related
Suppose I have these strings:
'akshay ' ,
' ankur'
I want to remove trailing and leading spaces present under quotation mark like this:
'akshay',
'ankur'
How can I achieve this in Notepad++ using RegEX?
Use this to find: '(\s*)(.*?)(\s*)' and this to replace: '\2'.
Find this regexp: (^')\s+(\w+)\s*(')|(^')\s*(\w+)\s+(')
Replace with : \1\2\3\4\5\6
Like this:
All the RegExp given above solve my problem in a better way. I appreciate to all who helped me to solve this problem. Thank you everyone.
Here i am going to add a RegExp given below which can be used to count total number of spaces inside single quotation. It can be used to remove all spaces also.
Find--> \s(?!(?:[^']*'[^']*')*[^']*$) and ReplaceWith-->Nothing to do(leave blank) then click 'ReplaceAll'.
I have a little problem with VS2010.
So I want to find a certain strings between quotes with a Regexpression but only if the line doesn't contain a single "tr" or "QObject::tr" example:
I want to display all this lines:
Hallotr("asa");
("hhajkshjkas");
( _"hhajkshjkas" );
But don't want to display this lines:
tr("hhajkshjkas");
QObject::tr("hhajkshjkas");
My Regexp looks like this:
[^t-r]"[a-zA-Z0-9<>=\\"" ]* and ^[^tr]*"[a-zA-Z0-9<>=\\"" ]*"
but it shows all lines even if there is a single tr on the beginning of the string. Or it shows only lines which don't contain tr.
Thanks for help guys.
So I got the solution this is my regexp. :
^~((.*QObject.+tr)|(:b*tr:b*\()).*:q
I have a comma separated CSV file with 3 quoted columns like this:
"this","is good","data"
Some rows have extra quotes in the second column:
"this","is "bad","data"
"this","is "really" bad","data"
This site (http://editplus.info/wiki/Search_and_Replace_Tricks#Delete_everything_inside_a_tag_pair_.28keeping_tags.29) has a RegEx string to select the text between tags ("," in this case), but I only want to replace any quote characters between the tags, not the whole string. Ideally I would only select those lines which have the offending quotes.
RegEx that selects whole second column:
(",").+(",")
RegEx that only selects the bad quotes or rows with them:
???
Any help is much appreciated. Thanks!
Ideally I would only select those lines which have the offending quotes.
^.*(?:,|^)"[^,"\n]*"[^,\n"]*".*$
DEMO
To replace the mismatched quotes with empty string, use the below regex.
([^,\n])"([^,\n])
Then replace the matched characters with \1\2
DEMO
Try this: It is tested in notepad++ for your all cases:
search by ([^,\n\r\t])"+([^,\n\r\t]) and replace with $1$2 (idea from #Avinash Raj)
Demo
Update for next requirement which is include comment
search by (^"|","|"$)|" and replace with $1
Update demo
Running a match using: /([\w ])"(?![,\n])/g
And substituting with: $1'
Replaces all offending double quotes with single quotes, producing:
"this","is 'bad","data"
"this","is 'really' bad","data"
Demo here: https://regex101.com/r/dL7jZ6/12 (Credit to Avinash Raj for finding the demo website)
Assuming the format is exactly how always how posted, I'd do something like:
[ ]".*?"
all! Have CSV files coming in with with text inside double quotes that contain one or more commas and I am wondering if there is a regex form for Notepad++ that would remove any number of commas inside a CSV file.
For example I need to go from the this:
text,text1,"interesting, text,"
To this:
text,text1,"interesting text"
There can be 1,2 or more commas inside the quotes.
Anyone know a of a way to make this happen using regex form in Notepad++?
Thanks in advance!
use this pattern
,(?!(([^"]*"){2})*[^"]*$)
and replace with nothing
it is looking for a comma , that does not see an optional even number of double quotes " to the end of the string
I am fairly new to regular expression therefore this may be the simplest question you've seen on StackOverflow :-)
I have a large JSON file with text like this:
{..., "text": "BLAH BLAH", ...}
The text may contain any of the special characters and also characters like \", which I understand can be seen as escape character in regular expression. I am trying to find and replace a single character colon : with tilde ~ within the portion followed by "text" preferably in Notepad++. Any help will be greatly appreciated.
This regex will find all the : in the value for fields named text and replace the character with a ~. Note there were issues using regular expressions with Notepad++ v5. My demo here was tested in Notepad++ v6.3.3
Regex: ("text":\s"[^"]*?):
Replace with: $1~
Input string: {"not text": "12:34", "text": "BLAH:BLAH", "Never get a": ":oskupee"}
Here is what I did (thanks for all the help #Mike, but I had to make many edits. That's why I am answering my own question so other users can get the complete answer)
Search for \"text\": \".*? : .*?\", in Notepad++
Find and replace with \1~\2 to replace all : with ~
Manually correct the mistakes
You can do this:
find: ("(?:[^"]+|(?<=\\)")*")\s*:
replace: $1~
The idea is to capture the content inside double quotes, to put it in the replacement.
I use a lookbehind to allow escaped double quotes inside double quotes.