Replace part of text in a file using batch - replace

Question

The file 'MyFile.txt' has a line in it and a part of that line I need replaced.
Example:
The line in the file is like this
53544THOIN91111160000000
I want to replace '111116' from the existing line in 'MyFile.txt', the thing here is '111116' is a variable and would keep changing. Its basically a Date with the format YYMMDD, i want to read the modified date from another file and replace these numbers in 'MyFile.txt'
Here is the code i tried.
set b=MyFile.txt
for /f "tokens= 1" %%c in (%b%) do (set line=%%c)
Set OLDDate=%line:~11,6%
SET filename="AnotherFile.txt"
FOR %%f IN (%filename%) DO SET filedatetime=%%~tf
SET Month=%filedatetime:~0,2%
SET Date=%filedatetime:~3,2%
SET Year=%filedatetime:~8,2%
SET NEWDate=%Year%%Month%%date%
ECHO OLD DATE = %OLDDate%
ECHO NEW DATE = %NEWDate%
I need %OLDDate% to be replaced by %NEWDate% in 'MyFile.txt' in the position ~11,6

Answer 1

Any reason why powershell couldn't do it?
# Example of PowerShell -replace parameter
clear-Host
$file = Get-ChildItem "D:\powershell\snippets\g*.txt"
foreach ($str in $file)
{
$content = Get-Content -path $str
$content | foreach {$_ -replace "the the", "the"} | Set-Content $str
}
write-Host "After replace `n"
$file
In the foreach loop you can replace any string with another.
Date logic can be used as follows:
$anotherfile = gi anotherfile.txt
Retrieving date info
$year = $anotherfile.LastWriteTime.Year