How do you get the number of spaces before a string starts in ColdFusion?
I mean, I have a string like this " Hello World!"
I want to get the count of spaces (in this case 3) before the word "Hello" starts.
I'm not too familiar with ColdFusion but considering this API you should be able to get the result you want with:
Len(str) - Len(LTrim(str))
But maybe there is a better solution :)
Related
I have search but found python and related solutions.
I have a string like
"Hello 'how' are % you?"
which I want to convert to below after Remove everything except numbers and alphabets
Hello how are you
I am using Regexreplace as follows but now sure what should be the replacement or if its a right approach
=REGEXREPLACE(B2 , "([^A-Za-z0-9]+)")
The main thing i want to remove from the string are the stuff like " or strange symbols
can anyone help?
You can use:
=TRIM(REGEXREPLACE(B2,"[\W_]+"," "))
Or, include the space in your character class:
=REGEXREPLACE(B2,"[\W_ ]+"," "))
Where: \W is short for [^A-Ba-b0-9_], so to include the underscore we added it to the character class.
you can use:
=TRIM(REGEXREPLACE(A1, "'|%|""", ))
I'm using Ruby 2.1. I have this logic that looks for consecutive pairs of strings in a bigger string
results = line.scan(/\b((\S+?)\b.*?\b(\S+?))\b/)
My question is, how do I iterate over the list of results and print out whether there are three or more characters between the two strings? For instance if my string were
"abc def"
The above would produce
[["abc def", "abc", "def"]]
and I'd like to know whether there are three or more characters between "abc" and "def."
Use a quantifier for the spaces inbetween: \b((\S+?)\b\s{3,}\b(\S+?))\b
Also, the inner boundries are not really needed:
\b((\S+?)\s{3,}(\S+?))\b
A straightforward way to check this is by running a separate regex:
results.select!{|x|p x[/\S+?\b(.*?)\b\S+?/,1].size}
will print the size for every of the bunch.
Another way is to take the size of the captured groups and subtract them:
results = []
line.scan(/\b((\S+?)\b.*?\b(\S+?))\b/) do |s, group1, group2|
results << $~ if s.size - group1.size - group2.size >= 3
end
I have a string, and I want to extract, using regular expressions, groups of characters that are between the character : and the other character /.
typically, here is a string example I'm getting:
'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh'
and so, I want to retrieved, 45.72643,4.91203 and also hereanotherdata
As they are both between characters : and /.
I tried with this syntax in a easier string where there is only 1 time the pattern,
[tt]=regexp(str,':(\w.*)/','match')
tt = ':45.72643,4.91203/'
but it works only if the pattern happens once. If I use it in string containing multiples times the pattern, I get all the string between the first : and the last /.
How can I mention that the pattern will occur multiple time, and how can I retrieve it?
Use lookaround and a lazy quantifier:
regexp(str, '(?<=:).+?(?=/)', 'match')
Example (Matlab R2016b):
>> str = 'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
>> result = regexp(str, '(?<=:).+?(?=/)', 'match')
result =
1×2 cell array
'45.72643,4.91203' 'hereanotherdata'
In most languages this is hard to do with a single regexp. Ultimately you'll only ever get back the one string, and you want to get back multiple strings.
I've never used Matlab, so it may be possible in that language, but based on other languages, this is how I'd approach it...
I can't give you the exact code, but a search indicates that in Matlab there is a function called strsplit, example...
C = strsplit(data,':')
That should will break your original string up into an array of strings, using the ":" as the break point. You can then ignore the first array index (as it contains text before a ":"), loop the rest of the array and regexp to extract everything that comes before a "/".
So for instance...
'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh'
Breaks down into an array with parts...
1 - 'abcd'
2 - '45.72643,4.91203/Rou'
3 - 'hereanotherdata/defgh'
Then Ignore 1, and extract everything before the "/" in 2 and 3.
As John Mawer and Adriaan mentioned, strsplit is a good place to start with. You can use it for both ':' and '/', but then you will not be able to determine where each of them started. If you do it with strsplit twice, you can know where the ':' starts :
A='abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
B=cellfun(#(x) strsplit(x,'/'),strsplit(A,':'),'uniformoutput',0);
Now B has cells that start with ':', and has two cells in each cell that contain '/' also. You can extract it with checking where B has more than one cell, and take the first of each of them:
C=cellfun(#(x) x{1},B(cellfun('length',B)>1),'uniformoutput',0)
C =
1×2 cell array
'45.72643,4.91203' 'hereanotherdata'
Starting in 16b you can use extractBetween:
>> str = 'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
>> result = extractBetween(str,':','/')
result =
2×1 cell array
{'45.72643,4.91203'}
{'hereanotherdata' }
If all your text elements have the same number of delimiters this can be vectorized too.
I have tab seperated records like this
1000 Muhammad Aashir 0213-4211685 123456 0
first I have read the line by using fgets and now i am trying to extract contents by using sscanf, but there is an unexpected problem... please help I am beginner
here is the code
char buffer[SIZE];
Account req;
while(fgets(buffer,SIZE,fptr))
{
cout<<endl<<buffer<<endl;
sscanf(buffer,"%d\t%s\t%s\t%s\t%ld\n",&req.acc_num,req.name,req.mobileno,req.pass,&req.acc_bal);
cout<<endl<<req.pass;
}
output of BUFFER is same as the record line
but after extracting values, when I am displaying the 'req.pass' the value is incorrect
req.pass is displaying '0213-4211685' but it has to display '123456'
sscanf will capture until reaching any kind of whitespace. In your case, req.name only contains Muhammad. This will cause the rest of your variables to contain the wrong info.
If you need to use sscanf(), you'll have to replace instances of " " in your name with an escape character, like "_" for example.
I'm having trouble figuring out how to transform a string into camel case in groovy. Say I start out with a string that looks like "1-800 FOO.BAR". Ultimately, I want this to turn into "1800FooDotBar". I've been able to get 1800FOODotBar by doing the following:
String str = "1-800 FOO.BAR"
String tempStr = str.replaceAll(/(?i)\.com/, "DotCom")
String newStr = tempStr.replaceAll(/\\W/, "")
I'm just not sure how to get rid of those capital letters in the middle. I've come across some information about a capitalize() method that should be able to help, but I'm just not familiar enough with Groovy to know how to use it. I think I need to split the string into individual strings for each word and then capitalize the first letter of each of those strings, but then how do I build the end result back up? I know that similar questions have been asked, but I'm just not seeing how to take that information and make complete Groovy code from it. Thanks in advance!
Very roughly:
String str = "1-800 FOO.BAR"
println str.replaceAll(/\./, " Dot ").split(/[^\w]/).collect { it.toLowerCase().capitalize() }.join("")
=> 1800FooDotBar