I am trying to get my head round using the TransparentBlt function in visual c++ MFC. What I am aiming to achieve is to put one bitmap over the top of the other. The first bitmap is just a standard Stretchblt. The second bitmap is to be placed over the top of the background of the first bitmap. I have made the background of the second bitmap icon pink and I do not want the pink to be visible. Basically I just want to use a function for displaying the icon without showing the pink, how do I do this?
#define TRANSPARENT_MASK RGB(250,84,248)
This is how I have done my the bottom layer bitmaps.
argDC->StretchBlt(WindowRect.left,WindowRect.top,WindowRect.Width(),WindowRect.Height(),
&memDC,0,0,bits.bmWidth-1, bits.bmHeight-1, SRCCOPY);
The last argument of TransparentBlt is crTransparent - the color that should be "transparent". You should specify TRANSPARENT_MASK in your case
Related
I have a wxBitmap which can be hidden or revealed on a wxPanel. When the wxBitmap is hidden I would like it to have the background of the wxPanel, instead it has a standard grey background.
To illustrate my point here are two images:
Bitmap shown:
http://i.stack.imgur.com/PzpR9.png
Bitmap hidden:
http://i.stack.imgur.com/GWs7r.png
I tried applying a mask and using alpha channel for transparency, but these do not solve the problem. What I need to do is set the background of the wxBitmap.
Any ideas how I can accomplish this?
I have noticed that if I minimise the window and then show it again, the problem is solved - no default grey background when the bitmap is hidden. I do not know what operation this (minimise + maximise) procedure performs and I have not yet figured out how to implement it programmatically.
i've implemented a owner draw button into my win32 app (no MFC). The button is a normal 20x20 bitmap (round icon with transparency). The problem is that the button is positioned on a solid background and i can see the buttons gray background (since the bitmap is round). I've tried responding to WM_CTLCOLORBTN with NULL_BRUSH but no luck.. I've tried displaying the button using a bitmap and a ico file but wont budge.. Does anyone know how to solve this problem?
This is my problem, the settings icon should be transparent at the edges (not white/gray)
It sounds like you're trying to make a non-rectangular control.
You could call SetWindowRgn to tell Windows that your control is non-rectangular.
In addition to what #joel's answer, if you want to make some area transperant put a unique color in the area where you want to have transperancy using some image editors (RGB(0xFF,0x00,0xFF)) is mostly used Then use TransperantBlt
You say it's a solid background but your image shows some kind of orange-yellow gradient as a background. If it really was a standard windows button solid color you can load the bitmap with LoadImage using the LR_LOADMAP3DCOLORS or LR_LOADTRANSPARENT. Since you have a gradient you'll have to use a more complicated technique to mask out the bitmap.
http://www.winprog.org/tutorial/transparency.html
I'm displaying a bitmap using GDI+. After loading the bitmap from a DLL resource I set the background colour (blue - #0000FF) to transparent using TransparentBlt. On Windows Vista and later this works as expected.
However, on a Windows XP system we're testing on this only works when any tooltip (e.g. the "title" property in IE, or Windows Explorer's tooltip shown when hovering the mouse over a file, etc) is displayed. The rest of the time the background colour is still blue.
Has anyone encountered this before, or know of a way to stop this occurring and for the blue to be properly made transparent?
Edit: After further investigation I found that setting colour depth in Windows XP to 16 bit colours instead of 32 bit colours caused TransparentBlt to start working normally again. Obviously this isn't an ideal solution, specifying what colour depth must be used, but does this give any hint to what might be happening?
Edit2: Code sample included.
m_pGDIBitmap = new Gdiplus::Bitmap(_Module.m_hInst, MAKEINTRESOURCE(lImageResource));
m_hMemDC = CreateCompatibleDC(hdc);
Gdiplus::Graphics myGraphics(m_hMemDC);
myGraphics.DrawImage(m_pGDIBitmap,
Gdiplus::Rect(0, 0, m_pGDIBitmap->GetWidth(), m_pGDIBitmap->GetHeight()),
0,
0,
m_pGDIBitmap->GetWidth(),
m_pGDIBitmap->GetHeight(),
Gdiplus::UnitPixel, &imAtt);
SetStretchBltMode(hdc, HALFTONE);
SetBrushOrgEx(hdc, rcBounds.left, rcBounds.top, NULL);
TransparentBlt(hdc, rcBounds.left, rcBounds.top, iScaledWidth, iScaledHeight, m_hMemDC, 0, 0, iBitmapWidth, iBitmapHeight, GetPixel(m_hMemDC, 0, 0));
You must show some sample code - the code that loads the bitmap and the code that blits it to display.
From the symptoms that you describe, my guess is that you load the bitmap not in its native format, but in the current display format. This means, that when the bit depth of the bitmap differs from the bit depth of the display, an automatic color space conversion is made. When this happens, the color that you provide to TransparentBlt is actually different from the color in the bitmap.
Possible alternative solutions:
Make sure that the bitmap is loaded in its native format without conversion.
Allow the conversion to take place, but instead of providing a hardcoded color value to TransparentBlt, make a GetPixel of a known "transparent" pixel of the bitmap (like top-left), and provide this value to the TransparentBlt.
What I ended up doing was more of a workaround, but it did work. I changed the background colour to black and added the following code before the DrawImage call:
Gdiplus::ImageAttributes imAtt;
imAtt.SetColorKey(Gdiplus::Color(0, 0, 0), Gdiplus::Color(0, 0, 0), Gdiplus::ColorAdjustTypeBitmap);
For some reason using this with blue as the background didn't work and using TransparentBlt on its own with either colour didn't work, but the combination applied the transparency correctly on the various OSes and colour depths that I tried.
If I had access to a paint program that supported bitmap files with an alpha channel, i.e. 32 bit bitmaps, I suspect making the background explicitly transparent and then using AlphaBlend would have worked as well but I didn't have the ability to try that at the time.
It's a while since I've done this, but I'm trying to add a custom button graphic to a windows button, with some transparent areas. I've tried various schemes but can't seem to get the transparent areas to show. Here's my code:
hbmpUpDisabled = LoadImage(instance,MAKEINTRESOURCE(IDB_UPARROWDISABLED), IMAGE_BITMAP, 0, 0, LR_DEFAULTSIZE | LR_LOADTRANSPARENT | LR_LOADMAP3DCOLORS );
SendMessage(GetDlgItem(hWndDlg, IDC_MOVEUP),BM_SETIMAGE,(WPARAM)IMAGE_BITMAP,(LPARAM)hbmpUpDisabled);
Does anyone notice any problems here? It works if my bitmap is a 1-bit bitmap. I couldn't get a 32 bit bitmap to work, and I'm not sure how to setup a 24 bit or 8 bit bitmap to do it.... I tried a custom 255,0,255 color (which IIRC is a default transparent value), but so far no joy....
LR_LOADMAP3DCOLORS should map grey - in the source image - to to the current button face color. Buttons do not use AlphaBlt or TransparentBlt so there is no way to actually (short of custom painting) set a bitmap with transparent or alpha'd areas onto a button and expect it to work. You just have to pre-prepare the bitmap with the correct button color in its background areas.
That said - I suspect that some of these restrictions may be lifted for buttons implemented by common controls v6. Add commctl 6 as a dependend assembly to your exe and see if the behaviour changes.
I'm creating a non-intrusive popup window to notify the user when processing a time-consuming operation. At the moment I'm setting its transparency by calling SetLayeredWindowAttributes which gives me a reasonable result:
alt text http://img6.imageshack.us/img6/3144/transparentn.jpg
However I'd like the text and close button to appear opaque (it doesn't quite look right with white text) while keeping the background transparent - is there a way of doing this?
In order to do "proper" alpha in a layered window you need to supply the window manager with a PARGB bitmap by a call to UpdateLayeredWindow.
The cleanest way to achieve this that I know of is the following:
Create a GDI+ Bitmap object with the PixelFormat32bppPARGB pixel format.
Create a Graphics object to draw in this Bitmap object.
Do all your drawing into this object using GDI+.
Destroy the Graphics object created in step 2.
Call the GetHBITMAP method on the Bitmap object to get a Windows HBITMAP.
Destroy the Bitmap object.
Create a memory DC using CreateCompatibleDC and select the HBITMAP from step 5 into it.
Call UpdateLayeredWindow using the memory DC as a source.
Select previous bitmap and delete the memory DC.
Destroy the HBITMAP created in step 5.
This method should allow you to control the alpha channel of everything that is drawn: transparent for the background, opaque for the text and button.
Also, since you are going to be outputting text, I recommend that you call SystemParametersInfo to get the default antialiasing setting (SPI_GETFONTSMOOTHING), and then the SetTextRenderingHint on the Graphics object to set the antialiasing type to the same type that is configured by the user, for a nicer look.
I suspect you'll need two top level windows rather than one - one that has the alpha blend and a second that is display above the first with the opaque text and button but with a transparent background. To accomplish this with a single window you'll need to use the UpdateLayeredWindow API call, but using this will cause your buttons to not redraw when they are interacted with (hover highlights, focus etc.)
It is possible that if this application is for Vista only there is a new API call that you can use, but I do not believe it is available in XP or earlier.
I can't say for sure, you'll need to try it, but since everything is a window, you could try setting the layered attributes for your button to make it opaque.
As for the text, you may be able to put that in its own frame with a set background and foreground color, and modify its layered attributes to make the background color transparent...
But since these are child windows and not the top-level window, I really don't know that it'll work.