I want to achieve something like this:
BEFORE:
SOME_TEXT=some_more_text
OTHER_TEXT=some_other_text
AFTER:
SOME_TEXT
OTHER_TEXT
I could print using awk or sed with regex and have the equals sign as the field separator.
But what's the most efficient way of doing this?
With awk, that would be as simple as:
awk -F= '{print $1}' thefile
With sed:
sed 's,=.*,,' thefile
That is provided, your input is a file named thefile.
Here is another solution which uses "cut".
$ cat > /tmp/d.log
SOME_TEXT=some_more_text
OTHER_TEXT=some_other_text
$ cat /tmp/d.log |cut -d"=" -f1
SOME_TEXT
OTHER_TEXT
If File contains your string. Do this,
cut -f1 -d= File
Related
this is my original string:
NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1
I want to only add back slash to all the spaces before ':'
so, this is what I finally want:
NetworkManager/system\ connections/Wired\ 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1
I need to do this in bash, so, sed, awk, grep are all ok for me.
I have tried following sed, but none of them work
echo NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1 | sed 's/ .*\(:.*$\)/\\ .*\1/g'
echo NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1 | sed 's/\( \).*\(:.*$\)/\\ \1.*\2/g'
echo NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1 | sed 's/ .*\(:.*$\)/\\ \1/g'
echo NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1 | sed 's/\( \).*\(:.*$\)/\\ \1\2/g'
thanks for answering my question.
I am still quite newbie to stackoverflow, I don't know how to control the format in comment.
so, I just edit my original question
my real story is:
when I do grep or use cscope to search keyword, for example "address1" under /etc folder.
the result would be like:
./NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1
if I use vim to open file under cursor, suppose my vim cursor is now at word "NetworkManager",
then vim will understand it as
"./NetworkManager/system"
that's why I want to add "\" before space, so the search result would be more vim friendly:)
I did try to change cscope's source code, but very difficult to fully achieve this. so have to do a post replacement:(
If you only want to do the replacements if there is a : present in the string, you can check if there are at least 2 columns, setting the (output)field separator to a colon.
Data:
cat file michaelvandam#Michaels-MacBook-Pro
NetworkManager/system connections/Wired 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1
NetworkManager/system connections/Wired 1.nmconnection 14 address1=10.1.10.71/24,10.1.10.1%
Example in awk:
awk 'BEGIN {FS=OFS=":"}{if(NF>1)gsub(" ","\\ ",$1)}1' file
Output
NetworkManager/system\ connections/Wired\ 1.nmconnection:14 address1=10.1.10.71/24,10.1.10.1
NetworkManager/system connections/Wired 1.nmconnection 14 address1=10.1.10.71/24,10.1.10.1
This could be simply done in awk program, with your shown samples, please try following.
awk 'BEGIN{FS=OFS=":"} {gsub(/ /,"\\\\&",$1)} 1' Input_file
Explanation: Simple explanation would be, setting field separator and output field separator as : for this program. Then in main program using gsub(Global substitution) function of awk. Where substituting space with \ in 1st field only(as per OP's remarks it should be done before :) and printing line then.
An idea for a perl one liner in bash to use \G and \K (similar #CarySwoveland's comment).
perl -pe 's/\G[^ :]*\K /\\ /g' myfile
See this demo at tio.run or a pattern demo at regex101.
This might work for you (GNU sed):
sed -E ':a;s/^([^: ]*) /\1\n/;ta;s/\n/\\ /g' file
Replace spaces before : by newlines then replace newlines by \ 's.
Alternative using the hold space:
sed -E 's/:/\n:/;h;s/ /\\ /g;G;s/\n.*\n//' file
Split the line on the first :.
Amend the front section, remove the middle and append the unadulterated back section.
My answer is ugly and I think RavinderSingh13's answer is THE ONE, but I already took the time to write mine and it works (It's written step by step, but it's a one line command):
I got inspired by HatLess answer:
first get the text before the : with cut (I put the string in a file to make it easy to read, but this works on echo):
cut -d':' -f1 infile
Then replace spaces using sed:
cut -d':' -f1 infile | sed 's/\([a-z]\) /\1\\ /g'
Then echo the output with no new line:
echo -n "$(cut -d':' -f1 infile | sed -e 's/\([a-z]\) /\1\\ /g')"
Add the missing : and what comes after it:
echo -n "$(cut -d':' -f1 infile | sed -e 's/\([a-z]\) /\1\\ /g')" | cat - <(echo -n :) | cat - <(cut -d':' -f2 infile)
I've read a lot of questions about how to replace spaces from a file but I have the following problem:
I have a file like so:
<foo>"crazy foo"</foo> <bar>dull-bar</bar>
and I'm trying to remove spaces between > < and only those ones so the file would be like:
`<foo>"crazy foo"</foo><bar>dull-bar</bar>`
So far I've tried to remove then by using sed and tr. Sed is not working by any chance and using tr '> <' '><' outputs:
<foo>"crazy foo"</foo><<bar>dull-bar</bar>
sed -i -e "s/> *</></g" YourFile
-i means YourFile is modified. Remove this option to test your command and display the result in shell output.
* matches n spaces.
The g at the end of sed expression means "Replace all the occurrences".
You could try something like this
echo "<foo>"crazy foo"</foo> <bar>dull-bar</bar>" | sed 's/>[[:space:]]*</></g '
awk -F"\"" '{print $3}' file.txt | sed 's/ //g'
Identifiable: fasdf/=egbalid=/more.garble/XY=foo.bar.baz
I have a line that can be uniquely identified with /Identifiable/. What I'd like to have is the value of XY (in this case foo.bar.baz). How can I get that in awk?
You could use grep for this purpose.
grep -oP '^(?=.*\bIdentifiable\b).*\bXY=\K[\w.]+' file
Example:
$ echo 'Identifiable: fasdf/=egbalid=/more.garble/XY=foo.bar.baz' | grep -oP '^(?=.*\bIdentifiable\b).*\bXY=\K[\w.]+'
foo.bar.baz
Assuming the XY value is always at the end of the line (it's always hard to guess when just 1 line of sample input is posted):
$ awk -F= '/Identifiable/{print $NF}' file
foo.bar.baz
Here is one way:
echo "Identifiable: fasdf/=egbalid=/more.garble/XY=foo.bar.baz" | awk -F"XY=" '{print $2}'
foo.bar.baz
I am not very experienced with regular expressions and sed/awk scripting.
I have urls that are similar to the following torrent url:
http://torcache.net/torrent/D7249CD9AF321C8578B3A7007ABBDD63B0475EEB.torrent?title=[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
I would like to have sed or awk script extract the text after the title i.e
from the example above just get:
[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
A simple approach with awk: use the = as the field separator:
awk -F"=" '{print $2}'
Thus:
echo "http://torcache.net/torrent/D7249CD9AF321C8578B3A7007ABBDD63B0475EEB.torrent?title=[kickass.to]against.the.ropes.by.carly.fall.epub.torrent" | awk -F"=" '{print $2}'
[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
Just remove everything before the title=: sed 's/.*title=//'
$ echo "http://torcache.net/torrent/D7249CD9AF321C8578B3A7007ABBDD63B0475EEB.torrent?title=[kickass.to]against.the.ropes.by.carly.fall.epub.torrent" | sed 's/.*title=//'
[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
Let's say:
s='http://torcache.net/torrent/D7249CD9AF321C8578B3A7007ABBDD63B0475EEB.torrent?title=[kickass.to]against.the.ropes.by.carly.fall.epub.torrent'
Pure BASH solution:
echo "${s/*title=}"
[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
OR using grep -P:
echo "$s"|grep -oP 'title=\K.*'
[kickass.to]against.the.ropes.by.carly.fall.epub.torrent
By using sed (no need to mention title in the regexp in your example) :
sed 's/.*=//'
An another solution exists with cut, another standard unix tool :
cut -d= -f2
Let A,B,C,D are the words
Input File :
..
A/B/C/D
W/B/C/Z
L/B/C/O
..
Output file:
..
A/B/C/A
W/B/C/W
L/B/C/L
..
Replace the word D with word A one the same line, only if /B/C/ delimiter present in the line and like wise for the other lines
Any sed/awk/perl oneliner to accomplish that
This is a awk solution:
awk -F/ -v OFS=/ '$2=="B" && $3=="C" {$4=$1}1' input.txt
You can do:
sed -re 's/^([^/]*)(\/B\/C\/)([^/]*)$/\1\2\1/' file
Demo:
$ cat file
A/B/C/D
W/B/C/Z
L/B/C/O
$ sed -re 's/^([^/]*)(\/B\/C\/)([^/]*)$/\1\2\1/' file
A/B/C/A
W/B/C/W
L/B/C/L
pearl.306> echo "A/B/C/D"|awk '{split($0,a,"/");print a[1]"/"a[2]"/"a[3]"/"a[1]}'
A/B/C/A
pearl.307>
another way is:
pearl.309> echo "A/B/C/D" | awk -F"/" '{OFS="/"}{$NF=$1;print}'
A/B/C/A
pearl.310>
pearl.318> cat file1
A/B/C/D
W/B/C/Z
L/B/C/O
pearl.319> awk -F"/" '{OFS="/"}{$NF=$1;print}' file1
A/B/C/A
W/B/C/W
L/B/C/L
pearl.320>
This might work for you:
sed 's|^\(\(.\)/B/C/\).|\1\2|' file
if A/B/C/D are real words e.g. wordA/wordB/wordC/wordD, then:
sed 's/|^\(\([^/]*\)/wordB/wordC/\).*|\1\2|' file
This should do the trick. perl -p -e 's/D/A/g'
In sed sed -e 's/D/A/'
perl -pe 's#(/B/C/)(.*)#$1$`#' file
this should work +