I have the following line, and I want to add a brackets before and after it:
from:
<span class="Footnote"> Matt. xx. 19.</span>
or:
<span class="Footnote"> 1 Thess. i. 7.</span>
and different values of verse references.. (in other words anything in between those > and <
to:
<span class="Footnote"> (Matt. xx. 19.)</span>
and so on (it takes anything in between those > and < and add () before and after it..
p.s. I use notepad++ to search and replace..
edit:
the first 3 replies work great, even for anything not in the same format of the verse.. which is helpful.. however I noticed in the code some differences that doesn't get changed.. like if the code has any tags in between.. like:
<span class="Footnote"> [See <i>Dan</i>, note 12, p. 26, <i>infra</i>. “Eternal” ="long.”]</span>
or if the code is divided in more than one line! like
<span class="Footnote"> some text
more text
</span>
Thanks in advance,
Find what:
Footnote">\s*([^>]+)\s*<
Replace with:
Footnote">(\1)<
Search for
<span class="Footnote">\s*([^<>]*?)\s*</span>
and replace with
<span class="Footnote">(\1)</span>
This changes
<span class="Footnote"> Matt. xx. 19. </span>
into
<span class="Footnote">(Matt. xx. 19.)</span>
Try this: (Couldnt test it, my family wants me to close the computer at Christmas breakfast).
preg_replace("/Footnote">([^>]*?)</span>/i","[\1]",$subject);
Related
I'm doing a find/replace and but I have already made a few changes the slow way. I want to use regex to replace the rest but make sure I don't replace ones I've already done. So, I need it to match 1 but not 2. The end result will be replacing all instances that look like 1 with 2. The -icon can be anything
1: <span class="glyphicons icon">
2: <span class="glyphicons glyphicons-icon">
More examples:
<span class="glyphicons hand">
<span class="glyphicons flower">
<span class="glyphicons bucket">
<span class="glyphicons glyphicons-stone_head">
<span class="glyphicons glyphicons-decapitated-corpse">
I need to replace the first 3 examples but not the last 2. The application is quite large so I'd really like to be able to do this with one 'replace all'.
Assuming icon can be any word, I'd try replacing glyphicons\s([A-Za-z]+)" by glyphicons glyphicons-$1".
I wrote a section of a webpage that had the following bit...
<span id="item01"> some first presented text</span>
<span id="item02"> some other text, presented second</span>
<span id="item03"> more text</span>
....
<span id="item15"> last bit of text.</span>
I then realized that it should have been numbered from 14 to 0, not 1 to 15. (Yes, bad design on my part, not planning out the JavaScript first.)
Question. Is there an easy way in vim to do math on the numbers in a regular expression? What I would like to do is a search on the text "item[00-99]", and have it return the text "item(15-original number)"
The search seems easy enough -- /item([0-9][0-9])/
(parentheses to put the found numbers into a buffer), but is it even possible to do math on this?
Macro for making numbered lists in vim? gives a way to number something from scratch, but I'm looking for a renumbering method.
:%s/item\zs\d\+/\=15 - submatch(0)/
will do what you want.
Breaking it down:
item\zs\d\+: match numbers after item (the \zs indicates the beginning of the match)
\=: indicate that the replace is an expression
15 - submatch(0): returns 15 minus the number matched
Another interesting way is to use g<CTRL-a> (:help v_g_CTRL-A for more information)
Start from
<span id="item01"> some first presented text</span>
<span id="item02"> some other text, presented second</span>
<span id="item03"> more text</span>
....
<span id="item15"> last bit of text.</span>
Use visual block mode to reset all numbers to 00:
<CTRL-V> select all numbers
r0 replace all numbers with zeros
You should be seen:
<span id="item00"> some first presented text</span>
<span id="item00"> some other text, presented second</span>
<span id="item00"> more text</span>
....
<span id="item00"> last bit of text.</span>
Now restore your block select with gv or just select all lines with V and press g<CTRL+a>
<span id="item01"> some first presented text</span>
<span id="item02"> some other text, presented second</span>
<span id="item03"> more text</span>
....
<span id="item015"> last bit of text.</span>
Unfortunately one last clean up is needed here. As you can see, all two digit numbers get 0 in front. Use visual block mode <CTRL+v> again to select and remove unwanted zeros.
<span id="item01"> some first presented text</span>
<span id="item02"> some other text, presented second</span>
<span id="item03"> more text</span>
....
<span id="item15"> last bit of text.</span>
Now you are done :)
If you have vim with perl (many distributions have that by default), you can
use :perldo commands to do it. (#Marth solution is better)
:perldo s/(?<=item)(\d+)/15 - $1/e
You might want to take a look at the VisIncr plugin. It adds support for increasing / decreasing columns of numbers, dates, and day names, in various formats. Quite handy when you have to deal with these kind of things.
In textmate-1.5 I can use the regex syntax (.*) to find both lines in the below use case:
<span class="class1"></span>
<span class="class2"></span>
Now I want to append more code to each of them so my find query is span class="(.*)" and my replace query is span class="(.*)" aria-hidden="true" which i had hoped would result in this:
<span class="class1" aria-hidden="true"></span>
<span class="class2" aria-hidden="true"></span>
but it actually resulted in this:
<span class="(.*)" aria-hidden="true"></span>
<span class="(.*)" aria-hidden="true"></span>
Using find/replace (not using column selection which would work for this example but not for the actual situation) is it possible to maintain the area matched by regex in the replace action with a representative wild character or something?
Change your replace query as,
span class="$1" aria-hidden="true"
$1 would refer the characters which are present inside group index 1.
(<span class="[^"]*")
Try this.Replace with $1 aria-hidden="true".See demo.
http://regex101.com/r/wQ1oW3/22
I am fairly new to regular expressions and have been having difficulty using one to extract the data I am after. Specifically, I am looking to extract the date touched and the the counter from the following:
<span style="color:blue;"><query></span>
<span style="color:blue;"><pages></span>
<span style="color:blue;"><page pageid="3420" ns="0" title="Test" touched="2011-07-08T11:00:58Z" lastrevid="17889" counter="9" length="6269" /></span>
<span style="color:blue;"></pages></span>
<span style="color:blue;"></query></span>
<span style="color:blue;"></api></span>
I am currently using vs2010. My current expression is:
std::tr1::regex rx("(?:.*touch.*;)?([0-9-]+?)(?:T.*count.*;)([0-9]+)(&.*)?");
std::tr1::regex_search(buffer, match, rx);
match[1] contains the following:
2011-07-08T11:00:58Z" lastrevid="17889" counter="9" length="6269" /></span>
<span style="color:blue;"></pages></span>
<span style="color:blue;"></query></span>
<span style="color:blue;"></api></span>
match[2] contains the following:
6269" /></span>
<span style="color:blue;"></pages></span>
<span style="color:blue;"></query></span>
<span style="color:blue;"></api></span>
I am looking for just "2011-07-08" in match[1] and just "9" in match[2]. The date format will never alter, but the counter will almost certainly be much larger.
Any help would be highly appreciated.
That's because cmatch::operator[](int i) returns a sub_match, whose sub_match::operator basic_string() (used in the context of cout) returns a string starting at the beginning of the match and ending at the end of the source string.
Use sub_match::str(), i.e. match[1].str() and match[2].str().
Moreover, you'll need your expression to be more specific: .* tries to match the world, and gives up some if it can't.
Try std::tr1::regex rx("touched="([0-9-]+).+counter="([0-9]+)");.
You could even use non-greedy matchers (like +? and *?) to prevent excessive matching.
Try
std::tr1::regex rx("(?:.*touch.*;)?([0-9-]+)(?:T.*count.*;)([0-9]+)(&.*)?");
removing the question mark makes the term greedy, so it will fill as much as it can.
I have this html with this type of snippit below all over:
<li><label for="summary">Summary:</label></li>
<li class="in">
<textarea class="ta" id="summary" name="summary" rows="4" cols="10" tabindex="4">
${fieldValue(bean: book, field: 'summary')}</textarea>
<a href="#" class="tt">
<img src="<g:createLinkTo dir='images/buttons/' file='icon.gif'/>" alt="Help icon for the summary field">
<span class="tooltip">
<span class="top"></span>
<span class="middle">Help text for summary</span>
<span class="bottom"></span>
</span>
</a>
</li>
I want to pull off the alt value and the text between XXXX and replace the a tag with the code below.
This is my stab at the reg ex
<a href="#" class="tt">.*alt="(.*)".*<span class="middle">(.*)<\/span><\/a>
Output with the callbacks
<ebs:cssToolTip alt="$1" text="$2"/>
I tried it out on http://rubular.com/ and it does not quite work. Any suggestions
You may want to ensure your regexp isn't greedily picking up characters - use ".*?" rather than straight ".*".
What do you mean, "it does not quite work"? How does it fail?
A suggestion (not tested your regexp): note that * is a greedy operator, so .* is rarely a good idea because it may match a lot more than what you intended.
Try:
<a href="#" class="tt">.*alt="([^"]*)".*<span class="middle">([^"]*)<\/span><\/a>
Think i solved it by getting an idea from another stackoverflow question
<a href="#" class="tt">.*alt="([^"]*)".*<span class="middle">([^<]*).*<\/a>
This seems to work on the http://rubular.com/ site
Here you go:
http://rubular.com/regexes/8434
You were facing two potential problems. First, without adding the //m option, '.' will not match newline characters. Second, you were using greedy matching. Adding the '*?' makes it better.
/<a href="#" class="tt">.*?alt="([^"]*)">.*?<span class="middle">(.*?)<\/span>/m