I'll give the step by step info.
Let's say we're in the about page, the URL is example.com/about.
There's an email a friend button, when clicked, the URL is example.com/emailafriend.
Then when I clicked the submit button, the referal URL will be submitted is example.com/emailafriend. Question, how to get the about page URL? BTW, I'm using request.META['HTTP_REFERER'].
You could work with the request path attribute and add that to your form's action attribute, like so:
<form method="post" action="/tell-a-friend?return_url={{ request.path }}">
...
</form>
Then, in your tell-a-friend view, HttpResponseRedirect to the return_url query parameter.
It looks like maybe you are using APPEND_SLASH which will do a redirect if you don't have a slash. Try changing the button link to sample.com/emailafriend/, note the ending slash.
Maybe simply pass sample.com/about as GET or POST param? Or even through session.
Related
I am very new to Django and I'm nearing the end of the django girls tutorial. I have added "#login_required" above my post_detail in views (view for clicking on a specific post) and added a login.html template. So when I click on a post title I get redirected to my login page (so far, so good) and the url is: http://127.0.0.1:8000/accounts/login/?next=/post/11/ (trying this on my computer atm.)
Then I type in my admin name/password and automatically get redirected to http://127.0.0.1:8000/accounts/profile/ and of course get a "Page not found (404)" (since I have no url/view/template for that). I thought "Dang, I just wanted to be redirected to /post/11/"!
Looked around on stack overflow and found this question:
Signing in leads to "/accounts/profile/" in Django (sounds about right)
and got the answer
Change the value of LOGIN_REDIRECT_URL in your settings.py.
So I looked up LOGIN_REDIRECT_URL in the Django documentation:
Default: '/accounts/profile/'
The URL where requests are redirected after login when the contrib.auth.login view gets no next parameter.
This is used by the login_required() decorator, for example.
This setting also accepts named URL patterns which can be used to reduce configuration duplication since you don’t have to define the URL in two places (settings and URLconf).
Deprecated since version 1.8: The setting may also be a dotted Python path to a view function. Support for this will be removed in Django 1.10.
But doesn't my contrib.auth.login get a next parameter? (looking at my url that say "?next=/post/11/" at the end) Please help me out here, I'm lost for what the problem could be here :(
You can view the page at:
http://finbel.pythonanywhere.com/
And the source code at:
https://github.com/Finbel/my-first-blog
UPDATE (1):
So I now know that the LOGIN_REDIRECT_URL is the thing that's deciding where I end up next, which must mean that it ignores the next-parameter in the url. I googled further on the problem and found this question which was very similar to my problem, i.e.
Documentation states that I need to use the "next" parameter and context processors. I have the {{next}} in my template, but I'm confused on how to actually pass the "/gallery/(username)". Any help would be greatly appreciated.
(I don't even have the {{next}} in my template, where/how should I add it?)
The preferred answer to that question seemed to be:
Django's login view django.contrib.auth.views.login accepts a dictionary named extra_context. The values in the dictionary are directly passed to the template. So you can use that to set the next parameter. Once that is done, you can set a hidden field with name next and value {{ next }} so that it gets rendered in the template.
But I'm not sure how to interpret this. While writing this edit I got an answer on this post (by kacperd) and will read it through now)
The problem is that contrib.auth.login doesn't get the next parameter.
When you try to get the login_required view without credentials your request is redirect to login view, and the template you created is rendered. The next parameter is present in this view, but when you perform the login action which is submitting the form, you are not including next in your request so contrib.auth.login doesn't get it and redirects to default page.
The solution to your problem is to include the next param and pass it forward. You can do this by modifying your login template. Simply add ?next={{ request.GET.next }} to form action attribute.
<form method="post" action="{% url 'django.contrib.auth.views.login' %}?next={{ request.GET.next }}">
I am following the article in the djangobook on Forms:
http://www.djangobook.com/en/2.0/chapter07.html
the search url in the article doesn't redirect it to my app(book) url. Instead it goes to 127.0.0.1:8000/search, it should have been 127.0.0.1:8000/book/search
I think you should specify the url on the form tag
<form action="/book/search/?" ...>
And make sure it points to the right address / view /url.py and all that
Hi i made some ModelForm. now when i enter i got this Error.
RuntimeError
Exception Value:
You called this URL via POST, but the URL doesn't end in a slash and you have APPEND_SLASH set. Django can't redirect to the slash URL while maintaining POST data. Change your form to point to 127.0.0.1:8000/comp/new/ (note the trailing slash), or set APPEND_SLASH=False in your Django settings.
What is causing this? May form action matches exactly the form URL comp/new and this match to my view to render and work with the data. But something went wrong....
My Url
url(r'^comp/new/$', 'company.views.add_company', name='add_company'),
My Form action
<form id="category_form" method="post" action="/comp/new/">
Probably your are using reverse so check your urls.py, the missing / should be there
I have a question: how to get the current path of the url. Let's say, I have 3 navigation bars, about , blog and contact page. In each page, I have facebook, twitter and a manual email a friend button. When I clicked the email a friend button, and the current URL is www.example.com/about, the current URL is now already www.example.com/emailafriend. How can I get the www.example/about? Also in blog and contact. Please help me. Thanks.
How does your email a friend button work? Is it a django view that takes the current URL and emails it? If so, you don't want the "current" URL, which, as you note, is actually the email a friend URL. What you want to do is pass the URL you want to share as a URL parameter, ie:
/share?url=http://www.example.com/blog
Adding more info based on comments:
When I was referencing URL above, I was not referring to your django URL configuration. Let's take a step back.
On your About page you have a link to email a friend, right? That link is probably generated in your template, but it's the same on every page. Something like:
Email a friend
Instead of this, try this:
Email a friend
Now you need to make your email_a_friend view handle this. It can get the url via
request.get('url', '').
Some additional information:
You might want to escape the {{ request.get_full_path }} function so that it's escaped and URL safe, then you'll have to unescape it in your view. Once you get the URL back to your view, you can do as you please with it.
{{ request.get_full_path|urlencode }}
Try using Relative URLs like for example From www.example.com/about to get to www.example.com/email use /email. Using relative urls is the simplest solution .
Take a look at this.
Absolute vs relative URLs
It sounds like your want to get the referring URL (the URL that sent you to the current page). That is available to you in the request object, although it is not 100% reliable:
request.META['HTTP_REFERER']
See the documentation on HttpRequest objects for more information.
I trying to implement the url template tag into my project.
I have a button that allows the user to save the data he is seeing.
So the url of this button is this:
(2)url(r'^nameviews/download/$', 'my.path.is.this.to.download' name="load"),
template:
Download
the url of the page that shows the information, and where the button is located is:
(1)(r'^nameviews/$', path.to.page),
but when I tried to click on the button (it should appear the url 2)it doesn't open the file with the data but instead gives me the same url that the main page (1)
the html validator gives me a error on the
<a href="">
It seems it doesn't recognize the url tag.
Anyone has any idea?
Resolved! I didn't really understood what's happen because I didn't change much but should have been some silly mistake.
Sorry!
Thanks any way :)
EDIT
Be careful with the order of the urls. At urls.py try this order:
url(r'^nameviews/download/$', name_of_view, name="load"),
url(r'^nameviews/$', name_of_view, name="first page"),
name_of_view is equal if the view is the same