Scenario where it is better to use union instread of struct - c++

Can some give me some scenario where it is wise to use union instead of struct in some problem?
Thanks

It is wise to use a union whenever you have a data bottleneck, and you have two pieces of data that are mutually exclusive, but available in the same data structure.
Let's say I have two messages that have identical data, except for two pieces of data are mutually exclusive between them, and are close in size (an 32 bit int, and a 4 byte array). I can make a union of the two, and the messages can share data structure without having an increase in size that they won't use.
Be aware of problems:
The data may not be mutually exclusive in the future.
Initialization of the mutually exclusive data.
Reusing the same instance of the data for both messages (you'll need to be sure you switch out the mutually exclusive data, or the receiver deals with junk data).
Having a union to refer to the same data with different type definitions is undefined behavior. So:
Do not use a union to cheat the type system.
Do not use a union to store a pointer and access an reference.
Do not use a union to create cheaper type casting.
Also, Do not use a union with data that is a pointer which can be deleted from another point in the code. You likely have a deleted pointer in your union and accidentally refer to the data using the other definition.
And most importantly, if you do not understand this answer. Do not use a union.

Unions can be a way to get at the actual binary representation of a data structure.
#include <iostream>
#include <iomanip>
union MyUnion {
int integer;
unsigned char bytes[sizeof(int)];
};
int main() {
MyUnion foo;
foo.integer = 42;
std::cout << "My computer represents " << foo.integer << " as:";
for (int i = 0; i < sizeof(foo.bytes); ++i) {
std::cout << ' ' << std::hex << std::setw(2) << std::setfill('0')
<< static_cast<unsigned int>(foo.bytes[i]);
}
std::cout << std::endl;
return 0;
}
There are other ways to accomplish this in C++, but using a union makes the intent rather transparent.
Note that the results may vary by platform (little-endian vs. big-endian) and possibly by compiler (how it packs and pads arrays and data types). Most of the time, you shouldn't need to do stuff like this.
Sometimes you have to deal with a legacy binary format with several different interpretations. ("If the first byte is a 3, then the next value is a zero-terminated ASCII string of at most 16 bytes, otherwise, the next DWORD-aligned int is an offset in the resource block ..."). If you understand all the endianness and packing issues involved, a union makes it relatively easy to tease apart such a struct.

Related

Is there any portable way to ensure a struct is defined without padding bytes using c++11? [duplicate]

This question already has answers here:
Compile-time check to make sure that there is no padding anywhere in a struct
(4 answers)
Closed 3 years ago.
Lets consider the following task:
My C++ module as part of an embedded system receives 8 bytes of data, like: uint8_t data[8].
The value of the first byte determines the layout of the rest (20-30 different). In order to get the data effectively, I would create different structs for each layout and put each to a union and read the data directly from the address of my input through a pointer like this:
struct Interpretation_1 {
uint8_t multiplexer;
uint8_t timestamp;
uint32_t position;
uint16_t speed;
};
// and a lot of other struct like this (with bitfields, etc..., layout is not defined by me :( )
union DataInterpreter {
Interpretation_1 movement;
//Interpretation_2 temperatures;
//etc...
};
...
uint8_t exampleData[8] {1u, 10u, 20u,0u,0u,0u, 5u,0u};
DataInterpreter* interpreter = reinterpret_cast<DataInterpreter*>(&exampleData);
std::cout << "position: " << +interpreter->movement.position << "\n";
The problem I have is, the compiler can insert padding bytes to the interpretation structs and this kills my idea. I know I can use
with gcc: struct MyStruct{} __attribute__((__packed__));
with MSVC: I can use #pragma pack(push, 1) MyStruct{}; #pragma pack(pop)
with clang: ? (I could check it)
But is there any portable way to achieve this? I know c++11 has e.g. alignas for alignment control, but can I use it for this? I have to use c++11 but I would be just interested if there is a better solution with later version of c++.
But is there any portable way to achieve this?
No, there is no (standard) way to "make" a type that would have padding to not have padding in C++. All objects are aligned at least as much as their type requires and if that alignment doesn't match with the previous sub objects, then there will be padding and that is unavoidable.
Furthermore, there is another problem: You're accessing through a reinterpreted pointed that doesn't point to an object of compatible type. The behaviour of the program is undefined.
We can conclude that classes are not generally useful for representing arbitrary binary data. The packed structures are non-standard, and they also aren't compatible across different systems with different representations for integers (byte endianness).
There is a way to check whether a type contains padding: Compare the size of the sub objects to the size of the complete object, and do this recursively to each member. If the sizes don't match, then there is padding. This is quite tricky however because C++ has minimal reflection capabilities, so you need to resort either hard coding or meta programming.
Given such check, you can make the compilation fail on systems where the assumption doesn't hold.
Another handy tool is std::has_unique_object_representations (since C++17) which will always be false for all types that have padding. But note that it will also be false for types that contain floats for example. Only types that return true can be meaningfully compared for equality with std::memcmp.
Reading from unaligned memory is undefined behavior in C++. In other words, the compiler is allowed to assume that every uint32_t is located at a alignof(uint32_t)-byte boundary and every uint16_t is located at a alignof(uint16_t)-byte boundary. This means that if you somehow manage to pack your bytes portably, doing interpreter->movement.position will still trigger undefined behaviour.
(In practice, on most architectures, unaligned memory access will still work, but albeit incur a performance penalty.)
You could, however, write a wrapper, like how std::vector<bool>::operator[] works:
#include <cstdint>
#include <cstring>
#include <iostream>
#include <type_traits>
template <typename T>
struct unaligned_wrapper {
static_assert(std::is_trivial<T>::value);
std::aligned_storage_t<sizeof(T), 1> buf;
operator T() const noexcept {
T ret;
memcpy(&ret, &buf, sizeof(T));
return ret;
}
unaligned_wrapper& operator=(T t) noexcept {
memcpy(&buf, &t, sizeof(T));
return *this;
}
};
struct Interpretation_1 {
unaligned_wrapper<uint8_t> multiplexer;
unaligned_wrapper<uint8_t> timestamp;
unaligned_wrapper<uint32_t> position;
unaligned_wrapper<uint16_t> speed;
};
// and a lot of other struct like this (with bitfields, etc..., layout is not defined by me :( )
union DataInterpreter {
Interpretation_1 movement;
//Interpretation_2 temperatures;
//etc...
};
int main(){
uint8_t exampleData[8] {1u, 10u, 20u,0u,0u,0u, 5u,0u};
DataInterpreter* interpreter = reinterpret_cast<DataInterpreter*>(&exampleData);
std::cout << "position: " << interpreter->movement.position << "\n";
}
This would ensure that every read or write to the unaligned integer is transformed to a bytewise memcpy, which does not have any alignment requirement. There might be a performance penalty for this on architectures with the ability to access unaligned memory quickly, but it would work on any conforming compiler.

Byte size of union and struct

#include <iostream>
using namespace std;
typedef union {
long i;
int k[5];
char c;
} UDATE;
struct data {
int cat;
UDATE cow;
double dog;
} too;
UDATE temp;
int main()
{
cout << sizeof(struct data)+sizeof(temp) << endl;
return 0;
}
under ubuntu 18.04, the answer to this question is 64, but I want to know how uDATE cow in struct is stored in memory, or the rules of data storage?
According to the C++ standard:
The size of a union is sufficient to contain the
largest of its data members. Each data member is allocated as if it
were the sole member of a struct.
So the memory layout of the union is the same as if you had a long there, an array of 5 ints there, or a char there, but spaced to the largest of these (the array of ints). I presume you're using GCC, and IIRC GCC sets a size of 32-bits for int even on a 64-bit architecture. UDATE would therefore have a size of 20-bytes. You'd naively expect, therefore, sizeof(struct data) + sizeof(temp) to return 52. The fact that you're apparently getting 64 is probably because GCC is aligning things to 64-bit boundaries and thus taking 24-bytes for UDATE, and inserting a 4-byte spacer between cat and cow in your data struct.
Note that the standard makes no guarantees made about type-punning - that is the frequently used low level technique where the union is written using one method and read using another to, for example, access the bytes that make up an integer - and claims that a union may only be accessed using the same entries that it was written using (baring an exception for a union of POD structs that share common initial members). However, in practice every compiler I've ever used will read the memory in the manner you'd expect if you'd simply cast a pointer from one type to another in the union using a reinterpret or C-style cast.

Type casting struct to integer and vice versa in C++

So, I've seen this thread Type casting struct to integer c++ about how to cast between integers and structs (bitfields) and undoubtly, writing a proper conversion function or overloading the relevant casting operators is the way to go for any cases where there is an operating system involved.
However, when writing firmware for a small embedded system where only one flash image is run, the case might be different insofar, as security isn't so much of a concern while performance is.
Since I can test whether the code works properly (meaning the bits of a bitfield are arranged the way I would expect them to be) each time when compiling my code, the answer might be different here.
So, my question is, whether there is a 'proper' way to convert between bitfield and unsigned int that does compile to no operations in g++ (maybe shifts will get optimised away when the compiler knows the bits are arranged correctly in memory).
This is an excerpt from the original question:
struct {
int part1 : 10;
int part2 : 6;
int part3 : 16;
} word;
I can then set part2 to be equal to whatever value is requested, and set the other parts as 0.
word.part1 = 0;
word.part2 = 9;
word.part3 = 0;
I now want to take that struct, and convert it into a single 32 bit integer. I do have it compiling by forcing the casting, but it does not seem like a very elegant or secure way of converting the data.
int x = *reinterpret_cast<int*>(&word);
EDIT:
Now, quite some time later, I have learned some things:
1) Type punning (changing the interpretation of data) by means of pointer casting is, undefined behaviour since C99 and C++98. These language changes introduced strict aliasing rules (They allow the compiler to reason that data is only accessed through pointers of compatible type) to allow for better optimisations. In effect, the compiler will not need to keep the ordering between accesses (or do the off-type access at all). For most cases, this does not seem to present a [immediate] problem, but when using higher optimisation settings (for gcc that is -O which includes -fstrict-aliasing) this will become a problem.
For examples see https://blog.regehr.org/archives/959
2) Using unions for type punning also seems to involve undefined behaviour in C++ but not C (See https://stackoverflow.com/a/25672839/4360539), however GCC (and probably others) does explicitly allow it: (See https://gcc.gnu.org/bugs/#nonbugs).
3) The only really reliable way of doing type punning in C++ seems to be using memcpy to copy the data to a new location and perform whatever is to be done and then to use another memcpy to return the changes. I did read somewhere on SO, that GCC (or most compilers probably) should be able to optimise the memcpy to a mere register copy for register-sized data types, but I cannot find it again.
So probably the best thing to do here is to use the union if you can be sure the code is compiled by a compiler supporting type punning through a union. For the other cases, further investigation would be needed how the compiler treats bigger data structures and memcpy and if this really involves copying back and forth, probably sticking with bitwise operations is the best idea.
union {
struct {
int part1: 10;
int part2: 6;
int part3: 16;
} parts;
int whole;
} word;
Then just use word.whole.
I had the same problem. I am guessing this is not very relevant today. But this is how I solved it:
#include <iostream>
struct PACKED{
int x:10;
int y:10;
int z:12;
PACKED operator=(int num )
{
*( int* )this = num;
return *this;
}
operator int()
{
int *x;
x = (int*)this;
return *x;
}
} __attribute__((packed));
int main(void) {
std::cout << "size: " << sizeof(PACKED) << std::endl;
PACKED bf;
bf = 0xFFF00000;
std::cout << "Values ( x, y, z ) = " << bf.x << " " << bf.y << " " << bf.z << std::endl;
int testint;
testint = bf;
std::cout << "As integer: " << testint << std::endl;
return 0;
}
This now fits on a int, and is assignable by standard ints. However I do not know how portable this solution is. The output of this is then:
size: 4
Values ( x, y, z ) = 0 0 -1
As integer: -1048576

What's a need for union { } in C++? [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
C/C++: When would anyone use a union? Is it basically a remnant from the C only days?
Hi all.
What are the reasons for unions to exist in C++? And what are they, actually?
I found this code:
#include <iostream>
using namespace std;
union mixture {
short number;
char symbol[2];
main() {
mixture m1, m2;
cout << "Enter 2 symbols to form short number made of them: ";
cin >> m1.symbol[0] >> m1.symbol[1];
cout << "2 more to go..: ";
cin >> m2.symbol[0] >> m2.symbol[1];
cout.setf(ios::hex);
cout << "Biggest received number: " << (m1.number > m2.number ? m1.number : m2.number) << endl;
system("pause");
return 0;
}
return 0;
But actually, what I win from using union { struct1, struct2 } instead of writing struct { struct2(struct1}: a(struct1.a), b(_struct1.b {}} struct2? to transparently support both types?
I do some embedding stuff (Arduino etc), but never seen the real usage for structs.
Examples, please.
The union lets you treat your data as either char or short without having to cast. Casting pointer between types can produce type-punning errors in the optimizer and generate incorrect output.
EDIT: For an example, I use unions to byte swap doubles and floats after reading them from a file. If you read byteswapped floating point numbers the numbers might get normalized or adjusted while bytes swapped, which of course results in junk once they're swapped:
union float_int
{
float ff;
int32_t ii;
};
float_int data;
read(fd, &data, 4); // Read 4 bytes
byteswap(data.ii); // Passing as a float can alter the bits.
float myvalue = data.ff; // My float is now byteswaped and ready to go.
A union is fundamentally different from a struct in that only one of the members is guaranteed to be usable at a time -- but this is a white lie, see next. (The data may or may not overlap depending upon the compiler, target, and various packing rules and this overlap can be [ab]used in cases The overlap can be [ab]used depending upon compiler, target, types, etc).
Conceptually a union represents a "discrete value" (X has/is A or B but X is not/does not have A and B) and it also allows the compiler (or whatever uses this model) to represent the data more efficiently in cases.
Happy coding.
In hardware level code you have to be sure your bits are in consecutive memory, this is one way to make sure of it.
edit: You dont HAVE to be sure, but there are plenty of cases it does.
Firstly, they're inherited from C and there was no good reason to remove support, so C++ retained support.
It's one of the only widely-supported ways to do type-punning (but still likely illegal by the letter of the standard).
It can save space in certain cases.

When would anyone use a union? Is it a remnant from the C-only days?

I have learned but don't really get unions. Every C or C++ text I go through introduces them (sometimes in passing), but they tend to give very few practical examples of why or where to use them. When would unions be useful in a modern (or even legacy) case? My only two guesses would be programming microprocessors when you have very limited space to work with, or when you're developing an API (or something similar) and you want to force the end user to have only one instance of several objects/types at one time. Are these two guesses even close to right?
Unions are usually used with the company of a discriminator: a variable indicating which of the fields of the union is valid. For example, let's say you want to create your own Variant type:
struct my_variant_t {
int type;
union {
char char_value;
short short_value;
int int_value;
long long_value;
float float_value;
double double_value;
void* ptr_value;
};
};
Then you would use it such as:
/* construct a new float variant instance */
void init_float(struct my_variant_t* v, float initial_value) {
v->type = VAR_FLOAT;
v->float_value = initial_value;
}
/* Increments the value of the variant by the given int */
void inc_variant_by_int(struct my_variant_t* v, int n) {
switch (v->type) {
case VAR_FLOAT:
v->float_value += n;
break;
case VAR_INT:
v->int_value += n;
break;
...
}
}
This is actually a pretty common idiom, specially on Visual Basic internals.
For a real example see SDL's SDL_Event union. (actual source code here). There is a type field at the top of the union, and the same field is repeated on every SDL_*Event struct. Then, to handle the correct event you need to check the value of the type field.
The benefits are simple: there is one single data type to handle all event types without using unnecessary memory.
I find C++ unions pretty cool. It seems that people usually only think of the use case where one wants to change the value of a union instance "in place" (which, it seems, serves only to save memory or perform doubtful conversions).
In fact, unions can be of great power as a software engineering tool, even when you never change the value of any union instance.
Use case 1: the chameleon
With unions, you can regroup a number of arbitrary classes under one denomination, which isn't without similarities with the case of a base class and its derived classes. What changes, however, is what you can and can't do with a given union instance:
struct Batman;
struct BaseballBat;
union Bat
{
Batman brucewayne;
BaseballBat club;
};
ReturnType1 f(void)
{
BaseballBat bb = {/* */};
Bat b;
b.club = bb;
// do something with b.club
}
ReturnType2 g(Bat& b)
{
// do something with b, but how do we know what's inside?
}
Bat returnsBat(void);
ReturnType3 h(void)
{
Bat b = returnsBat();
// do something with b, but how do we know what's inside?
}
It appears that the programmer has to be certain of the type of the content of a given union instance when he wants to use it. It is the case in function f above. However, if a function were to receive a union instance as a passed argument, as is the case with g above, then it wouldn't know what to do with it. The same applies to functions returning a union instance, see h: how does the caller know what's inside?
If a union instance never gets passed as an argument or as a return value, then it's bound to have a very monotonous life, with spikes of excitement when the programmer chooses to change its content:
Batman bm = {/* */};
Baseball bb = {/* */};
Bat b;
b.brucewayne = bm;
// stuff
b.club = bb;
And that's the most (un)popular use case of unions. Another use case is when a union instance comes along with something that tells you its type.
Use case 2: "Nice to meet you, I'm object, from Class"
Suppose a programmer elected to always pair up a union instance with a type descriptor (I'll leave it to the reader's discretion to imagine an implementation for one such object). This defeats the purpose of the union itself if what the programmer wants is to save memory and that the size of the type descriptor is not negligible with respect to that of the union. But let's suppose that it's crucial that the union instance could be passed as an argument or as a return value with the callee or caller not knowing what's inside.
Then the programmer has to write a switch control flow statement to tell Bruce Wayne apart from a wooden stick, or something equivalent. It's not too bad when there are only two types of contents in the union but obviously, the union doesn't scale anymore.
Use case 3:
As the authors of a recommendation for the ISO C++ Standard put it back in 2008,
Many important problem domains require either large numbers of objects or limited memory
resources. In these situations conserving space is very important, and a union is often a perfect way to do that. In fact, a common use case is the situation where a union never changes its active member during its lifetime. It can be constructed, copied, and destructed as if it were a struct containing only one member. A typical application of this would be to create a heterogeneous collection of unrelated types which are not dynamically allocated (perhaps they are in-place constructed in a map, or members of an array).
And now, an example, with a UML class diagram:
The situation in plain English: an object of class A can have objects of any class among B1, ..., Bn, and at most one of each type, with n being a pretty big number, say at least 10.
We don't want to add fields (data members) to A like so:
private:
B1 b1;
.
.
.
Bn bn;
because n might vary (we might want to add Bx classes to the mix), and because this would cause a mess with constructors and because A objects would take up a lot of space.
We could use a wacky container of void* pointers to Bx objects with casts to retrieve them, but that's fugly and so C-style... but more importantly that would leave us with the lifetimes of many dynamically allocated objects to manage.
Instead, what can be done is this:
union Bee
{
B1 b1;
.
.
.
Bn bn;
};
enum BeesTypes { TYPE_B1, ..., TYPE_BN };
class A
{
private:
std::unordered_map<int, Bee> data; // C++11, otherwise use std::map
public:
Bee get(int); // the implementation is obvious: get from the unordered map
};
Then, to get the content of a union instance from data, you use a.get(TYPE_B2).b2 and the likes, where a is a class A instance.
This is all the more powerful since unions are unrestricted in C++11. See the document linked to above or this article for details.
One example is in the embedded realm, where each bit of a register may mean something different. For example, a union of an 8-bit integer and a structure with 8 separate 1-bit bitfields allows you to either change one bit or the entire byte.
Herb Sutter wrote in GOTW about six years ago, with emphasis added:
"But don't think that unions are only a holdover from earlier times. Unions are perhaps most useful for saving space by allowing data to overlap, and this is still desirable in C++ and in today's modern world. For example, some of the most advanced C++ standard library implementations in the world now use just this technique for implementing the "small string optimization," a great optimization alternative that reuses the storage inside a string object itself: for large strings, space inside the string object stores the usual pointer to the dynamically allocated buffer and housekeeping information like the size of the buffer; for small strings, the same space is instead reused to store the string contents directly and completely avoid any dynamic memory allocation. For more about the small string optimization (and other string optimizations and pessimizations in considerable depth), see... ."
And for a less useful example, see the long but inconclusive question gcc, strict-aliasing, and casting through a union.
Well, one example use case I can think of is this:
typedef union
{
struct
{
uint8_t a;
uint8_t b;
uint8_t c;
uint8_t d;
};
uint32_t x;
} some32bittype;
You can then access the 8-bit separate parts of that 32-bit block of data; however, prepare to potentially be bitten by endianness.
This is just one hypothetical example, but whenever you want to split data in a field into component parts like this, you could use a union.
That said, there is also a method which is endian-safe:
uint32_t x;
uint8_t a = (x & 0xFF000000) >> 24;
For example, since that binary operation will be converted by the compiler to the correct endianness.
Some uses for unions:
Provide a general endianness interface to an unknown external host.
Manipulate foreign CPU architecture floating point data, such as accepting VAX G_FLOATS from a network link and converting them to IEEE 754 long reals for processing.
Provide straightforward bit twiddling access to a higher-level type.
union {
unsigned char byte_v[16];
long double ld_v;
}
With this declaration, it is simple to display the hex byte values of a long double, change the exponent's sign, determine if it is a denormal value, or implement long double arithmetic for a CPU which does not support it, etc.
Saving storage space when fields are dependent on certain values:
class person {
string name;
char gender; // M = male, F = female, O = other
union {
date vasectomized; // for males
int pregnancies; // for females
} gender_specific_data;
}
Grep the include files for use with your compiler. You'll find dozens to hundreds of uses of union:
[wally#zenetfedora ~]$ cd /usr/include
[wally#zenetfedora include]$ grep -w union *
a.out.h: union
argp.h: parsing options, getopt is called with the union of all the argp
bfd.h: union
bfd.h: union
bfd.h:union internal_auxent;
bfd.h: (bfd *, struct bfd_symbol *, int, union internal_auxent *);
bfd.h: union {
bfd.h: /* The value of the symbol. This really should be a union of a
bfd.h: union
bfd.h: union
bfdlink.h: /* A union of information depending upon the type. */
bfdlink.h: union
bfdlink.h: this field. This field is present in all of the union element
bfdlink.h: the union; this structure is a major space user in the
bfdlink.h: union
bfdlink.h: union
curses.h: union
db_cxx.h:// 4201: nameless struct/union
elf.h: union
elf.h: union
elf.h: union
elf.h: union
elf.h:typedef union
_G_config.h:typedef union
gcrypt.h: union
gcrypt.h: union
gcrypt.h: union
gmp-i386.h: union {
ieee754.h:union ieee754_float
ieee754.h:union ieee754_double
ieee754.h:union ieee854_long_double
ifaddrs.h: union
jpeglib.h: union {
ldap.h: union mod_vals_u {
ncurses.h: union
newt.h: union {
obstack.h: union
pi-file.h: union {
resolv.h: union {
signal.h:extern int sigqueue (__pid_t __pid, int __sig, __const union sigval __val)
stdlib.h:/* Lots of hair to allow traditional BSD use of `union wait'
stdlib.h: (__extension__ (((union { __typeof(status) __in; int __i; }) \
stdlib.h:/* This is the type of the argument to `wait'. The funky union
stdlib.h: causes redeclarations with either `int *' or `union wait *' to be
stdlib.h:typedef union
stdlib.h: union wait *__uptr;
stdlib.h: } __WAIT_STATUS __attribute__ ((__transparent_union__));
thread_db.h: union
thread_db.h: union
tiffio.h: union {
wchar.h: union
xf86drm.h:typedef union _drmVBlank {
Unions are useful when dealing with byte-level (low level) data.
One of my recent usage was on IP address modeling which looks like below :
// Composite structure for IP address storage
union
{
// IPv4 # 32-bit identifier
// Padded 12-bytes for IPv6 compatibility
union
{
struct
{
unsigned char _reserved[12];
unsigned char _IpBytes[4];
} _Raw;
struct
{
unsigned char _reserved[12];
unsigned char _o1;
unsigned char _o2;
unsigned char _o3;
unsigned char _o4;
} _Octet;
} _IPv4;
// IPv6 # 128-bit identifier
// Next generation internet addressing
union
{
struct
{
unsigned char _IpBytes[16];
} _Raw;
struct
{
unsigned short _w1;
unsigned short _w2;
unsigned short _w3;
unsigned short _w4;
unsigned short _w5;
unsigned short _w6;
unsigned short _w7;
unsigned short _w8;
} _Word;
} _IPv6;
} _IP;
Unions provide polymorphism in C.
An example when I've used a union:
class Vector
{
union
{
double _coord[3];
struct
{
double _x;
double _y;
double _z;
};
};
...
}
this allows me to access my data as an array or the elements.
I've used a union to have the different terms point to the same value. In image processing, whether I was working on columns or width or the size in the X direction, it can become confusing. To alleve this problem, I use a union so I know which descriptions go together.
union { // dimension from left to right // union for the left to right dimension
uint32_t m_width;
uint32_t m_sizeX;
uint32_t m_columns;
};
union { // dimension from top to bottom // union for the top to bottom dimension
uint32_t m_height;
uint32_t m_sizeY;
uint32_t m_rows;
};
The union keyword, while still used in C++031, is mostly a remnant of the C days. The most glaring issue is that it only works with POD1.
The idea of the union, however, is still present, and indeed the Boost libraries feature a union-like class:
boost::variant<std::string, Foo, Bar>
Which has most of the benefits of the union (if not all) and adds:
ability to correctly use non-POD types
static type safety
In practice, it has been demonstrated that it was equivalent to a combination of union + enum, and benchmarked that it was as fast (while boost::any is more of the realm of dynamic_cast, since it uses RTTI).
1Unions were upgraded in C++11 (unrestricted unions), and can now contain objects with destructors, although the user has to invoke the destructor manually (on the currently active union member). It's still much easier to use variants.
A brilliant usage of union is memory alignment, which I found in the PCL(Point Cloud Library) source code. The single data structure in the API can target two architectures: CPU with SSE support as well as the CPU without SSE support. For eg: the data structure for PointXYZ is
typedef union
{
float data[4];
struct
{
float x;
float y;
float z;
};
} PointXYZ;
The 3 floats are padded with an additional float for SSE alignment.
So for
PointXYZ point;
The user can either access point.data[0] or point.x (depending on the SSE support) for accessing say, the x coordinate.
More similar better usage details are on following link: PCL documentation PointT types
From the Wikipedia article on unions:
The primary usefulness of a union is
to conserve space, since it provides a
way of letting many different types be
stored in the same space. Unions also
provide crude polymorphism. However,
there is no checking of types, so it
is up to the programmer to be sure
that the proper fields are accessed in
different contexts. The relevant field
of a union variable is typically
determined by the state of other
variables, possibly in an enclosing
struct.
One common C programming idiom uses
unions to perform what C++ calls a
reinterpret_cast, by assigning to one
field of a union and reading from
another, as is done in code which
depends on the raw representation of
the values.
In the earliest days of C (e.g. as documented in 1974), all structures shared a common namespace for their members. Each member name was associated with a type and an offset; if "wd_woozle" was an "int" at offset 12, then given a pointer p of any structure type, p->wd_woozle would be equivalent to *(int*)(((char*)p)+12). The language required that all members of all structures types have unique names except that it explicitly allowed reuse of member names in cases where every struct where they were used treated them as a common initial sequence.
The fact that structure types could be used promiscuously made it possible to have structures behave as though they contained overlapping fields. For example, given definitions:
struct float1 { float f0;};
struct byte4 { char b0,b1,b2,b3; }; /* Unsigned didn't exist yet */
code could declare a structure of type "float1" and then use "members" b0...b3 to access the individual bytes therein. When the language was changed so that each structure would receive a separate namespace for its members, code which relied upon the ability to access things multiple ways would break. The values of separating out namespaces for different structure types was sufficient to require that such code be changed to accommodate it, but the value of such techniques was sufficient to justify extending the language to continue supporting it.
Code which had been written to exploit the ability to access the storage within a struct float1 as though it were a struct byte4 could be made to work in the new language by adding a declaration: union f1b4 { struct float1 ff; struct byte4 bb; };, declaring objects as type union f1b4; rather than struct float1, and replacing accesses to f0, b0, b1, etc. with ff.f0, bb.b0, bb.b1, etc. While there are better ways such code could have been supported, the union approach was at least somewhat workable, at least with C89-era interpretations of the aliasing rules.
Lets say you have n different types of configurations (just being a set of variables defining parameters). By using an enumeration of the configuration types, you can define a structure that has the ID of the configuration type, along with a union of all the different types of configurations.
This way, wherever you pass the configuration can use the ID to determine how to interpret the configuration data, but if the configurations were huge you would not be forced to have parallel structures for each potential type wasting space.
One recent boost on the, already elevated, importance of the unions has been given by the Strict Aliasing Rule introduced in recent version of C standard.
You can use unions do to type-punning without violating the C standard.
This program has unspecified behavior (because I have assumed that float and unsigned int have the same length) but not undefined behavior (see here).
#include <stdio.h>
union float_uint
{
float f;
unsigned int ui;
};
int main()
{
float v = 241;
union float_uint fui = {.f = v};
//May trigger UNSPECIFIED BEHAVIOR but not UNDEFINED BEHAVIOR
printf("Your IEEE 754 float sir: %08x\n", fui.ui);
//This is UNDEFINED BEHAVIOR as it violates the Strict Aliasing Rule
unsigned int* pp = (unsigned int*) &v;
printf("Your IEEE 754 float, again, sir: %08x\n", *pp);
return 0;
}
I would like to add one good practical example for using union - implementing formula calculator/interpreter or using some kind of it in computation(for example, you want to use modificable during run-time parts of your computing formulas - solving equation numerically - just for example).
So you may want to define numbers/constants of different types(integer, floating-point, even complex numbers) like this:
struct Number{
enum NumType{int32, float, double, complex}; NumType num_t;
union{int ival; float fval; double dval; ComplexNumber cmplx_val}
}
So you're saving memory and what is more important - you avoid any dynamic allocations for probably extreme quantity(if you use a lot of run-time defined numbers) of small objects(compared to implementations through class inheritance/polymorphism). But what's more interesting, you still can use power of C++ polymorphism(if you're fan of double dispatching, for example ;) with this type of struct. Just add "dummy" interface pointer to parent class of all number types as a field of this struct, pointing to this instance instead of/in addition to raw type, or use good old C function pointers.
struct NumberBase
{
virtual Add(NumberBase n);
...
}
struct NumberInt: Number
{
//implement methods assuming Number's union contains int
NumberBase Add(NumberBase n);
...
}
struct NumberDouble: Number
{
//implement methods assuming Number's union contains double
NumberBase Add(NumberBase n);
...
}
//e.t.c. for all number types/or use templates
struct Number: NumberBase{
union{int ival; float fval; double dval; ComplexNumber cmplx_val;}
NumberBase* num_t;
Set(int a)
{
ival=a;
//still kind of hack, hope it works because derived classes of Number dont add any fields
num_t = static_cast<NumberInt>(this);
}
}
so you can use polymorphism instead of type checks with switch(type) - with memory-efficient implementation(no dynamic allocation of small objects) - if you need it, of course.
From http://cplus.about.com/od/learningc/ss/lowlevel_9.htm:
The uses of union are few and far between. On most computers, the size
of a pointer and an int are usually the same- this is because both
usually fit into a register in the CPU. So if you want to do a quick
and dirty cast of a pointer to an int or the other way, declare a
union.
union intptr { int i; int * p; };
union intptr x; x.i = 1000;
/* puts 90 at location 1000 */
*(x.p)=90;
Another use of a union is in a command or message protocol where
different size messages are sent and received. Each message type will
hold different information but each will have a fixed part (probably a
struct) and a variable part bit. This is how you might implement it..
struct head { int id; int response; int size; }; struct msgstring50 { struct head fixed; char message[50]; } struct
struct msgstring80 { struct head fixed; char message[80]; }
struct msgint10 { struct head fixed; int message[10]; } struct
msgack { struct head fixed; int ok; } union messagetype {
struct msgstring50 m50; struct msgstring80 m80; struct msgint10
i10; struct msgack ack; }
In practice, although the unions are the same size, it makes sense to
only send the meaningful data and not wasted space. A msgack is just
16 bytes in size while a msgstring80 is 92 bytes. So when a
messagetype variable is initialized, it has its size field set
according to which type it is. This can then be used by other
functions to transfer the correct number of bytes.
Unions provide a way to manipulate different kind of data in a single area of storage without embedding any machine independent information in the program
They are analogous to variant records in pascal
As an example such as might be found in a compiler symbol table manager, suppose that a
constant may be an int, a float, or a character pointer. The value of a particular constant
must be stored in a variable of the proper type, yet it is most convenient for table management if the value occupies the same amount of storage and is stored in the same place regardless of its type. This is the purpose of a union - a single variable that can legitimately hold any of one of several types. The syntax is based on structures:
union u_tag {
int ival;
float fval;
char *sval;
} u;
The variable u will be large enough to hold the largest of the three types; the specific size is implementation-dependent. Any of these types may be assigned to u and then used in
expressions, so long as the usage is consistent