I wrote function, and for example I have the next line (this is only a part from the function):
up (St(d)::Dt::St(c)::[rp]) = Pr (Sym(d), Sym(c))
Pr, Sym, St, Dt - are all datatypes; d and c are strings.
When I run the function up, on arguments ([St("hello"),Dt,St("hi"),rp]), it's print val it =Pr(Sym(#), Sym(#)), instead of val it = Pr(Sym("hello"), Sym("hi")). Why? Thanks.
This has been answered multiple times already. The solution is as Adam Sh describes.
The same goes for lists and strings, just set the Control.Print.printLength.
Related
I am having error when uploading my website on heroku as having default values in function.
Until now I have used default value lots of times and they are in 50000 column javascript file and I cant really find all of them.
So I tried to find all functions with default values in sublime using regex.
I tried this regular expression.
function.*\(.*\=.*\)
But it's finding this kind of string(which is not default value function).
Function(e)) return Q.grep(t, function(t, i) { return !!e.call(t, i, t) !== n })
Sample function to be searched
var abc = function(x , y = 1)
function abc(x , y = 1)
Please help, I am new to regular expression and it's really difficult to find answer.
Try this regex function[a-zA-Z ]*\([a-zA-Z \,]+[a-zA-Z ]*[=]. It will match the functions with default parameters regardless of number of parameters. I hope this helped.
function\([^)]+\)
and take refernce from this:
Regular expression to find all function calls with parameters in VS2010
Try this one function[\s\w]*\([\w\s\d,]*[\w\s]+=[\w\d\s'",]*\). Default value may be string, and also function may have name:
var abc = function some_name (x , y = 1, z = "string", z_z) { var = 1
I work in Qt Creator (Community) 5.5.1. For example, I have
string="44° 36' 14.2\" N, 33° 30' 58.6\" E, 0m"
of QString. I know, that I must parse it, but i don't know how, because I have never faced with the problem like it. From our string I want to get some other smaller strings:
cgt = "44"; cmt = "36"; cst = "14.2"
cgg = "33"; cmg = "30"; csg = "58.6"
What must I do for working my programm how I said?
I need real code. Thanks.
The simplest way to start would be string.split(' ') - that would yield the list of the string components that were separated by the space character (' '). If you're sure the string will always be formatted exactly like this, you can first remove all the special characters (° and so on).
Then analyze the resulting QStringList. Again, if the format is fixed, you can check that the number of list items matches the expected number, and then get degrees as list[0], minutes as ``list[1]` and so on.
Another alternative would be to use QRegExp for parsing the string (splitting it into substrings based on regex), but I find it too complicated for use cases where split works just as well.
"I need code" is not the kind of question you should be asking, SO is about "gimme knowledge" not about "do my work" questions. A good question should demonstrate your effort to solve the problem, so people can tell you what you are doing wrong. Not only does your question lack any such effort, but you didn't expend any even when Devopia did half of the work for you. Keep that in mind for your future questions.
struct G {
double cgt, cmt, cst, cgg, cmg, csg;
};
G parse(QString s) {
QStringList list = s.split(QRegExp("[^0-9.]"), QString::SkipEmptyParts);
G g;
g.cgt = list.at(0).toDouble();
g.cmt = list.at(1).toDouble();
g.cst = list.at(2).toDouble();
g.cgg = list.at(3).toDouble();
g.cmg = list.at(4).toDouble();
g.csg = list.at(5).toDouble();
return g;
}
I have the following strings in a long string:
a=b=c=d;
a=b;
a=b=c=d=e=f;
I want to first search for above mentioned pattern (X=Y=...=Z) and then output like the following for each of the above mentioned strings:
a=d;
b=d;
c=d;
a=b;
a=f;
b=f;
c=f;
d=f;
e=f;
In general, I want all the variables to have an equal sign with the last variable on the extreme right of the string. Is there a way I can do it using regexprep in MATLAB. I am able to do it for a fixed length string, but for variable length, I have no idea how to achieve this. Any help is appreciated.
My attempt for the case of two equal signs is as follows:
funstr = regexprep(funstr, '([^;])+\s*=\s*+(\w+)+\s*=\s*([^;])+;', '$1 = $3; \n $2 = $3;\n');
Not a regexp but if you stick to Matlab you can make use of the cellfun function to avoid loop:
str = 'a=b=c=d=e=f;' ; %// input string
list = strsplit(str,'=') ;
strout = cellfun( #(a) [a,'=',list{end}] , list(1:end-1), 'uni', 0).' %'// Horchler simplification of the previous solution below
%// this does the same than above but more convoluted
%// strout = cellfun( #(a,b) cat(2,a,'=',b) , list(1:end-1) , repmat(list(end),1,length(list)-1) , 'uni',0 ).'
Will give you:
strout =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
Note: As Horchler rightly pointed out in comment, although the cellfun instruction allows to compact your code, it is just a disguised loop. Moreover, since it runs on cell, it is notoriously slow. You won't see the difference on such simple inputs, but keep this use when super performances are not a major concern.
Now if you like regex you must like black magic code. If all your strings are in a cell array from the start, there is a way to (over)abuse of the cellfun capabilities to obscure your code do it all in one line.
Consider:
strlist = {
'a=b=c=d;'
'a=b;'
'a=b=c=d=e=f;'
};
Then you can have all your substring with:
strout = cellfun( #(s)cellfun(#(a,b)cat(2,a,'=',b),s(1:end-1),repmat(s(end),1,length(s)-1),'uni',0).' , cellfun(#(s) strsplit(s,'=') , strlist , 'uni',0 ) ,'uni',0)
>> strout{:}
ans =
'a=d;'
'b=d;'
'c=d;'
ans =
'a=b;'
ans =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
This gives you a 3x1 cell array. One cell for each group of substring. If you want to concatenate them all then simply: strall = cat(2,strout{:});
I haven't had much experience w/ Matlab; but your problem can be solved by a simple string split function.
[parts, m] = strsplit( funstr, {' ', '='}, 'CollapseDelimiters', true )
Now, store the last part of parts; and iterate over parts until that:
len = length( parts )
for i = 1:len-1
print( strcat(parts(i), ' = ', parts(len)) )
end
I do not know what exactly is the print function in matlab. You can update that accordingly.
There isn't a single Regex that you can write that will cover all the cases. As posted on this answer:
https://stackoverflow.com/a/5019658/3393095
However, you have a few alternatives to achieve your final result:
You can get all the values in the line with regexp, pick the last value, then use a for loop iterating throughout the other values to generate the output. The regex to get the values would be this:
matchStr = regexp(str,'([^=;\s]*)','match')
If you want to use regexprep at any means, you should write a pattern generator and a replace expression generator, based on number of '=' in the input string, and pass these as parameters of your regexprep func.
You can forget about Regex and Split the input to generate the output looping throughout the values (similarly to alternative #1) .
I have a regular expression that parses a line# string from a log. That line# is then subjected to another regular expression to just extract the line#.
For example:
Part of this regex:
m = re.match(r"^(\d{4}-\d{2}-\d{2}\s*\d{2}:\d{2}:\d{2}),?(\d{3}),?(?:\s+\[(?:[^\]]+)\])+(?<=])(\s+?[A-Z]+\s+?)+(\s?[a-zA-Z0-9\.])+\s?(\((?:\s?\w)+\))\s?(\s?.)+", line)
Will match this:
(line 206)
Then this regex:
re.findall(r'\b\d+\b', linestr)
Gives me
['206']
In order to further process my information I need to have the line number as an integer and am lost for a solution as to how to do that.
You may try:
line_int = int(re.findall(r'\b\d+\b', linestr)[0])
or if you have more than one element in the list:
lines_int = [int(i) for i in re.findall(r'\b\d+\b', linestr)]
or even
lines_int = map(int, re.findall(r'(\b\d+\b)+', linestr))
I hope it helps -^.^-
Use int() to convert your list of one "string number" to an int:
myl = ['206']
int(myl[0])
206
if you have a list of these, you can conver them all to ints using list comprehension:
[int(i) for i in myl]
resulting in a list of ints.
You can hook this into your code as best fits, e.g.,
int(re.findall(r'\b\d+\b', linestr)[0])
int(re.findall(r'\b\d+\b', linestr)[0])
?
I am using vb.net to parse my own basic scripting language, sample below. I am a bit stuck trying to deal with the 2 separate types of nested brackets.
Assuming name = Sam
Assuming timeFormat = hh:mm:ss
Assuming time() is a function that takes a format string but
has a default value and returns a string.
Hello [[name]], the time is [[time(hh:mm:ss)]].
Result: Hello Sam, the time is 19:54:32.
The full time is [[time()]].
Result: The full time is 05/06/2011 19:54:32.
The time in the format of your choice is [[time([[timeFormat]])]].
Result: The time in the format of your choice is 19:54:32.
I could in theory change the syntax of the script completely but I would rather not. It is designed like this to enable strings without quotes because it will be included in an XML file and quotes in that context were getting messy and very prone to errors and readability issues. If this fails I could redesign using something other than quotes to mark out strings but I would rather use this method.
Preferably, unless there is some other way I am not aware of, I would like to do this using regex. I am aware that the standard regex is not really capable of this but I believe this is possible using MatchEvaluators in vb.net and some form of recursion based replacing. However I have not been able to get my head around it for the last day or so, possibly because it is hugely difficult, possibly because I am ill, or possibly because I am plain thick.
I do have the following regex for parts of it.
Detecting the parentheses: (\w*?)\((.*?)\)(?=[^\(+\)]*(\(|$))
Detecting the square brackets: \[\[(.*?)\]\](?=[^\[+\]]*(\[\[|$))
I would really appreciate some help with this as it is holding the rest of my project back at the moment. And sorry if I have babbled on too much or not put enough detail, this is my first question on here.
Here's a little sample which might help you iterate through several matches/groups/captures. I realize that I am posting C# code, but it would be easy for you to convert that into VB.Net
//these two may be passed in as parameters:
string tosearch;//the string you are searching through
string regex;//your pattern to match
//...
Match m;
CaptureCollection cc;
GroupCollection gc;
Regex r = new Regex(regex, RegexOptions.IgnoreCase);
m = r.Match(tosearch);
gc = m.Groups;
Debug.WriteLine("Number of groups found = " + gc.Count.ToString());
// Loop through each group.
for (int i = 0; i < gc.Count; i++)
{
cc = gc[i].Captures;
counter = cc.Count;
int grpnum = i + 1;
Debug.WriteLine("Scanning group: " + grpnum.ToString() );
// Print number of captures in this group.
Debug.WriteLine(" Captures count = " + counter.ToString());
if (cc.Count >= 1)
{
foreach (Capture cap in cc)
{
Debug.WriteLine(string.format(" Capture found: {0}", cap.ToString()));
}
}
}
Here is a slightly simplified version of the code I wrote for this. Thanks for the help everyone and sorry I forgot to post this before. If you have any questions or anything feel free to ask.
Function processString(ByVal scriptString As String)
' Functions
Dim pattern As String = "\[\[((\w+?)\((.*?)\))(?=[^\(+\)]*(\(|$))\]\]"
scriptString = Regex.Replace(scriptString, pattern, New MatchEvaluator(Function(match) processFunction(match)))
' Variables
pattern = "\[\[([A-Za-z0-9+_]+)\]\]"
scriptString = Regex.Replace(scriptString, pattern, New MatchEvaluator(Function(match) processVariable(match)))
Return scriptString
End Function
Function processFunction(ByVal match As Match)
Dim nameString As String = match.Groups(2).Value
Dim paramString As String = match.Groups(3).Value
paramString = processString(paramString)
Select Case nameString
Case "time"
Return getLocalValueTime(paramString)
Case "math"
Return getLocalValueMath(paramString)
End Select
Return ""
End Function
Function processVariable(ByVal match As Match)
Try
Return moduleDictionary("properties")("vars")(match.Groups(1).Value)
Catch ex As Exception
End Try
End Function