I am trying to use regular expressions to match certain lines in a file, but I am having some trouble.
The file contains text like this:
Mario, 123456789
Luigi, 234-567-890
Nancy, 345 5666 77533
Bowser, 348759823745908732589
Peach, 534785
Daisy, 123-456-7890
I'm trying to match just the numbers as either XXX-XXX-XXX or XXX XXX XXX pattern.
I've tried a few different ways, but it always expects something I don't want it to or it tell me everything is false.
I'm using PowerShell to do this.
At first I tried:
{$match = $i -match "\d{3}\-\d{3}\-\d{3}|\d{3}\ \d{3}\ \d{3}"
Write-Host $match}
But when I do that it matches the long strong of numbers and XXX-XXX-XXXXX.
I read something saying that n would match the exact quantity, so I tried that...
{$match = $i -match "\d{n3}\-\d{n3}\-\d{n3}|\d{n3}\ \d{n3}\ \{n3}"
Write-Host $match}
That made everything false...
So I tried
{$match = $i -match "\d\n{3}\-\d\n{3}\-\d\n{3}|\d\n{3}\ \d\n{3}\ \d\n{3}"
I also tried the lazy quantifier, ?:
{$match = $i -match "\d{3?}\-\d{3?}\-\d{3?}|\d{3?}\ \{3?}\ \{3?}"
Write-Host $match}
Still false...
The final thing I tried was this...
{$match = $i -match "\d[0-9\{3\}\-\d[0-9]\{3\}\-\d[0-9]{3\}|\d[0-9]\{3\}\ \d[0-9]\{3}\ \d[0-9]\{3\}"<br>
Write-Host $match}
Still no luck...
The following pattern gives two matches:
Get-Content .\test.txt | Where-Object {$_ -match '\d{3}[-|\s]\d{3}[-|\s]\d{3}'}
Luigi, 234-567-890
Daisy,
123-456-7890
If you want to exclude the last match, add the '$' anchor (represents the end of the string:
Get-Content .\test.txt | Where-Object {$_ -match '\d{3}[-|\s]\d{3}[-|\s]\d{3}$'}
Luigi, 234-567-890
If you want to be very specific and match lines from start to end (use the ^ anchor, denotes the start of the string):
Get-Content .\test.txt | Where-Object {$_ -match '^\w+,\s+\d{3}[-|\s]\d{3}[-|\s]\d{3}$'}
Luigi, 234-567-890
Your first answer is the closest. The {3} matches exactly 3 characters. I think the n you saw was supposed to represent any number, not an actual n character. The reason it matches the long strings is that you only specified that the match must find 3 digits, dash or space, 3 digits, dash or space, then 3 more digits. You did not specify that it doesn't count if there are more digits after that.
To not match when there is a number after, you can use a negative lookahead.
(\d{3}-\d{3}-\d{3}|\d{3}\ \d{3}\ \d{3})(?!\d)
Alternatively, if you want to only match at the end of the line, possibly with trailing space
(\d{3}-\d{3}-\d{3}|\d{3}\ \d{3}\ \d{3})\s*$
As Gideon said, your first is the best place to start.
"\b\d{3}\-\d{3}\-\d{3}\b|\b\d{3}\ \d{3}\ \d{3}\b"
The \b special character added before and after each statement is a word boundary - basically a space or newline or punctuation like a period or comma. This ensures that 9999 doesn't match, but 999. does.
Try this:
/(\d+[- ])+\d+/
It's better not to have so rigid regular expressions, unless you are absolutely sure there that your input will not change.
So this regex matches at least a digit, then greedily searches for more digits followed by a space or a dash. This is also repeated as much as possible then followed by at least another digit.
When manipulating data in PowerShell, it usually is a good idea to create objects representing the data (after all, PowerShell is all about objects). Filtering based on object properties is usually easier and more robust. Your problem is a good example.
Here is what we are after:
the persons: $persons
where: where
the number of that person: $_.number
matches: -match
the pattern
starting with three digits: ^\d{3}
followed by three digits between dashes or spaces: (-\d{3}-|\ \d{3}\ )
ending on three digits: \d{3}$
Below is the entire script:
$persons = import-csv -Header "name", "number" -delimiter "," data.csv
$persons | where {$_.number -match "^\d{3}(\-\d{3}\-|\ \d{3}\ )\d{3}$"}
You can also use Select-String:
Select-String '(\d{3}[ -]){2}\d{3}$' .\file.txt | % {$_.Line}
Related
I need to strip out a UNC fqdn name down to just the name or IP depending on the input.
My examples would be
\\tom.overflow.corp.com
\\123.43.234.23.overflow.corp.com
I want to end up with just tom or 123.43.234.23
I have the following code in my array which is striping out the domain name perfect, but Im still left with \\tom
-Split '\.(?!\d)')[0]
Your regex succeeds in splitting off the tokens of interest in principle, but it doesn't account for the leading \\ in the input strings.
You can use regex alternation (|) to include the leading \\ at the start as an additional -split separator.
Given that matching a separator at the very start of the input creates an empty element with index 0, you then need to access index 1 to get the substring of interest.
In short: The regex passed to -split should be '^\\\\|\.(?!\d)' instead of '\.(?!\d)', and the index used to access the resulting array should be [1] instead of [0]:
'\\tom.overflow.corp.com', '\\123.43.234.23.overflow.corp.com' |
ForEach-Object { ($_ -Split '^\\\\|\.(?!\d)')[1] }
The above yields:
tom
123.43.234.23
Alternatively, you could remove the leading \\ in a separate step, using -replace:
'\\tom.overflow.corp.com', '\\123.43.234.23.overflow.corp.com' |
ForEach-Object { ($_ -Split '\.(?!\d)')[0] -replace '^\\\\' }
Yet another alternative is to use a single -replace operation, which does not require a ForEach-Object call (doesn't require explicit iteration):
'\\tom.overflow.corp.com', '\\123.43.234.23.overflow.corp.com' -replace
'?(x) ^\\\\ (.+?) \.\D .+', '$1'
Inline option (?x) (IgnoreWhiteSpace) allows you to make regexes more readable with insignificant whitespace: any unescaped whitespace can be used for visual formatting.
^\\\\ matches the \\ (escaped with \) at the start (^) of each string.
(.+?) matches one or more characters lazily.
\.\D matches a literal . followed by something other than a digit (\d matches a digit, \D is the negation of that).
.+ matches one or more remaining characters, i.e., the rest of the input.
$1 as the replacement operand refers to what the 1st capture group ((...)) in the regex matched, and, given that the regex was designed to consume the entire string, replaces it with just that.
I'm stealing Lee_Daileys $InSTuff
but appending a RegEx I used recently
$InStuff = -split #'
\\tom.overflow.corp.com
\\123.43.234.23.overflow.corp.com
'#
$InStuff |ForEach-Object {($_.Trim('\\') -split '\.(?!\d{1,3}(\.|$))')[0]}
Sample Output:
tom
123.43.234.23
As you can see here on RegEx101 the dots between the numbers are not matched
The Select-String function uses regex and populates a MatchInfo object with the matches (which can then be queried).
The regex "(\.?\d+)+|\w+" works for your particular example.
"\\tom.overflow.corp.com", "\\123.43.234.23.overflow.corp.com" |
Select-String "(\.?\d+)+|\w+" | % { $_.Matches.Value }
while this is NOT regex, it does work. [grin] i suspect that if you have a really large number of such items, then you will want a regex. they do tend to be faster than simple text operators.
this will get rid of the leading \\ and then replace the domain name with .
# fake reading in a text file
# in real life, use Get-Content
$InStuff = -split #'
\\tom.overflow.corp.com
\\123.43.234.23.overflow.corp.com
'#
$DomainName = '.overflow.corp.com'
$InStuff.ForEach({
$_.TrimStart('\\').Replace($DomainName, '')
})
output ...
tom
123.43.234.23
So Im creating an array of all the versions of a particular pkg in a directory
What I want to do is strip out all the characters except the version numbers
The first array has info such as
GoogleChrome.45.45.34.nupkg
GoogleChrome.34.28.34.nupkg
So the output I need is
45.45.34
34.28.34
$dirList = Get-ChildItem $sourceDir -Recurse -Include "*.nupkg" -Exclude
$pkgExclude |
Foreach-Object {$_.Name}
$reg = '.*[0-9]*.nupkg'
$appName ='GoogleChrome'
$ouText = $dirList | Select-String $appName$reg -AllMatches | % {
$_.Matches.Value }
$ouText
$verReg='(\d+)(.)(?!nupkg)'
The last regex matches the pattern of what I want to keep but I cant figure out how to extract what I dont need.
You do not need to post-process matches if you apply the right pattern from the start.
In order to extract . separated digits in between GoogleChrome. and .nupkg you may use
Select-String '(?<=GoogleChrome\.)[\d.]+(?=\.nupkg)' -AllMatches
See the regex demo
Details
(?<=GoogleChrome\.) - the location should be preceded with GoogleChrome. substring
[\d.]+ - one or more digits or/and .
(?=\.nupkg) - there must be .nupkg immediately to the right of the current location.
If .nupkg should not be relied upon, use
Select-String '(?<=GoogleChrome\.)\d+(?:\.\d+)+' -AllMatches
Here, \d+(?:\.\d+)+ will match 1 or more digits followed with 1 or more occurrences of a . and 1+ digits only if preceded with GoogleChrome..
(\d+.?)+(?!nupkg)
this would give you desired output in the match, check the regex demo
Im trying to get list of versions from my custom attribute in powershell script. Atrribute looks like this:
[assembly: CompatibleVersions("1.7.1.0","1.7.1.1","1.2.2.3")]
And I end up with regex like this but it does'nt work at all:
'\(\"([^\",?]*)\"+\)'
You should do this as a two-step process: First you parse out the CompatibleVersions attribute, and then you split out those version numbers. Otherwise you will have difficulties finding the version numbers individually without likely finding otheer version-like numbers.
$s = '[assembly: CompatibleVersions("1.7.1.0","1.7.1.1","1.2.2.3")]'
$versions = ($s | Select-String -Pattern 'CompatibleVersions\(([^)]+)\)' | % { $_.Matches }).Groups[1].Value
$versions.Split(',') | % { $_.Trim('"') } | Write-Host
# 1.7.1.0
# 1.7.1.1
# 1.2.2.3
Start by grabbing the parentheses pair and everything inside:
$string = '[assembly: CompatibleVersions("1.7.1.0","1.7.1.1","1.2.2.3")]'
if($string -match '\(([^)]+)\)'){
# Remove the parentheses themselves, split by comma and then trim the "
$versionList = $Matches[0].Trim("()") -split ',' |ForEach-Object Trim '"'
}
You may use
$s | select-string -pattern "\d+(?:\.\d+)+" -AllMatches | Foreach {$_.Matches} | ForEach-Object {$_.Value}
The \d+(?:\.\d+)+ pattern will match:
\d+ - 1 or more digits
(?:\.\d+)+ - 1 or more sequences of a . and 1+ digits.
See the regex demo on RegexStorm.
'"([.\d]+)"' will match any substring composed of dots and digits (\d) and comprised into double quotes (")
Try it here
A number between .. can be 0, but cannot be 00, 01 or similar.
Pay attention to the starting [
This is a regex for the check:
^\[assembly: CompatibleVersions\("(?:[1-9]\d*|0)(?:\.(?:[1-9]\d*|0)){3}"(?:,"(?:[1-9]\d*|0)(?:\.(?:[1-9]\d*|0)){3}")*\)]$
Here is the regex with tests.
But if you are reading a list, you should use instead:
^\[assembly: CompatibleVersions\("((?:[1-9]\d*|0)(?:\.(?:[1-9]\d*|0)){3}"(?:,"(?:[1-9]\d*|0)(?:\.(?:[1-9]\d*|0)){3}")*)\)]$
By it you will extract the "...","..."... consequence from the inner parenthesis.
After that split the result string by '","' into a list and remove last " from the last element and the first " from the first element. Now you have list of correct versions Strings.
Alas, regex cannot create a list without split() function.
I am working on a script that will generate AD usernames based off of a csv file. Right now I have the following line working.
Select-Object #{n=’Username’;e={$_.FirstName.ToLower() + $_.LastName.ToLower() -replace "[^a-zA-Z]" }}
As of right now this takes the name and combines it into a AD friendly name. However I need to name to be shorted to no more than 20 characters. I have tried a few different methods to shorten the username but I haven't had any luck.
Any ideas on how I can get the username shorted?
Probably the most elegant approach is to use a positive lookbehind in your replacement:
... -replace '(?<=^.{20}).*'
This expression matches the remainder of the string only if it is preceded by 20 characters at the beginning of the string (^.{20}).
Another option would be a replacement with a capturing group on the first 20 characters:
... -replace '^(.{20}).*', '$1'
This captures at most 20 characters at the beginning of the string and replaces the whole string with just the captured group ($1).
$str[0..19] -join ''
e.g.
PS C:\> 'ab'[0..19]
ab
PS C:\> 'abcdefghijklmnopqrstuvwxyz'[0..19] -join ''
abcdefghijklmnopqrst
Which I would try in your line as:
Select-Object #{n=’Username’;e={(($_.FirstName + $_.LastName) -replace "[^a-z]").ToLower()[0..19] -join '' }}
([a-z] because PowerShell regex matches are case in-senstive, and moving .ToLower() so you only need to call it once).
And if you are using Strict-Mode, then why not check the length to avoid going outside the bounds of the array with the delightful:
$str[0..[math]::Min($str.Length, 19)] -join ''
To truncate a string in PowerShell, you can use the .NET String::Substring method. The following line will return the first $targetLength characters of $str, or the whole string if $str is shorter than that.
if ($str.Length -gt $targetLength) { $str.Substring(0, $targetLength) } else { $str }
If you prefer a regex solution, the following works (thanks to #PetSerAl)
$str -replace "(?<=.{$targetLength}).*"
A quick measurement shows the regex method to be about 70% slower than the substring method (942ms versus 557ms on a 200,000 line logfile)
I'm trying to parse some very badly delimited files and ultimately change them to a CSV. I'm looking to match on number, whitespace, and then letter, and replace the whitespace with a comma.
For example If I had the line '08:34:45 home' I'd like it to recognize the '5 h' and make it '08:34:45,home'. I understand why what I have below isn't working correctly, but can someone explain how to tell Powershell that I want to keep the \d and the \D?
Get-Content -path C:\file.txt |
ForEach-Object {$_ -replace "(\d\s\D)",','}
What you put in parentheses ( ) is captured by the regular expression, and you can access it with $1 for the first set, $2 for the second set, etc.
so you could try two capture groups:
$_ -replace '(\d)\s(\D)', '$1,$2'
See also: http://www.powershelladmin.com/wiki/Powershell_regular_expressions#Example_-_Replace_With_Captures for more details.