OpenMP: parallel for(i;...) and i value - c++

Question

I have a following parallel snippet:
#include <omp.h>
#include "stdio.h"
int main()
{
omp_set_num_threads(4);
int i;
#pragma omp parallel private(i)
{
#pragma omp for
for(i = 0;i < 10; i++) {
printf("A %d: %d\n", omp_get_thread_num(),i);
}
#pragma omp critical
printf("i %d: %d\n", omp_get_thread_num(), i );
}
}
I thought that after the loop, each thread will have i equal to i last value in the thread's loop. My desired output would be:
A 0: 0
A 0: 1
A 0: 2
A 3: 9
A 2: 6
A 2: 7
A 2: 8
A 1: 3
A 1: 4
A 1: 5
i 0: 3
i 3: 10
i 2: 9
i 1: 6
whereas what I get is:
A 0: 0
A 0: 1
A 0: 2
A 3: 9
A 2: 6
A 2: 7
A 2: 8
A 1: 3
A 1: 4
A 1: 5
i 0: -1217085452
i 3: -1217085452
i 2: -1217085452
i 1: -1217085452
How to make i to hold last iteration's value? lastprivate(i) makes i = 10 for all threads, and that is not what I want.

Answer 1

It turns out you can't. OpenMP alters program semantics.
Parallel for loops are rewritten by the compiler according to well-defined set of rules.
This also implies you cannot break from, return from such a loop. You can also not directly manipulate the loop variable. The loop condition can not call random functions or do any conditional expression, in short: a omp parallel for loop is not a for loop
#include <omp.h>
#include "stdio.h"
int main()
{
omp_set_num_threads(4);
#pragma omp parallel
{
int i;
#pragma omp for
for(i = 0;i < 10; i++) {
printf("A %d: %d\n", omp_get_thread_num(),i);
}
#pragma omp critical
printf("i %d: %d\n", omp_get_thread_num(), i );
}
}

Answer 2

Thanks to sehe`s post, I figure out the following dirty trick that solves the problem
int i, last_i;
#pragma omp parallel private(i)
{
#pragma omp for
for(i = 0;i < 10; i++) {
printf("A %d: %d\n", omp_get_thread_num(),i);
last_i = i;
}
#pragma omp critical
printf("i %d: %d\n", omp_get_thread_num(), last_i );
}
}