How to read from std::cin until the end of the stream? - c++

My problem is, that I want to read the input from std::cin but don't know how long the input is. Also I have to char and can't use std::string.
There are two ways I have to handle:
a) The user inputs text and when he hits [ENTER] the program stops reading.
b) The user redirects std::cin to a file (like .\a.oput < file) which can hold multiple lines.
Edit: Just noticed that std::cin.eof() is always false also in the case of reading form a file.
For a) I could read until \n occures. For b) Edit: No (I could read until std::cin.eof() occures.)
But when I don't know whether I'm getting an a) or a b) problem, how can I break the reading process?
This is what I have for a) ...
char buffer = ' ';
while(std::cin >> std::noskipws >> buffer && buffer != '\n')
{
// do some stuff with buffer
}
... and b)
char buffer = ' ';
while(std::cin >> std::noskipws >> buffer)
{
// do some stuff with buffer
}
Also I know there is std::cin.tellg() to get the current position in the stream.
Edit: So it seems like in case of the file the input streams gets terminated, in the way that std::cin >> std::noskipws >> buffer gets false.
What the code above does for a):
It waits for the user to make an input and press [ENTER]
Then it loops through every char entered by the user on the last line.
Then it waits again for the user to make an input and press [ENTER]
Infinite-waiting-processing-loop
So how do I do it?

You could require the input to always end EOF (meaning from commmand line requiring ^D to be pressed) and then use the process for b as always. This would then enable multiline input from cmdline as well

You could use the (old) getline function, which takes a pointer to a char array and can use a delimiter. But you wont be able to ensure that in every case it will read to the eof (as the char buffer might be too small), but using a char-array and not paying attention to the size of it is a very dangerous (and from the point of security catastrophic) thing anyways as it can lead to buffer-overflows which can be easily exploited.
This code should enable you to extract line by line from the input:
char buffer[256];
while(getline(buffer,256,'\n')) { //get a line
/* do something with the line */
}
This to read a maximum amount of chars:
char buffer[256];
while(getline(buffer,256)) {//get a maximum amount out of the input
/* do something with the line */
}

Related

How does cin accomplish waiting for user input? [duplicate]

I ran this code
char c;
cin >> c;
cout << c;
cin >> c;
cout << c;
and wrote to the console ab, the pressed enter. So I got ab at the next line. But I can't understand how it works. Before pressing enter the program doesn't read anything, right? After pressing, it reads a, save it to char c, then reads char c, writes a to the console. It's OK. But how can it read b being at the second line? It isn't b at the second line
cin is the standard input stream. The streaming nature is vital in-depth for understanding C++ I/O.
By default, doing cin >> x means:
From the point currently in the stream, skip any whitespace which might be there and then keep reading as long as possible & necessary to get a valid representation of x.
Let us disregard for a moment the fact that input comes from the keyboard. The content of the stream at start is a b LINEFEED. You execute cin >> c, which will read the first character, a, from input. That's enough to fill in c, so reading stops. The cin stream now contains b LINEFEED. The variable c is then written to standard output.
Another cin >> c comes next, so one more character is read (this time b). Again, one character is enough, so reading ends and the stream contents is just LINEFEED. The b is then sent to the standard output stream.
The fact that the standard input and standard output streams are normally tied to the console does not affect their internal working in any way. cin doesn't "forget" what was in it just because some output appeared on the screen in the meantime. In particular, cin reads the keyboard, not "characters on the console." It just so happens that pressing keys both echoes them on the console and feeds them to cin.
So the fact that your program has output the character a in the meantime has no effect on the contents of the cin stream.
cin is a blocked input. Whatever comes from the keyboard is stored in a buffer. When you press enter the system passes the buffer to the application code (std::cin code). Operator >> will decide how much to read from that buffer - one char, string, int, float etc. Depends on the type of the operand.
cin and cout are buffered streams. Both 'a' and 'b' goes into the input buffer when you press enter. The '>>' operator reads from that buffer (one char at a time in your case). The '<<' writes to the output buffer. The only thing that should surprise you is that you see "ab" on output without printing "\n" (the latter symbol should flush the contents of the output buffer to the terminal).In short, both cin and cout are buffers. Input and output operators work with those buffers. Newline symbol initiates the data transfer from real input to input buffer and from output buffer to the real output. There more thing about I/O you can learn.
Basically, cin has an overload for data type char to only grab 1 character from the input stream, so your program basically goes like this :
char c;
cin >> c; // reads 'a' from the input stream (input stream contains 'ab\n')
cout << c; // prints 'a'
cin >> c; // changes c to 'b' (reads 'b')
cout << c; // prints 'b'

Pause Function it is Looping Forever

I am trying to implement a pause function in C++, but it is looping forever.
I am using macOS but I am trying to create a pause function that will work in any system... I believe my cin >> is not capturing '\n' or '\r' from the keyboard and it is looping forever.
void Transferencia::pause() {
char enter = 0;
while(enter != '\n' && enter != '\r') {
cout << "(Press Enter to Continue...) ";
cin >> enter;
}
cin.clear();
}
I want to pause my program until user press the key "enter".
But even when I press "enter/return" it keeps looping...
At very first: enter != '\n' || enter != '\r' is a tautology: Even if enter does equal one of the characters it cannot be equal to the other one. So one of the tests must be true... You actually want to stay in the loop when enter is unequal to both values.
std::cin >> ... won't read data before you press enter, but it will discard the newlines (actually, all whitespace). So it would suffice just to read one single character right without loop (the loop again would get an endless one); solely: If the user doesn't enter anything at all before pressing 'enter' key, there's no character to read from std::cin and we'd still be waiting.
What you can do is reading entire lines:
std::string s;
std::getline(std::cin, s);
That will accept empty lines as well, so does exactly what you want (note: no loop around!).
Edit (stolen from the comments; thanks, Thomas Matthews): An even more elegant way is
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
as it won't create any additional resources that would be discarded afterwards anyway (the std::string object!).
Edit 2:
Depending on type of last input operation, there might still be a newline (or even further data) buffered, e. g. after int n; std::cin >> n;. In this case, you need to skip the input yet buffered. So you would need ignore twice.
However, if the last input operation consumed the newline already (e. g. std::getline – or if there wasn't any preceding input operation at all), then this would lead to user having to press enter twice. So you need to detect what's has been going on before.
std::cin.rdbuf().in_avail() allows you to detect how many characters are yet buffered. So you can have:
if(std::cin.rdbuf().in_avail())
{
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
std::cout << "press enter" << std::endl;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
On some systems (including mine), though, in_avail can return 0 even though a newline is yet buffered! std::cin.sync_with_stdio(false); can fix the issue; you should execute it before very first input operation. Hopefully, you don't use C++ (streams) and C (scanf, printf, etc) IO intermixed then...
The easiest way to do this is with getline().
cin >> ignores whitespace, newline characters included. getline() will read an entire line, newline character included. However, it does not copy the newline character to the output string. If the user simply hit the enter key and nothing else, you'd end up with an empty string.
So, to get your desired behavior, you would construct your loop like this:
string line;
while(true)
{
cout << "(Press Enter to Continue...) " << endl;
getline(cin, line);
if(line == "")
break;
}
#Aconcagua has answered your question but this is what I want to add in.
Normally, for handling some specific kind of event in computer, we usually follow event-driven paradigm or event-callback.
The idea is there is an event loop that waits for a new event coming into the system. This case, keyboard is an event, the event loop then calls event-callback. What event-callback does is it compares the value of input with some conditions then do some other tasks (it might change some state of the program or notify users).
The idea is keep CPU busy by either 2 ways.
event-driven : do other tasks while waiting for a new event
multithreading: multiple threads in the system. This approach has the disadvantage is at data-race
Have fun

Safe operation to clear the empty input buffer in C++

I was looking at this post and few other. What happens if ignore() is called when input buffer is already empty? I observed in below code that if ignore() is called when buffer is already empty, it will not work and waits for some character to be entered first.
int main(void)
{
char myStr[50];
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
cout<<"Enter the String\n";
cin>>myStr;
// After reading remove unwanted characters from the buffer
// so that next read is not affected
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
}
cin.clear() after ignore() creates further problem if the buffer is already empty it looks. I guess clearing the buffer after cin() is safe. But what if I do not know the status of input buffer and I clear even when it is already empty? Do I have to check first if input buffer is empty using cin.fail() or something similar if any?
Secondly, cin itself may not be safe as space is not allowed. So getline() is suggested by some SO posts as given here. But does getline() also requires clearing input buffer or is it safe always? Does the code below work without any trouble (it works now, but now sure if it is safe code).
void getString(string& str)
{
do
{
cout<<"Enter the String: ";
getline(std::cin,str);
} while (str.empty());
}
Other SO references:
Ref 3
Breaking down main:
int main(void)
{
char myStr[50];
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
A bad idea, but you noticed that already. There must be a newline in the stream or you sit and wait for one. If the user's not expecting this behaviour you can expect to wait a long time and have a frustrated user. That's a bad scene.
cout<<"Enter the String\n";
cin>>myStr;
Also a bad idea, but for a different reason. >> doesn't know it should stop at 49 characters to prevent overflowing myStr. Bad things happen at that 50th character.
// After reading remove unwanted characters from the buffer
// so that next read is not affected
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
This one is safe. >> won't consume the newline, or any other whitespace and in order for the stream to hand over the data from the console someone must have hit enter and provided a newline.
}
A general rule of thumb is to not ignore unless you have reason to ignore, and if you have reason, ignore right away. Do not wait until before the next stream operation to ignore, be cause what if this operation is the first? Or the previous operation did not leave anything to ignore?. ignore after the operation that left what you want ignored in the stream. So
std::string getfirstword()
{
std::string firstword;
if (std::cin >> firstword)
{
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
return firstword;
}
return ""; // or perhaps
// throw std::runtime_error("There is no first word.");
// is more appropriate. Your call.
}
is good, but
std::string getfirstword()
{
cin.ignore (std::numeric_limits<std::streamsize>::max(),'\n');
std::string firstword;
if (std::cin >> firstword)
{
return firstword;
}
return "";
}
is an offence in the eyes of all that is holy. Don't do it.
As for getline, it gets a line. All of it up to the end of the file or the end of the line, whichever comes first. It also eats the end of the line for you so you don't have to worry about a stray newline harshing your mellow later.
If you only want part of the line, you will have to break it down. Typical usage for this is something along the lines of
std::string line;
if (std::getline(std::cin,line))
{
std::istringstream istr(line);
std::string firstword;
if (istr >> firstword)
{
// do something with firstword
}
else
{
// there is no firstword. Do something else.
}
}
getline reads everything up to and including the newline. It's no longer in the stream, so I'd consider this safe. You don't have to worry about garbage hanging around on the end of the line. You may have to worry about the next line, though.

Simple C++ not reading EOF

I'm having a hard time understanding why while (cin.get(Ch)) doesn't see the EOF. I read in a text file with 3 words, and when I debug my WordCount is at 3 (just what I hoped for). Then it goes back to the while loop and gets stuck. Ch then has no value. I thought that after the newline it would read the EOF and break out. I am not allowed to use <fstream>, I have to use redirection in DOS. Thank you so much.
#include <iostream>
using namespace std;
int main()
{
char Ch = ' ';
int WordCount = 0;
int LetterCount = 0;
cout << "(Reading file...)" << endl;
while (cin.get(Ch))
{
if ((Ch == '\n') || (Ch == ' '))
{
++WordCount;
LetterCount = 0;
}
else
++LetterCount;
}
cout << "Number of words => " << WordCount << endl;
return 0;
}
while (cin >> Ch)
{ // we get in here if, and only if, the >> was successful
if ((Ch == '\n') || (Ch == ' '))
{
++WordCount;
LetterCount = 0;
}
else
++LetterCount;
}
That's the safe, and common, way to rewrite your code safely and with minimal changes.
(Your code is unusual, trying to scan all characters and count whitespace and newlines. I'll give a more general answer to a slightly different question - how to read in all the words.)
The safest way to check if a stream is finished if if(stream). Beware of if(stream.good()) - it doesn't always work as expected and will sometimes quit too early. The last >> into a char will not take us to EOF, but the last >> into an int or string will take us to EOF. This inconsistency can be confusing. Therefore, it is not correct to use good(), or any other test that tests EOF.
string word;
while(cin >> word) {
++word_count;
}
There is an important difference between if(cin) and if(cin.good()). The former is the operator bool conversion. Usually, in this context, you want to test:
"did the last extraction operation succeed or fail?"
This is not the same as:
"are we now at EOF?"
After the last word has been read by cin >> word, the string is at EOF. But the word is still valid and contains the last word.
TLDR: The eof bit is not important. The bad bit is. This tells us that the last extraction was a failure.
The Counting
The program counts newline and space characters as words. In your file contents "this if fun!" I see two spaces and no newline. This is consistent with the observed output indicating two words.
Have you tried looking at your file with a hex editor or something similar to be sure of the exact contents?
You could also change your program to count one more word if the last character read in the loop was a letter. This way you don't have to have newline terminated input files.
Loop Termination
I have no explanation for your loop termination issues. The while-condition looks fine to me. istream::get(char&) returns a stream reference. In a while-condition, depending on the C++ level your compiler implements, operator bool or operator void* will be applied to the reference to indicate if further reading is possible.
Idiom
The standard idiom for reading from a stream is
char c = 0;
while( cin >> c )
process(c);
I do not deviate from it without serious reason.
you input file is
this is fun!{EOF}
two spaces make WordCount increase to 2
and then EOF, exit loop! if you add a new line, you input file is
this is fun!\n{EOF}
I took your program loaded it in to visual studio 2013, changed cin to an fstream object that opened a file called stuff.txt which contains the exact characters "This is fun!/n/r" and the program worked. As previous answers have indicated, be careful because if there's not a /n at the end of the text the program will miss the last word. However, I wasn't able to replicate the application hanging in an infinite loop. The code as written looks correct to me.
cin.get(char) returns a reference to an istream object which then has it's operator bool() called which returns false when any of the error bits are set. There are some better ways to write this code to deal with other error conditions... but this code works for me.
In your case, the correct way to bail out of the loop is:
while (cin.good()) {
char Ch = cin.get();
if (cin.good()) {
// do something with Ch
}
}
That said, there are probably better ways to do what you're trying to do.

Why does this program work?

I recently wrote a program that takes inputted char data, tests if it is acceptable (a-z, # marks the end of the input) and puts it in a stack which then tests to see if it's a palindrome. I was expecting to enter it one char by a time, but if I enter a string ended by pound it.. works. Here is some of the relevant code:
char buffer;
bool pound_test = false;
bool palindrome = false;
bool keep_going = true;
stack<char> stack1, stack2, stack3;
string str = "";
cout << "Please enter a string, then end it with the pound sign. " << endl;
while(pound_test == false) {
cin >> buffer;
if((buffer >= 97) && (buffer <= 122))
{
stack1.push(buffer);
stack2.push(buffer);
str += buffer;
}
if((buffer >= 65) && (buffer <= 90)) {
buffer = buffer + 32;
stack1.push(buffer);
stack2.push(buffer);
str += buffer;
}
if(buffer == '#')
pound_test = true;
}
So, when the user enters one long string, like "racecar#" and presses enter, the program properly puts it into the stack. My question is simply: why? Wouldn't the data have to be inputted one char at a time for it to work properly, because the cin is in the loop itself, and the loop has to repeat to enter multiple chars into the stack, right? Thanks!
Edit: Thanks for the answers/comments everyone! I'm really impressed by the quick and kind replies. I'm certainty going to use this site again.
Console input (via the cin std::istream object) in most systems is line buffered. So when you call cin::operator>> for a single character, the function does not in fact return until you press newline (because the underlying I/O system does not make data available to cin until then). Any data entered up-to and including the <newline> will be buffered and subsequent calls to cin::operator>> will be serviced from the buffer until it is exhausted.
In this case cin >> buffer, where buffer is of type char will indeed get a single character, but before that the console buffered an entire line and will use it to satisfy subsequent console input operations.
If you step through your code in your debugger the operation may be clearer to you.
The "system" (OS, library, whatever — depends on the implementation) ate the string of data coming from input, but your program read it char by char.
While all the answers about os buffering are true, I think the confusion can be traced to cin's operator >> (char); because C++ can overload methods based on their argument types, the char version of operator >> is only assigning one character at a time, even though the whole string is buffered. I believe you're thinking that operator >> should try to put the whole string into your character; but since it "knows" you're reading one character at a time, it only assigns one character at a time. I'm not sure if this is specified behavior for cin or not, but that seems to be what's happening.
The cin operator reads from the standard input stream (if not configured otherwise). The stdin works as follows: you type and when you press Enter, it is sent to stdin and therefore cin reads the whole string up to the moment when you pressed Enter.
If you wish to read char by char, you should use getchar.
The way your keyboard input is seen by cin >> buffer;is not a property of your program, but of the combination of OS, Shell, C runtime and maybe thousand things I forgot.