I need to place a form in all my subsites and home page. It's placed on right column. It's action is "/". If there are some errors I must display them.
I made Form class etc. I display it via {{ form.as_p }} and designed all.
The problem is - how to put it on all sites? I don't want to make form instance in all my views functions.
What is the best solution for that?
Looks like a work for a context processor. :-)
def my_form_processor(request):
return {'my_form': MyForm()}
Related
I'm pretty much trying to create a web app that takes 2 svn urls and does something with them.
The code for my form is simple, I'm also using WTForms
class SVN_Path(Form):
svn_url=StringField('SVN_Path',[validators.URL()])
I'm trying to create 2 forms with 2 submit buttons that submit the 2 urls individually so my test3.html looks like this:
<form action="" method="post" name="SVNPath1">
{{form1.hidden_tag()}}
<p>
SVN Directory:
{{form1.svn_url(size=50)}}
<input type="submit" value="Update">
<br>
{% for error in form1.svn_url.errors %}
<span style="color: red;">[{{error}}]</span>
{% endfor %}
</p>
</form>
<form action="" method="post" name="SVNPath2">
{{form2.hidden_tag()}}
<p>
SVN Directory:
{{form2.svn_url(size=50)}}
<input type="submit" value="Update">
<br>
{% for error in form2.svn_url.errors %}
<span style="color: red;">[{{error}}]</span>
{% endfor %}
</p>
</form>
MY FIRST QUESTION is how do I know which submit button was clicked so I can run the proper function on the corresponding svn url. I have tried doing something like
if request.form1['submit'] == 'Update':
if request.form2['submit'] == 'Update':
but that does not work at all. I'm new to web dev in general and flask so a detailed explanation would be helpful.
SECONDLY, since submits weren't working properly I also tried an alternative to keep my work moving so in my .py file I have
#app.route('/test3', methods=['GET','POST'])
def test3():
basepath=createDir()
form1=SVN_Path()
form2=SVN_Path()
if request.method=="POST":
if form1.validate_on_submit():
svn_url = form1.svn_url.data
prev_pdf=PDF_List(svn_url,basepath,'prev') #some function
if form2.validate_on_submit():
svn_url2 = form2.svn_url.data
new_pdf=PDF_List(svn_url,basepath,'new') #some function
return render_template('test3.html', form1=form1, form2=form2)
CreateDir is a function that creates a directory in the local /tmp using timestamps of the local time.
Whenever I go the webpage it creates a directory, lets call it dir1, since its calling CreateDir. Thats what I want, but when I click submit on the form it creates another directory dir2 in the tmp folder which is NOT what I want since I want everything to being the same dir1 directory.
In addition when I put a url in one of the forms and click submit, it automatically puts it the same value in the 2nd form as well.
Sorry if this is really long and possibly confusing, but any help is appreciated.
:) Let's see if we can clarify this a little.
To your first question:
As #dim suggested in his comment, You have a few options:
You can submit your form to separate unique urls. That way you know which form was submitted
You can create two similar but different Form classes (the fields will need different names like prev_svn_url and cur_svn_url). This way in your view function, you instantiate two different forms and you'll know which form was submitted based on form.validate_on_submit()
The third option would be to add a name attribute to your submit button and then change the value attributes to something like 'Update Previous' and 'Update Current'. This way in your view function you can check the value of request.data[<submit button name>] to determine if 'Update Previous' was pressed or 'Update Current'.
To your second question:
Multiple directories are being created because you're calling createDir() each time the page is loaded to show the forms and when the forms get posted. In order to create just once, you'll need some kind of logic to determine that the directory was not previously created before calling createDir()
In addition: Since both forms are from the same SVN_Path class, they read post data exactly the same way, that's why whatever you type in form 1 appears in form 2.
Now for my 2 cents:
I assume you're trying to write some kind of application that takes two SVN urls as input, creates a folder and does something with those URLs in that folder. If this is the case, the way you are currently going about it is inefficient and won't work well. You can achieve this with just one form class having 2 svn_url fields (with different names of course) and then handling all of that in one post.
EDIT: The job of the submit button is to tell the browser that you're ready to send the data on the form to the server. In this case you should only need one submit button (SubmitFiled => when rendered). Clicking that one submit button will send data from both input fields to your view function.
Your form should look something like:
class SVN_Path(Form):
prev_svn_url=StringField('Previous SVN_Path',[validators.URL()])
new_svn_url=StringField('New SVN_Path',[validators.URL()])
and your view function:
def test():
form = SVN_Path()
if request.method == "POST":
if form.validate_on_submit():
basepath = createDir() # Only create dir when everything validates
prev_svn_url = form.prev_svn_url.data
new_svn_url = form.new_svn_url.data
prev_pdf = PDF_List(prev_svn_url, basepath, 'prev')
new_pdf = PDF_List(new_svn_url, basepath, 'new')
...
return render_template('test3.html', form1=form1, form2=form2)
My question is, how could I go about passing information in django from the template to a view without url parameters. I know that sessions can help me do this however, I can't find any resources online that show how to create a key value pair in the sessions from within a template. For example, If I had a link
{{ c.class_id }}
which would lead you to a specific university class homepage, how could I pass along c.class_id to the view that is responsible for rendering this specific homepage? Would I have to put this link inside a form and then POST it to the view?
You can use GET parameters. Example:
{{ c.class_id }}
To retrieve the parameter from the Django view, use:
param_value = request.GET['param_name']
I have an app with a Restaurant model. I'd like to understand what is the best way to put together a view that displays the list of restaurant objects, but also has a search form above that a user could enter parameters to filter the results displayed. If no parameters are entered, all the restaurants should be shown. I'm already using haystack and have a search form, but currently it is on a standalone search.html template. I also have an ListView on a separate template, and I guess I'm looking for an end result that combines these.
I did some reading on line and it's unclear what the best way to do it is:
using just listview from Django with some queryset filtering
combining haystack SearchView with django class based views?
this is my best bet so far - creating a customized version of SearchView from Haystack
ideally, ultimately the search capabilities would include things like allow autocompleting the user's inputs, and dynamically filter the results as the user types.
any thoughts on what the best way is to go about this and any examples out there?
There probably is out there some package that gives you everything automatically, displaying the queryset list and allowing simple adding of a search bar and so on (like the admin site). But I take it you are still a beginner to web development, so I'd strongly suggest you drop the listviews, drop haystack, drop everything, and do it all yourself.
See, they're not bad approaches or anything, but they're like shortcuts. And shortcuts are good only if they shorten the original way, which in your case isn't all that long.
To give you an example, here's a simple approach to displaying a list of items:
views.py
def restaraunt_list(request):
restaraunts = Restaraunt.objects.all().order_by('name')[:100] # Just for example purposes. You can order them how you'd like, and you probably want to add pagination instead of limiting the view number arbitrarily
context = {'restaraunts': restaraunts}
return render_to_response('index.html', context)
index.html:
<ul>
{% for rest in restaraunts %}
<li>{{ rest }}</li>
{% endfor %}
</ul>
That's it. Now it displays it in a list. Now to add a search filter all you need to do is this:
index.html (add this anywhere you want it)
<form>
<input type='text' name='q' id='q'></input>
<input type='submit' value='search!'></input>
</form>
When a user sends the data from 'q' it is sent through GET, and then on server side you add this:
def restaraunt_list(request):
restaraunts = Restaraunt.objects.all()
# filter results!
if request.method == 'GET':
q = request.GET['q']
if q != '':
restaraunts = restaraunts.filter(name__contains=q)
# ordering is the last thing you do
restaraunts = restaraunts.order_by('name')[:100]
context = {'restaraunts': restaraunts}
return render_to_response('index.html', context)
Now, this will work, but from what you wrote I understand you want the search to be live the moment a key is pressed. For that, you'd need to use AJAX (go learn how it works, I'm not gonna delve into it here). As for autocomplete, you should check out jQuery UI.
But, like I said, before jumping ahead and using all those stuff, I suggest you first learn the basics. Go through the django tutorial (if you haven't already), and use the amazingly detailed django-docs every step of the way. When some specific things won't work and you're stuck, come here to Stackoverflow and someone will surely help you. good luck!
I've started using Django and am going right to generic views. Great architecture! Well, the documents are great, but for the absolute beginner it is a bit like unix docs, where they make the most sense when you already know what you're doing. I've looked about and cannot find this specifically, which is, how do you set up an object_list template so that you can click on an entry in the rendered screen and get the object_detail?
The following is working. The reason I'm asking is to see if I am taking a reasonable route or is there some better, more Djangoish way to do this?
I've got a model which has a unicode defined so that I can identify my database entries in a human readable form. I want to click on a link in the object_list generated page to get to the object_detail page. I understand that a good way to do this is to create a system where the url for the detail looks like http://www.example.com/xxx/5/ which would call up the detail page for row 5 in the database. So, I just came up with the following, and my question is am I on the right track?
I made a template page for the list view that contains the following:
<ul>
{% for aninpatient in object_list %}
<li><a href='/inpatient-detail/{{ aninpatient.id }}/'>{{ aninpatient }}</a></li>
{% endfor %}
</ul>
Here, object_list comes from the list_detail.object_list generic view. The for loop steps through the object list object_list. In each line I create an anchor in html that references the desired href, "/inpatient-detail/nn/", where nn is the id field of each of the rows in the database table. The displayed link is the unicode string which is therefore a clickable link. I've set up templates and this works just fine.
So, am I going in the right direction? It looks like it will be straightforward to extend this to be able to put edit and delete links in the template as well.
Is there a generic view that takes advantage of the model to create the detail page? I used ModelForm helper from django.forms to make the form object, which was great for creating the input form (with automatic validation! wow that was cool!), so is there something like that for creating the detail view page?
Steve
If you're on django < 1.3 then what you are doing is basically perfect. Those generic views are quite good for quickly creating pages. If you're on django 1.3 you'll want to use the class based generic views. Once you get a handle on those they are are crazy good.
Only note I have is that you should use {% url %} tags in your templates instead of hardcoding urls. In your urls.conf file(s) define named urls like:
url('inpatient-detail/(?P<inpatient_id>\d+)/$', 'your_view', name='inpatient_detail')
and in your template (for django < 1.3):
...
In 1.3 a new url tag is available that improves life even more.
I want to do the following:
Having a model (p.e. a model which handles data about photographic reports) create a section which has a preview of an specific flickr album. The URL will be provided by an URLField (until the first save the preview will not be available).
After the first save, it'll show previews of all the images inside that album, and make them selectable (through jQuery for example). Then again, when the images are selected and the object is saved (I think I can use django signals for this) it will notify a specific user telling him a selection has been made.
Is there any plugins available, or any easy way to implement this in django-admin?
Update: 22 days and no anwers... does that mean it can't be done in django-admin?
I personally can't think of any easy way to implement this in the Django admin, simply because I doubt many people who've done it have thought to open source it. I can imagine that it would be very specific to a certain user's / programmer's needs.
In any case, if you wanted to solve this issue, I'd say that your best bet would be overriding the Django admin templates in your django/contrib/admin/templates/admin folder. I believe you'd be best off by editing change_form.html.
My basic approach would be this:
Check the name of the model using opts.verbose_name. For example, if you wanted to do this processing for a model whose verbose name is "Gallery", you would do
{% ifequal opts.verbose_name "Gallery" %}
<!-- neat gallery view -->
{% else %}
<!-- regular form -->
{% endifequal %}
Make a custom template tag that will display the gallery view / form given the object_id and the type of object. This way you can replace the <!-- neat gallery view --> with a {% show_gallery object_id %}. See the Django Docs for more info on creating custom template tags. It's pretty straightforward.
Add whatever Javascript or custom stuff in your template tag template. What you choose to do is up to you.
Sorry you haven't gotten many more answers to your question. Hope this helps!