can Hudson Build do multiple builds with different web.configs - build

I use hudson build to build my application. I have a web.debug.config, a web.release.config and a web.beta.config. My question is this. Is there a way to make hudson build job to do a separate build for each of these every time I do a build?

You could use a matrix (multi-configuration) project to do this, making the matrix variable the configuration type.
The linked documentation isn't too great, but hopefully it will get you going.

There is a serious lack of documentation on the Matrix projects and after trying all sorts I gave up on that and have a much simpler solution to what I was trying to achieve.
To achieve a build of each config I just added extra build steps with different command line parameters like this.
Click add a build step -> Build a VS project or solution with MSBUILD
In the command line arguments field add the following:
/property:Configuration=Debug
I then simply added another build step that does another build except with:
/property:Configuration=Release
And another with /property:Configuration=Beta
This runs through each build sequentially using the different configs on each build.

Related

Visual Studio 2015 - Pre build event to determine which projects to compile

Motivation
PreBuild to disable compilation of redundant projects for faster compilation cycle.
Background
I have a VS15 ALL solution that contains many projects.
I have a single project, PreBuild, that all the other projects are dependent on, meaning, this PreBuild compiles first.
In addition, we also have a PostBuild project that do some more work once binaries are ready.
All projects are configured to build in Release mode (which is desired).
When a team member wants to release some binaries, he hits F7, Build Solution.
Now, the PreBuild, activates a separate dedicated process that calculates which projects should be released. The nature of the calculation is irrelevant to this discussion.
Problem
Out of the many many projects, it is often the case that only a few projects needs to be released. However, once the PreBuild process is done, ALL the projects are will compile which is very time consuming.
Question
Is it possible, after a solution build had started, to change the released projects?
Suggested unwanted approaches
A developer handpicks only the relevant projects and only build those.
PreBuild Kill & Revive. Once desired projects are calculated, PreBuild kills the VS15 process and activate a cmd compiling only the relevant projects.
Suggested approach
Change file ALL.sln and remove the the unwanted projects.
This would work had I changed that file prior to the process start but I'm not sure it would work if this change occurs during the process.
The simplest way I can think of, while still keeping most of the current infrastructure in place: have a dedicated project which invokes the release build (by calculating dependencies and invoking msbuild) and configure VS so it can be select just that project for a build. All from within your ALL.sln so the rest of the features remain. Steps:
Get rid of the PreBuild/PostBuild projects. I assume the PostBuild you mention is also meant for the actual release builds; if not just leave it there. Note by not requiring all projects to depend on the PreBuild project you already got rid of one maintainance burden.
Add one single project which will do the release building, say ReleaseBuild. Such name is also better than having PreBuild/PostBuild projects since it clearly states the intent of the project. A Makefile project is suitable, though technically it could be as simple as an msbuild file with just one Build target. Configure the build command line to do whatever is needed, i.e. figuring out what to build then build. For the sake of an example: say you use Powershell to do this you would configure the build commandline to be
Powershell -NoProfile -File BuildRelease.ps1 $(Platform)
and BuildRelease.ps1 contains something like
$projectsToRelease = CalculateMyProjectsForRelease()
$platform = $Args[0]
$projectsToRelease | %{& msbuild $_ "/p:Configuration=Release;Platform=$platform"}
In Configuration Manager add an extra Configuration called Deploy or so. This will be used to select what to build: you probably have Debug and Release configurations now already. Those stay in place, and are simply used to build everything. The idea is this extra configuration will take care of building the actual release. This is fairly consistent with the standard way of working in VS and easy to discover and understand for newcomers. Using the checkboxes, make it so that when the Deploy configuration is selected only the ReleaseBuild is built and none of the others whereas when Debug or Release is selected the ReleaseBuild project is not built. Looks like this:
To build a release, select Deploy from the configuration drop down menu in the VS toolbar and hit F7 (or whatever way you use to invoke Build Solution). Any build errors/warnings will be parsed and shown as usual in the Error List.
This is also easy to extend: suppose you only have a couple of release build versions just add more configurations like DeployA DeployB DeployC and adjust the build command line for them.

Pass selected file to Make target in Eclipse

At the company I'm currently working for, several IDEs are being used (they develop firmware for different embedded platforms).
All their C projects use a Makefile, so we decided to also add rules to their default Makefile to run static code analysis tools.
One of the IDEs they use is Eclipse.
Here we have added additional targets to the Make Target view, that triggers the lint target from the Makefile, for example.
Since we use multiple IDEs we can tell the tools called by the Makefile to generate specific output for the IDE being used.
For Eclipse we do this by adjusting the Build Command and adding something like IDE_ENV=eclipse to the end.
This works just fine.
Recently one of the engineers mentioned that it would be really helpful if he could run the tools, as defined in the Makefile, for a single file.
So, I updated the Makefile and it now accepts a variable SOURCE_FILE with the path of the file that needs to be checked.
In Eclipse I tried adding SOURCE_FILE=${selected_resource_loc} and just SOURCE_FILE=${resource_loc}, but these variable do not seem to work when running a Make Target.
I also tried to use $(selected_resource_loc) and $(resource_loc) directly in the Makefile, but without any luck.
Can somebody tell me how I can pass the current selected file to Make when running a target from the Make Target view?
Some Eclipse special variables can be not recognized in a build configuration. Instead of running build procedure try to use External Tools Configuration.
Similar problem was described here: Custom command for Eclipse on current file .

Adding empty platform configuration to MSBuild

As part of a test process, I'm trying to create an empty MSBuild Platform Target for MVS 2010 whose only job is to call a batch file when I click "build". I want to completely ignore the build and link process of the c++ files, just call a batch file (perhaps with the post-build events?).
So far I've duplicated the Win32 platform at \MSBuild\Microsoft.Cpp\v4.0\Platforms and named it "TestPlatform", and started hacking away at it and managed to disable the build step, but it, quite reasonably, fails during the link step when it cant find my SampleProject.o file that the build file did not generate.
I've ordered the book "Inside the Microsoft Build Engine: Using MSBuild and Team Foundation Build" book by Hashimi and Bartholomew, but while it gets here I would appreciate if anyone has any words of wisdom on the subject. Specifically:
1 - How do I bypass the link step.
2 - How do I add a custom step to call a DoSomething.bat file instead
Thank you for your help :)
For my particular case, I found that adding a copy of the C:\Program Files (x86)\MSBuild\Microsoft.Cpp\v4.0\Platforms\Win32 platform (C:\Program Files (x86)\MSBuild\Microsoft.Cpp\v4.0\Platforms\TestPlatform) and adding the TestPlatform to my project configuration was enough to bring out the TestPlatform tab in the Configuration Manager dropdown menu.
To make it not compile or link anything but still run postbuild events the easiest way is to select in project properties:
Configuration Properties / General / Configuration Type : Utility
This seems to bypass all building steps but does call the postbuild events, where I simply put a call to a batch file.
It's not exactly what you are proposing, but a different way of achieving some of the same results is found here: run a custom msbuild target from VisualStudio
That shows how to wire up a command in the IDE to call a custom target in your project. So you could wire up an IDE command to call your RunThisBatchFile target in the current project.
Alternatively, you could override the rogue targets with a condition, something like:
<Target Name="Link" Condition="'$(Platform)' == 'TestPlatform'">
...
You may need to find a bunch of these and I'm not sure if it is 100% possible to get around the InitialTargets that may be defined for a C++ project file.
This is all covered in "MSBuild Trickery"

Is there a way to make Jenkins share a common source code directory / check out location for a full and an incremental build?

I am using Jenkins CI as the build server on a project that I am working on, I am also using Klocwork as a static analysis tool to identify deviations from our coding standards.
At present Jenkins has two builds (being performed in separate directories), a full build on a nightly basis that wipes out the workspace and performs a fresh checkout and full rebuild of everything.
In addition to the overnight build I also have an incremental build happening within 15 mins of a check in. Both builds are using the Klocwork analysis tool.
Klockwork works by displaying a list of potential issues which can then be fixed or chosen to be ignored if they are not applicable to the project, when issues are being ignored Klocwork uses the build file paths to remember where the issues that have been ignored reside. This means that when in Klocwork once I have ignored a warning in the full build and an incremental build is triggered the warning once again returns as the build path is different.
The most sensible solution I can see to this is for Jenkins to perform its full build on a nightly basis but for the incremental build to do an update in the full build location and to then do an incremental build - in the same way that an IDE on a PC functions.
The problem is that I have Jenkins running the full build and the incremental build as two separate jobs which causes them to check out into different locations and I cannot find a way of having the two jobs share a common directory.
Also I cannot find a way of having a single job that performs a nightly full checkout and rebuild, and an incremental build with an update on check in at the same time.
Is anyone familiar with a way of making Jenkins use a common source directory across multiple jobs?
Many thanks,
Pete.
Here's what I did.
Used one job to only check out source code.
In other jobs configuration settings', I set an environment variable that pointed to the workspace directory tree that contains the first job's source code (command line access to the Jenkins server is helpful here to figure out where it is, but not necessary). Then in my config scripting in Jenkins in the regular jobs, I 'cd' to that location and use the environment variable as path to all files so these other jobs would use the first job's checked out code.
Used locks, so regular jobs would not be running at same time as the check-out code job.
Since some results files (because of the tests being run) were generated and created in the source code tree because of the specifics of some of these jobs, in the config post-action script, I copied/moved the desired results back to the workspace of the job that should have them so I could process these results in the right job.
Worked for me.
You can easily make the two builds share the same build-area,
simply by extracting the files in both build-jobs to a shared location.
I strongly advise NOT to do this, as you can quickly get to a situation where
the nightly-build is cleaning the build-area while the incremental build is still running
(or that the incremental-build is checking-out sources while the nightly is still running).
Suggest you connect Klockwork only to one of the build-jobs (the nightly, probably)
so to avoid duplicate warnings.

Visual Studio: how to create a project that would compile 2 exe files?

So I have main.cpp and main2.cpp with int main in each. I want to get 2 exes out of it. Is it possible and what would be instruction to create such project?
Nope, Visual Studio's project model is rigidly built around the assumption that "one project generates one output".
If you need two executables, you have to create two projects. You can keep them in the same solution to make things easier for yourself, but they have to be separate projects.
Edit
Ok, as other answers have pointed out, it can of course be done, if you're desperate. You can add a custom build step, which does anything you like, including building another executable. (However, the build system won't understand that this file should be considered project output, and so some scenarios may fail: for example the file won't be automatically copied to the output folder, and when checking dependencies before a rebuild, it might not be able to understand which files to check, and what (or how) to rebuild.)
Visual Studio (at least up to 2008, not sure about 2010) also allows the use of nmake files, but then I think you're stretching the definition of "a Visual Studio project".
But under "normal" circumstances, one project implies one output. And in order to get two executables, you'd normally create two projects.
You need a solution which includes two projects. Have a read of the Visual Studio documentation on solutions and projects.
Here's my solution, since nobody in a Google search seems to suggest this method. It's quite simple and I've used/seen it used in other IDEs (like Code::Blocks).
Within your project, create a configuration for each output that you want. Then, only include one main source file in each configuration.
In VS, this means for each source file with main: right-click -> Properties -> Excluded From Build = Yes. So, once you're done, only one main source is built for each configuration. You can then specify a different output for each configuration in the Project Properties. I did this on VS 2010, but it should probably work with other versions.
I'm using this approach so that I can have several tests for one project, without cluttering the solution with more test projects than actual code projects.
I don't know if it can be done ,but the only change you have ,to do this ,is with custom build step.
EDIT: Since someone downvoted this ,i did a test making a dummy configuration.
In the custom build step I two Link-cmds (copied form original link-cmdline and modified it a bit) taking as input main1.obj resp. main2.obj and outputting App1.exe resp. App2.exe.
It's executed after Compiling and before linking.
It worked !
The downside is I cannot prevent (yet) the linking ot the orinal exe (which errors on duplicate main function).
Solution to this could be to have a lib project excluding the sources with main()from build and build them in the custum-step too.
So the answer to the question should : Yes ,it can be done!
You can't have more than one main() function in a single visual studio project. So you can't compile 2 executables, the only way is to make two different project in the same solution
You can create a solution with two project one for each output you want. Then head to Build menu and select Batch Build.. and select both projects.
If you want both exe files to be in one place you can specify a custom Post-build action:
For both project:
view the project properties page and in Build events select Post-Build events, then in the Command line field enter the command that will copy the output to the location you want, something like:
copy $(TargetPath) c:\yourlocation /Y
Then after you build the solution the output files will be copied to that location.
Another option you have is to use conditional compilation with sth like
main()
{
#ifdef VERSION1
call_main_logic();
#else
call_main2_logic();
#endif
}
and then define different configurations within the project. For each configuration you will then need to define preprocessor symbols appropriately (in: project settings -> configuration properties -> C/C++ -> preprocessor).
Please note, that it will be only one executable created at a time, but with switching configurations you'll get the one that does what you want at the moment.
... which may suit your needs or not, depending on more specific situation that you are in.
Edit: In addition, since different configurations create their separate output folders, you will have your both execs as outputs.