I'm trying to match some paths, but not others via regexp. I want to match anything that starts with "/profile/" that is NOT one of the following:
/profile/attributes
/profile/essays
/profile/edit
Here is the regex I'm trying to use that doesn't seem to be working:
^/profile/(?!attributes|essays|edit)$
For example, none of these URLs are properly matching the above:
/profile/matt
/profile/127
/profile/-591m!40v81,ma/asdf?foo=bar#page1
You need to say that there can be any characters until the end of the string:
^/profile/(?!attributes|essays|edit).*$
Removing the end-of-string anchor would also work:
^/profile/(?!attributes|essays|edit)
And you may want to be more restrictive in your negative lookahead to avoid excluding /profile/editor:
^/profile/(?!(?:attributes|essays|edit)$)
comments are hard to read code in, so here is my answer in nice format
def mpath(path, ignore_str = 'attributes|essays|edit',anything = True):
any = ''
if anything:
any = '.*?'
m = re.compile("^/profile/(?!(?:%s)%s($|/)).*$" % (ignore_str,any) )
match = m.search(path)
if match:
return match.group(0)
else:
return ''
Related
I am trying to pull a certain number from various strings. The number has to be standalone, before ', or before (. The regex I came up with was:
\b(?<!\()(x)\b(,|\(|'|$) <- x is the numeric number.
If x is 2, this pulls the following string (almost) fine, except it also pulls 2'abd'. Any advice what I did wrong here?
2(2'Abf',3),212,2'abc',2(1,2'abd',3)
Your actual question is, as I understand it, get these specific number except those in parenthesis.
To do so I suggest using the skip_what_to_avoid|what_i_want pattern like this:
(\((?>[^()\\]++|\\.|(?1))*+\))
|\b(2)(?=\b(?:,|\(|'|$))
The idea here is to completely disregard the overall matches (and there first group use for the recursive pattern to capture everything between parenthesis: (\((?>[^()\\]++|\\.|(?1))*+\))): that's the trash bin. Instead, we only need to check capture group $2, which, when set, contains the asterisks outside of comments.
Demo
Sample Code:
import regex as re
regex = r"(\((?>[^()\\]++|\\.|(?1))*+\))|\b(2)(?=\b(?:,|\(|'|$))"
test_str = "2(2'Abf',3),212,2'abc',2(1,2'abd',3)"
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches):
matchNum = matchNum + 1
if match.groups()[1] is not None:
print ("Found at {start}-{end}: {group}".format(start = match.start(2), end = match.end(2), group = match.group(2)))
Output:
Found at 0-1: 2
Found at 16-17: 2
Found at 23-24: 2
This solution requires the alternative Python regex package.
Given string:
some_function(inputId = "select_something"),
(...)
some_other_function(inputId = "some_other_label")
I would like to arrive at:
some_function(inputId = ns("select_something")),
(...)
some_other_function(inputId = ns("some_other_label"))
The key change here is the element ns( ... ) that surrounds the string available in the "" after the inputId
Regex
So far, I have came up with this regex:
:%substitute/\(inputId\s=\s\)\(\"[a-zA-Z]"\)/\1ns(/2/cgI
However, when deployed, it produces an error:
E488: Trailing characters
A simpler version of that regex works, the syntax:
:%substitute/\(inputId\s=\s\)/\1ns(/cgI
would correctly inser ns( after finding inputId = and create string
some_other_function(inputId = ns("some_other_label")
Challenge
I'm struggling to match the remaining part of the string, ex. "select_something") and return it as:
"select_something")).
You have many problems with your regex.
[a-zA-Z] will only match one letter. Presumably you want to match everything up to the next ", so you'll need a \+ and you'll also need to match underscores too. I would recommend \w\+. Unless more than [a-zA-Z_] might be in the string, in which case I would do .\{-}.
You have a /2 instead of \2. This is why you're getting E488.
I would do this:
:%s/\(inputId = \)\(".\{-}\)"/\1ns(\2)/cgI
Or use the start match atom: (that is, \zs)
:%s/inputId = \zs\".\{-}"/ns(&)/cgI
You can use a negated character class "[^"]*" to match a quoted string:
%s/\(inputId\s*=\s*\)\("[^"]*"\)/\1ns(\2)/g
So I have this code that extract the integer from a string of the form: Dir.<int>
def MatchDir(s):
RegExp = re.compile('Dir.([0-9]+)')
result = RegExp.match(s)
try:
return int(result.group(1))
except:
return None
problem is that it also matches strings such as Dir.123_test which is not desired.
How to resolve this to match only strings of the from Dir.<int> (no char is acceptable before or after this specific form)
Use ^ and $ to match the start and end of string:
RegExp = re.compile('^Dir.([0-9]+)$')
This won't allow anything other than Dir. and a number
I'm trying to create a regular expression to match some certain characters, unless they appear within two of another character.
For example, I would want to match abc or xxabcxx but not tabct or txxabcxt.
Although with something like tabctxxabcxxtabcxt I'd want to match the middle abc and not the other two.
Currently I'm trying this in Java if that changes anything.
Try this:
String s = "tabctxxabcxxtabcxt";
Pattern p = Pattern.compile("t[^t]*t|(abc)");
Matcher m = p.matcher(s);
while (m.find())
{
String group1 = m.group(1);
if (group1 != null)
{
System.out.printf("Found '%s' at index %d%n", group1, m.start(1));
}
}
output:
Found 'abc' at index 7
t[^t]*t consumes anything that's enclosed in ts, so if the (abc) in the second alternative matches, you know it's the one you want.
EDITED! It was way wrong before.
Oooh, this one's tougher than I thought. Awesome. Using fairly standard syntax:
[^t]{2,}abc[^t]{2,}
That will catch xxabcxx but not abc, xabc, abcx, xabcx, xxabc, xxabcx, abcxx, or xabcxx. Maybe the best thing to do would be:
if 'abc' in string:
if 't' in string:
return regex match [^t]{2,}abc[^t]{2,}
else:
return false
else:
return false
Is that sufficient for your intention?
I have a string in the format:
t='#abc #def Hello this part is text'
I want to get this:
l=["abc", "def"]
s='Hello this part is text'
I did this:
a=t[t.find(' ',t.rfind('#')):].strip()
s=t[:t.find(' ',t.rfind('#'))].strip()
b=a.split('#')
l=[i.strip() for i in b][1:]
It works for the most part, but it fails when the text part has the '#'.
Eg, when:
t='#abc #def My email is red#hjk.com'
it fails. The #names are there in the beginning and there can be text after #names, which may possibly contain #.
Clearly I can append initally with a space and find out first word without '#'. But that doesn't seem an elegant solution.
What is a pythonic way of solving this?
Building unashamedly on MrTopf's effort:
import re
rx = re.compile("((?:#\w+ +)+)(.*)")
t='#abc #def #xyz Hello this part is text and my email is foo#ba.r'
a,s = rx.match(t).groups()
l = re.split('[# ]+',a)[1:-1]
print l
print s
prints:
['abc', 'def', 'xyz']
Hello this part is text and my email is foo#ba.r
Justly called to account by hasen j, let me clarify how this works:
/#\w+ +/
matches a single tag - # followed by at least one alphanumeric or _ followed by at least one space character. + is greedy, so if there is more than one space, it will grab them all.
To match any number of these tags, we need to add a plus (one or more things) to the pattern for tag; so we need to group it with parentheses:
/(#\w+ +)+/
which matches one-or-more tags, and, being greedy, matches all of them. However, those parentheses now fiddle around with our capture groups, so we undo that by making them into an anonymous group:
/(?:#\w+ +)+/
Finally, we make that into a capture group and add another to sweep up the rest:
/((?:#\w+ +)+)(.*)/
A last breakdown to sum up:
((?:#\w+ +)+)(.*)
(?:#\w+ +)+
( #\w+ +)
#\w+ +
Note that in reviewing this, I've improved it - \w didn't need to be in a set, and it now allows for multiple spaces between tags. Thanks, hasen-j!
t='#abc #def Hello this part is text'
words = t.split(' ')
names = []
while words:
w = words.pop(0)
if w.startswith('#'):
names.append(w[1:])
else:
break
text = ' '.join(words)
print names
print text
How about this:
Splitting by space.
foreach word, check
2.1. if word starts with # then Push to first list
2.2. otherwise just join the remaining words by spaces.
You might also use regular expressions:
import re
rx = re.compile("#([\w]+) #([\w]+) (.*)")
t='#abc #def Hello this part is text and my email is foo#ba.r'
a,b,s = rx.match(t).groups()
But this all depends on how your data can look like. So you might need to adjust it. What it does is basically creating group via () and checking for what's allowed in them.
[i.strip('#') for i in t.split(' ', 2)[:2]] # for a fixed number of #def
a = [i.strip('#') for i in t.split(' ') if i.startswith('#')]
s = ' '.join(i for i in t.split(' ') if not i.startwith('#'))
[edit: this is implementing what was suggested by Osama above]
This will create L based on the # variables from the beginning of the string, and then once a non # var is found, just grab the rest of the string.
t = '#one #two #three some text afterward with # symbols# meow#meow'
words = t.split(' ') # split into list of words based on spaces
L = []
s = ''
for i in range(len(words)): # go through each word
word = words[i]
if word[0] == '#': # grab #'s from beginning of string
L.append(word[1:])
continue
s = ' '.join(words[i:]) # put spaces back in
break # you can ignore the rest of the words
You can refactor this to be less code, but I'm trying to make what is going on obvious.
Here's just another variation that uses split() and no regexpes:
t='#abc #def My email is red#hjk.com'
tags = []
words = iter(t.split())
# iterate over words until first non-tag word
for w in words:
if not w.startswith("#"):
# join this word and all the following
s = w + " " + (" ".join(words))
break
tags.append(w[1:])
else:
s = "" # handle string with only tags
print tags, s
Here's a shorter but perhaps a bit cryptic version that uses a regexp to find the first space followed by a non-# character:
import re
t = '#abc #def My email is red#hjk.com #extra bye'
m = re.search(r"\s([^#].*)$", t)
tags = [tag[1:] for tag in t[:m.start()].split()]
s = m.group(1)
print tags, s # ['abc', 'def'] My email is red#hjk.com #extra bye
This doesn't work properly if there are no tags or no text. The format is underspecified. You'll need to provide more test cases to validate.