Writing Java equivalent of the Fortran program - fortran

Question

I have something like this in fortran.
20: call TESTBEGIN(a,b,c)
if(c<1) goto 40
30: call TESTMIDDLE(e,f,g)
if(g==1) goto 20
40: return
But my code is like this
Subroutine testCase()
20: CALL beginTest(a,b)
IF (b.EQ.-1) GOTO 999
30: CALL middleTest(c,b)
IF (b.EQ.-1) GOTO 20
40: CALL endTest(d,b)
IF (b.EQ.-1) GOTO 30
CALL LastTest(e,b)
IF (.b.EQ.-1) GOTO 40
DO I =1,j
DTEMP(j)=1.0
END DO
some code
999:return

Answer 1

Something like that?
do
{
c = TESTBEGIN(a,b);
if (c < 1) break;
g = TESTMIDDLE(e,f);
} while ( g == 1 );
For the second code snippet try a state machine:
for(int state = 1; state != 0; )
{
switch(state)
{
case 1:
state = (beginTest(a) == -1) ? 0 : 2;
break;
case 2:
state = (middleTest(c) == -1) ? 1 : 3;
break;
case 3:
state = (endTest(d) == -1) ? 2 : 4;
break;
case 4:
state = (lastTest(e) == -1) ? 3 : 5;
break;
}
case 5:
state = 0;
// DO I =1,j // Honestly I don't know what does it do.
// DTEMP(j)=1.0
break;
}
Or better try to reconsider the algorithm, I think you could do it more easy to read and understand using Java.