std::map<string, class> print the value of the key - c++

Question

My program is written in C++.
#include <iostream>
#include <string>
#include <map>
using namespace std;
class Details
{
int x;
int y;
};
typedef std::map<string, Details> Det;
Det det;
Details::Details(int p, int c) {
x = p;
y = c;
}
int main(){
det.clear();
insertNew("test", 1, 2);
cout << det["test"] << endl;
return 0;
}
I want to print the value of a key with the simplest way. Eg det["test"] fails to compile.
How to I print values (1,2) for (x,y) that correspond to key "test"?

Answer 1

My best guess is that you have no default or copy constructor in your Obj (you don't have any in the code you posted, but I assume you have one that takes two integers). You've also got a typo in the catalog.insert() line. Here is what worked for me, using your code:
class Obj {
public:
Obj() {}
Obj(int x, int y) : x(x), y(y) {}
int x;
int y;
};
int main (int argc, char ** argv) {
std::map<std::string, Obj> catalog;
catalog.insert(std::map<std::string, Obj>::value_type("test", Obj(1,2)));
std::cout << catalog["test"].x << " " << catalog["test"].y << std::endl;
return 0;
}

Answer 2

Create an operator<< for your class Obj and then you can do something like std::cout << catalog["test"]; (I'm assuming that the missing parens in the insert call are just a copy-paste-o).

Answer 3

I've changed a bit your code.
#include <map>
#include <iostream>
#include <string>
using namespace std;
class Obj {
public:
Obj( int in_x, int in_y ) : x( in_x ), y( in_y )
{};
int x;
int y;
};
int main()
{
std::map< string, Obj* > catalog;
catalog[ "test" ] = new Obj(1,2);
for( std::map<string, Obj*>::iterator i=catalog.begin(); i != catalog.end(); ++i )
{
cout << "x:" << i->second->x << " y:" << i->second->y << endl;
}
}

Answer 4

Given these types:
class Obj {
int x;
int y; };
std::map<string, Obj> catalog;
Given a populated catalog object:
for(auto ob = catalog.begin(); ob != catalog.end(); ++ob)
{
cout << ob->first << " " << ob->second.x << " " << ob->second.y;
}