how functions of a not fully constructed objects are called? - c++

creating an object using a constructor and along with that calling functions of object which is being constructed:
class A
{
public:
A()
{
this->show();
}
void show()
{
cout<<"show called!";
}
};
and now i m creating object in main() as below:
int main()
{
A a;
int xy;
cin>>xy;
return 0;
}
my doubt is that when i am creating an object using constructor then how i am able to call object function while object is not fully constructed?
virtual function calls:
class A
{
public:
A()
{
}
virtual void show()
{
cout<<"show called!";
}
};
class B:public A
{
public:
B()
{
A *a=this;
a->show();
}
void show()
{
cout<<"derived show";
}
};
int main()
{
A a;
B b;
int xy;
cin>>xy;
return 0;
}
working fine with output: derived show

It's fine to call virtual functions and non-static member functions:
See section 12.7 of http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2011/n3242.pdf:
4 Member functions, including virtual functions (10.3), can be called
during construction or destruction (12.6.2).
However when using virtual functions in a constructor there are some restrictions. It's a bit of a mouthful:
When a virtual function is called directly or indirectly from a
constructor (including the mem-initializer or
brace-or-equal-initializer for a non-static data member) or from a
destructor, and the object to which the call applies is the object
under construction or destruction, the function called is the one
defined in the constructor or destructor’s own class or in one of its
bases, but not a function overriding it in a class derived from the
constructor or destructor’s class, or overriding it in one of the
other base classes of the most derived object (1.8).
I interpret the above paragraph as saying the virtual functions called will not be in any derived class. This makes sense because at this point in the execution phase any constructor in a derived class will not have begun execution.
Additionally part 1 places a restriction that use of non-static members should occur after the construction begins. In your example the members are being invoked after the construction begins, so you're not violating part 1:
1 For an object with a non-trivial constructor, referring to any
non-static member or base class of the object before the constructor
begins execution results in undefined behavior.

This code is completely legal. You can call methods
in the class constructor.
All constants (from the initialization list) are already initialized and all base class constructors are called.
However, You should not call virtual methods in the constructor. See Scott Meyers explanation for this restriction.

The thing to think about is, which parts of the object are constructed at the time when you call show()?
Since you call show() from within your constructor's body (and not e.g. from within the constructor's initializer list) you can rest assured that all of the A object's member variables have already been constructed (since that happens before the constructor body is executed).
What might trip you up would be if show() was a virtual method, and A::A() was being called from the constructor of a subclass of A. In that case, you might want show() to call B::show(), but that won't happen because the vtable for B hasn't been set up yet (you would end up calling A::show() instead, or crashing the program if A::show() was a pure-virtual method)

You are calling a function in an partially constructed object, which may result in erroneous behavior if such function deals with class members and such. I am not sure whether its invoking undefined behaviour or not, but I don't think its a good practice. And the situation gets worse with inheritance and virtual functions!
In your example, show could be declared static and there will be no risk in calling it.

Consider a class as 2 separate parts: The object containing fields (variables) and the methods (functions). The methods of a given class exist independent of any particular instance, so it can be called at any time by a valid instance, even mid-construction.
The fields are "created" when the object is instantiated, before the constructor is run. However, they have no values set to them. So, if your constructor calls any methods BEFORE the fields are initialised to sensible values, then you're going to experience some undefined behaviour.
Whenever possible, if you must call a method inside a constructor, be sure to initialise as many fields as possible to sensible values.

my doubt is that when i am creating an object using constructor then how i am able to call object function while object is not fully constructed?
what happens in your example is fine, as long as you initialize where you are supposed to (the initialization list). you are using static dispatch on an object which has initialized members (specifically, A has no such variables to initialize).
what then is invalid?
not initializing your members correctly, or using them before they are really initialized. favor the initialization list without using this.
using dynamic dispatch from within your constructor's body (or initializer). your object is not fully constructed.
unusually, you could also attempt to typecast it to a subclass from the constructor.

Related

What happens when a destructor calls an abstract function

I'm having trouble understanding what's the reason for the crash in the following code :
class A {
public:
virtual ~A() { goo(); }
void goo() { absFoo(); }
virtual void absFoo() = 0;
};
class B : public A {
public:
void absFoo() { cout << "In B \n"; }
};
int main()
{
B b1;
b1.goo();
}
The main prints "In B" as expected, but in the end when it crashes, I can't debug it either, the compiler pops a weird message.
So my question is, when the destructor of A calls "goo()", does "absFoo()", crash
because we're referring to an abstract function?
Or does the compiler actually look for a definition in the derived classes? (And it doesn't exist anymore because it was destructed beforehand so it crashes)
I know that if we had called "absFoo()" directly from the destructor, the reason would have been the abstract function. But since here it's an outside function calling "absFoo()" I'm having trouble understanding the real reason.
What happens when a destructor calls an abstract function
First, let us consider what happens when a destructor calls any virtual function (the same applies to the constructor by the way): When a virtual function foo is called in the destructor of T, the call will not be dispatched dynamically to an implementation in a derived type (the lifetime of any derived object has already ended), but statically to the implementation T::foo.
If T::foo is pure virtual, then calling it without dynamic dispatch will have undefined behaviour. That is what happens when a pure virtual function is (indirectly) called in a destructor (or constructor).
Just to complement the already accepted answer, this is the documentation from cppreference.
When a virtual function is called directly or indirectly from a
constructor or from a destructor (including during the construction or
destruction of the class’s non-static data members, e.g. in a member
initializer list), and the object to which the call applies is the
object under construction or destruction, the function called is the
final overrider in the constructor’s or destructor’s class and not one
overriding it in a more-derived class.
In other words, during construction or destruction, the more-derived classes do not exist.
As the object is deconstructed, the vtable is updated to match the new status of the object.
Since you've removed the last function, the compiler will do whatever it considers fit; which in the case of a debug compilation in visual studio, will fallback to an abort reporting that a pure virtual function was called.
The vtable however is not part of the standard, it's an implementation detail, and there's no requirement for your program to crash; it's just what is considered the nicest thing to do when you've called a pure virtual function.

C++ Calling overwritten function in derived from base class

I have 2 classes, A and B and I need an overwritten function in B to be called from A's constructor. Here is what I have already:
class A {
A(char* str) {
this->foo();
}
virtual void foo(){}
}
class B : public A {
B(char* str) : A(str) {}
void foo(){
//stuff here isn't being called
}
}
How would I get code to be called in B::foo() from A::A()?
I need an overwritten function in B to be called from A's constructor
This design is not possible in C++: the order of construction of a B object is that first the base A sub-object is constructed, then B is constructed on top of it.
The consequence is that, while in A constructor, you are still constructing an A object: any virtual function called at this point will be the one for A. Only when the A construction is finished and the B construction starts, will the virtual functions of B become effective.
For achieveing what you want, you have to use a two step pattern: 1) you construct the object, 2) you initialize it.
I think you are referring to Calling Virtuals During Initialization Idiom (aka Dynamic Binding During Initialization), so please have a look here, where everything is explained:
https://en.wikibooks.org/wiki/More_C%2B%2B_Idioms/Calling_Virtuals_During_Initialization
https://isocpp.org/wiki/faq/strange-inheritance#calling-virtuals-from-ctor-idiom
2nd site has very good explanation, but it's way longer than 1st.
In a constructor, the base class' function will get called, not the overridden version. The reason for this is that, using your example, B's initialization is not complete when A's constructor is called, and thus calling B's foo would be done with an incomplete B instance if this were otherwise allowed.

How does the base destructor invoke the derived destructor?

In the code below, b is a base-class pointer. However, when I invoke the destructor (either explicitly or implicitly via delete), the derived class destructor is invoked first. I don't understand how this works. There could be any number of derived classes, each with their own destructors. How can the compiler know which derived class destructor to invoke from the base destructor?
#include <iostream>
using namespace std;
class Base {
public:
virtual ~Base() { cout << "Base destructor" << endl; }
};
class Derived : public Base {
public:
~Derived() { cout << "Derived destructor" << endl; }
};
int main(int argc, char * argv[]) {
Base * b = new Derived();
b->~Base(); // delete b; has the same result
}
dynamic binding, the compiler doesn't decide, the runtime does because the destructor is virtual. C++ destruction calls the destructor on the current class and implicitly calls the parent class until it hits the base class.
The call to virtual destructor works the same as a call to any other virtual function, as a result of virtual dispatch via virtual table. Apart from this,
b->~Base(); // delete b; "has the same result"
this is not true, because delete also frees the memory, which you haven't done here. delete b calls a destructor for *b and deallocates raw memory to operating system. You have only destroyed the building but haven't given ground back.
This is done the same way as virtual functions. Its called dynamic binding. When non virtual member functions are resolved statically means at compile-time, virtual members are resolved dynamically means during run time. Compiler maintains a vtable for this. If the object has one or more virtual functions, the compiler puts a hidden pointer in the object called a "virtual-pointer" or "v-pointer." This v-pointer points to a global table called the "virtual-table" or "v-table.". Read more in details from here.
It doesn't. It happens the other way around. Normal virtual function despatching calls the derived destructor, and the derived destructor calls the base destructor.
Note: My first answer was so off-base that I deleted it. It was so far off-base that someone should have down voted my response. This is another try.
In the opening post, master_latch asked:
How can the compiler know which derived class destructor to invoke from the base destructor?
How this happens is implementation specific.
Why this has to happen is "because the standard says so." Here's what the standard says:
C++11 12.4 paragraph 5:
After executing the body of the destructor and destroying any automatic objects allocated within the body, a destructor for class X calls the destructors for X’s direct non-variant members, the destructors for X’s direct base classes and, if X is the type of the most derived class, its destructor calls the destructors for X’s virtual base classes. All destructors are called as if they were referenced with a qualified name, that is, ignoring any possible virtual overriding destructors in more derived classes. Bases and members are destroyed in the reverse order of the completion of their constructor. A return statement in a destructor might not directly return to the caller; before transferring control to the caller, the destructors for the members and bases are called. Destructors for elements of an array are called in reverse order of their construction.
C++11 12.4 paragraph 10:
In an explicit destructor call, the destructor name appears as a ~ followed by a type-name or decltype-specifier that denotes the destructor’s class type. The invocation of a destructor is subject to the usual rules for member functions, ...
The example code in C++11 12.4 paragraph 10 indicates the intent of the above:
struct B {
virtual ~B() { }
};
struct D : B {
~D() { }
};
D D_object;
B* B_ptr = &D_object;
void f() {
D_object.B::~B(); // calls B’s destructor
B_ptr->~B(); // calls D’s destructor
...
}
master_latch, your example of using b->~Base(); is identical to the second call in the example code. Think of b->~Base(); as if it meant b->__destruct_me(). It is in a sense no different than a call to any other virtual function.
A compliant implementation has to do this because "because the standard says so." How an implementation does it? The standard doesn't say. (That's good requirementese, by the way. Say what has to be done, but don't say how to do it.)
Most implementations (every implementation I have poked into) do this by generating multiple functions for a destructor. One function implements the body of the destructor as specified by the programmer. A wrapper destructor executes this body of the destructor function, then destroys non-static data members in reverse order of construction, and then invokes parent class destructors. That classes can virtually inherit from some parent class adds another twist. This means that a third destructor function for a given class might be needed.
So how does an implementation know that b->~Base() should call the wrapper destructor for class Derived? Dynamically casting a pointer to a polymorphic class to a void* pointer yields a pointer to the most derived object.
C++11 5.2.7 paragraph 7:
If T is “pointer to cv void,” then the result is a pointer to the most derived object pointed to by v. Otherwise, a run-time check is applied to see if the object pointed or referred to by v can be converted to the type pointed or referred to by T.
In other words, dynamically casting a polymorphic pointer to void* yields a pointer to the object as it was declared or allocated. The virtual table (not a part of the standard) dictates how to find the destructor. The implementation ensures that the pointer to the virtual table can be determined from a void* pointer to the most derived object. This is what lets the implementation know which destructor to call. From that point on, the pointer to that most derived object is no longer a void* pointer.

How to fix pure virtual function called runtime error?

I understand why I am getting the error I am getting (pure virtual function called). I am trying to call pure virtual functions from within the destructor of my base class shown below. However, I do not know how to rework my code to prevent this from happening. Here are the base and derived classes (the relevant portions anyway):
Base class:
TailFileManager::TailFileManager(const std::string &filename, const int fileOpenPeriod_ms)
: m_Stop(false)
{
m_WorkerThread.reset(new boost::thread(boost::bind(&TailFileManager::TailFile, this, filename, fileOpenPeriod_ms)));
}
TailFileManager::~TailFileManager()
{
m_Stop = true;
m_WorkerThread->join();
}
void TailFileManager::TailFile(const std::string &filename, const int fileOpenPeriod_ms)
{
std::ifstream ifs(filename.c_str());
while (! ifs.is_open())
{
boost::this_thread::sleep(boost::posix_time::milliseconds(fileOpenPeriod_ms));
ifs.open(filename.c_str());
}
ifs.seekg(0, std::ios::end);
while (! m_Stop)
{
ifs.clear();
std::string line;
while (std::getline(ifs, line))
{
OnLineAdded(line);
}
OnEndOfFile();
}
ifs.close();
}
Derived class:
ETSLogTailFileManager::ETSLogTailFileManager(const std::string &filename, const int heartbeatPeriod_ms)
: TailFileManager(filename, heartbeatPeriod_ms),
m_HeartbeatPeriod_ms(heartbeatPeriod_ms),
m_FoundInboundMessage(false),
m_TimeOfLastActivity(0)
{
}
ETSLogTailFileManager::~ETSLogTailFileManager()
{
}
void ETSLogTailFileManager::OnLineAdded(const std::string &line)
{
// do stuff...
}
void ETSLogTailFileManager::OnEndOfFile()
{
// do stuff...
}
You shouldn't call virtual functions during construction or destruction, because the calls won't do what you think, and if they did, you'd still be unhappy. If you're a recovering Java or C# programmer, pay close attention to this Item, because this is a place where those languages zig, while C++ zags.
Re-work your design i.e you may call some cleanup function before object get destroyed, idea is just avoid virtual function during const/dest (if there are any!), if you are working with C++...
The rules for virtual invocation are different. C++ 2003, section 12.7 "Construction and Destruction", says:
Lets refresh some old memories ...
Member functions, including virtual functions (10.3), can be called during construction or destruction (12.6.2). When a virtual function is called directly or indirectly from a constructor (including from the mem-initializer for a data member) or from a destructor, and the object to which the call applies is the object under construction or destruction, the function called is the one defined in the constructor or destructorâs own class or in one of its bases, but not a function overriding it in a class derived from the constructor or destructorâs class, or overriding it in one of the other base classes of the most derived object (1.8). If the virtual function call uses an explicit class member access (5.2.5) and the object-expression refers to the object under construction or destruction but its type is neither the constructor or destructorâs own class or one of its bases, the result of the call is undefined.
Because of this difference in behavior, it is recommended that you never invoke an object's virtual function while it is being constructed or destroyed.
Never Call Virtual Functions during Construction or Destruction
An Excerpt from Effective C++, Third Edition
by Scott Meyers
June 6, 2005
http://www.artima.com/cppsource/nevercall.html
As far as the C++ standard is concerned:
if you call a virtual function in a constructor or destructor, then the function is
dynamically dispatched as if its dynamic type were that of the current constructor/destructor being executed (§12.7/4)
if that function happened to a pure virtual, then this is undefined behavior (§10.4/6); the Itanium ABI defines the behavior: __cxa_pure_virtual is called.
So, you have a bit of a thorny issue...
A possible solution to the problem would be to break it down in two parts, in order to break the destruction in two parts. This could be achieved with a Strategy pattern:
provide a customizable interface, your strategy
provide a manager class that encapsulate the functionality and defers to the strategy for the customizable parts
Let's make it clearer:
class Interface {
public:
friend class Manager;
private:
virtual void finalize() = 0;
}; // class Interface
class Manager {
public:
explicit Manager(std::unique_ptr<Interface>&&);
~Manager();
private:
std::unique_ptr<Interface> _interface;
}; // class Manager
Manager::~Manager() {
_interface->finalize();
}
The trick ? At the point where finalize() is called the destruction of _interface has not begun yet! The call to the destructor will happen later; and thus you do not suffer from a half-dead object's fate.
I'll end this answer by a warning about join-ing a thread in a destructor now. Beware that destructors are automatically called in case of stack unwinding, it might therefore be dangerous to wait indefinitely while failing; especially if the thread is waiting for data that should be provided by the currently being unwound one... a classic case of dead-lock.
References (n3337):
§12.7/4 Member functions, including virtual functions (10.3), can be called during construction or destruction (12.6.2). When a virtual function is called directly or indirectly from a constructor or from a destructor, including during the construction or destruction of the class’s non-static data members, and the object to which the call applies is the object (call it x) under construction or destruction, the function called is the final overrider in the constructor’s or destructor’s class and not one overriding it in a more-derived class.
§10.4/6 Member functions can be called from a constructor (or destructor) of an abstract class; the effect of making a virtual call (10.3) to a pure virtual function directly or indirectly for the object being created (or destroyed) from such a constructor (or destructor) is undefined.
You write,
“I am trying to call pure virtual functions from within the destructor of my base class shown below.”
And the code in question is
TailFileManager::~TailFileManager()
{
m_Stop = true;
m_WorkerThread->join();
}
Happily in a single-threaded execution this couldn't possibly call a pure virtual function. But the thread that you're joining might call a pure virtual function on this object, possibly via a non-virtual member function. If so, then the issue is with the threading, specifically the lifetime management of this object.
Unfortunately you do not show the relevant code. Try to reduce things to a small, complete, working example. Where "working" in the sense that it reproduces the problem.
Depending on what system you're on this may work:
Set a breakpoint on the pure function call handler: __cxa_pure_virtual.
This worked for me using gdb: break __cxa_pure_virtual then, when the breakpoint was hit, up showed my code that was busted. (In my case, I am introducing a second thread and destruction was currently happening on a different thread while the object was being used.)
Documentation of __cxa_pure_virtual: https://www.swag.uwaterloo.ca/acd/docs/ItaniumC++ABI.htm#pure-virtual

Calling member functions from a constructor

I know this question has a similar title to this: C++: calling member functions within constructor? but I am asking a more general question.
Is it good practice to call member functions from within a constructor? It makes reading the code easier and I prefer the encapsulation type way of doing it (ie. each block of code has a single objective).
An illustrative example, in python:
class TestClass:
def __init__(self):
self.validate()
def validate(self):
# this validates some data stored in the class
Is this a better way of doing it than writing the validate code inside the constructor? Are there drawbacks to this method? For example is it more costly with the function overhead?
I personally prefer it for readability but that's just my preference.
Cheers
I don't think there is anything inherently wrong in calling member functions from a constructor provided that they are not virtual functions.
The problem with calling virtual member functions from a constructor is that a subclass can override the function. This will cause the constructor to call the overridden implementation in the subclass, before the constructor for the subclass part of the object has been called.
In Java, any one of the private, static or final access modifiers will make the method safe to call from a constructor by preventing a virtual call to the superclass method. I don't think these techniques are available in Python.
There is at least one associated "gotcha" you should be aware of:
N3797 12.6.2/14
Member functions (including virtual member functions, 10.3) can be called for an object under construction. Similarly, an object under construction can be the operand of the typeid operator (5.2.8) or of a dynamic_cast (5.2.7). However, if these operations are performed in a ctor-initializer (or in a function called directly or indirectly from a ctor-initializer) before all the mem-initializers for base classes have completed, the result
of the operation is undefined. [Example:
class A {
public:
A(int);
};
class B : public A {
int j;
public:
int f();
B() : A(f()), // undefined: calls member function
// but base A not yet initialized
j(f()) { } // well-defined: bases are all initialized
};
class C {
public:
C(int);
};
class D : public B, C {
int i;
public:
D() : C(f()), // undefined: calls member function
// but base C not yet initialized
i(f()) { } // well-defined: bases are all initialized
};
— end example]
The main problem with this is that the member function has to work with an object that may be only partially initialized. And if it (even accidentally) passes a reference to the object somewhere else, other code has to od the same. This can get pretty confusing and error-prone, especially once you start overriding such a function in a subclass.
So in general, this practice should be avoided or at least confined to functions that can't be overriden, and they should never pass a reference to the object being constructed to any other code.
I'm more familiar with C++ than Python, but I see no problem with calling member functions from constructors, especially when this practice is able to factor out similar code from multiple constructors. Anything that reduces redundancy is good in my books.
From a readability point of view it is definitely better. One thing you might have to ask yourself here though is whether the validate method is allowed to run after the object is initialized. If that is not the case, you can a) use some kind of private initialized variable or b) use the Builder pattern to get your objects into a valid state before using them.
Make sure the function is private. You do not want to mess with subclasses overriding it (Unless this is desired by design, in which case make it abstract/virtual).
first, this member function cannnot be virtural function,
second, this member function must be implemented in the same file, if you declare it in *.h, then implement it in *.cpp, gcc/clang will report this error undefined reference to