inherited python vars in nested tornado templates - templates

I am trying to nest tornado templates using {% include %}:
<html>
{% for headline in HL['headlines'] %}
{% include 'hl_1.html' %}
{% end %}
</ul>
</body>
</html>
The template above works, and the sub-template above works. What I cannot figure out how to do is pass in the name of the sub-template (e.g.replacing 'hl_1.html' with a string parameter in the parent template's namespace). AFter reviewing the template.py source code it seems that {% include accepts a string and nothing else. But it would be fantastic if one could dynamically specify sub-templates.
Has anyone tried this and succeeded?
thanks

The way this is achieved usually is by using UI modules.
This is how I would structure your app.
First main.py:
import tornado.ioloop
import tornado.web
import views
class MainHandler(tornado.web.RequestHandler):
def get(self):
HL = {
'headlines': ['head1', 'head2', 'head3'],
}
self.render('tmpl.html', HL=HL)
if __name__ == "__main__":
application = tornado.web.Application([
(r"/", MainHandler),
], ui_modules=views)
application.listen(8888)
tornado.ioloop.IOLoop.instance().start()
Then your template tmpl.html:
<html>
{% for headline in HL['headlines'] %}
{% module Headline(headline) %}
{% end %}
</ul>
</body>
</html>
Finally, views.py, where you can define all your UI modules:
from tornado.web import UIModule
class Headline(UIModule):
def render(self, name):
return '<h1>%s</h1>' % name
UI modules are like "reusable templates", that accept parameters.

Related

Set script src to dynamic value when inheriting from base template in flask

So I have some flask code, and am wondering if there is any way to make the url inside the html dynamic. The flask code is as following:
from flask import Flask, render_template
app = Flask(__name__)
application = app
#app.route('/')
def index():
return render_template('index.html')
#app.route('/register')
def register():
return render_template('register.html')
if __name__ == '__main__':
app.run(debug=True)
In base.html, I have some code, and at the end, I have
<script src="{{ url_for('static', filename='js/base.js') }}"></script>
The code rendered results in:
<script src="/static/js/base.js"></script>
I'm having another html file inherit from base.html. index.html is below:
<h1>some code (the code doesn't really matter)</h1>
I want to be able to add a script tag at the end with it being <script src="/static/js/base.js"></script>, without adding anything. Is there any way to do that?
In other words, if the template is index.html, I want the script tag source to be index.js; if the template is challenge.html, I want the script tag source to be challenge.js.
You can use Jinja assignments (template variables) in the parent and set them in the child.
base.html
{% set main_js = main_js|default('') %}
{% if main_js %}
<script src="/static/js/{{ main_js }}.js"></script>
{% endif %}
index.html
{% extends 'base.html'%}
{% set main_js = 'index' %}
You can use the same technique for things like the page title, meta tags, etc.

Bootstrap templates auto-generated?

I'm having trouble setting up Flask-bootstrap. From the official documentation, it seems like all I have to do is apply the Bootstrap constructor to my app, and the templates will be automatically created. So I tried this:
from flask import Flask
from flask.ext.bootstrap import Bootstrap
app = Flask(__name__)
Bootstrap(app)
#app.route('/')
def index():
return '<h1>Where is Bootstrap?</h1>'
if __name__ == '__main__':
app.run(debug=True)
When I run it, no new directories are created and I find no base templates anywhere. Am I missing a critical step? Is there some directory to be created first (I tried creating templates and static and setting the permissions to 777 but that didn't help)? Or perhaps the base templates are first to be generated from the command line?
The base templates are part of the Flask-Bootstrap package you installed. You extend the boostrap base template and override the blocks in it to create a page with a standard layout. You still need to write bootstrap related markup. This is explained right in the docs you linked to.
my_project/templates/my_page.html:
{% extends "bootstrap/base.html" %}
{% block title %}This is an example page{% endblock %}
{% block navbar %}
<div class="navbar navbar-fixed-top">
<!-- ... -->
</div>
{% endblock %}
{% block content %}
<h1>Hello, Bootstrap</h1>
{% endblock %}

Django - Global navigation in base.html using model

I have a number of templates that extend base.html. I want the base.html template to house my global navigation and have the text and links in the global navigation be based on a model Division (i.e. the CharField in the model will be used as the button text in the global nav, and the id will be used to build the URL). I thought tags might work, but what I end up with is this (yes, I'm new to Django and Python):
current_tags.py
from django import template
# Import your model
from libs.display.models import Division
from django.db import models
register = template.Library()
#register.simple_tag
def do_get_divisions(self):
d = Division.objects.all()
mylist = []
for each in d:
mylist.append(str(each.DivisionValue))
return my list
I'm attempting just getting the text value in each object to print at this point because I can't get or work with the objects in the template, as you'll see below.
base.html
<!DOCTYPE html>
<html>
<head>
{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}style.css" />
</head>
<body>
{% load current_tags %}
<p>{% do_get_divisions "" %}</p> **THIS ACTUALLY PRINTS mylist**
{% for each in do_get_divisions %} **THIS DOESN'T PRINT ANYTHING**
<p>{{ each }}</p>
{% endfor %}
{% block content %}
{% endblock %}
</body>
</html>
I'm sure there is a better way to do global nav based on a model in Django. I basically want to get all the Division objects and put them into a <ul> to use as my global nav in base.html. I am not that familiar with Django, but my views.py don't help me because I am rendering other templates, not base.html, which are extending base.html. For what it's worth, here's one views.py, where /display/info.html template extends base.html:
# Create your views here.
from django.http import HttpResponse
from apps.pulldata.models import Data
from django.shortcuts import render, get_object_or_404
from django.http import Http404
def info(request, group_id):
group = get_object_or_404(Data, pk=group_id)
s = group.XInGroup.all()
return render(request, 'display/info.html', {'Group': group, 's': s})
You cannot put a templatetag into another. Your for-loop is a templatetag that expects the name of an element in your context to iterate over.
If you want to handle the navigation in a template tag you should consider using inclusion tags.
Inclusion tags are functions that use templates to render their data.
A very basic implementation could look something like this:
tags.py
#register.inclusion_tag('navigation.html')
def navigation(selected_id=None):
return {
'navigation': Division.objects.all(),
'selected':selected_id,
}
In your templatetag file you create a dictionary with the navigation items and optionally the currentl selected item to highlight this navigation element.
navigation.html
<ul>
{% for item in navigation %}
<li{% if item.id == selected %} class="selected"{% endif %}>
{{ item.DivisionValue }}
</li>
{% endfor %}
</ul>
the navigation.html uses the dictionary from the python function as context so you start with simply iterating over the navigation.
base.html
{% navigation %}
or
{% navigation current_division.id %}
In the base.html you call the inclusion tag like a normal template tag. if you want to highlight the current item you add its id as a argument.

how to get template working in django?

I was on the 3rd tutorial of this https://docs.djangoproject.com/en/1.5/intro/tutorial03/ site. I got stuck where we load template for our views under the section Write views that actually do something.
The first code is working fine ( as there is no template loading):
from django.http import HttpResponse
from polls.models import Poll
def index(request):
latest_poll_list = Poll.objects.order_by('-pub_date')[:5]
output = ', '.join([p.question for p in latest_poll_list])
return HttpResponse(output)
But when I laod the template with code below it shows same result as above( that is
with no template)
from django.http import HttpResponse
from django.template import Context, loader
from polls.models import Poll
def index(request):
latest_poll_list = Poll.objects.order_by('-pub_date')[:5]
template = loader.get_template('polls/index.html')
context = Context({
'latest_poll_list': latest_poll_list,
})
return HttpResponse(template.render(context))
The template use is:
{% if latest_poll_list %}
<ul>
{% for poll in latest_poll_list %}
<li>{{ poll.question }}</li>
{% endfor %}
</ul>
{% else %}
<p>No polls are available.</p>
{% endif %}
The template is in polls/template/polls/index.html where polls is my app( as used in tutorial)
PS:I have followed everything as it is till this point from tutorial.
As you can see in the Django documentation, django.template.loaders.app_directories.Loader looks for template files in a directory named templates inside the app directory.
You said that your template is in "polls/template/polls/index.html", but it should be in "polls/templates/polls/index.html" (notice the added s to templates).

How to implement breadcrumbs in a Django template?

Some solutions provided on doing a Google search for "Django breadcrumbs" include using templates and block.super, basically just extending the base blocks and adding the current page to it. http://www.martin-geber.com/thought/2007/10/25/breadcrumbs-django-templates/
http://www.djangosnippets.org/snippets/1289/ - provides a template tag but I'm not sure this would work if you don't have your urls.py properly declared.
I'm wondering what's the best way? And if you have implemented breadcrumbs before how did you do it?
--- Edit --
My question was meant to be: is there a general accepted method of doing breadcrumbs in Django, but from the answers I see there is not, and there are many different solutions, I'm not sure who to award the correct answer to, as I used a variation of using the block.super method, while all the below answers would work.
I guess then this is too much of a subjective question.
Note: I provide the full snippet below, since djangosnippets has been finicky lately.
Cool, someone actually found my snippet :-) The use of my template tag is rather simple.
To answer your question there is no "built-in" django mechanism for dealing with breadcrumbs, but it does provide us with the next best thing: custom template tags.
Imagine you want to have breadcrumbs like so:
Services -> Programming
Services -> Consulting
Then you will probably have a few named urls: "services", and "programming", "consulting":
(r'^services/$',
'core.views.services',
{},
'services'),
(r'^services/programming$',
'core.views.programming',
{},
'programming'),
(r'^services/consulting$',
'core.views.consulting',
{},
'consulting'),
Now inside your html template (lets just look at consulting page) all you have to put is:
//consulting.html
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Services' services %}
{% breadcrumb_url 'Consulting' consulting %}
{% endblock %}
If you want to use some kind of custom text within the breadcrumb, and don't want to link it, you can use breadcrumb tag instead.
//consulting.html
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Services' services %}
{% breadcrumb_url 'Consulting' consulting %}
{% breadcrumb 'We are great!' %}
{% endblock %}
There are more involved situations where you might want to include an id of a particular object, which is also easy to do. This is an example that is more realistic:
{% load breadcrumbs %}
{% block breadcrumbs %}
{% breadcrumb_url 'Employees' employee_list %}
{% if employee.id %}
{% breadcrumb_url employee.company.name company_detail employee.company.id %}
{% breadcrumb_url employee.full_name employee_detail employee.id %}
{% breadcrumb 'Edit Employee ' %}
{% else %}
{% breadcrumb 'New Employee' %}
{% endif %}
{% endblock %}
DaGood breadcrumbs snippet
Provides two template tags to use in your HTML templates: breadcrumb and breadcrumb_url. The first allows creating of simple url, with the text portion and url portion. Or only unlinked text (as the last item in breadcrumb trail for example). The second, can actually take the named url with arguments! Additionally it takes a title as the first argument.
This is a templatetag file that should go into your /templatetags directory.
Just change the path of the image in the method create_crumb and you are good to go!
Don't forget to {% load breadcrumbs %} at the top of your html template!
from django import template
from django.template import loader, Node, Variable
from django.utils.encoding import smart_str, smart_unicode
from django.template.defaulttags import url
from django.template import VariableDoesNotExist
register = template.Library()
#register.tag
def breadcrumb(parser, token):
"""
Renders the breadcrumb.
Examples:
{% breadcrumb "Title of breadcrumb" url_var %}
{% breadcrumb context_var url_var %}
{% breadcrumb "Just the title" %}
{% breadcrumb just_context_var %}
Parameters:
-First parameter is the title of the crumb,
-Second (optional) parameter is the url variable to link to, produced by url tag, i.e.:
{% url person_detail object.id as person_url %}
then:
{% breadcrumb person.name person_url %}
#author Andriy Drozdyuk
"""
return BreadcrumbNode(token.split_contents()[1:])
#register.tag
def breadcrumb_url(parser, token):
"""
Same as breadcrumb
but instead of url context variable takes in all the
arguments URL tag takes.
{% breadcrumb "Title of breadcrumb" person_detail person.id %}
{% breadcrumb person.name person_detail person.id %}
"""
bits = token.split_contents()
if len(bits)==2:
return breadcrumb(parser, token)
# Extract our extra title parameter
title = bits.pop(1)
token.contents = ' '.join(bits)
url_node = url(parser, token)
return UrlBreadcrumbNode(title, url_node)
class BreadcrumbNode(Node):
def __init__(self, vars):
"""
First var is title, second var is url context variable
"""
self.vars = map(Variable,vars)
def render(self, context):
title = self.vars[0].var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.vars[0]
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_unicode(title)
url = None
if len(self.vars)>1:
val = self.vars[1]
try:
url = val.resolve(context)
except VariableDoesNotExist:
print 'URL does not exist', val
url = None
return create_crumb(title, url)
class UrlBreadcrumbNode(Node):
def __init__(self, title, url_node):
self.title = Variable(title)
self.url_node = url_node
def render(self, context):
title = self.title.var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.title
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_unicode(title)
url = self.url_node.render(context)
return create_crumb(title, url)
def create_crumb(title, url=None):
"""
Helper function
"""
crumb = """<span class="breadcrumbs-arrow">""" \
"""<img src="/media/images/arrow.gif" alt="Arrow">""" \
"""</span>"""
if url:
crumb = "%s<a href='%s'>%s</a>" % (crumb, url, title)
else:
crumb = "%s %s" % (crumb, title)
return crumb
The Django admin view modules have automatic breadcumbs, which are implemented like this:
{% block breadcrumbs %}
<div class="breadcrumbs">
{% trans 'Home' %}
{% block crumbs %}
{% if title %} › {{ title }}{% endif %}
{% endblock %}
</div>
{% endblock %}
So there is some kind of built-in support for this..
My view functions emit the breadcrumbs as a simple list.
Some information is kept in the user's session. Indirectly, however, it comes from the URL's.
Breadcrumbs are not a simple linear list of where they've been -- that's what browser history is for. A simple list of where they've been doesn't make a good breadcrumb trail because it doesn't reflect any meaning.
For most of our view functions, the navigation is pretty fixed, and based on template/view/URL design. In our cases, there's a lot of drilling into details, and the breadcrumbs reflect that narrowing -- we have a "realm", a "list", a "parent" and a "child". They form a simple hierarchy from general to specific.
In most cases, a well-defined URL can be trivially broken into a nice trail of breadcrumbs. Indeed, that's one test for good URL design -- the URL can be interpreted as breadcrumbs and displayed meaningfully to the users.
For a few view functions, where we present information that's part of a "many-to-many" join, for example, there are two candidate parents. The URL may say one thing, but the session's context stack says another.
For that reason, our view functions have to leave context clues in the session so we can emit breadcrumbs.
Try django-breadcrumbs — a pluggable middleware that add a breadcrumbs callable/iterable in your request object.
It supports simple views, generic views and Django FlatPages app.
I had the same issue and finally I've made simple django tempalate tag for it: https://github.com/prymitive/bootstrap-breadcrumbs
http://www.djangosnippets.org/snippets/1289/ - provides a template tag but i'm not sure this would work if you don't have your urls.py properly declared.
Nothing will work if you don't have your urls.py properly declared. Having said that, it doesn't look as though it imports from urls.py. In fact, it looks like to properly use that tag, you still have to pass the template some variables. Okay, that's not quite true: indirectly through the default url tag, which the breadcrumb tag calls. But as far as I can figure, it doesn't even actually call that tag; all occurrences of url are locally created variables.
But I'm no expert at parsing template tag definitions. So say somewhere else in the code it magically replicates the functionality of the url tag. The usage seems to be that you pass in arguments to a reverse lookup. Again, no matter what your project is, you urls.py should be configured so that any view can be reached with a reverse lookup. This is especially true with breadcrumbs. Think about it:
home > accounts > my account
Should accounts, ever hold an arbitrary, hardcoded url? Could "my account" ever hold an arbitrary, hardcoded url? Some way, somehow you're going to write breadcrumbs in such a way that your urls.py gets reversed. That's really only going to happen in one of two places: in your view, with a call to reverse, or in the template, with a call to a template tag that mimics the functionality of reverse. There may be reasons to prefer the former over the latter (into which the linked snippet locks you), but avoiding a logical configuration of your urls.py file is not one of them.
Try django-mptt.
Utilities for implementing Modified Preorder Tree Traversal (MPTT) with your Django Model classes and working with trees of Model instances.
This answer is just the same as #Andriy Drozdyuk (link). I just want to edit something so it works in Django 3.2 (in my case) and good in bootstrap too.
for create_crumb function (Remove the ">" bug in the current code)
def create_crumb(title, url=None):
"""
Helper function
"""
if url:
crumb = '<li class="breadcrumb-item">{}</li>'.format(url, title)
else:
crumb = '<li class="breadcrumb-item active" aria-current="page">{}</li>'.format(title)
return crumb
And for __init__ in BreadcrumbNode, add list() to make it subscriptable. And change smart_unicode to smart_text in render method
from django.utils.encoding import smart_text
class BreadcrumbNode(Node):
def __init__(self, vars):
"""
First var is title, second var is url context variable
"""
self.vars = list(map(Variable, vars))
def render(self, context):
title = self.vars[0].var
if title.find("'")==-1 and title.find('"')==-1:
try:
val = self.vars[0]
title = val.resolve(context)
except:
title = ''
else:
title=title.strip("'").strip('"')
title=smart_text(title)
And add this in base.html for the view for Bootstrap. Check the docs
<nav style="--bs-breadcrumb-divider: '>';" aria-label="breadcrumb">
<ol class="breadcrumb">
{% block breadcrumbs %}
{% endblock breadcrumbs %}
</ol>
</nav>
Obviously, no one best answer, but for practical reason I find that it is worth considering the naïve way. Just overwrite and rewrite the whole breadcrumb... (at least until the official django.contrib.breadcrumb released )
Without being too fancy, it is better to keep things simple. It helps the newcomer to understand. It is extremely customizable (e.g. permission checking, breadcrumb icon, separator characters, active breadcrumb, etc...)
Base Template
<!-- File: base.html -->
<html>
<body>
{% block breadcrumb %}
<ul class="breadcrumb">
<li>Dashboard</li>
</ul>
{% endblock breadcrumb %}
{% block content %}{% endblock content %}
</body>
</html>
Implementation Template
Later on each pages we rewrite and overwrite the whole breadcrumb block.
<!-- File: page.html -->
{% extends 'base.html' %}
{% block breadcrumb %}
<ul class="breadcrumb">
<li>Dashboard</li>
<li>Level 1</li>
<li class="active">Level 2</li>
</ul>
{% endblock breadcrumb %}
Practicallity
Realworld use cases:
Django Oscar: base template, simple bread
Django Admin: base template, simple bread, permission check breadcrumb
You could also reduce the boiler plate required to manage breadcrumbs using django-view-breadcrumbs, by adding a crumbs property to the view.
urls.py
urlpatterns = [
...
path('posts/<slug:slug>', views.PostDetail.as_view(), name='post_detail'),
...
]
views.py
from django.views.generic import DetailView
from view_breadcrumbs import DetailBreadcrumbMixin
class PostDetail(DetailBreadcrumbMixin, DetailView):
model = Post
template_name = 'app/post/detail.html'
base.html
{% load django_bootstrap_breadcrumbs %}
{% block breadcrumbs %}
{% render_breadcrumbs %}
{% endblock %}
Something like this may work for your situation:
Capture the entire URL in your view and make links from it. This will require modifying your urls.py, each view that needs to have breadcrumbs, and your templates.
First you would capture the entire URL in your urls.py file
original urls.py
...
(r'^myapp/$', 'myView'),
(r'^myapp/(?P<pk>.+)/$', 'myOtherView'),
...
new urls.py
...
(r'^(?P<whole_url>myapp/)$', 'myView'),
(r'^(?P<whole_url>myapp/(?P<pk>.+)/)$', 'myOtherView'),
...
Then in your view something like:
views.py
...
def myView(request, whole_url):
# dissect the url
slugs = whole_url.split('/')
# for each 'directory' in the url create a piece of bread
breadcrumbs = []
url = '/'
for slug in slugs:
if slug != '':
url = '%s%s/' % (url, slug)
breadcrumb = { 'slug':slug, 'url':url }
breadcrumbs.append(breadcrumb)
objects = {
'breadcrumbs': breadcrumbs,
}
return render_to_response('myTemplate.html', objects)
...
Which should be pulled out into a function that gets imported into the views that need it
Then in your template print out the breadcrumbs
myTemplate.html
...
<div class="breadcrumb-nav">
<ul>
{% for breadcrumb in breadcrumbs %}
<li>{{ breadcrumb.slug }}</li>
{% endfor %}
</ul>
</div>
...
One shortcoming of doing it this way is that as it stands you can only show the 'directory' part of the url as the link text. One fix for this off the top of my head (probably not a good one) would be to keep a dictionary in the file that defines the breadcrumb function.
Anyways that's one way you could accomplish breadcrumbs, cheers :)
You might want to try django-headcrumbs (don’t worry, they are not going to eat your brains).
It’s very lightweight and absolutely straightforward to use, all you have to do is annotate your views (because defining crumbs structure in templates sounds crazy to me) with a decorator that explains how to get back from the given view.
Here is an example from the documentation:
from headcrumbs.decorators import crumb
from headcrumbs.util import name_from_pk
#crumb('Staff') # This is the root crumb -- it doesn’t have a parent
def index(request):
# In our example you’ll fetch the list of divisions (from a database)
# and output it.
#crumb(name_from_pk(Division), parent=index)
def division(request, slug):
# Here you find all employees from the given division
# and list them.
There are also some utility functions (e.g. name_from_pk you can see in the example) that automagically generate nice names for your crumbs without you having to wright lots of code.
I've created template filter for this.
Apply your custom filter (I've named it 'makebreadcrumbs') to the request.path like this:
{% with request.resolver_match.namespace as name_space %}
{{ request.path|makebreadcrumbs:name_space|safe }}
{% endwith %}
We need to pass url namespace as an arg to our filter.
Also use safe filter, because our filter will be returning string that needs to be resolved as html content.
Custom filter should look like this:
#register.filter
def makebreadcrumbs(value, arg):
my_crumbs = []
crumbs = value.split('/')[1:-1] # slice domain and last empty value
for index, c in enumerate(crumbs):
if c == arg and len(crumbs) != 1:
# check it is a index of the app. example: /users/user/change_password - /users/ is the index.
link = '{}'.format(reverse(c+':index'), c)
else:
if index == len(crumbs)-1:
link = '<span>{}</span>'.format(c)
# the current bread crumb should not be a link.
else:
link = '{}'.format(reverse(arg+':' + c), c)
my_crumbs.append(link)
return ' > '.join(my_crumbs)
# return whole list of crumbs joined by the right arrow special character.
Important:
splited parts of the 'value' in our filter should be equal to the namespace in the urls.py, so the reverse method can be called.
Hope it helped.
A generic way, to collect all callable paths of the current url could be resolved by the following code snippet:
from django.urls import resolve, Resolver404
path_items = request.path.split("/")
path_items.pop(0)
path_tmp = ""
breadcrumb_config = OrderedDict()
for path_item in path_items:
path_tmp += "/" + path_item
try:
resolve(path_tmp)
breadcrumb_config[path_item] = {'is_representative': True, 'current_path': path_tmp}
except Resolver404:
breadcrumb_config[path_item] = {'is_representative': False, 'current_path': path_tmp}
If the resolve function can't get a real path from any urlpattern, the Resolver404 exception will be thrown. For those items we set the is_representative flag to false. The OrderedDict breadcrumb_config holds after that the breadcrumb items with there configuration.
For bootstrap 4 breadcrumb for example, you can do something like the following in your template:
<nav aria-label="breadcrumb">
<ol class="breadcrumb">
{% for crumb, values in BREADCRUMB_CONFIG.items %}
<li class="breadcrumb-item {% if forloop.last or not values.is_representative %}active{% endif %}" {% if forloop.last %}aria-current="page"{% endif %}>
{% if values.is_representative %}
<a href="{{values.current_path}}">
{{crumb}}
</a>
{% else %}
{{crumb}}
{% endif %}
</li>
{% endfor %}
</ol>
</nav>
Only the links which won't raises a 404 are clickable.
I believe there is nothing simpler than that (django 3.2):
def list(request):
return render(request, 'list.html', {
'crumbs' : [
("Today", "https://www.python.org/"),
("Is", "https://www.python.org/"),
("Sunday", "https://www.djangoproject.com/"),
]
})
Breadcrumbs.html
<div class="page-title-right">
<ol class="breadcrumb m-0">
{% if crumbs %}
{% for c in crumbs %}
<li class="breadcrumb-item {{c.2}}">{{c.0}}</li>
{% endfor %}
{% endif %}
</ol>
</div>
css:
.m-0 {
margin: 0!important;
}
.breadcrumb {
display: flex;
flex-wrap: wrap;
padding: 0 0;
margin-bottom: 1rem;
list-style: none;
border-radius: .25rem;
}
dl, ol, ul {
margin-top: 0;
margin-bottom: 1rem;
}
ol, ul {
padding-left: 2rem;
}