For example:
http://foobar.com/foo/bar/foobar.php
From this address, I need to extract the following:
http://foobar.com/foo/bar
I have tried with the following regex:
(?<namespace>.*)/.*?
but returned value is
http:
Can anyone help? Thanks.
Try this:
^(?<namespace>.*)/[^/]+$
A quick explanation:
^ # the start of input
(?<namespace>.*)/ # zero or more chars followed by a '/' (which the last '/')
[^/]+ # one or more chars other than '/'
$ # the end of input
I think a regex is overkill here. What programming language are you using? This would be how it's done in JavaScript.
var url = 'http://foobar.com/foo/bar/foobar.php'
url.split('/').slice(0,-1).join('/')
You could even use substr for some performance!
var url = 'http://foobar.com/foo/bar/foobar.php'
url.substr(0, url.lastIndexOf('/'))
The only reason I offered the array way is because I'm not sure of cross browser compatibility on lastIndexOf.
Try with this expression:
^(?<namespace>.*)/.*$
Related
I have a challenge getting the desired result with RegEx (using C#) and I hope that the community can help.
I have a URL in the following format:
https://somedomain.com/subfolder/category/?abc=text:value&ida=0&idb=1
I want make two modifications, specifically:
1) Remove everything after 'value' e.g. '&ida=0&idb=1'
2) Replace 'category' with e.g. 'newcategory'
So the result is:
https://somedomain.com/subfolder/newcategory/?abc=text:value
I can remove the string from 1) e.g. ^[^&]+ above but I have been unable to figure out how to replace the 'category' substring.
Any help or guidance would be much appreciated.
Thank you in advance.
Use the following:
Find: /(category/.+?value)&.+
Replace: /new$1 or /new\1 depending on your regex flavor
Demo & explanation
Update according to comment.
If the new name is completely_different_name, use the following:
Find: /category(/.+?value)&.+
Replace: /completely_different_name$1
Demo & explanation
You haven't specified language here, I mainly work on python so the solution is in python.
url = re.sub('category','newcategory',re.search('^https.*value', value).group(0))
Explanation
re.sub is used to replace value a with b in c.
re.search is used to match specific patterns in string and store value in the group. so in the above code re.search will store value from "https to value" in group 0.
Using Python and only built-in string methods (there is no need for regular expressions here):
url = r"https://somedomain.com/subfolder/category/?abc=text:value&ida=0&idb=1"
new_url = (url.split('value')[0] + "value").replace("category", 'newcategory')
print(new_url)
Outputs:
https://somedomain.com/subfolder/newcategory/?abc=text:value
I'm trying to write wordpress pretty permalinks regex.
I have following urls. I need 2 matches,
1st : last word between / and / before get/
2nd : string which is start with get/
Url's may be like these
http://localhost/akasia/yacht-technical-services/yacht-crew/get/gulets/for/sale/
Here I need "yacht-crew" and "get/gulets/for/sale/"
http://localhost/akasia/testimonials/get/motoryachts/for/sale/
here I need "testimonials" and get/motoryachts/for/sale/
http://localhost/akasia/may/be/lots/of/seperator/but/ineed/last/get/ships/for/rent/
here I need "last" and get/ships/for/rent/
I catch 2nd part with
(.(get/(.)?))
but for first part there is no luck.
I will be appreciated if someone helps.
Regards
Deniz
I suggest the following:
([^\/]+?)\/(get\/.+)
https://regex101.com/r/uN6yH3/1
The concept is that you match non-slash characters up to the first slash (non-greedy) that is followed by the word "get" grouping it, and then just grab the rest as the second group.
I am assuming PHP.
$path = parse_url($url,PHP_URL_PATH);
$s = strrpos($path,'/');
$matches[] = substr($path,$s+1);
I am trying to write a regex to get the filename from a url if it exists.
This is what I have so far:
(?:[^/][\d\w\.]+)+$
So from the url http://www.foo.com/bar/baz/filename.jpg, I should match filename.jpg
Unfortunately, I match anything after the last /.
How can I tighten it up so it only grabs it if it looks like a filename?
The examples above fails to get file name "file-1.name.zip" from this URL:
"http://sub.domain.com/sub/sub/handler?file=data/file-1.name.zip&v=1"
So I created my REGEX version:
[^/\\&\?]+\.\w{3,4}(?=([\?&].*$|$))
Explanation:
[^/\\&\?]+ # file name - group of chars without URL delimiters
\.\w{3,4} # file extension - 3 or 4 word chars
(?=([\?&].*$|$)) # positive lookahead to ensure that file name is at the end of string or there is some QueryString parameters, that needs to be ignored
This one works well for me.
(\w+)(\.\w+)+(?!.*(\w+)(\.\w+)+)
(?:.+\/)(.+)
Select all up to the last forward slash (/), capture everything after this forward slash. Use subpattern $1.
Non Pcre
(?:[^/][\d\w\.]+)$(?<=\.\w{3,4})
Pcre
(?:[^/][\d\w\.]+)$(?<=(?:.jpg)|(?:.pdf)|(?:.gif)|(?:.jpeg)|(more_extension))
Demo
Since you test using regexpal.com that is based on javascript(doesnt support lookbehind), try this instead
(?=\w+\.\w{3,4}$).+
I'm using this:
(?<=\/)[^\/\?#]+(?=[^\/]*$)
Explanation:
(?<=): positive look behind, asserting that a string has this expression, but not matching it.
(?<=/): positive look behind for the literal forward slash "/", meaning I'm looking for an expression which is preceded, but does not match a forward slash.
[^/\?#]+: one or more characters which are not either "/", "?" or "#", stripping search params and hash.
(?=[^/]*$): positive look ahead for anything not matching a slash, then matching the line ending. This is to ensure that the last forward slash segment is selected.
Example usage:
const urlFileNameRegEx = /(?<=\/)[^\/\?#]+(?=[^\/]*$)/;
const testCases = [
"https://developer.mozilla.org/en-US/docs/Web/API/MutationObserverInit#yo",
"https://developer.mozilla.org/static/fonts/locales/ZillaSlab-Regular.subset.bbc33fb47cf6.woff2",
"https://developer.mozilla.org/static/build/styles/locale-en-US.520ecdcaef8c.css?is-nice=true"
];
testCases.forEach(testStr => console.log(`The file of ${testStr} is ${urlFileNameRegEx.exec(testStr)[0]}`))
It might work as well:
(\w+\.)+\w+$
You know what your delimiters look like, so you don't need a regex. Just split the string. Since you didn't mention a language, here's an implementation in Perl:
use strict;
use warnings;
my $url = "http://www.foo.com/bar/baz/filename.jpg";
my #url_parts = split/\//,$url;
my $filename = $url_parts[-1];
if(index($filename,".") > 0 )
{
print "It appears as though we have a filename of $filename.\n";
}
else
{
print "It seems as though the end of the URL ($filename) is not a filename.\n";
}
Of course, if you need to worry about specific filename extensions (png,jpg,html,etc), then adjust appropriately.
> echo "http://www.foo.com/bar/baz/filename.jpg" | sed 's/.*\/\([^\/]*\..*\)$/\1/g'
filename.jpg
Assuming that you will be using javascript:
var fn=window.location.href.match(/([^/])+/g);
fn = fn[fn.length-1]; // get the last element of the array
alert(fn.substring(0,fn.indexOf('.')));//alerts the filename
Here is the code you may use:
\/([\w.][\w.-]*)(?<!\/\.)(?<!\/\.\.)(?:\?.*)?$
names "." and ".." are not considered as normal.
you can play with this regexp here https://regex101.com/r/QaAK06/1/:
In case you are using the JavaScript URL object, you can use the pathname combined with the following RegExp:
.*\/(.[^(\/)]+)
Benefit:
It matches anything at the end of the path, but excludes a possible trailing slash (as long as there aren't two trailing slashes)!
Try this one instead:
(?:[^/]*+)$(?<=\..*)
This is worked for me, no matter if you have '.' or without '.' it take the sufix of url
\/(\w+)[\.|\w]+$
I am trying to get the content between Start and End tag for the below mentioned strings
Products
Services & Solution
Regex used:
<([a-z0-9]+)([^<]+)\*(?:>(.\*?)</\\2>|\\D+/>)
It is working fine for the first string but not with the later once
Why so complex? Won't simple />([^<]+)</ capture the content of an element?
Depending on the flavour of regex - use lookahead and lookbehind methods to get just the match between > and < i.e.
(?<=>)[^>]*(?=<)
(?<=>) - looks ahead for a >
(?=<) - looks behind for a <
[^>]* - matches the text in the link itself
lookahead and lookbehind are zero width matches so will will just get what you need
Usually you don't want to parse HTML your self with regex, parser are better at that.
Assuming you are using PCRE here's a random guess at the expression you are looking for:
(?is)<([a-z]+)\b[^<>]*(?:>(.*?)</\1>|/>)
Note that this will not work with nested tags.
Just get rid of the tags.
var str = 'Products '
var str2 = 'Services & Solution '
var RE_findOpenAndCloseTag = /^<[^>]+>|<\/[^>]>$/g;
str.replace( RE_findOpenAndCloseTag, '' ) == "Products ";
str2.replace( RE_findOpenAndCloseTag, '' ) == "Services & Solution ";
Note that RE_findOpenAndCloseTag assumes that tags will always start with a < and not contain an > unless it's closing the tag.
Thus this will fail.
'>">This will fail
But an easier way would be to convert the tags into a node, then get the innerHTML.
Try this it will resolve your issue (Just Add |</\1>)
<([a-z0-9]+)([^<]+)*(?:>(.*?)|\D+/>|</\1>)
For more detail please refer
Here's the regular expression I use, and I parse it using CAtlRegExp of MFC :
(((h|H?)(t|T?)(t|T?)(p|P?)(s|S?))://)?([a-zA-Z0-9]+[\.]+[a-zA-Z0-9]+[\.]+[a-zA-Z0-9])
It works fine except with one flaw. When URL is preceded by characters, it still accepts it as a URL.
ex inputs:
this is a link www.google.com (where I can just tokenize the spaces and validate each word)
is...www.google.com (this string still matches the RegEx above :( )
Please help...
Thanks...
Use the IgnoreCase flag instead of catering for each case.
Stick a ^ at the beginning if you want the start of the string to be the start of the URL
You're missing a lot of characters from possible, valid URLs.
You need to tell the regex to only match at the start and end of the string. I'm not sure how you do that in VC++ - in most regexs you enclose the pattern with ^ and $. The ^ says "the start of the string" and the $ says "the end of the string."
^(((h|H?)(t|T?)(t|T?)(p|P?)(s|S?))\://)?([a-zA-Z0-9]+[\\.]+[a-zA-Z0-9]+[\\.]+[a-zA-Z0-9])$
The second is matching because the string still contains a valid URL.
How about using CUrl (that is, 'C-Url', in ATL, not curl as in libcurl) which can 'parse' urls with CUrl::CrackUrl . If that function returns FALSE you assume it's not a valid URL.
That said, decomposing URL is sufficiently complex to warrant a proper parser, not a regex based decomposition. Cfr. rfc 2396 etc. for an overview on the complexities.
Start the regex with ^ to and end it with $ to have the regex match only if the entire sting matches (if that's what you want):
^(((h|H?)(t|T?)(t|T?)(p|P?)(s|S?))\://)?([a-zA-Z0-9]+[\.]+[a-zA-Z0-9]+[\.]+[a-zA-Z0-9])$
What about this one: (((f|ht)tp://)[-a-zA-Z0-9#:%_\+.~#?&//=]+) ?
This Regular Expression has been tested to work for the following
http|https://host[:port]/[?][parameter=value]*
public static final String URL_PATTERN = "(https?|ftp)://(www\\.)?(((([a-zA-Z0-9.-]+\\.){1,}[a-zA-Z]{2,4}|localhost))|((\\d{1,3}\\.){3}(\\d{1,3})))(:(\\d+))?(/([a-zA-Z0-9-._~!$&'()*+,;=:#/]|%[0-9A-F]{2})*)?(\\?([a-zA-Z0-9-._~!$&'()*+,;=:/?#]|%[0-9A-F]{2})*)?(#([a-zA-Z0-9._-]|%[0-9A-F]{2})*)?";
PS. It also validates on localhost link.
(Thoroughly written by me :-))