Need help coding a CriteriaQuery "in" predicate - jpa-2.0

Question

I have a query that I have been trying to turn into a CriteraQuery, but I don't get how to code the "IN" term of the query.
The JPA Query that works looks like this:
#NamedQuery(name = "User.fromSearchID",
query = "SELECT q FROM User q,"
+ " IN (q.data) AS s WHERE s.data LIKE :search"
+ " ORDER BY q.id")
And the entity that it works on looks like this:
#Entity
public class User {
#Id private Integer id;
#OneToMany private List<UserData> data;
... }
And the referenced entity is
#Entity
public class UserData {
#Id private Long id;
private String key;
private String data;
... }
The intended result (the NamedQuery works) is to pull out all User entities that have some match in their list of data attributes. For some reason the CriteraQuery syntax escapes my intuition. Any help?

Answer 1

I assume users should be unique?
Then JP QL version without rather old fashion IN is:
String searchArgument = "data1";
String query = " SELECT DISTINCT(u) " +
" FROM User u JOIN u.data ud " +
" WHERE ud.data LIKE :search ORDER BY u.id";
List<User> result =em.createQuery(query, User.class).
setParameter("search", searchArgument).getResultList();
And same via Criteria API:
String searchArgument = "data1";
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<User> cq = cb.createQuery(User.class);
Root<User> user = cq.from(User.class);
Predicate dataLike = cb.like(user.join("data").<String>get("data"),
cb.parameter(String.class, "search"));
cq.distinct(true).select(user)
.where(dataLike)
.orderBy(cb.asc(user.get("id")));
TypedQuery<User> findUniqueUserByUserDataData = em.createQuery(cq);
findUniqueUserByUserDataData.setParameter("search", searchArgument);