Replace XML fragments using XSLT? - xslt

Question

I've got this bit of XML:
<?xml version="1.0" encoding="UTF-8"?>
<photo-caption>
<p>
<?EM-dummyText caption?>
<ld pattern=" "/>
<s2>Photo </s2>
<source>
<?EM-dummyText photographer?>
</source>
</p>
</photo-caption>
I want this output:
<?xml version="1.0" encoding="UTF-8"?>
<photo-caption>
<p>
<s2><?EM-dummyText heading?></s2>
<?EM-dummyText caption?>
</p>
</photo-caption>
This is the XSLT I'm using at the moment:
<xsl:stylesheet version="1.0"
exclude-result-prefixes="subst"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:subst="http://tempuri.org">
<xsl:strip-space elements="*"/>
<xsl:output method="xml" encoding="utf-8" indent="yes"/>
<subst:photo-caption>
<p>
<s2>
<?EM-dummyText heading?>
</s2>
<?EM-dummyText caption?>
</p>
</subst:photo-caption>
<xsl:variable name="subst" select="document('')/*/subst:photo-caption"/>
<xsl:template match="photo-caption">
<xsl:copy-of select="$subst"/>
</xsl:template>
</xsl:stylesheet>
... which yields this the output:
<?xml version="1.0" encoding="utf-8"?>
<subst:photo-caption xmlns:subst="http://tempuri.org" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<p>
<s2><?EM-dummyText heading?></s2><?EM-dummyText caption?>
</p>
</subst:photo-caption>
How do I remove the prefixes and namespace attributes from the output? Or is there a better way to do this?

Answer 1

If you simply want to output that fragment then use
<xsl:template match="photo-caption">
<photo-caption>
<p>
<s2>
<xsl:processing-instruction name="EM-dummyText">heading</xsl:processing-instruction>
</s2>
<xsl:processing-instruction name="EM-dummyText">caption</xsl:processing-instruction>
</p>
</photo-caption>
</xsl:template>