Speed difference between If-Else and Ternary operator in C...? - c++

So at the suggestion of a colleague, I just tested the speed difference between the ternary operator and the equivalent If-Else block... and it seems that the ternary operator yields code that is between 1x and 2x faster than If-Else. My code is:
gettimeofday(&tv3, 0);
for(i = 0; i < N; i++)
{
a = i & 1;
if(a) a = b; else a = c;
}
gettimeofday(&tv4, 0);
gettimeofday(&tv1, 0);
for(i = 0; i < N; i++)
{
a = i & 1;
a = a ? b : c;
}
gettimeofday(&tv2, 0);
(Sorry for using gettimeofday and not clock_gettime... I will endeavor to better myself.)
I tried changing the order in which I timed the blocks, but the results seem to persist. What gives? Also, the If-Else shows much more variability in terms of execution speed. Should I be examining the assembly that gcc generates?
By the way, this is all at optimization level zero (-O0).
Am I imagining this, or is there something I'm not taking into account, or is this a machine-dependent thing, or what? Any help is appreciated.

There's a good chance that the ternary operator gets compiled into a cmov while the if/else results in a cmp+jmp. Just take a look at the assembly (using -S) to be sure. With optimizations enabled, it won't matter any more anyway, as any good compiler should produce the same code in both cases.

You could also go completely branchless and measure if it makes any difference:
int m = -(i & 1);
a = (b & m) | (c & ~m);
On today's architectures, this style of programming has grown a bit out of fashion.

This is a nice explanation: http://www.nynaeve.net/?p=178
Basically, there are "conditional set" processor instructions, which is faster than branching and setting in separate instructions.

If there is any, change your compiler!
For this kind of questions I use the Try Out LLVM page. It's an old release of LLVM (still using the gcc front-end), but those are old tricks.
Here is my little sample program (simplified version of yours):
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
int main (int argc, char* argv[]) {
int N = atoi(argv[0]);
int a = 0, d = 0, b = atoi(argv[1]), c = atoi(argv[2]);
int i;
for(i = 0; i < N; i++)
{
a = i & 1;
if(a) a = b+i; else a = c+i;
}
for(i = 0; i < N; i++)
{
d = i & 1;
d = d ? b+i : c+i;
}
printf("%d %d", a, d);
return 0;
}
And there is the corresponding LLVM IR generated:
define i32 #main(i32 %argc, i8** nocapture %argv) nounwind {
entry:
%0 = load i8** %argv, align 8 ; <i8*> [#uses=1]
%N = tail call i32 #atoi(i8* %0) nounwind readonly ; <i32> [#uses=5]
%2 = getelementptr inbounds i8** %argv, i64 1 ; <i8**> [#uses=1]
%3 = load i8** %2, align 8 ; <i8*> [#uses=1]
%b = tail call i32 #atoi(i8* %3) nounwind readonly ; <i32> [#uses=2]
%5 = getelementptr inbounds i8** %argv, i64 2 ; <i8**> [#uses=1]
%6 = load i8** %5, align 8 ; <i8*> [#uses=1]
%c = tail call i32 #atoi(i8* %6) nounwind readonly ; <i32> [#uses=2]
%8 = icmp sgt i32 %N, 0 ; <i1> [#uses=2]
br i1 %8, label %bb, label %bb11
bb: ; preds = %bb, %entry
%9 = phi i32 [ %10, %bb ], [ 0, %entry ] ; <i32> [#uses=2]
%10 = add nsw i32 %9, 1 ; <i32> [#uses=2]
%exitcond22 = icmp eq i32 %10, %N ; <i1> [#uses=1]
br i1 %exitcond22, label %bb10.preheader, label %bb
bb10.preheader: ; preds = %bb
%11 = and i32 %9, 1 ; <i32> [#uses=1]
%12 = icmp eq i32 %11, 0 ; <i1> [#uses=1]
%.pn13 = select i1 %12, i32 %c, i32 %b ; <i32> [#uses=1]
%tmp21 = add i32 %N, -1 ; <i32> [#uses=1]
%a.1 = add i32 %.pn13, %tmp21 ; <i32> [#uses=2]
br i1 %8, label %bb6, label %bb11
bb6: ; preds = %bb6, %bb10.preheader
%13 = phi i32 [ %14, %bb6 ], [ 0, %bb10.preheader ] ; <i32> [#uses=2]
%14 = add nsw i32 %13, 1 ; <i32> [#uses=2]
%exitcond = icmp eq i32 %14, %N ; <i1> [#uses=1]
br i1 %exitcond, label %bb10.bb11_crit_edge, label %bb6
bb10.bb11_crit_edge: ; preds = %bb6
%15 = and i32 %13, 1 ; <i32> [#uses=1]
%16 = icmp eq i32 %15, 0 ; <i1> [#uses=1]
%.pn = select i1 %16, i32 %c, i32 %b ; <i32> [#uses=1]
%tmp = add i32 %N, -1 ; <i32> [#uses=1]
%d.1 = add i32 %.pn, %tmp ; <i32> [#uses=1]
br label %bb11
bb11: ; preds = %bb10.bb11_crit_edge, %bb10.preheader, %entry
%a.0 = phi i32 [ %a.1, %bb10.bb11_crit_edge ], [ %a.1, %bb10.preheader ], [ 0, %entry ] ; <i32> [#uses=1]
%d.0 = phi i32 [ %d.1, %bb10.bb11_crit_edge ], [ 0, %bb10.preheader ], [ 0, %entry ] ; <i32> [#uses=1]
%17 = tail call i32 (i8*, ...)* #printf(i8* noalias getelementptr inbounds ([6 x i8]* #.str, i64 0, i64 0), i32 %a.0, i32 %d.0) nounwind ; <i32> [#uses=0]
ret i32 0
}
Okay, so it's likely to be chinese, even though I went ahead and renamed some variables to make it a bit easier to read.
The important bits are these two blocks:
%.pn13 = select i1 %12, i32 %c, i32 %b ; <i32> [#uses=1]
%tmp21 = add i32 %N, -1 ; <i32> [#uses=1]
%a.1 = add i32 %.pn13, %tmp21 ; <i32> [#uses=2]
%.pn = select i1 %16, i32 %c, i32 %b ; <i32> [#uses=1]
%tmp = add i32 %N, -1 ; <i32> [#uses=1]
%d.1 = add i32 %.pn, %tmp ; <i32> [#uses=1]
Which respectively set a and d.
And the conclusion is: No difference
Note: in a simpler example the two variables actually got merged, it seems here that the optimizer did not detect the similarity...

Any decent compiler should generate the same code for these if optimisation is turned on.

Understand that it's entirely up to the compiler how it interprets ternary expression (unless you actually force it not to with (inline) asm). It could just as easily understand ternary expression as 'if..else' in its Internal Representation language, and depending on the target backend, it may choose to generate conditional move instruction (on x86, CMOVcc is such one. There should also be ones for min/max, abs, etc). The main motivation of using conditional move is to transfer the risk of branch mispredict to a memory/register move operation. The caveat to this instruction is that nearly all the time, the operand register that will be conditionally loaded will have to be evaluated down to register form to take advantage of the cmov instruction.
This means that the unconditional evaluation process now has to be unconditional, and this will appear to increase the length of the unconditional path of the program. But understand that branch mispredict is most often resolved as 'flushing' the pipeline, which means that the instructions that would have finished executing are ignored (turned to No Operation instructions). This means that the actual number of instructions executed is higher because of the stalls or NOPs, and the effect scales with the depth of the processor pipeline and the misprediction rate.
This brings an interesting dilemma in determining the right heuristics. First, we know for sure that if the pipeline is too shallow or the branch prediction is fully able to learn pattern from branch history, then cmov is not worth doing. It's also not worth doing if the cost of evaluation of conditional argument is greater on than the cost from misprediction on average.
These are perhaps the core reasons why compilers have difficulty exploiting cmov instruction, since the heuristics determination is largely dependent on the runtime profiling information. It makes more sense to use this on JIT compiler since it can provide runtime instrumentation feedback and build a stronger heuristics for using this ("Is the branch truly unpredictable?"). On static compiler side without training data or profiler, it's most difficult to assume when this will be useful. However, a simple negative heuristic is, as aforementioned, if the compiler knows that the dataset is completely random or forcing cond. to uncond. evaluation is costly (perhaps due to irreducible, costly operations like fp divides), it would make good heuristics not to do this.
Any compiler worth its salt will do all that. Question is, what will it do after all dependable heuristics have been used up...

Related

Delete complete branch from llvm ir

There is a branch in ir that I want to delete completely(condtion + branch + true_basic_block + false_basic_block). It looks like this:
%4 = icmp sge i32 %2, %3
br i1 %4, label %5, label %7
; <label>:5 ; preds = %0
%6 = load i32* %x, align 4
store i32 %6, i32* %z, align 4
br label %9
; <label>:7 ; preds = %0
%8 = load i32* %y, align 4
store i32 %8, i32* %z, align 4
br label %9
; <label>:9 ; preds = %7, %5
%10 = call dereferenceable(140) %"class.std::basic_ostream"*#_ZStlsISt11char_traitsIcEERSt13basic_ostreamIcT_ES5_PKc(%"class.std::basic_ostream"* dereferenceable(140) #_ZSt4cout, i8* getelementptr inbounds ([5 x i8]* #.str, i32 0, i32 0))
%11 = load i32* %z, align 4
%12 = call dereferenceable(140) %"class.std::basic_ostream"* #_ZNSolsEi(%"class.std::basic_ostream"* %10, i32 %11)
%13 = call dereferenceable(140) %"class.std::basic_ostream"* #_ZNSolsEPFRSoS_E(%"class.std::basic_ostream"* %12, %"class.std::basic_ostream"* (%"class.std::basic_ostream"*)* #_ZSt4endlIcSt11char_traitsIcEERSt13basic_ostreamIT_T0_ES6_)
ret i32 0
Now to delete it , is there a removeBranch function , or do I need to delete instructions one by one. I have been trying the latter way but I have seen every error from "Basic block in main does not have an terminator" to "use remains when def is destroyed", and many more.. I have used erasefromparent, replaceinstwithvalue, replaceinstwithinst, removefromparent, etc.
Can anyone be kind enough to point me in the correct direction?
This is my function_pass :
bool runOnFunction(Function &F) override {
for (auto& B : F)
for (auto& I : B)
if(auto* brn = dyn_cast<BranchInst>(&I))
if(brn->isConditional()){
Instruction* cond = dyn_cast<Instruction>(brn->getCondition());
if(cond->getOpcode() == Instruction::ICmp){
branch_vector.push_back(brn);
//removeConditionalBranch(dyn_cast<BranchInst>(brn));
}
}
/*For now just delete the branches in the vector.*/
for(auto b : branch_vector)
removeConditionalBranch(dyn_cast<BranchInst>(b));
return true;
}
This is the output :
I don't know of any RemoveBranch utility function, but something like this should work. The idea is to delete the branch instruction, then delete anything that becomes dead as a result, and then merge the initial block with the join block.
// for DeleteDeadBlock, MergeBlockIntoPredecessor
#include "llvm/Transforms/Utils/BasicBlockUtils.h"
// for RecursivelyDeleteTriviallyDeadInstructions
#include "llvm/Transforms/Utils/Local.h"
void removeConditionalBranch(BranchInst *Branch) {
assert(Branch &&
Branch->isConditional() &&
Branch->getNumSuccessors() == 2);
BasicBlock *Parent = Branch->getParent();
BasicBlock *ThenBlock = Branch->getSuccessor(0);
BasicBlock *ElseBlock = Branch->getSuccessor(1);
BasicBlock *ThenSuccessor = ThenBlock->getUniqueSuccessor();
BasicBlock *ElseSuccessor = ElseBlock->getUniqueSuccessor();
assert(ThenSuccessor && ElseSuccessor && ThenSuccessor == ElseSuccessor);
Branch->eraseFromParent();
RecursivelyDeleteTriviallyDeadInstructions(Branch->getCondition());
DeleteDeadBlock(ThenBlock);
DeleteDeadBlock(ElseBlock);
IRBuilder<> Builder(Parent);
Builder.CreateBr(ThenSuccessor);
bool Merged = MergeBlockIntoPredecessor(ThenSuccessor);
assert(Merged);
}
This code only handles the simple case you've shown, with the then and else blocks both jumping unconditionally to a common join block (it will fail with an assertion error for anything more complicated). More complicated control flow will be a bit trickier to handle, but you should still be able to use this code as a starting point.

Input in LLVM, I think I do not understand dominance and the location of phi nodes

My goal is to do something simple in LLVM. I want to, using the C library function getchar, define an LLVM function that reads an input from the commandline. Here is my algorithm in pseudocode:
getInt:
get a character, set the value to VAL
check if VAL is '-'
if yes then set SGN to -1 and set VAL to the next character else set SGN to 1
set NV = to the next char minus 48
while (NV >= 0) // 48 is the first ASCII character that represents a number
set VAL = VAL*10
set VAL = VAL + NV
set NV to the next char minus 48
return SGN*VAL
So now, the LLVM code I come up with for doing this is in my head the most straightforward way to translate the above into LLVM IR. However, I get the error
"PHI nodes not grouped at the top of the basic block." If I move some things around to fix this error, I get errors about dominance. Below is the LLVM IR code that gives me the PHI nodes error. I believe I am misunderstanding something basic about LLVM IR, so any help you can give is super appreciated.
define i32 #getIntLoop() {
_L1:
%0 = call i32 #getchar()
%1 = phi i32 [ %0, %_L1 ], [ %3, %_L2 ], [ %8, %_L4 ]
%2 = icmp eq i32 %1, 45
br i1 %2, label %_L2, label %_L5
_L2: ; preds = %_L1
%3 = call i32 #getchar()
br label %_L3
_L3: ; preds = %_L4, %_L2
%4 = call i32 #getchar()
%5 = icmp slt i32 %4, 40
br i1 %5, label %_L5, label %_L4
_L4: ; preds = %_L3
%6 = sub i32 %4, 48
%7 = mul i32 %1, 10
%8 = add i32 %6, %7
br label %_L3
_L5: ; preds = %_L3, %_L1
br i1 %2, label %_L6, label %_L7
_L6: ; preds = %_L5
%9 = mul i32 -1, %1
ret i32 %9
_L7: ; preds = %_L5
ret i32 %1
}
You're getting a very clear error, though. According to the LLVM IR language reference:
There must be no non-phi instructions between the start of a basic
block and the PHI instructions: i.e. PHI instructions must be first in
a basic block.
You have a phi in L1 which violates this.
Why does it have %_L1 as one of its sources? There are no jumps to %_L1 anywhere else. I think you should first understand how phi works, possibly by compiling small pieces of C code into LLVM IR with Clang and see what gets generated.
Put simply, a phi is needed to have consistency in SSA form while being able to assign one of several values into the same register. Make sure you read about SSA - it explains Phi node as well. And additional good resource is the LLVM tutorial which you should go through. In particular, part 5 covers Phis. As suggested above, running small pieces of C through Clang is a great way to understand how things work. This is in no way "hacky" - it's the scientific method! You read the theory, think hard about it, form hypotheses about how things work and then verify those hypotheses by running Clang and seeing what it generates for real-life control flow.

Find values in a basicblock,which are computed in previous basicblocks

In a basicblock I wants to find all the values used in instructions, That are not computed in the same basicblock.
Example,
for.body5:
%i.015 = phi i32 [ 0, %for.body.lr.ph ], [ %inc, %for.body ]
%add1 = add nsw i32 %2, %i.015
%arrayidx = getelementptr inbounds [100 x i32]* %b, i32 0, i32 %i.015
store i32 %add1, i32* %arrayidx, align 4, !tbaa !0
%arrayidx2 = getelementptr inbounds [100 x i32]* %a, i32 0, i32 %i.015
store i32 %add1, i32* %arrayidx2, align 4, !tbaa !0
%inc = add nsw i32 %i.015, 1
%cmp = icmp slt i32 %inc, %3
br i1 %cmp, label %for.body, label %for.cond3.preheader
In above example i should get,
%2
%b
%a
%3
Which are declared and/or assigned in other basicblocks.
Please Suggest me a method.
Thanks in advance.
Hi I havent tested this out, but I would do something like this:
vector<Value*> values;
BasicBlock::iterator it;
User::op_iterator it;
// Iterate over all of the instructions in the Block
for (it=block->begin(); it++; it != block->end()){
// Iterate over the operands used by an instruction. 'op_begin' Defined in llvm::User class.
for (operand_it=it->op_begin(); operand_it++; operand_it != it->op_end() ){
// Could this if else statement be reduced?
// If this operand is an argument it was not defined in the block.
if (isa<Argument>(operand_it)){
values.push_back(operand_it);
}
// Otherwize, it could be a constant value or ...
else if (!isa<Instruction>(operand_it)){
continue;
}
// Check if the parent of the instruction is not the block in question.
else if (((Instruction*)operand_it)->getParent() != block){
values.push_back(operand_it);
}
}
}

nested if vs loop condition

I have to do a comparison and I want to know which will be faster.
1)
for (i=0;i<4;i++){
if (object1(i)==object2(i))
retval = true;
else {
retval = false;
break;
}
}
2)
if ( (object1(0)==object2(0) && (object1(1)==object2(1) && (object1(2)==object2(2) && (object1(3)==object2(3)){
retval = true;
else
retval = false;
Or both will perform the same?
Thanks for Advice
Strictly speaking the most efficient path would be:
retval = object1(0) == object2(0) && object1(1) == object2(1).....
This basically does the same as your loop, but doesn't have to compare the result to true to determine the outcome of the condition.
However, I strongly recommend keeping the loop, as it is far easier to adapt to add or remove numbers.
You need to measure. But in any case the first code can be simplified quite a bit:
for (i = 0; i < 4; ++i)
if (object1(i) != object2(i))
return false;
return true;
Now choose the more readable form. I’d choose the loop here, unless you have confirmed that there is a performance problem caused by this code.
If the optimization flags are on, then the compiler might produce same machine instructtions for both code, unlooping the for loop completely, as the exact number of iteration is known to the compiler:
loop unrolling
By the way, if you care so much, then you could write this:
bool retValue = (object1(0)==object2(0)) &&
(object1(1)==object2(1)) &&
(object1(2)==object2(2)) &&
(object1(3)==object2(3));
which avoids both: for loop, as well as if-else branch, and it doesn't depend on compiler optimization.
As always with optimization, the one and single rule is MEASURE.
Furthermore, I guess that the compiler could optimize this code in some ways you (and I) couldn't even imagine. Therefore I'd suggest to write it in the most readable form.
I like to play with the Try out LLVM and Clang page for this:
struct Object {
int operator()(int i) const;
};
bool loop(Object const& left, Object const& right) {
bool retval = false;
for (int i = 0; i < 4; i++) {
if (left(i) == right(i) )
retval = true;
else {
retval = false;
break;
}
}
return true;
}
bool inlineif(Object const& left, Object const& right) {
bool retval = true;
if ( left(0) == right(0) &&
left(1) == right(1) &&
left(2) == right(2) &&
left(3) == right(3))
retval = true;
else
retval = false;
return retval;
}
bool betterloop(Object const& left, Object const& right) {
for (int i = 0; i < 4; ++i)
if (left(i) != right(i))
return false;
return true;
}
bool betterif(Object const& left, Object const& right) {
return left(0) == right(0) &&
left(1) == right(1) &&
left(2) == right(2) &&
left(3) == right(3);
}
Produces the following IR for loops (regardless of how they are written):
define zeroext i1 #_Z4loopRK6ObjectS1_(%struct.Object* %left, %struct.Object* %right) uwtable {
br label %1
; <label>:1 ; preds = %7, %0
%i.0 = phi i32 [ 0, %0 ], [ %8, %7 ]
%2 = icmp slt i32 %i.0, 4
br i1 %2, label %3, label %9
; <label>:3 ; preds = %1
%4 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %left, i32 %i.0)
%5 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %right, i32 %i.0)
%6 = icmp eq i32 %4, %5
br i1 %6, label %7, label %9
; <label>:7 ; preds = %3
%8 = add nsw i32 %i.0, 1
br label %1
; <label>:9 ; preds = %3, %1
ret i1 true
}
And a very similar IR for the two if (so I'll give only one):
define zeroext i1 #_Z8betterifRK6ObjectS1_(%struct.Object* %left, %struct.Object* %right) uwtable {
%1 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %left, i32 0)
%2 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %right, i32 0)
%3 = icmp eq i32 %1, %2
br i1 %3, label %4, label %16
; <label>:4 ; preds = %0
%5 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %left, i32 1)
%6 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %right, i32 1)
%7 = icmp eq i32 %5, %6
br i1 %7, label %8, label %16
; <label>:8 ; preds = %4
%9 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %left, i32 2)
%10 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %right, i32 2)
%11 = icmp eq i32 %9, %10
br i1 %11, label %12, label %16
; <label>:12 ; preds = %8
%13 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %left, i32 3)
%14 = tail call i32 #_ZNK6ObjectclEi(%struct.Object* %right, i32 3)
%15 = icmp eq i32 %13, %14
br label %16
; <label>:16 ; preds = %12, %8, %4, %0
%17 = phi i1 [ false, %8 ], [ false, %4 ], [ false, %0 ], [ %15, %12 ]
ret i1 %17
}
The important instructions here is br which is the branching instruction. It can be used either as a simple goto or with conditions on the edges:
br i1 %11, label %12, label %16
means if i1 is true, go to label %12, otherwise go to label %16.
It seems that "naturally" LLVM will not unroll the traditional loop version, so the if version performs better here. I am quite surprised, actually, that it does not and I cannot figure out why it would not...
So, the inline if code might be a bit faster, but it might also be unnoticeable depending on the cost of left(i) == right(i) (and even then), as CPU are quite good at branch prediction.

Do modern C++ compilers inline functions which are called exactly once?

As in, say my header file is:
class A
{
void Complicated();
}
And my source file
void A::Complicated()
{
...really long function...
}
Can I split the source file into
void DoInitialStuff(pass necessary vars by ref or value)
{
...
}
void HandleCaseA(pass necessary vars by ref or value)
{
...
}
void HandleCaseB(pass necessary vars by ref or value)
{
...
}
void FinishUp(pass necessary vars by ref or value)
{
...
}
void A::Complicated()
{
...
DoInitialStuff(...);
switch ...
HandleCaseA(...)
HandleCaseB(...)
...
FinishUp(...)
}
Entirely for readability and without any fear of impact in terms of performance?
You should mark the functions static so that the compiler know they are local to that translation unit.
Without static the compiler cannot assume (barring LTO / WPA) that the function is only called once, so is less likely to inline it.
Demonstration using the LLVM Try Out page.
That said, code for readability first, micro-optimizations (and such tweaking is a micro-optimization) should only come after performance measures.
Example:
#include <cstdio>
static void foo(int i) {
int m = i % 3;
printf("%d %d", i, m);
}
int main(int argc, char* argv[]) {
for (int i = 0; i != argc; ++i) {
foo(i);
}
}
Produces with static:
; ModuleID = '/tmp/webcompile/_27689_0.bc'
target datalayout = "e-p:64:64:64-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:64:64-f32:32:32-f64:64:64-v64:64:64-v128:128:128-a0:0:64-s0:64:64-f80:128:128-n8:16:32:64"
target triple = "x86_64-unknown-linux-gnu"
#.str = private constant [6 x i8] c"%d %d\00" ; <[6 x i8]*> [#uses=1]
define i32 #main(i32 %argc, i8** nocapture %argv) nounwind {
entry:
%cmp4 = icmp eq i32 %argc, 0 ; <i1> [#uses=1]
br i1 %cmp4, label %for.end, label %for.body
for.body: ; preds = %for.body, %entry
%0 = phi i32 [ %inc, %for.body ], [ 0, %entry ] ; <i32> [#uses=3]
%rem.i = srem i32 %0, 3 ; <i32> [#uses=1]
%call.i = tail call i32 (i8*, ...)* #printf(i8* getelementptr inbounds ([6 x i8]* #.str, i64 0, i64 0), i32 %0, i32 %rem.i) nounwind ; <i32> [#uses=0]
%inc = add nsw i32 %0, 1 ; <i32> [#uses=2]
%exitcond = icmp eq i32 %inc, %argc ; <i1> [#uses=1]
br i1 %exitcond, label %for.end, label %for.body
for.end: ; preds = %for.body, %entry
ret i32 0
}
declare i32 #printf(i8* nocapture, ...) nounwind
Without static:
; ModuleID = '/tmp/webcompile/_27859_0.bc'
target datalayout = "e-p:64:64:64-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:64:64-f32:32:32-f64:64:64-v64:64:64-v128:128:128-a0:0:64-s0:64:64-f80:128:128-n8:16:32:64"
target triple = "x86_64-unknown-linux-gnu"
#.str = private constant [6 x i8] c"%d %d\00" ; <[6 x i8]*> [#uses=1]
define void #foo(int)(i32 %i) nounwind {
entry:
%rem = srem i32 %i, 3 ; <i32> [#uses=1]
%call = tail call i32 (i8*, ...)* #printf(i8* getelementptr inbounds ([6 x i8]* #.str, i64 0, i64 0), i32 %i, i32 %rem) ; <i32> [#uses=0]
ret void
}
declare i32 #printf(i8* nocapture, ...) nounwind
define i32 #main(i32 %argc, i8** nocapture %argv) nounwind {
entry:
%cmp4 = icmp eq i32 %argc, 0 ; <i1> [#uses=1]
br i1 %cmp4, label %for.end, label %for.body
for.body: ; preds = %for.body, %entry
%0 = phi i32 [ %inc, %for.body ], [ 0, %entry ] ; <i32> [#uses=3]
%rem.i = srem i32 %0, 3 ; <i32> [#uses=1]
%call.i = tail call i32 (i8*, ...)* #printf(i8* getelementptr inbounds ([6 x i8]* #.str, i64 0, i64 0), i32 %0, i32 %rem.i) nounwind ; <i32> [#uses=0]
%inc = add nsw i32 %0, 1 ; <i32> [#uses=2]
%exitcond = icmp eq i32 %inc, %argc ; <i1> [#uses=1]
br i1 %exitcond, label %for.end, label %for.body
for.end: ; preds = %for.body, %entry
ret i32 0
}
Depends on aliasing (pointers to that function) and function length (a large function inlined in a branch could throw the other branch out of cache, thus hurting performance).
Let the compiler worry about that, you worry about your code :)
A complicated function is likely to have its speed dominated by the operations within the function; the overhead of a function call won't be noticeable even if it isn't inlined.
You don't have much control over the inlining of a function, the best way to know is to try it and find out.
A compiler's optimizer might be more effective with shorter pieces of code, so you might find it getting faster even if it's not inlined.
If you split up your code into logical groupings the compiler will do what it deems best: If it's short and easy, the compiler should inline it and the result is the same. If however the code is complicated, making an extra function call might actually be faster than doing all the work inlined, so you leave the compiler the option to do that too. On top of all that, the logically split code can be far easier for a maintainer to grok and avoid future bugs.
I suggest you create a helper class to break your complicated function into method calls, much like you were proposing, but without the long, boring and unreadable task of passing arguments to each and every one of these smaller functions. Pass these arguments only once by making them member variables of the helper class.
Don't focus on optimization at this point, make sure your code is readable and you'll be fine 99% of the time.