how to concat the attribute names of the parent nodes - xslt

I have a XML Document like this:
<Module Name="DacInPlaceUpgradeLtmTest" Desc="" >
<TestCase Name="ExecuteInPlaceUpgradeTest">
<TestCase Name="BugRepro">
<TestCase Name="295130">
<Variation Id="1" Desc="Sql - EmptyAlterScript">
<Variation Id="2" Desc="Sql - EmptyDatabase">
</TestCase>
</TestCase>
</TestCase>
</Module>
I use xsl to get a value:
ExectionInplaceUPgradeTest BugRepro 295130
by using following template:
<xsl:template match="TestCase//Variation">
<xsl:for-each select="..#Name">
Today, I can only get 295130, I wonder how can I get all Attribtes of the parent nodes which is TestCase.

I wonder how can I get all Attributes of the parent nodes which is TestCase
You might need the XPath ancestor-or-self axis:
ancestor-or-self::TestCase/#Name
how to concat the attribte names of the parent nodes
It really depends on the template context and on the code you are already working on. taking as a reference your fragment, I would write better:
<xsl:template match="TestCase[Variation]">
<xsl:for-each select="ancestor-or-self::TestCase/#Name">
<xsl:value-of select="concat(.,' ')"/>
</xsl:for-each>
</xsl:template>
This will print the wanted string starting from the TestCase node which has a Variation node as a child.

This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="Variation[#Id = 1]">
<xsl:apply-templates mode="printName"
select="ancestor::TestCase"/>
</xsl:template>
<xsl:template match="TestCase" mode="printName">
<xsl:if test="not(position()=1)">
<xsl:text> </xsl:text>
</xsl:if>
<xsl:value-of select="#Name"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
when applied on the provided XML document:
<Module Name="DacInPlaceUpgradeLtmTest" Desc="" >
<TestCase Name="ExecuteInPlaceUpgradeTest">
<TestCase Name="BugRepro">
<TestCase Name="295130">
<Variation Id="1" Desc="Sql - EmptyAlterScript"/>
<Variation Id="2" Desc="Sql - EmptyDatabase"/>
</TestCase>
</TestCase>
</TestCase>
</Module>
produces the wanted, correct result:
ExecuteInPlaceUpgradeTest BugRepro 295130
II. XPath 2.0/XSLT 2.0 solution
//TestCase[Variation]
/ancestor-or-self::TestCase
/#Name/string(.)
The above XPath 2.0 expression when evaluated on the above XML document produces exactly the wanted, correct result:
ExecuteInPlaceUpgradeTest BugRepro 295130
It can be used in the following XSLT 2.0 solution:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:sequence select=
"//TestCase[Variation]
/ancestor-or-self::TestCase
/#Name/string(.)
"/>
</xsl:template>
</xsl:stylesheet>

Related

Is there a way to replace the for-each with apply-templates in an XSLT Transform?

Environment: XSLT 1.0
The transform will take each element in partOne section and lookup #field attribute in partTwo section using #find attribute and then output #value attribute.
I'm using a for-each loop and was wondering if apply-templates could work?
xml
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="file.xslt"?>
<xml>
<partOne>
<target field="hello"/>
<target field="world"/>
</partOne>
<partTwo>
<number input="2" find="hello" value="valone" />
<number input="2" find="world" value="valtwo" />
<number input="2" find="hello" value="valthree" />
<number input="2" find="world" value="valfour" />
</partTwo>
</xml>
xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="/xml/partOne/target">
,<xsl:value-of select="#field"/>
<xsl:for-each select="/xml/partTwo/number[#find=current()/#field]">
,<xsl:value-of select="#value"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output:
,hello
,valone
,valthree
,world
,valtwo
,valfour
Well, it seems straight-forward to change
<xsl:for-each select="/xml/partTwo/number[#find=current()/#field]">
,<xsl:value-of select="#value"/>
</xsl:for-each>
to
<xsl:apply-templates select="/xml/partTwo/number[#find=current()/#field]"/>
with a template
<xsl:template match="partTwo/number">
,<xsl:value-of select="#value"/>
</xsl:template>
As your root template so far processes all elements you need to change it to
<xsl:template match="/">
<xsl:apply-templates select="xml/partOne"/>
</xsl:template>
to avoid processing the partTwo element(s) twice.
For the cross-reference you might want to use a key in both versions:
<xsl:key name="ref" match="partTwo/number" use="#find"/>
and then select="key('ref', #field)" instead of select="/xml/partTwo/number[#find=current()/#field]" for the apply-templates or for-each.

Compare data of 2 xmls in xslt

I am new to XSL. Hence please help me with the below.
I have 2 xmls. I have to do the following in XSL transformation.
if Employee/EmployeeInfo/FirstName = EmployeeSegment/EmployeeSummary/GivenName and Employee/EmployeeInfo/LastName = EmployeeSegment/EmployeeSummary/Surname
employeeId = EmployeeSegment/EmployeeSummary/EmpId
XML1
<Employee>
<EmployeeInfo>
<FirstName>ABC</FirstName>
<LastName>DEF</LastName>
</EmployeeInfo>
</Employee>
XML2
<EmployeeSegment>
<EmployeeSummary>
<EmpId>1234</EmpId>
<GivenName>ABC</GivenName>
<Surname>DEF</Surname>
</EmployeeSummary>
</EmployeeSegment>
I have tried the following. It is not working.
<xsl:param name="cjEmployeeSegment" select="document('CJ_Response.xml')"/>
<xsl:for-each select="/ns3:Employee/ns3:EmployeeInfo">
<xsl:variable name="empFirstName">
<xsl:value-of select="ns1:FirstName"/>
</xsl:variable>
<xsl:variable name="empLastName">
<xsl:value-of select="ns1:LastName"/>
</xsl:variable>
<xsl:for-each select="$cjEmployeeSegment/v32:EmployeeSegment/v31:EmployeeSummary">
<xsl:if test="$empFirstName=v31:GivenName and $empLastName=v31:Surname">
<ns12:EmployeeIdentifier>
<ns12:EmployeeID>
<xsl:value-of select="v31:EmpId"/>
</ns12:EmployeeID>
</ns12:EmployeeIdentifier>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
Assuming you are processing the following input:
XML
<Employee>
<EmployeeInfo>
<FirstName>ABC</FirstName>
<LastName>DEF</LastName>
</EmployeeInfo>
</Employee>
and there is another XML document named CJ_Response.xml:
<EmployeeSegment>
<EmployeeSummary>
<EmpId>1234</EmpId>
<GivenName>ABC</GivenName>
<Surname>DEF</Surname>
</EmployeeSummary>
</EmployeeSegment>
you can use the following stylesheet:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="cj_Response" select="document('CJ_Response.xml')"/>
<xsl:template match="/Employee">
<root>
<xsl:for-each select="EmployeeInfo">
<xsl:variable name="lookup" select="$cj_Response/EmployeeSegment/EmployeeSummary[GivenName = current()/FirstName and Surname = current()/LastName]" />
<xsl:if test="$lookup">
<EmployeeIdentifier>
<EmployeeID>
<xsl:value-of select="$lookup/EmpId"/>
</EmployeeID>
</EmployeeIdentifier>
</xsl:if>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
to return:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<EmployeeIdentifier>
<EmployeeID>1234</EmployeeID>
</EmployeeIdentifier>
</root>
Of course, this will fail miserably if there are two or more employees with the same name.

How to iterate each xml tag having different names and values ? How to start iterating from a particular tag ? in xslt 2.0

I have the below xml text,
<SUBSCRIBER>
<Anumber>639081000000</Anumber>
<FirstCallDate>20130430104419</FirstCallDate>
<SetyCode>TNT</SetyCode>
<Status>ACT</Status>
<RoamIndicator/>
<PreloadCode>P1</PreloadCode>
<CreationDate>20130116100037</CreationDate>
<PreActiveEndDate/>
<ActiveEndDate>20130804210541</ActiveEndDate>
<GraceEndDate>20140502210541</GraceEndDate>
<RetailerIndicator/>
<OnPeakAccountID>9100</OnPeakAccountID>
<OnPeakSmsExpDate>20130804210504</OnPeakSmsExpDate>
<UnivWalletAcc/>
<UnliSmsOnCtl>20130606211359</UnliSmsOnCtl>
<UnliSmsTriCtl/>
<UnliSmsGblCtl/>
<UnliMocOnCtl>20130606211359</UnliMocOnCtl>
<UnliMocTriCtl/>
<UnliMocGblCtl/>
<UnliSurfFbcCtl>20130606212353</UnliSurfFbcCtl>
</SUBSCRIBER>
How can I iterate/parse over each xml tag name and get the value ( I need the name of the tag and value in a different variables) ? And also, How can I start iterating from particular tag name ? Ex: I would like to start iterating UnivWalletAcc
Please advise.
So far, I have tried the following,
<xsl:template match="SUBSCRIBER">
<xsl:variable name="tagName">
<xsl:value-of select="/*/*/name()"/>
</xsl:variable>
<xsl:variable name="tagValue">
<xsl:value-of select="/*/*/text()"/>
</xsl:variable>
<xsl:value-of select="$tagName"/>
<xsl:value-of select="$tagValue"/>
</xsl:template>
As an alternative to Veenstra's solution, instead of the xsl:if in the SUBSCRIBER/* template, you can control the iteration in the apply-templates:
<xsl:template match="SUBSCRIBER">
<data>
<xsl:apply-templates select="UnivWalletAcc,
UnivWalletAcc/following-sibling::*" />
</data>
</xsl:template>
With the following XSLT you can loop through all childs of the node SUBSCRIBER:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<!-- Identity template that will loop over all nodes and attributes -->
<xsl:template match="#*|node()">
<xsl:apply-templates select="#*|node()" />
</xsl:template>
<!-- Template to match the root and create new root -->
<xsl:template match="SUBSCRIBER">
<data>
<xsl:apply-templates select="#*|node()" />
</data>
</xsl:template>
<!-- Template to loop over all childs of SUBSCRIBER node -->
<xsl:template match="SUBSCRIBER/*">
<!-- This will test if we have seen the UnivWalletAcc node already, if so, output something, otherwise, output nothing -->
<xsl:if test="preceding-sibling::UnivWalletAcc or self::UnivWalletAcc">
<tag>
<tagName><xsl:value-of select="name()" /></tagName>
<tagValue><xsl:value-of select="." /></tagValue>
</tag>
</xsl:if>
</xsl:template>
</xsl:stylesheet>

XPATH for first element whose name is among the names of some other elements

<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
<choice>
I want to select the first element in <choice> whose name matches the name of any element in <choices>.
If name(node-set) returned a list of names instead of only the name of the first node, I could use
select="choice/*[name() = name(choices/*)][1]"
But it doesn't (at least not in 1.0), so instead I join the names together in a string and use contains():
<xsl:variable name="choices.str">
<xsl:for-each select="choices/*">
<xsl:text> </xsl:text><xsl:value-of select="concat(name(),' ')"/>
</xsl:for-each>
</xsl:variable>
<xsl:apply-templates select="choice/*[contains($choices.str,name())][1]"/>
and get what I want:
Red, the value of <corr>
Is there a more straightforward way?
I. Use this XPath 2.0 one-liner:
/*/choice/*[name() = /*/choices/*/name()][1]
When this XPath expression is evaluated against the following XML document (the provided one, but corrected to become a well-formed XML document):
<t>
<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
</choice>
</t>
the correct element is selected:
<corr>Red</corr>
II. XSLT 1.0 (no keys!):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="vNames">
<xsl:for-each select="/*/choices/*">
<xsl:value-of select="concat(' ', name(), ' ')"/>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/">
<xsl:copy-of select=
"/*/choice/*
[contains($vNames, concat(' ', name(), ' '))]
[1]"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the same XML document (above), again the correct element is selected (and copied to the output):
<corr>Red</corr>
III. Using keys:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kChoiceByName" match="choice/*"
use="boolean(/*/choices/*[name()=name(current())])"/>
<xsl:template match="/">
<xsl:copy-of select="/*/choice/*[key('kChoiceByName', true())][1]"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied against the same XML document (above), the same correct result is produced:
<corr>Red</corr>
It is recommended to the reader to try to understand how this all "works" :)
You can use the key() function like this...
When this input document...
<t>
<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
</choice>
</t>
...is supplied as input to this XSLT 1.0 style-sheet...
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:key name="kChoices" match="choices/*" use="name()" />
<xsl:template match="/">
<xsl:variable name="first-choice" select="(*/choice/*[key('kChoices',name())])[1]" />
<xsl:value-of select="$first-choice" />
<xsl:text>, the value of <</xsl:text>
<xsl:value-of select="name( $first-choice)" />
<xsl:text>></xsl:text>
</xsl:template>
</xsl:stylesheet>
...this output text is produced...
Red, the value of <corr>
XSLT 2.0 Aside
In XSLT 2.0, you would be able to use the following alternatives for the computation of the $first-choice variable...
Option 1:
(*/choice/*[for $c in . return ../../choices/*[name()=name($c)]])[1]
Option 2:
(*/choice/*[some $c in ../../choices/* satisfies name($c)=name()])[1]

XPath/XSLT nested predicates: how to get the context of outer predicate?

It seems that this question was not discussed on stackoverflow before, save for Working With Nested XPath Predicates ... Refined where the solution not involving nested predicates was offered.
So I tried to write the oversimplified sample of what I'd like to get:
Input:
<root>
<shortOfSupply>
<food animal="doggie"/>
<food animal="horse"/>
</shortOfSupply>
<animalsDictionary>
<cage name="A" animal="kittie"/>
<cage name="B" animal="dog"/>
<cage name="C" animal="cow"/>
<cage name="D" animal="zebra"/>
</animals>
</root>
Output:
<root>
<hungryAnimals>
<cage name="B"/>
<cage name="D"/>
</hungryAnimals>
</root>
or, alternatively, if there is no intersections,
<root>
<everythingIsFine/>
</root>
And i want to get it using a nested predicates:
<xsl:template match="cage">
<cage>
<xsl:attribute name="name">
<xsl:value-of select="#name"/>
</xsl:attribute>
</cage>
</xsl:template>
<xsl:template match="/root/animalsDictionary">
<xsl:choose>
<!-- in <food> in <cage> -->
<xsl:when test="cage[/root/shortOfSupply/food[ext:isEqualAnimals(./#animal, ?????/#animal)]]">
<hungryAnimals>
<xsl:apply-templates select="cage[/root/shortOfSupply/food[ext:isEqualAnimals(#animal, ?????/#animal)]]"/>
</hungryAnimals>
</xsl:when>
<xsl:otherwise>
<everythingIsFine/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
So what should i write in place of that ??????
I know i could rewrite the entire stylesheet using one more template and extensive usage of variables/params, but it makes even this stylesheet significantly more complex, let alone the real stylesheet i have for real problem.
It is written in XPath reference that the dot . sign means the current context node, but it doesn't tell whether there is any possibility to get the node of context before that; and i just can't believe XPath is missing this obvious feature.
XPath 2.0 one-liner:
for $a in /*/animalsDictionary/cage
return
if(/*/shortOfSupply/*[my:isA($a/#animal, #animal)])
then $a
else ()
When applied on the provided XML document selects:
<cage name="B"/>
<cage name="D"/>
One cannot use a single XPath 1.0 expression to find that a given cage contains a hungry animal.
Here is an XSLT solution (XSLT 2.0 is used only to avoid using an extension function for the comparison -- in an XSLT 1.0 solution one will use an extension function for the comparison and the xxx:node-set() extension to test if the RTF produced by applying templates in the body of the variable contains any child element):
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:my="my:my" exclude-result-prefixes="xs my">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<my:Dict>
<a genName="doggie">
<name>dog</name>
<name>bulldog</name>
<name>puppy</name>
</a>
<a genName="horse">
<name>horse</name>
<name>zebra</name>
<name>pony</name>
</a>
<a genName="cat">
<name>kittie</name>
<name>kitten</name>
</a>
</my:Dict>
<xsl:variable name="vDict" select=
"document('')/*/my:Dict/a"/>
<xsl:template match="/">
<root>
<xsl:variable name="vhungryCages">
<xsl:apply-templates select=
"/*/animalsDictionary/cage"/>
</xsl:variable>
<xsl:choose>
<xsl:when test="$vhungryCages/*">
<hungryAnimals>
<xsl:copy-of select="$vhungryCages"/>
</hungryAnimals>
</xsl:when>
<xsl:otherwise>
<everythingIsFine/>
</xsl:otherwise>
</xsl:choose>
</root>
</xsl:template>
<xsl:template match="cage">
<xsl:if test="
/*/shortOfSupply/*[my:isA(current()/#animal,#animal)]">
<cage name="{#name}"/>
</xsl:if>
</xsl:template>
<xsl:function name="my:isA" as="xs:boolean">
<xsl:param name="pSpecName" as="xs:string"/>
<xsl:param name="pGenName" as="xs:string"/>
<xsl:sequence select=
"$pSpecName = $vDict[#genName = $pGenName]/name"/>
</xsl:function>
</xsl:stylesheet>
When this transformation is applied on the provided XML document (corrected to be well-formed):
<root>
<shortOfSupply>
<food animal="doggie"/>
<food animal="horse"/>
</shortOfSupply>
<animalsDictionary>
<cage name="A" animal="kittie"/>
<cage name="B" animal="dogs"/>
<cage name="C" animal="cow"/>
<cage name="D" animal="zebras"/>
</animalsDictionary>
</root>
the wanted, correct result is produced:
<root>
<hungryAnimals>
<cage name="B"/>
<cage name="D"/>
</hungryAnimals>
</root>
Explanation: Do note the use of the XSLT current() function.
XPath 1.0 is not "relationally complete" - it can't do arbitrary joins. If you're in XSLT, you can always get round the limitations by binding variables to intermediate nodesets, or (sometimes) by using the current() function.
XPath 2.0 introduces range variables, which makes it relationally complete, so this limitation has gone.
Doesn't <xsl:when test="cage[#animal = /root/shortOfSupply/food/#animal]"> suffice to express your test condition?
Notice The dot operator in XPath is related to the current context. In XSLT the current template context_ is given by the function current(), which most of the time (not always) coincides with the ..
You can perform the test (and the apply templates as well), using the parent axis abbreviation (../):
cage[#animal=../../shortOfSupply/food/#animal]
Moreover the match pattern in the the first template is wrong, it should be relative to the root:
/root/animalsDictionary
#Martin suggestion is also obviously correct.
Your final template slightly modified:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="root/animalsDictionary">
<xsl:choose>
<xsl:when test="cage[#animal=../../shortOfSupply/food/#animal]">
<hungryAnimals>
<xsl:apply-templates select="cage[#animal
=../../shortOfSupply/food/#animal]"/>
</hungryAnimals>
</xsl:when>
<xsl:otherwise>
<everythingIsFine/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="cage">
<cage name="{#name}"/>
</xsl:template>
</xsl:stylesheet>