Code for searching for a string in a binary file - c++

Question

I have asked this question a few days ago:
How to look for an ANSI string in a binary file?
and I got a really nice answer, what later turned into a much harder question: Can input iterators be used where forward iterators are expected? what is now really not on a level what I could understand.
I am still learning C++ and I am looking for an easy way to search for a string in a binary file.
Could someone show me a simple code for a minimalistic C++ console program which looks for a string in a binary file and outputs the locations to stdout?
Possibly, can you show me
a version where the file is being copied to memory (supposing the binary file is small)
and an other one which uses the proper way from the linked questions
Sorry if it sounds like I'm asking for someone's code, but I am just learning C++ and I think maybe others could benefit from this question if someone could post some high quality code what is nice to learn from.

Answer 1

Your requirement specification is unclear, for example - where does "121" appear in "12121"... just at the first character (after which searching continues at the 4th), or at the 3rd as well? The code below uses the former approach.
#include <iostream>
#include <fstream>
#include <string>
#include <string.h>
int main(int argc, const char* argv[])
{
if (argc != 3)
{
std::cerr << "Usage: " << argv[0] << " filename search_term\n"
"Prints offsets where search_term is found in file.\n";
return 1;
}
const char* filename = argv[1];
const char* search_term = argv[2];
size_t search_term_size = strlen(search_term);
std::ifstream file(filename, std::ios::binary);
if (file)
{
file.seekg(0, std::ios::end);
size_t file_size = file.tellg();
file.seekg(0, std::ios::beg);
std::string file_content;
file_content.reserve(file_size);
char buffer[16384];
std::streamsize chars_read;
while (file.read(buffer, sizeof buffer), chars_read = file.gcount())
file_content.append(buffer, chars_read);
if (file.eof())
{
for (std::string::size_type offset = 0, found_at;
file_size > offset &&
(found_at = file_content.find(search_term, offset)) !=
std::string::npos;
offset = found_at + search_term_size)
std::cout << found_at << std::endl;
}
}
}

Answer 2

This is one way to do part 1. Not sure I would I describe it as high quality but maybe on the minimalist side.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(int argc, char *argv[])
{
std::ifstream ifs(argv[1], ios::binary);
std::string str((std::istreambuf_iterator<char>(ifs)), std::istreambuf_iterator<char>());
size_t pos = str.find(argv[2]);
if (pos != string::npos)
cout << "string found at position: " << int(pos) << endl;
else
cout << "could not find string" << endl;
return 0;
}